SOLUTIONS TO SECOND PRACTICE EXAM Math 21a, Spring 2003

Similar documents
3 = arccos. A a and b are parallel, B a and b are perpendicular, C a and b are normalized, or D this is always true.

7/8/2010 FIRST HOURLY PRACTICE IV Maths 21a, O.Knill, Summer 2010

MA 351 Fall 2007 Exam #1 Review Solutions 1

Tangent and Normal Vector - (11.5)

Math 3c Solutions: Exam 1 Fall Graph by eliiminating the parameter; be sure to write the equation you get when you eliminate the parameter.

Exercises for Multivariable Differential Calculus XM521

APPM 2350, Summer 2018: Exam 1 June 15, 2018

(6, 4, 0) = (3, 2, 0). Find the equation of the sphere that has the line segment from P to Q as a diameter.

MATH 12 CLASS 5 NOTES, SEP

(a) The points (3, 1, 2) and ( 1, 3, 4) are the endpoints of a diameter of a sphere.

SOLUTIONS TO HOMEWORK ASSIGNMENT #2, Math 253

Final Review Worksheet

MATH H53 : Mid-Term-1

Practice problems for Exam 1. a b = (2) 2 + (4) 2 + ( 3) 2 = 29

MATH 32A: MIDTERM 1 REVIEW. 1. Vectors. v v = 1 22

DEPARTMENT OF MATHEMATICS AND STATISTICS UNIVERSITY OF MASSACHUSETTS. MATH 233 SOME SOLUTIONS TO EXAM 1 Fall 2018

MTHE 227 Problem Set 2 Solutions

SOME PROBLEMS YOU SHOULD BE ABLE TO DO

VANDERBILT UNIVERSITY. MATH 2300 MULTIVARIABLE CALCULUS Practice Test 1 Solutions

REVIEW 2, MATH 3020 AND MATH 3030

HOMEWORK 2 SOLUTIONS

Math 53 Spring 2018 Practice Midterm 2

(1) Recap of Differential Calculus and Integral Calculus (2) Preview of Calculus in three dimensional space (3) Tools for Calculus 3

Practice Midterm Exam 1. Instructions. You have 60 minutes. No calculators allowed. Show all your work in order to receive full credit.

MATH 1020 WORKSHEET 12.1 & 12.2 Vectors in the Plane

10/6/2009 FIRST HOURLY PRACTICE III Math 21a, Fall Name:

MATH 332: Vector Analysis Summer 2005 Homework

APPM 2350 Section Exam points Wednesday September 26, 6:00pm 7:30pm, 2018

MATH 2433 Homework 1

Calculus III. Math 233 Spring Final exam May 3rd. Suggested solutions

Name: ID: Math 233 Exam 1. Page 1

Exam. There are 6 problems. Your 5 best answers count. Please pay attention to the presentation of your work! Best 5

(b) Find the range of h(x, y) (5) Use the definition of continuity to explain whether or not the function f(x, y) is continuous at (0, 0)

Vector Functions & Space Curves MATH 2110Q

Math 461 Homework 8. Paul Hacking. November 27, 2018

Math 461 Homework 8 Paul Hacking November 27, 2018

9/27/2017 FIRST HOURLY PRACTICE 5 Math 21a, Fall Name:

MAT 272 Test 1 Review. 1. Let P = (1,1) and Q = (2,3). Find the unit vector u that has the same

1 Vectors and 3-Dimensional Geometry

MATH Final Review

1. If the line l has symmetric equations. = y 3 = z+2 find a vector equation for the line l that contains the point (2, 1, 3) and is parallel to l.

MATH UN1201, Section 3 (11:40am 12:55pm) - Midterm 1 February 14, 2018 (75 minutes)

Tom Robbins WW Prob Lib1 Math , Fall 2001

SOME PROBLEMS YOU SHOULD BE ABLE TO DO

Practice Problems for the Final Exam

Math 273 Solutions to Review Problems for Exam 1

BROWN UNIVERSITY MATH 0350 MIDTERM 19 OCTOBER 2017 INSTRUCTOR: SAMUEL S. WATSON

Major Ideas in Calc 3 / Exam Review Topics

1 Vectors and the Scalar Product

Math 114, Section 003 Fall 2011 Practice Exam 1 with Solutions

EXAM 2 ANSWERS AND SOLUTIONS, MATH 233 WEDNESDAY, OCTOBER 18, 2000

1.1 Single Variable Calculus versus Multivariable Calculus Rectangular Coordinate Systems... 4

Department of Mathematical and Statistical Sciences University of Alberta

CALCULUS 3 February 6, st TEST

7/12/2018 FIRST HOURLY Practice 1 Maths 21a, O.Knill, Summer Name:

Chapter 12 Review Vector. MATH 126 (Section 9.5) Vector and Scalar The University of Kansas 1 / 30

MATH 32A: MIDTERM 2 REVIEW. sin 2 u du z(t) = sin 2 t + cos 2 2

1 + f 2 x + f 2 y dy dx, where f(x, y) = 2 + 3x + 4y, is

Solutions for the Practice Final - Math 23B, 2016

MATH 2083 FINAL EXAM REVIEW The final exam will be on Wednesday, May 4 from 10:00am-12:00pm.

