CHAPTER 2: FORCES AND MOTION

Similar documents
Chapter 2: FORCE and MOTION

Physics-MC Page 1 of 29 Inertia, Force and Motion 1.

Wallace Hall Academy

REVISING MECHANICS (LIVE) 30 JUNE 2015 Exam Questions

St. Joseph s Anglo-Chinese School

Mechanics. Time (s) Distance (m) Velocity (m/s) Acceleration (m/s 2 ) = + displacement/time.

Page 2. Example Example Example Jerk in a String Example Questions B... 39

Momentum Practice Problems

EDEXCEL NATIONAL CERTIFICATE/DIPLOMA MECHANICAL PRINCIPLES AND APPLICATIONS NQF LEVEL 3 OUTCOME 2

Honors Physics Review

Topic 2 Revision questions Paper

Newton s 3 Laws of Motion

Name. VCE Physics Unit 3 Preparation Work

Chapter Work, Energy and Power. Q1. The co-efficient of restitution e for a perfectly elastic collision is [1988] (a) 1 (b) 0 (c) (d) 1 Ans: (a)

Force. The cause of an acceleration or change in an object s motion. Any kind of a push or pull on an object.

Physics 101 Lecture 5 Newton`s Laws

Motion. Argument: (i) Forces are needed to keep things moving, because they stop when the forces are taken away (evidence horse pulling a carriage).

Physics 12 Final Exam Review Booklet # 1

3. What type of force is the woman applying to cart in the illustration below?

24/06/13 Forces ( F.Robilliard) 1

3/10/2019. What Is a Force? What Is a Force? Tactics: Drawing Force Vectors

UNIVERSITY OF MALTA G.F. ABELA JUNIOR COLLEGE

The diagram below shows a block on a horizontal frictionless surface. A 100.-newton force acts on the block at an angle of 30. above the horizontal.

A+B. Scalar quantities are described by magnitude only (examples: distance, speed, temperature, energy, and mass).

Version PREVIEW Semester 1 Review Slade (22222) 1

Study Guide For Midterm - 25 weeks Physics Exam. d. the force exerted by a towing cable on the car. c. the upward force the road exerts on the car.

LAWS OF MOTION Newtons laws of motion. (i) First law: Law of inertia. Every body continues to be in its state of rest or of uniform motion in a

AQA Physics P2 Topic 1. Motion

WORK, POWER AND ENERGY

What Is a Force? Slide Pearson Education, Inc.

OCR Physics Specification A - H156/H556

1. The diagram below shows the variation with time t of the velocity v of an object.

1. A tennis ball of mass m moving horizontally with speed u strikes a vertical tennis racket. The ball bounces back with a horizontal speed v.

3. How long must a 100 N net force act to produce a change in momentum of 200 kg m/s? (A) 0.25 s (B) 0.50 s (C) 1.0 s (D) 2.0 s (E) 4.

MOMENTUM, IMPULSE & MOMENTS

4.) A baseball that weighs 1.6 N leaves a bat with a speed of 40.0 m/s. Calculate the kinetic energy of the ball. 130 J

UNIT 2G. Momentum & It s Conservation

The graph shows how an external force applied to an object of mass 2.0 kg varies with time. The object is initially at rest.

2017 PHYSICS FINAL REVIEW PACKET EXAM BREAKDOWN

Simon Fraser University 2000 April 18 Physics 100 Final Examination

Subject: Triple Physics Unit title: P4.5 Forces (Paper 2) Strand Content Checklist (L) R A G Forces and their interactions

A. B. C. D. E. v x. ΣF x

Physics. Assignment-1(UNITS AND MEASUREMENT)

Forces & Newton s Laws. Honors Physics

Sometimes (like on AP test) you will see the equation like this:

AS Unit G481: Mechanics

Isaac Newton ( ) 1687 Published Principia Invented Calculus 3 Laws of Motion Universal Law of Gravity

ADVANCED LEVEL PHYSICS ECHANICS

Forces. Isaac Newton stated 3 laws that deal with forces and describe motion. Backbone of Physics

Q2. A book whose mass is 2 kg rests on a table. Find the magnitude of the force exerted by the table on the book.

