Common Fixed Point Theorems for Two Pairs of Weakly Compatible Mappings in Fuzzy Metric Spaces Using (CLR ST ) Property

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IOSR Journal of Mathematics (IOSR-JM) e-issn: 2278-5728, p-issn: 2319-765X. Volume 12, Issue 6 Ver. I (Nov. - Dec.2016), PP 66-71 www.iosrjournals.org Common Fixed Point Theorems for Two Pairs of Weakly Compatible Mappings in Fuzzy Metric Spaces Using (CLR ST ) Property Pranjali Sharma 1, Shailesh Dhar Diwan 2 1 Department of Mathematics, Shri Shankaracharya Institute of Prof. Mgmt. and Tech. Raipur (C.G.), India, 2 Department of Mathematics, Sant Guru Ghasidas Govt. P. G. College, Kurud, Dhamtari (C.G.), India, Abstract: In this paper, we establish some common fixed point theorems for two pairs of weakly compatible mappings in fuzzy metric spaces using the (CLR ST ) property. Our results extend, generalize and improve several results of metric spaces to fuzzy metric spaces. Keywords: Fuzzy metric space, t-norm, weakly compatible mappings, (CLR ST ) property, (E. A) property, fixed point. 2010 Mathematics Subject Classification: 54H25, 47H10. I. Introduction The idea of fuzzy set was first introduced in 1965 by Iranian mathematician L.A. Zadeh [21]. Fuzzy set is defined by a membership function which assigns each object to a grade of membership between zero and one. Following the concept of fuzzy set, Kramosil and Michalek [11] established the concept of fuzzy metric space. George and Veeramani [5] modified the concept of fuzzy metric space by imposing some stronger conditions using continuous t-norm and defined the hausdorff topology of fuzzy metric spaces. Gregori and Sapena [7] defined the concepts of convergent sequence, cauchy sequence, completeness and compactness in sense of fuzzy metric space. Grabiec [6] introduced the fuzzy version of Banach contraction principle. Generalizing the concept of commuting mapping Sessa [18] introduced the concept of weakly commuting mappings. In metric spaces, Pant [14] initiated the study of concept of R-weakly commuting mappings. Mishra [13] proved some common fixed point theorems for compatible mappings in fuzzy metric spaces. Generalization of compatible mappings is given by Jungck [10] and Pathak et al. [15]. Fang [3] proved some fixed point theorems in fuzzy metric spaces, which improve, generalize some results of Metric spaces. Vasuki [20] fuzzify weakly commuting maps. Aamri and El Moutawakil [1] defined the (E.A) property for self mappings which contains the class of noncompatible as well as compatible mappings. It is observed that (E.A) property and common property (E.A) require the closedness of the subspaces for the existence of fixed point. Recently, Sintunavarat and Kuman [19] defined the notion of CLRg property. It is important to note that CLRg property never requires completeness of subspace. In this paper, we prove some common fixed point theorems for two pairs of weakly compatible mappings in fuzzy metric space using (CLR ST ) property. Our results generalize various known results of metric spaces to fuzzy metric spaces. II. Preliminaries Definition 2.1 [17] : A binary operation : [0,1] [0,1] [0,1] is called continuous t-norm if it satisfies the following conditions: 1) is commutative and associative; 2) is continuous; 3) a 1 = a, for all a 0, 1 ; 4) a b c d whenever a c and b d, for all a, b, c, d [0, 1] Remark 2.2 [17]: The concept of t-norm can be considered as fuzzy union. Definition 2.3[5] : The 3-tuple (X, M, ) is said to be a fuzzy metric space (FMS) if, X is a non empty set, is a continuous t-norm, M is a fuzzy set on X X (0, ) satisfying the following conditions: 1) M(x, y, t) > 0; 2) M(x, y, t) =1 if and only if x=y; 3) M(x, y, t) = M(y, x, t); 4) M(x, y, t) M(y, z, s) M(x, z, t + s); M(x, y, ): (0, ) [0, 1] is continuous, for all x, y, z X and s, t > 0. DOI: 10.9790/5728-1206016671 www.iosrjournals.org 66 Page