MATH 255 Applied Honors Calculus III Winter Midterm 1 Review Solutions

Chapter 13: Vectors and the Geometry of Space

Chapter 13: Vectors and the Geometry of Space

True or False. Circle T if the statement is always true; otherwise circle F. for all angles θ. T F. 1 sin θ

Math 210, Final Exam, Practice Fall 2009 Problem 1 Solution AB AC AB. cosθ = AB BC AB (0)(1)+( 4)( 2)+(3)(2)

Course Notes Math 275 Boise State University. Shari Ultman

10.3 Parametric Equations. 1 Math 1432 Dr. Almus

BROWN UNIVERSITY MATH 0350 MIDTERM 19 OCTOBER 2017 INSTRUCTOR: SAMUEL S. WATSON. a b. Name: Problem 1

WORKSHEET #13 MATH 1260 FALL 2014

Solutions to old Exam 3 problems

Look out for typos! Homework 1: Review of Calc 1 and 2. Problem 1. Sketch the graphs of the following functions:

Calculus with Analytic Geometry 3 Fall 2018

OHSx XM521 Multivariable Differential Calculus: Homework Solutions 13.1

Math 234. What you should know on day one. August 28, You should be able to use general principles like. x = cos t, y = sin t, 0 t π.

Page Problem Score Max Score a 8 12b a b 10 14c 6 6

Topic 2-2: Derivatives of Vector Functions. Textbook: Section 13.2, 13.4

x + ye z2 + ze y2, y + xe z2 + ze x2, z and where T is the

Figure 10: Tangent vectors approximating a path.

Name: ID: Math 233 Exam 1. Page 1

Final Exam Math 317 April 18th, 2015

Mathematics 2203, Test 1 - Solutions

MATH 200 WEEK 5 - WEDNESDAY DIRECTIONAL DERIVATIVE

Geometry and Motion Selected answers to Sections A and C Dwight Barkley 2016

VECTORS AND THE GEOMETRY OF SPACE

Fall Exam 4: 8&11-11/14/13 - Write all responses on separate paper. Show your work for credit.

3. Interpret the graph of x = 1 in the contexts of (a) a number line (b) 2-space (c) 3-space

1. (a) The volume of a piece of cake, with radius r, height h and angle θ, is given by the formula: [Yes! It s a piece of cake.]

HOMEWORK 3 MA1132: ADVANCED CALCULUS, HILARY 2017

Math 103, Review Problems for the First Midterm

Math 3c Solutions: Exam 2 Fall 2017

Vectors, dot product, and cross product

Math 263 Final. (b) The cross product is. i j k c. =< c 1, 1, 1 >

Calculus III. Exam 2

MATH 280 Multivariate Calculus Fall Integrating a vector field over a curve

Math 323 Exam 2 - Practice Problem Solutions. 2. Given the vectors a = 1,2,0, b = 1,0,2, and c = 0,1,1, compute the following:

Practice problems. 1. Given a = 3i 2j and b = 2i + j. Write c = i + j in terms of a and b.

Chapter 14: Vector Calculus

Name: SOLUTIONS Date: 11/9/2017. M20550 Calculus III Tutorial Worksheet 8

MATH H53 : Final exam

Arc Length and Curvature

Transcription:

SOLUTIONS TO SECOND PRACTICE EXAM Math a, Spring 3 Problem ) ( points) Circle for each of the questions the correct letter. No justifications are needed. Your score will be C W where C is the number of correct answers and W is the number of wrong answers. * denotes the place with the correct answer. The vector connecting the point (,, ) with the point (,, ) is parallel to the vector, 6,. The length of the sum of two vectors is the sum of the length of the vectors. For any three vectors, v ( w + u) = w v + u v. T or any three vectors, ( v w) u = ( w v) u. For any three vectors ( u v) w = ( u w) v. The vectors i + j and k are orthogonal. For any vector v one has v ( v) =. If we attach the vector,, to the point P = (, 3, ), the head of the vector points to the point Q = (3,, ). The set of points which have distance from a plane form a single plane. The set of points which satisfy x + x + y z = is a cone. If u + v and u v are orthogonal, then the vectors u and v have the same length. If P, Q, R are 3 different points in space that don t lie in a line, then P Q RQ is a vector orthogonal to the plane containing P, Q, R. The line r(t) = (+t, +3t, +t) hits the plane x+3y +z = 9 at a right angle. If in rectangular coordinates, a point is given by (,, ), then its spherical coordinates are (ρ, θ, φ) = (, π/, π/). If the velocity vector of the curve r(t) is never zero and always parallel to a constant vector v for all times t, then the curve is a straight line. The equation r = 3z in cylindrical coordinates defines a cone. There are curves for which the binormal vector is not defined at some points. The curvature of a curve is the length of the acceleration vector. A surface which is given as r = sin(z) in cylindrical coordinates stays the same when we rotate it around the y axis. The identity v w + v w = v w holds for all vectors v, w.