Center of Mass & Linear Momentum

PRACTICE TEST for Midterm Exam

Extra Circular Motion Questions

CHAPTER 2 TEST REVIEW

1. A train moves at a constant velocity of 90 km/h. How far will it move in 0.25 h? A. 10 km B km C. 25 km D. 45 km E. 50 km

The Laws of Motion. Newton s first law Force Mass Newton s second law Gravitational Force Newton s third law Examples

Force, Energy & Periodic Motion. Preparation for unit test

Chapter 4: Newton s Laws of Motion

AP Physics Momentum Practice Test. Answers: A,E,E,A,E,B,D,C,B,A,B,E,D,C 16.(a)5450,5650 (b)2.25e7 (c)3 (d)1.5e7 17.(a)9 (b)2 (c)1.5 (d) (e).

1. A sphere with a radius of 1.7 cm has a volume of: A) m 3 B) m 3 C) m 3 D) 0.11 m 3 E) 21 m 3

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.

Welcome back to Physics 211

Physics 111 Lecture 4 Newton`s Laws

Pleeeeeeeeeeeeeease mark your UFID, exam number, and name correctly. 20 problems 3 problems from exam 2

W = F x W = Fx cosθ W = Fx. Work

Written Homework problems. Spring (taken from Giancoli, 4 th edition)

v (m/s) 10 d. displacement from 0-4 s 28 m e. time interval during which the net force is zero 0-2 s f. average velocity from 0-4 s 7 m/s x (m) 20

AP PHYSICS 1. Energy 2016 EDITION

Chapter 4. Forces and Newton s Laws of Motion. continued

Why constant (or straight line) motion? Remember, if an object turns at a constant speed it is accelerating.

(35+70) 35 g (m 1+m 2)a=m1g a = 35 a= =3.27 g 105

*ANSWER KEY * ANSWER KEY* ANSWER KEY* Newton's First Law of Motion Study Guide

Kinematics 1D Kinematics 2D Dynamics Work and Energy

3. Kinetics of Particles

Everybody remains in a state of rest or continues to move in a uniform motion, in a straight line, unless acting on by an external force.

Chapter 4. Answer Key. Physics Lab Sample Data. Mini Lab Worksheet. Tug-of-War Challenge. b. Since the rocket takes off from the ground, d i

The Concept of Force. field forces d) The gravitational force of attraction between two objects. f) Force a bar magnet exerts on a piece of iron.

PS113 Chapter 4 Forces and Newton s laws of motion

MOTION & FORCES. Observing Motion. Speed and Velocity. Distance vs. Displacement CHAPTERS 11 & 12

Exam Question 5: Work, Energy, Impacts and Collisions. June 18, Applied Mathematics: Lecture 5. Brendan Williamson.

7. Two forces are applied to a 2.0-kilogram block on a frictionless horizontal surface, as shown in the diagram below.

Chapter 4. Table of Contents. Section 1 Changes in Motion. Section 2 Newton's First Law. Section 3 Newton's Second and Third Laws

Chapter 5 Force and Motion

AP Physics C. Momentum. Free Response Problems

Physics Pre-comp diagnostic Answers

1 Forces. 2 Energy & Work. GS 104, Exam II Review

2016 PHYSICS FINAL REVIEW PACKET

HSC PHYSICS ONLINE B F BA. repulsion between two negatively charged objects. attraction between a negative charge and a positive charge

Preparing for Six Flags Physics Concepts

Thomas Whitham Sixth Form Mechanics in Mathematics

No Brain Too Small PHYSICS

Momentum, Impulse, Work, Energy, Power, and Conservation Laws

frictionless horizontal surface. The bullet penetrates the block and emerges with a velocity of o

PHYSICS. Chapter 5 Lecture FOR SCIENTISTS AND ENGINEERS A STRATEGIC APPROACH 4/E RANDALL D. KNIGHT Pearson Education, Inc.

Momentum, Impulse, Work, Energy, Power, and Conservation Laws

AQA Forces Review Can you? Scalar and vector quantities Contact and non-contact forces Resolving forces acting parallel to one another

Announcements. Principle of Work and Energy - Sections Engr222 Spring 2004 Chapter Test Wednesday

Recall: Gravitational Potential Energy

Chapter 5 Lecture. Pearson Physics. Newton's Laws of Motion. Prepared by Chris Chiaverina Pearson Education, Inc.