M(x, y, t) is considered as the degree of nearness of x and y with respect to t. Example 2.4 [5]: Let (X, d) be a metric space, t-norm a b= min {a, b} x, y X and t > 0. M d (x, y, t) = t t d( x, y) then (X, M, ) is a Fuzzy metric space., Definition 2.5 ([20], [14] ): Two self mappings f and g of a fuzzy metric space (X, M, ) are said to be weakly commuting if, M ( fgx, gfx, t) M(fx, gx t), for all x X, t > 0. Definition 2.6( [9], [13] ): Two self mappings f and g of a fuzzy metric space (X, M, ) are said to be compatible if, lim n M fgx n, gfx n, t = 1, whenever {x n } is a sequence in X such that, lim n fx n = lim n gx n = x, for some x X, t > 0. Definition 2.7 [10]: Two self mappings f and g of a fuzzy metric space (X, M, ) are said to be weakly compatible if they commute at their coincidence point that is, if fx = gx for some x ε X, then M (fgx, gfx, t) =1 It is obvious that if two mappings are compatible then they are weakly compatible, but converse is not true. Definition 2.8 ( [1], [12]) : Two self mappings f and g of a fuzzy metric space (X, M, ) are said to satisfy the (E.A) property if there exist a sequence {x n } in X such that for all t > 0, lim n M fx n, gx n, t = 1. Definition 2.9 [19] : Two self mappings f and g of a fuzzy metric space (X, M, ) are said to satisfy the common limit in the range of g (CLRg) property if there exist a sequence {x n }in X such that, lim n fx n = lim n g x n = gu, for some u X. Definition 2.10 [2]: Two pairs (A, S) and (B, T) of self mappings of a fuzzy metric space (X, M, ) are said to satisfy the (E.A) property if there exist two sequences {x n } and {y n } in X such that for all t > 0, lim n Ax n = lim n Sx n = lim n By n = lim n Ty n = z, for some z in X. Definition 2.12 [8]: Two pairs (A, S) and (B, T) of self mappings of a fuzzy metric space (X, M, ) are said to satisfy the ( CLR ST ) property if there exist two sequences {x n } and {y n } in X such that for all t > 0, lim n Ax n = lim n Sx n = lim n By n = lim n Ty n = z, where z S(X) T(X). III. Main Result Theorem 3.1 Let A, B, S and T be self mappings a fuzzy metric space ( X, M, ) such that, I. The pairs (A, S) and (B, T) shares the (CLR ST ) property, II. Both the pairs (A, S) and (B, T) are weakly compatible. III. There exist a constant k (0, 1) such that, M Ax, By, kt 2 min { M Sx, Ty, t 2, M Sx, Ax, t M Ty, By, t, M Sx, By, 2 t M Ty, Ax, t, M Ty, Ax, t, M Sx, By, 2t M Ty, By, t } for all x, y X and t > 0, then A, B, S and T have a unique common fixed point in X. Proof: Since the pairs (A, S) and (B, T) share the (CLR ST ) property, then there exists two sequences {x n } and {y n } in X such that, lim n Ax n = lim n S x n = lim n T y n = lim n By n = z, DOI: 10.9790/5728-1206016671 www.iosrjournals.org 67 Page

