On Almost Simple Transcendental Field Extensions

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International Journal of Alebra, Vol. 9, 2015, no. 2, 53-58 HIKARI Ltd, www.m-hikari.com http://dx.doi.or/10.12988/ija.2015.412123 On Almost Simple Transcendental Field Extensions Antonio González Fernández, Rodrio Jiménez Correa and Jesús Efrén Pérez Terrazas Facultad de Matemáticas Universidad Autónoma de Yucatán Anillo Periférico Norte, 13615, Chuburná Hidalo Inn Mérida, Yucatán, México Copyriht c 2015 Antonio González Fernández, Rodrio Jiménez Correa and Jesús Efrén Pérez Terrazas. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the oriinal work is properly cited. Abstract We study some properties of almost simple transcendental field extensions in order to analyze the endomorphisms rin of alebraically bounded Λ modules where Λ is a semienerically tame finite-dimensional k alebra, k a perfect field. Mathematics Subject Classification: 12E05, 16G60 Keywords: alebraically bounded modules, field extension, perfect field, semienerically tame alebra, transcendental extension 1. Introduction The notion of alebraically bounded module was introduced in [5] in order to study the representation type of finite dimensional alebras over perfect fields. Here we deal with the rin of endomorphisms of such modules, and the main result is the followin:

54 A. González, R. Jiménez and E. Pérez Corollary 1.1. Let k be a perfect field, K an alebraic closure of k, and Λ a finite-dimensional k alebra. Assume that Λ K is tame and G is an alebraically bounded Λ module. Let us denote E G = End Λ (G) op, D G = E G /rad (E G ), by Z G the center of D G and by A G the alebraic elements of Z G over k. Then A G /k is a finite field extension and Z G = k (t, w), where t is transcendental over k and k (t, w) /k (t) is a separable finite field extension. Also we have E G = F E as k vector spaces, F a subrin of E G and F = k (t) as k alebras, and G is finitely enerated as riht F module. To achieve the previous result we study some properties of almost simple transcendental field extensions (see 3.1), throuh classical results of Field Theory. In a forthcomin paper we will use the previous corollary and the results of [1] to produce bimodules that parametrize finite dimensional Λ modules, when Λ is a semienerically tame finite-dimensional k alebra, with k a perfect field. 2. Basic Features Lemma 2.1. Let E/k be a field extension, f k [x] {0} and E [x] such that f k [x], then k [x]. Proof: By the division alorithm there is an identity f = fq + r such that q, r k [x] and rad (f) > rad (r) ; then the identity ( q) f = r in E [x] implies r = 0 and = q. Proposition 2.2. Let E/k be a field extension. Then the canonical homomorphism of E alebras ψ : E k k (x) = E (x) is injective. If E/k is an alebraic field extension then ψ is surjective. Proof: It is easy to verify the existence ( of an homomorphism ) of E alebras ψ : E k k (x) E (x) determined by ψ e f = ef, for e E, f, k [x], 0. The restriction ψ E k k[x] : E k k [x] E [x] is an isomorphism, and this implies that ψ is injective (use clearin denominators). Now assume E/k is an alebraic field extension and let be h E [x] with rad (h) = m > 0, and E a splittin field of h, i.e. h = uh 1 h m where u E {0} and h i = x r i, r i E, for each i. Let h i h i k [x] be the minimal polynomial of r i over k, and so hh k [x], where h = u 1 h 1 h m. By lemma 2.1 we et h E [x]. Usin the identity 1 = h we can verify that any element of E (x) has the form n e i x i, where h hh e i E for each i and k [x] {0}, and so ψ is surjective. i=0

On almost simple transcendental field extensions 55 Remark 2.3. y 1 1 x is not a unit in k (y) k k (x). Proposition 2.4. Let E/k be an alebraic field extension, then E (x) /k (x) is an alebraic field extension. m Proof: Note that if e E is a root of the polynomial c j x j k [x] then j=0 m ( ) ex i is a root of the polynomial c j j y j k (x) [y]. From the proof of the x ij j=0 proposition 2.2 we know that any element of E (x) has the form n i=0 e i x i, where e i E for each i and k [x] {0}. Then, the statement holds because the sum of alebraic elements is alebraic. Corollary 2.5. Let E/k be an alebraic field extension. Then E k k (x 1,..., x n ) = E (x 1,..., x n ) as E alebras. Proof: By induction over n. The inductive step follows by propositions 2.2, 2.4 and the identity (k (x 1,..., x m 1 )) (x m ) = k (x 1,..., x m ), and so we have E k k (x 1,..., x m ) = E k k (x 1,..., x m 1 ) k(x1,...,x m 1 ) k (x 1,..., x m ) = E (x1,..., x m 1 ) k(x1,...,x m 1 ) (k (x 1,..., x m 1 )) (x m ) = E (x1,..., x m ). 3. Properties of ast Field Extensions Definition 3.1. Let E/k a field extension. We call E an almost simple transcendental field extension of k, or ast, if there exists an alebraic field extension L/k, and n N, such that E k L = n L (x) as L alebras. In this case we say that L realizes the ast property of E/k. Applyin proposition 2.2 we et the followin result: Lemma 3.2. Assume that L realizes the ast property of E/k. If L /L is an alebraic field extension then L realizes the ast property of E/k. The next claim is theorem 7 of section 4 of chapter 4 of [4] (or see [2]). Theorem 3.3. Let t be transcendental over k. Then t is alebraic over k (s) for s k (t) k. Moreover, if s = f(t) with f(x) and (x) relative primes in (t) k[x] then [k (t) : k (s)] = max{de (f), de ()} and the polynomial f(x) s(x) is irreducible in k (s) [x].