Transcription:

CHAPTER 2: FORCES AND MOTION 2.1 Linear Motion Linear Motion is motion in a straight line with constant acceleration. Classification Scalar Vector Physical quantity with Magnitude only Magnitude and direction Example Distance Speed Displacement Velocity Acceleration Definitions: Speed: Velocity: Acceleration: Rate of change of distance Rate of change of displacement Rate of change of velocity 2.1.1 Equations of Linear Motion s = ½ (u + v) t v u a t s = ut + ½ at 2 where s = displacement [m] u = initial velocity [m s -1 ] v = final velocity [m s -1 ] t = time [s] v 2 = u 2 + 2as Hoo Sze Yen www.physicsrox.com Page 1 of 13

2.2 Linear Motion Graphs 2.2.1 Ticker timer Ticker timers work with alternating current (AC) only. Ticker timers typically have a frequency of 50 Hz. The period of one tick is 1 = 0.02 s. 50 Movement Explanation Consistent distance = uniform velocity Short distance = low velocity Long distance = high velocity Increasing distance = increasing velocity / acceleration Decreasing distance = decreasing velocity / deceleration To calculate the average velocity from a ticker tape strip or graph: Average velocity Total distance Total time To calculate the acceleration from a ticker tape strip or graph: s1 Step 1: Calculate the initial velocity, u. t s2 Step 2: Calculate the final velocity, v. t v u Step 3: Calculate the acceleration, a. t s 1 s 2 s 2 Remember! Time for acceleration must be ONE LESS tick/strip s 1 Hoo Sze Yen www.physicsrox.com Page 2 of 13

2.2.2 Linear Motion Graphs v = 0 (a = 0) Displacement-time graphs Velocity = slope of the graph s/m Velocity-time graphs Acceleration = slope of the graph Displacement = area under the graph v/m s -1 Acceleration-time graphs Velocity = area under the graph a/m s -2 v = constant (a = 0) s/m v/m s -1 a/m s -2 v a = constant s/m v/m s -1 a/m s -2 v a = constant s/m v/m s -1 a/m s -2 v a v/m s -1 a/m s -2 v a v/m s -1 a/m s -2 REMEMBER! gradient gradient DISPLACEMENT Displacement-time graph VELOCITY Velocity-time graph ACCELERATION Acceleration-time graph area under the graph area under the graph Hoo Sze Yen www.physicsrox.com Page 3 of 13

2.3 Inertia Inertia is the natural characteristics of an object to oppose any attempted change on its original state, whether at rest or in motion. It is the tendency of an object to remain at rest, or to keep moving at constant speed in a straight line Newton s First Law of Motion(Law of Inertia) Every object in a state of uniform motion tends to remain in that state of motion unless an external force is applied to it. 2.4 Momentum Momentum = mass velocity p = mv where p = momentum [kg m s -1 ] m = mass [kg] v = velocity [m s -1 ] Principle of conservation of momentum In any collision or interaction between two or more objects in an isolated system, the total momentum before collision is equal to the total momentum after collision. m 1 u 1 + m 2 u 2 = m 1 v 1 + m 2 v 2 Three types of collisions: 1) Elastic collision Both objects move separately after collision. Note: In an elastic collision, the kinetic energy is conserved. m 1 u 1 + m 2 u 2 = m 1 v 1 + m 2 v 2 E.g.: a cue ball hitting a snooker ball, bowling ball striking a pin, bumper cars colliding into each other 2) Inelastic collision Both objects move together after collision. m 1 u 1 + m 2 u 2 = (m 1 + m 2 )v E.g.: a boy running and jumping onto a skateboard and both move together after collision 3) Explosion Both objects are initially stationary, and move in opposite directions after the explosion. m 1 v 1 = - m 2 v 2 E.g. : a bullet fired from a stationary gun, a man jumping out of a stationary boat, a boy jumping off a stationary skateboard Hoo Sze Yen www.physicsrox.com Page 4 of 13

2.5 Force Force is a push or pull. Force changes the size, shape, state of rest, velocity and/or direction of an object. Force is a vector quantity. Newton s Second Law of Motion The acceleration of a body, a, is directly proportional to the net force acting upon it, F, and inversely proportional to its mass, m. F = ma where F = force [N] m = mass [kg] a = acceleration caused by F [m s -2 ] 2.5.1 Balanced Forces (Forces in Equilibrium) Balanced forces is a state where net force is zero. When an object is in a state of balanced forces or forces in equilibrium, the object will either be: stationary, or moving with uniform velocity. Examples of balanced forces: Normal reaction Friction Forward force Tension Weight Weight Normal reaction is the reaction force generated perpendicular from the surface Friction is the resistance force generated between the object and surface when a force is applied to move the object Tension is the force generated in a taut string when a force is applied on the string An airplane moving with uniform velocity at constant height is in a state of balanced forces. Weight = Lift Thrust = Drag 2.5.2 Unbalanced Forces Unbalanced forces may cause an object to start moving, to speed it up, to slow it down, or to bring it to a stop. The greater the unbalanced force, the greater the acceleration or deceleration produced. Hoo Sze Yen www.physicsrox.com Page 5 of 13