where, z S(X) T(X). Since z S(X), there exists a point u X such that, Su = z. We assert that Au = Su. On using inequality III with x = u, y = y n, we get, (M(Au, By n, kt)) 2 min { (M(Su, Ty n, t)) 2, M(Su, Au, t) M(Ty n, By n, t), M(Su, By n, 2t) M(Ty n, Au, t), M(Ty n, Au, t), M(Su, By n, 2t) M(Ty n, By n, t)} Taking as limit n (M(Au, z, kt)) 2 min { (M(z, z, t)) 2, M(z, Au, t) M(z, z, t), M(z, z, 2t) M(Au, z, t), M(Au, z, t), M(z, z, 2t) M(z, z, t)} = min{ 1, M(z, Au, t). 1, 1. M(Au, z, t), M(Au, z, t), 1. 1} = M (z, Au, t) It is possible only when Au = z. Therefore Au = Su = z. Also z T(X), there exists a point v X such that Tv = z. We show that Bv = Tv. On using inequality (III) with x = u, y = v, we get, (M(z, Bv, kt)) 2 min { (M(z, z, t)) 2, M(z, z, t) M(z, Bv, t), M(z, Bv, 2t) M(z, z, t), M(z, z, t), M(z, Bv, 2t) M(z, Bv, t)} (M(z, Bv, kt)) 2 min { 1, 1. M(z, Bv, t), M(z, Bv, 2t).1, 1, M(z, Bv, 2t) M(z, Bv, t)} ( M(z, Bv, kt)) 2 (M(z, Bv, t)) 2 It is possible when Bv = z, therefore Bv = Tv = z. Since the pair (A, S) is weakly compatible, therefore Az = ASu = SAu = Sz. Putting x = z and y = v in inequality (III), we have (M(Az, Bv, kt)) 2 min { (M(Sz, Tv, t)) 2, M(Sz, Az, t) M(Tv, Bv, t), M(Sz, Bv, 2t) M(Tv, Az, t), M(Tv, Az, t), M(Sz, Bv, 2t) M(Tv, Bv, t)} (M(Az, z, kt)) 2 min { (M(Az, z, t)) 2, M(Az,A z, t) M(z, z, t), M(Az, z, 2t) M(z, Az, t), M(z, Az, t), M(Az, z, 2t) M(z, z, t)} (M(Az, z, kt)) 2 min { (M(Az, z, t)) 2, 1.1, M(Az, z, 2t) M(z, Az, t), M(z, Az, t), M(Az, z, 2t).1} (M(Az, z, kt)) 2 (min M(Az, z, t)) 2 It is possible when Az = z, therefore Az = Sz = z. Which shows that z is a common fixed point of the pair (A, S). Also the pair (B, T) is weakly compatible, therefore Bz = BTv = TBv = Tz. On using inequality (III) with x = u, y = z, we have (M(Au, Bz, kt)) 2 min {( M(Su, Tz, t)) 2, M(Su, Au, t) M(Tz, Bz, t), M(Su, Bz, 2t) M(Tz, Au, t), M(Tz, Au, t), M(Su, Bz, 2t) M(Tz, Bz, t)} (M(z, Bz, kt)) 2 min { (M(z, Bz, t)) 2, M(z, z, t) M(Bz, Bz, t), M(z, Bz, 2t) M(Bz, z, t), M(Bz, z, t), M(z, Bz, 2t) M(Bz, Bz, t)} (M(z, Bz, kt)) 2 min { (M(z, Bz, t)) 2, 1.1, M(z, Bz, 2t) M(Bz, z, t), M(Bz, z, t), M(z, Bz, 2t).1} (M(z, Bz, kt)) 2 ( M(z, Bz, t)) 2 It is possible when Bz = z, therefore Bz = Tz = z, which shows that z is a common fixed point of the pair (B, T). Therefore z is a common fixed point of both the pairs (A, S) and (B, T). Now we prove the uniqueness of common fixed, let z 1 and z 2 be two common fixed points of f and g then from condition III, M z 1, z 2, kt 2 = M Az 1, Bz 2, kt 2 min { M Sz 1, Tz 2, t 2, M Sz 1, Az 1, t M Tz 2, Bz 2, t, M Sz 1, Bz 2, 2 t M Tz 2, Az 1, t, M Tz 2, Az 1, t, M Sz 1, Bz 2, 2t M Tz 2, Bz 2, t } = min { M z 1, z 2, t 2, M z 1, z 1, t M z 2, z 2, t, M z 1, z 2, 2 t M z 2, z 1, t, M z 2, z 1, t, M z 1, z 2, 2t M z 2, z 2, t } DOI: 10.9790/5728-1206016671 www.iosrjournals.org 68 Page

= M z 1, z 2, t 2 Therefore, M z 1, z 2, kt 2 M z 1, z 2, t 2 It is possible only when z 1 = z 2. Therefore z is unique common fixed point of both the pairs (A, S) and (B, T). Example 3.5: Let (X, M, ) be a fuzzy metric space, with a b = min {a, b} where X = [1, 15), and M(x,y t t)=, for all x, y X and t > 0. Define self maps A, B. S, T as, t+ x y Let {x n }= {1 + 2 n } and {y n}= {1 + 1 n } 1, x 1 (2,15) A x = 14, x (1, 2] 1, x 1 (2,15) B x = 4, x (1, 2] x + 2, x 2,15 S x = 4 1, x = 1 14, x (1, 2] x 1, x 2,15 A x = 1, x = 1 14, x (1, 2] lim Ax n = lim Bx n = lim Sx n = lim Tx n = 1 n n n n And 1 S(X) T(X) all the conditions of Theorem 3.1 are satisfied for some fixed k (0, 1) and 1 is the unique common fixed point of the pairs (A, S) and (B, T). Corollary 3.3: Let A, B, S and T be self mappings of a fuzzy metric space (X, M, ) such that I. The pair (A, S) satisfies CLR s property. II. A(X) T(X) III. T(X) is a closed subset of S(X) IV. B(y n ) converges for every sequence {y n } in X, whenever T(y n ) converges. V. Both the pairs (A, S) and (B, T) are weakly compatible. VI. There exist a constant k (0, 1) such