Counting Perfect Polynomials

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Enrique Treviño joint work with U. Caner Cengiz and Paul Pollack 49th West Coast Number Theory December 18, 2017 49th West Coast Number Theory 2017 1

Caner (a) Caner Cengiz (b) Paul Pollack 49th West Coast Number Theory 2017 2

Perfect Numbers n is perfect if n is the sum of its proper divisors, i.e. Examples: n = d d n d n 6 = 1 + 2 + 3 28 = 1 + 2 + 4 + 7 + 14 496 = 1 + 2 + 4 + 8 + 16 + 31 + 31 2 + 31 4 + 31 8 2 p 1 (2 p 1) = 1 + 2 + 4 + + 2 p 1 + (2 p 1) (1 + 2 + 4 + + 2 p 2) for 2 p 1 prime (i.e., a Mersenne prime). 49th West Coast Number Theory 2017 3

Polynomials Mod 2 A polynomial mod 2 is one of the form where a i {0, 1}. a n x n + a n 1 x n 1 +... + a 1 x + a 0, We consider the operation mod 2, i.e., 1 + 1 = 0, 0 + 1 = 1 + 0 = 1, 0 + 0 = 0. For example x 2 + 1 = x 2 + 2x + 1 = (x + 1) 2. 49th West Coast Number Theory 2017 4

Perfect Polynomials Mod 2 Let σ(p) be the sum of the divisors of a polynomial P in mod 2. A polynomial is said to be perfect mod 2 if σ(p) = P. x 2 + x = x(x + 1), so σ(x 2 + x) = 1 + x + (x + 1) + x 2 + x = x 2 + x. So x 2 + x is perfect. σ(x 2 + 1) = 1 + (1 + x) + (1 + x 2 ) = 1 + x + x 2, so x 2 + 1 is not perfect. 49th West Coast Number Theory 2017 5

Family of perfect polynomials Let P(x) = (x(x + 1)) 2n 1. We ll show σ(p) = P. 1 + x + x 2 + + x 2n 1 = x 2n 1 x 1 = x 2n + 1 x + 1 = (x + 1 1)2n. 1 + (1 + x) + + (1 + x) 2n 1 = (1 + x)2n 1 x = 1 + x 2n 1 x = x 2n 1. σ(p) = σ(x 2n 1 )σ((x + 1) 2n 1 ) = (x + 1) 2n 1 x 2n 1 = P. 49th West Coast Number Theory 2017 6

Weirdo Perfects Figure: Perfect numbers not in the infinite family. Found by Canaday in 1941 49th West Coast Number Theory 2017 7

Even and Odd Perfects We say that P is an even perfect if x(x + 1) P and P is perfect. We say that P is odd otherwise. Conjecture All perfect polynomials are EVEN. 49th West Coast Number Theory 2017 8

What did we know Theorem (Canaday) An odd perfect polynomial is a square. Theorem (Gallardo-Rahavandrainy) If A is an odd perfect polynomial, then it has at least 5 distinct irreducible factors. Moreover, the number of irreducible factors of A, counted with multiplicity, is at least 12. 49th West Coast Number Theory 2017 9

What did we prove Theorem (Cengiz-Enrique-Pollack) The number of perfect polynomials of norm x is O ɛ (x 1 12 +ɛ ) for every ɛ > 0. The norm of A is 2 deg A. Theorem (Cengiz-Enrique-Pollack) There are no odd perfect polynomials of degree 200, i.e., there are no odd perfect polynomials of norm 2 200 1.6 10 60. Theorem (Cengiz-Enrique-Pollack) If A is a non-splitting perfect polynomial of degree 200, then A is one of Canaday s polynomials. 49th West Coast Number Theory 2017 10

Main Tool Lemma (Fundamental lemma) Let M be a polynomial which is not perfect, and let k 2 be a fixed positive integer. Let x 10. Then there exists a constant C k depending only on k, as well as a set S depending only on M, k and x, of cardinality bounded by x C k / log log x, with the following property: if A is a perfect polynomial of norm x for which (a) M is a unitary divisor of A: i.e., A = MN with gcd(m, N) = 1, and (b) N = A/M is k-free, i.e., P k N for any irreducible polynomial P, then A has a decomposition of the form M N, where 1 M is an element of S, 2 M and N are unitary divisors of A, 3 both factors M and N are perfect, 4 N is k-free, 5 M is a unitary divisor of M. 49th West Coast Number Theory 2017 11

Algorithm H.-W. Algorithm Given a polynomial B and a stopping bound H, with deg B H, the following algorithm (a) outputs only perfect polynomials A of degree H having B as a unitary divisor, and (b) outputs every such A that is indecomposable. 1 Check if σ(b) = B. If yes, then output B and break. 2 Compute D = σ(b)/ gcd (B, σ(b)). 3 If gcd (B, D) 1, break. 4 Let P be an irreducible factor of D of largest degree. 5 Recursively call the algorithm with inputs BP k and stopping bound H, for all positive integers k with deg(bp k ) H. Note: indecomposable means A has no nontrivial factorization as a product of two relatively prime perfect polynomials. 49th West Coast Number Theory 2017 12

Recursion Figure: Recursion for the Algorithm 49th West Coast Number Theory 2017 13

How did we go so high? To check odd perfects: From the algorithm, we need only check whether P 2 is a unitary divisor for deg P 20. Because if A is perfect. It has at least 5 prime divisors and A is a square. To check even perfects that are not in the infinite family: If P(x) is perfect, then P(x + 1) is perfect. If P is perfect x P (x + 1) P. We need only check the algorithm for x, x 2, x 100. 49th West Coast Number Theory 2017 14

Thank you! 49th West Coast Number Theory 2017 15