2.6 Impulse and Impulsive Force where Ft = impulsive [kg m s -1 ] F = impulsive force [N] m = mass [kg] u = initial velocity [m s -1 ] v = final velocity [m s -1 ] 2.7 Safety Features in Vehicles Impulse = change of momentum Ft = mv mu Impulsive force = rate of change of momentum mv mu F t 1. Padded dashboards 2. Shatterproof windscreen glass 3. Inflatable airbags 4. Collapsible steering wheels 5. Headrest 6. Padded seats 7. Seatbelt 8. Antilock brake systems (ABS) 9. Steel struts 10. Steel cage 11. Reverse collision warning systems 12. Bumper bars 2.8 Gravity All objects are pulled towards the centre of the earth by a force known as the earth s gravitational force. Any object dropped towards earth which falls under the influence of the earth s gravitational force (without any influence of other external forces, such as air friction) is said to be going through a free fall. In reality, free falls only happen within a vacuum space. The diagram on the right shows the non-uniform gravitational field of the Earth, g which is represented by radial lines directed towards the centre of the Earth. The field is strongest where the lines are closest. 2.6.1 Free fall An object undergoing free fall will fall at the rate of gravitational acceleration which is at a constant of 9.81 m s -2 at sea level. The gravitational acceleration is not influenced by the size or mass of the object. Objects dropped from the same height will fall at the same rate and will hit the ground at the same time, regardless of the mass. Baseball Bowling ball Hoo Sze Yen www.physicsrox.com Page 6 of 13

However, for objects with very small mass and very large surface area like feathers, pieces of paper and cloth, they will fall at a lower rate. This is because the larger the surface area, the greater the air resistance. If the same objects are placed in a vacuum tube, they will fall at the same rate. 2.6.2 Weight Weight is the product of mass and gravitational acceleration. where W = weight [N] m = mass [m] g = gravitational acceleration [m s -2 ] 2.6.3 Lifts W = mg a W = mg R Common formula: R = mg + ma Where R =reading of the scale [N] m= mass of person [kg] g= gravitational acceleration [m s -2 ] a= upward acceleration of the lift [m s -2 ] If the lift is stationary or moving with uniform velocity (a = 0): R = mg If the lift is moving upwards with acceleration: R = mg + ma If the lift is movingupwards with deceleration: R = mg + m(-a) R = mg ma If the lift is moving downwards with acceleration: R = mg - ma If the lift is moving downwards with deceleration: R = mg m(-a) R = mg + ma Hoo Sze Yen www.physicsrox.com Page 7 of 13

2.9 Forces in Equilibrium Equilibrium: - resultant force = 0 - acceleration = 0 (stationary or uniform velocity) Newton s Third Law For every action there is an equal and opposite reaction. 2.9.1 Nett / Resultant Forces F x = F cos θ F y = F sin θ Using the parallelogram method You can solve resultant force by using scaled diagram or calculation. 1. Scaled diagram Draw the forces to scale using a ruler and a protractor. Magnitude of resultant force is obtained by measuring and converting back to value using the scale, and the angle is measured with a protractor. 2. Calculator α R θ F 2 R y R x = F 1 + F 2 cosθ R y = F 2 R = 2 2 x R y R F 1 Angle of R, α = tan -1 Ry R Note: If two equal forces x Rx are acting upon an object at an angle, the simplified solution is: θ θ F F R = F cos θ + F cos θ R = 2 F cos θ Hoo Sze Yen www.physicsrox.com Page 8 of 13