that, M Ax, By, kt 2 min M Sx, Ty, t 2, M Sx, Ax, t M Ty, By, t, M Sx, By, 2 t M Ty, Ax, t, M Ty, Ax, t, M Sx, By, 2t M Ty, By, t Then A, B, S and T have a unique common fixed point. Proof: Let the pair (A, S) satisfy the CLR g property, then there exist a sequence x n in X such that, lim n Ax n = lim n S x n = z, where z S(X) As A(X) T(X) therefore Ax n = Ty n lim n Ax n = lim n S x n = lim n T y n = z, where z S X T X. Now we show that lim n B y n = z In inequality (VI) put x=x n and y=y n we get, Taking limit as n M Ax n, By n, kt 2 min { M Sx n, Ty n, t 2, M Sx n, Ay n, t M Ty n, By n, t, M Sx n, By n, 2 t M Ty n, Ax n, t, M Ty n, Ax n, t, M Sx n, By n, 2t M Ty n, By n, t } M z, l, kt 2 min { M z, z, t 2, M z, z, t M z, l, t, M z, l, 2 t M z, z, t, M z, z, t, M z, l, 2t M z, l, t } = M z, l, t 2 It is possible only when z=l. DOI: 10.9790/5728-1206016671 www.iosrjournals.org 69 Page

Therefore, lim n Ax n = lim n S x n = lim n T y n = lim n B y n = z, where z S(X) T(X), h ence the pairs (A, S) and (B, T) share the (CLR ST ) property. Therefore by theorem 3.1 A, B, S and T have a unique common fixed point. Theorem 3.4: Let A and S be self mappings a fuzzy metric space (X, M, ) such that, I. The pairs (A, S) satisfies the (CLR S ) property, II. The pair (A, S) is weakly compatible. III. There exist a constant k (0, 1) such that, M Ax, Ay, kt 2 min { M Sx, Sy, t 2, M Sx, Ax, t M Sy, Ay, t, M Sx, Ay, 2 t M Sy, Ax, t, M Sy, Ax, t, M Sx, Ay, 2t M Sy, Ay, t } for all x, y X and t > 0.Then A and S have a unique common fixed point in X. Proof: Since the pairs (A, S) satisfies the ( CLR ST ) property, then there exists a sequence {x n } in X such that, lim n Ax n = lim n S x n = z, where z S(X). Therefore, there exists a point u X such that Su = z. We assert that Au = Su. On using inequality ( III ) with x = u, y = x n, we get, M Au, Ax n, kt 2 min { M Su, Sx n, t 2, M Su, Au, t M Sx n, Ax n, t, M Su, Ax n, 2 t M Sx n, Au, t, Taking limit as n M Sx n, Au, t, M Su, Ax n, 2t M Sx n, Ax n, t } M Au, z, kt 2 min { M z, z, t 2, M z, Au, t M z, z, t, M z, z, 2 t M z, Au, t, M z, Au, t, M z, z, 2t M z, z, t } M Au, z, kt 2 ( M z, Au, t 2 It is possible only when Au = z. Therefore Au = Su = z and hence u is a coincidence point of (A, S). Since the pair (A, S) is weakly compatible therefore, Az = ASu = SAu = Sz. Putting x = z, y = x n in inequality (III), we get M Az, Ax n, t 2 min { M Sz, Sx n, t 2, M Sz, Az, t M Sx n, Ax n, t, M Sz, Ax n, 2 t M Sz, Az, t, Taking limit as n M Sx n, Az, t, M Sz, Ax n, 2t M Sx n, Ax n, t M Az, z, kt 2 min { M Az, z, t 2, M Az, Az, t M z, z, t, M Az, z, 2 t M z, Az, t, M z, Az, t, M Az, z, 2t M z, z, t } = min { M Az, z, t 2, 1.1, M Az, z, 2 t M z, Az, t, = M Az, z, t 2 M z, Az, t, M Az, z, 2t. 1} It is possible only when Az = z, therefore Az = Sz = z, therefore z is a common fixed point of A and S. Now we prove the uniqueness of common fixed, let z 1 and z 2 be two common fixed points of f and g then from condition 3, M z 1, z 2, kt 2 = M Az 1, Bz 2, kt 2 min { M Sz 1, Tz 2, t 2, M Sz 1, Az 1, t M Tz 2, Bz 2, t, M Sz 1, Bz 2, 2 t M Tz 2, Az 1, t, M Tz 2, Az 1, t, M Sz 1, Bz 2, 2t M Tz 2, Bz 2, t } = min { M z 1, z 2, t 2, M z 1, z 1, t M z 2, z 2, t, M z 1, z 2, 2 t M z 2, z 1, t, M z 2, z 1, t, M z 1, z 2, 2t M z 2, z 2, t } = M z 1, z 2, t 2 Therefore, M z 1, z 2, kt 2 M z 1, z 2, t 2 It is possible only when z 1 = z 2, therefore z is unique common fixed point of A and S. DOI: 10.9790/5728-1206016671 www.iosrjournals.org 70 Page

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