Chapter 9 Solids and Fluids (c)
EXAMPLE A small swimming pool has an area of 0 square meters. A wooden 4000-kg statue of density 500 kg/m 3 is then floated on top of the pool. How far does the water rise? Note: Density of water = 000 kg/m 3
Solution Given: ρ wood /ρ H0 = 0.5, A = 0 m, M = 4000 kg Find: h h Level is the same as if 4000 kg of water were added = 4 m 3 Consider problem: A volume V = 4 m 3 of water is added to a swimming pool. What is h? h = V / A = 40 cm
. Three objects rest on bathroom scales at a lake bottom. Object is a lead brick of volume 0. m 3 Object is a gold brick of volume 0. m 3 Object 3 is a lead brick of volume 0. m 3 DATA: specific gravity of lead =.3 specific gravity of gold = 9.3 specific gravity of mercury = 3.6 Which statement is true? a) # and # have the same buoyant force b) # and # register the same weights on the scales c) # and #3 have the same buoyant force d) # and #3 register the same weights on the scales e) If the lake were filled with mercury, the scales would not change. Quiz. What is your section number?
Equation of Continuity What goes in must come out! M = mass density ρa x = ρav t Mass that passes a point in pipe during time t Eq.of Continuity ρ A v = ρ A v
Example Water flows through a 4.0 cm diameter pipe at 5 cm/s. The pipe then narrows downstream and has a diameter of of.0 cm. What is the velocity of the water through the smaller pipe? Eq.of Continuity ρ A v = ρ A v Solution A v v = = r r A v v = 4v = 0 cm/s
Laminar Flow and Turbulence Laminar or Streamline Flow: Fluid elements move along smooth paths that don t cross Friction in laminar flow is called viscosity Turbulent flow Irregular paths Sets in for high gradients (large velocities or small pipes)
Laminar Flow No turbulence Non-viscous Ideal Fluids No friction between fluid layers Incompressible Density is same everywhere
Bernoulli s Equation P + ρv + ρgy = constant Physical content: the sum of the pressure, kinetic energy per unit volume, and the potential energy per unit volume has the same value at all points along a streamline. How can we derive this?
Bernoulli s Equation: derivation Physical basis: Work-energy relation All together now: With We get:
Example: Venturi Meter A very large pipe carries water with a very slow velocity and empties into a small pipe with a high velocity. If P is 7000 Pa lower than P, what is the velocity of the water in the small pipe?
Solution Given: P = 7000 Pa, ρ = 000 kg/m 3 Find: v Basic formula P + ρgh + ρv = constant P = v P v + ρ P = ρ v = 3.74 m/s
Applications of Bernoulli s Equation Venturi meter Curve balls Airplanes Beach Ball Demo
Example Water drains out of the bottom of a cooler at 3 m/s, what is the depth of the water above the valve? Basic formula Solution a b P + ρgh + ρv P a = constant + ρ gha + ρva = Pb + ρghb + v h = = 45.9 cm g Compare water at top(a) of cooler with water leaving valve(b). ρv b
Viscosity Diffusion Osmosis Three Vocabulary Words
Viscosity F = η Av d Viscosity refers to friction between the layers Pressure drop required to force water through pipes (Poiselle s Law) At high enough velocity, turbulence sets in
Diffusion Molecules move from region of high concentration to region of low concentration Fick s Law: Mass C C Diffusion rate = = DA time L D = diffusion coefficient
Osmosis Osmosis is the movement of water through a boundary while denying passage to specific molecules, e.g. salts