2.9.2 Pulleys T m 2 T Assume motion and acceleration in this direction Based on the force formula: F = ma F = Net force acting on the system m = Total mass of the system a = Acceleration of the system F 2 m 1 F 1 F 1 F 2 = (m 1 + m 2 ) a To find out the rope tension: F = ma F 1 T = m 1 a T = F 2 m 2 a Example: Calculate the acceleration and rope tension in the following system. To calculate acceleration: To calculate tension: 5 kg 3 kg F = ma 50 30 = (5+3)a a = 2.5 m s -2 Isolate the left side of the pulley (5 kg object is moving down): T 5 kg F = ma 50 T = 5(2.5) T = 37.5 N 50 N OR Isolate the right side of the pulley (3 kg object is moving up): T 3 kg F = ma T 30 = 3(2.5) T = 37.5 N 30 N You will get the same value of tension whether you isolate the left or right side. Hoo Sze Yen www.physicsrox.com Page 9 of 13

2.9.3 Inclined Planes R F r θ θ W=mg R = mg cos θ Fr = mg sin θ where W = weight of object [N] m = mass of object [kg] g = gravitational acceleration [m s -2 ] R = reaction caused by weight of object perpendicular to plane [N] F r = friction caused by weight of object parallel to plane [N] When solving questions with inclined planes, use the following shortcut: Weight of object parallel to the plane = mg sin θ mgsinθ θ 2.10 Work, Energy, Power and Efficiency 2.10.1 Work Work is the product of the applied force and its displacement in the direction of the net force. Work is a scalar quantity. When work is done, energy is transferred to the object or changed into a different form. Work is only done when the object has been displaced. If there is no displacement, there is no work done. Displacement must be parallel to the force exerted. where W = work [J] F = force creating the work [N] s = displacement [m] W = Fs Hoo Sze Yen www.physicsrox.com Page 10 of 13

2.10.2 Energy Energy is the potential or ability of a system to do work. Energy is a scalar quantity. First law of thermodynamics a.k.a. the principle of conservation of energy states that energy may neither be created nor destroyed; it can only change form. 2.10.2.1 Kinetic Energy Kinetic energy is energy acquired by an object during movement. where E = kinetic energy [J] m = mass [kg] v = velocity of the object [m s -1 ] E = ½ mv 2 2.10.2.2 Potential Energy Potential energy is the energy within an object because of its position or state. Potential energy is stored energy giving the body potential to do work. Gravitational potential energy: E = mgh where E = potential energy [J] m = mass [kg] g = gravitational acceleration [m s -2 ] h = height of the location of the object [m] Elastic potential energy: E = ½Fx where E = potential energy [J] F = force exerted [N] x = extension or compression of the spring [m] 2.10.3 Power F/N x/m Power is the rate at which energy is used OR the rate at which work is done. E W P t t where P = power [W] E = energy [J] W = work [J] t = time [s] Hoo Sze Yen www.physicsrox.com Page 11 of 13

2.10.4 Efficiency Efficiency is the ratio at which the output power is compared to the input power. Output power Efficiency 100% Input power 2.11 Maximising Efficiency The second law of thermodynamics a.k.a. the law of entropy states that in any energy transformation, some energy will be lost in the form of heat. Efficiency should be maximized in order to conserve energy resources. For example, to maximize efficiency of refrigerators: Use refrigerators that have freezers at the top instead of the side Keep the cooling coils clean Do not put the fridge too near the wall or in a room that is too hot Door seals should be in good condition Do not open the fridge door unnecessarily Defrost the fridge regularly Don t set the thermostat low all the time Send it for repair if the motor is not working properly 2.12 Elasticity Elasticity is the ability of an object to return to its original shape and size after the applied external force applied onto it has been removed. 2.10.1 Hooke s Law Hooke s Law states that the extension or compression of a spring is directly proportional to the force acting on it provided the elastic limit of the spring has not been exceeded. Spring extension, x (cm) Elastic limit Tension force, F (N) F = kx where F = force exerted on the spring [N] k = spring constant [N m -1 ] x = spring extension / compression [m] Note: Because F=kx and E=½Fx, you can derive it to: E = ½ kx 2 Hoo Sze Yen www.physicsrox.com Page 12 of 13

2.10.2 Spring stiffness Factors which affect the stiffness of a spring: 1) Length of spring The greater the length the spring, the lower the stiffness 2) Diameter of wire The greater the diameter of wire, the higher the stiffness 3) Diameter of coil The greater the diameter of coil, the lower the stiffness 4) Material of wire Different materials have different stiffness values 2.10.3 Spring systems Parallel arrangement Series arrangement W W The load is equally distributed among the springs. If n springs are used: Total extension = n x The same load is applied to each spring. If n springs are used: Total extension = nx END OF CHAPTER Hoo Sze Yen www.physicsrox.com Page 13 of 13