Problem ) ( points) Match the equation with their graphs. To do so, it can help to look at the intersection of each surface with the xy-plane. I II.. - III.. - IV - V.9.8.7.6 VI. -... -.. I,II,III,IV,V or VI? Equation II z = sin(x)y IV z = cos( π I x + 3y + z = (+x +y ) ) I,II,III,IV,V or VI? Equation III z = y 3 V z = x VI z = x + y

Problem 3) ( points) Match the equation with their graphs and describe the x-y trace (the intersection of the surface with the xy-plane) with at most three words in each case. I II III IV V VI Enter I,II,III,IV,V,VI here Equation Describe the x-y trace in words V x y z = hyperbola I x + y = z a point II x + y + z = an ellipse III x y = a hyperbola IV x y z = a hyperbola VI x + y z = a circle Problem ) ( points) Find the distance between the point P = (,, ) and the plane which contains the points A = (,, ) and B = (,, ) and C = (,, ). To do so: a) Find an equation of the plane. 3

Solution: n = ((,, ) (,, )) ((,, ) (,, )) = (,, ) is normal to the plane. Therefore x + y z = d =. The constant d = was obtained by plugging in a point. b) Find the distance. Solution: Project the vector P A onto the vector n to obtain d = / 3 Problem ) ( points) An ant has gotten into the math department surface cabinet and is walking around on one of the models. Her position in cylindrical coordinates is for t 6π. r(t) = t θ(t) = t z(t) = t a) What are the parametric equations describing the ant s path in rectangular coordinates? Solution; x(t) = r(t) cos(θ(t)) = t cos(t) y(t) = r(t) sin(θ(t)) = t sin(t) z(t) = t b) Write an equation (in either rectangular or cylindrical coordinates) which might describe the surface the ant is walking on. Sketch the surface given by your equation, and indicate the ant s path. (Hint: there are many possible surfaces. You may find some easier to draw than others.) Solution: One solution is z = x / + y / = r /, the paraboloid.

Problem 6) ( points) a) Find the curvature of the curve r(t) = t, t 3, at the point t =. b) Is there a point r(t) with r for which the curvature is zero? Explain. Hint. Use the formula κ(t) = r (t) r (t) / r (t) 3. Solution. a) r (t) = t, 3t, r (t) =, 6t, r (t) r (t) = (,, 6t ) so that κ(t) = r (t) r / r (t) 3 = 6t/ t + 9t 3. For t =, we obtain κ() = 6/3 3. b) We have r for all t. But then, r (t) r (t) = (,, 6t ) so that the curvature is not zero. The answer is no. Problem 7) ( points) Let a and b be two vectors in R 3. Assume that the length of a b is equal to. What is the length of ( a + b) ( a b)? Solution. ( a+ b) ( a b) = a a a b+ b a b b = a b + b a = a b has length twice the length of a b. The answer is. This problem can also be solved geometrically. A single picture is necessary. The paralelogram spanned by (a-b) and (a+b) contains four triangles, each of which is half of the parallogram spanned by a and b. a a b a+b a-b Problem 8) ( points)

Consider the parametrized curve r(t) = e t cos(t), e t sin(t), e t. a) Find a parametric equation for the tangent line to this curve at t = π. Solution. r(π) = ( e π,, e π ). r (t) = (e t (cos(t) sin(t)), e t (sin(t) + cos(t)), e t ). r (π) = ( e π, e π, e π ). The parametrization of the tangent curve is r(t) = r(π) + t r (π). In other words, x(t) = e π t, y(t) = t, z(t) = e π + t. b) Find a scalar equation for the plane perpendicular to the curve at the same point. Solution. n = ( e π, e π, e π ) is normal to the plane which is therefore given by x + y + z = d = e π. c) Find the arc length of the segment of the curve for which t. Solution: 3e t = 3(e ) dt Problem 9) ( points) Let C be the curve of the intersection of the elliptical cylinder x with the plane 3z = y. + y 9 = in three dimensions a) Find a parametric equation r(t) = (x(t), y(t), z(t)) of C. Solution. x(t) = cos(t), y(t) = 3 sin(t), z(t) = (/3), y(t) = sin(t). b) Find the arc length of C. Solution. x (t) = sin(t), y (t) = 3 cos(t), z (t) = cos(t). π x (t) + y (t) + z (t) dt = π sin (t) + 9 cos (t) + 6 cos (t) dt = π. 6