56 A. González, R. Jiménez and E. Pérez Lemma 3.4. Let α be alebraic over k and L/k a field extension, L containin a splittin field of m α,k (x) k [x], the minimal (monic) polynomial of α over k. i) If α is not separable over k, then L k k (α) contains nilpotent elements. ii) If α is separable over k, then L k k (α) = n L as L-alebras, where n = de (m α,k (x)). Proof: Recallin that k (α) = k [x] / m α,k (x), we have L k k (α) = L k (k [x] / m α,k (x) ) = L [x] / m α,k (x). In L [x] there is a factorization m α,k (x) = m (x α i ) n i. By the Chinese Remainder Theorem, we et L k k (α) = m L [x] / (x α i ) n i, and so we et the first claim because if α is not separable then there are repeated roots. If α is separable then n i = 1 for each i, followin the final claim. Theorem 3.5. Let E/k be an ast field extension, and A the intermediate field of the alebraic elements of E over k, then A/k is a separable finite (then simple) field extension. Moreover, if L realizes the ast property of E/k, i.e. E k L = n L (x), then [A : k] n. In particular, E is transcendental over k. Proof: Let be α A k and m α,k (x) k [x] its minimal polynomial. By lemma 3.2 we can assume that L contains a splittin field of m α,k (x). Observe that 0 is the only nilpotent element of n L (x) ; it follows, by the lemma 3.4, that α is separable, and so A/k is separable. The lemma 3.4 also provides a set of orthoonal idempotents associated to m α,k (x), as many idempotents as its deree, then de (m α,k (x)) n. Now let be γ A k such that m γ,k (x) has maximal deree: k (γ, α) is a separable finite field extension of k then, by the Theorem of the Primitive Element, there exists δ A such that k (γ, α) = k (δ). By maximality of the deree of m γ,k (x) we et k (γ) = k (δ), so α k (γ). It follows A = k (γ). Finally E A : otherwise E k L would have finite dimension over L. Remark 3.6. Notice that theorem 3.5 can be proved without the hypothesis L/k alebraic. Theorem 3.7. Let be E/k be an ast field extension. If t E is transcendental over k then E/k (t) is a finite field extension. As a consequence, the transcendence deree of E/k is 1.

On almost simple transcendental field extensions 57 Proof: Let us assume that L realizes the ast property of E/k, i.e. E k L = n L (x). Let t E be as in the statement and consider a k (t) basis {b j } j J of E. Applyin proposition 2.2 we have an injective composition of homomorphisms of L alebras θ : L (t) = k (t) k L ι 1 E k L, where ι : k (t) E is the canonical inclusion, and homomorphisms of L alebras ϑ i : L (t) θ E k L = n L (x) π i L (x), where π i is the canonical projection correspondin to i. Notice that 1 1 k (t) k L implies that ϑ i 0 for each i, and so ϑ i is injective for i {1,..., n}. It is easy to verify that {b j 1} j J is a L (t) basis of E k L for the structure of vector space induced by θ. Notice that t / L since L/k is alebraic. Then by theorem 3.3, for each i, L (x) is finite dimensional over the imae of ϑ i, and so J has to be finite. Proof of corollary 1.1: By lemma 2.17 and theorem 3.2 of [5] we have that Z G /k is an ast field extension, then applyin theorems 3.5 and 3.7 we et that A G /k is a finite field extension, Z G /k is of transcendence deree one and, for t Z G transcendental over k, that [Z G : k (t)] <. Since k is perfect there exists a separatin transcendency basis for Z G (see corollary of pae 166 of [4]), i.e., we can choose t 0 transcendental over k such that Z G /k (t 0 ) is a separable field extension. By the Theorem of the Primitive Element Z G /k (t 0 ) is an alebraic simple extension. Now let π : E G D G be the canonical epimorphism and T E G such that π (T ) = t 0. Then π induces an isomorphism of k alebras between k [T ] and k [t 0 ]. By lemma 2.5.5 of [6] each element of k [T ] {0} is invertible in E G, and so there is a subrin F of E G that we can identify with k (T ) = k (t 0 ). For the final claim we recall that eneric modules are finitely enerated over their endomorphisms rins and that D G is finitely enerated over Z G (see [5]). Remark 3.8. With the hypothesis of corollary 1.1 it can be shown, applyin Wedderburn s Principal Theorem, that E G = A B as k vector spaces, A a subrin of E G, where A = A G as k alebras. Acknowledements. We thank the support of rants PIFI-2013-31MSU0098J and P/PROFOCIE-2014-31MSU0098J-13

58 A. González, R. Jiménez and E. Pérez References [1] R. Bautista, E. Pérez, L. Salmerón. On semienerically tame alebras over perfect fields. Submitted. [2] A. González, R. Jiménez, E. Pérez. El Teorema de Lüroth. Abstraction & Application 11 (2014) 52-56. [3] E. Guerrero, E. Pérez. Álebra Abstracta, de rupos a preliminares de la Teoría de Galois. Ediciones de la Universidad Autónoma de Yucatán, 2010. [4] N. Jacobson. Lectures in Abstract Alebra, III. Theory of Fields and Galois Theory. Spriner-Verla, 1964. http://dx.doi.or/10.1007/978-1- 4612-9872-4 [5] E. Pérez. On semieneric tameness and base field extension. To appear in Glasow Mathematical Journal. [6] L. H. Rowen. Rin Theory (Student Edition). Academic Press, 1991. http://dx.doi.or/10.1016/b978-0-08-092548-6.50005-2 Received: January 11, 2015; Published: February 4, 2015