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Version.0: 006 abc General Certificate of Education Chemistry 642 CM5 Thermodynamics and Further Inorganic Chemistry Mark Scheme 2006 examination - June series Mark schemes are prepared by the Principal Examiner and considered, together with the relevant questions, by a panel of subject teachers. This mark scheme includes any amendments made at the standardisation meeting attended by all examiners and is the scheme which was used by them in this examination. The standardisation meeting ensures that the mark scheme covers the candidates responses to questions and that every examiner understands and applies it in the same correct way. As preparation for the standardisation meeting each examiner analyses a number of candidates scripts: alternative answers not already covered by the mark scheme are discussed at the meeting and legislated for. If, after this meeting, examiners encounter unusual answers which have not been discussed at the meeting they are required to refer these to the Principal Examiner. It must be stressed that a mark scheme is a working document, in many cases further developed and expanded on the basis of candidates reactions to a particular paper. Assumptions about future mark schemes on the basis of one year s document should be avoided; whilst the guiding principles of assessment remain constant, details will change, depending on the content of a particular examination paper. Copyright 2006 AQA and its licensors. All rights reserved

Chemistry, CM5 AQA A2, Mark Scheme, June 2006 series CM5 Section A Question (a) (i) Fe + 2Cl FeCl 2 + 2 (allow ionic formulae) or Fe + 2 + Fe 2+ + 2 (ii) PV = nrt n = PV/RT (allow either formula but penalise contradiction) n = 0000 02 0 6 8.3 298 = 4.53 0-3 (mol) (answer must have at least 3 sig. figs. Ignore units) (iii) Moles of iron = 4.5(3) 0 3 mol ( allow conseq on (a)(ii)) ( or = 4.2(5) 0 3 if candidate uses given moles of hydrogen) Mass of iron = 4.53 0 3 55.8 = 0.253 g (mark is for method mass = moles A r ) (Mass of iron can be 56) (iv) 0.253 00/0.263 = 96. % (mark is for answer to 2 sig. figs. ) (allow conseq on mass of iron. E.g. = 90% from 4.2(5) 0 3 moles of 2 and Fe) (Do not allow answers greater than or equal to 00%) (b) (i) Fe 2+ Fe 3+ + e (ignore state symbols) Cr 2 O 2 7 + 4 + + 6e 2Cr 3+ + 7 2 O Cr 2 O 2 7 + 4 + + 6Fe 2+ 2Cr 3+ + 7 2 O + 6Fe 3+ (ii) Moles of dichromate = moles Fe 2+ /6 (Allow conseq, mark is for method (a)(iii)/6 ) = 4.53 0 3 /6 = 7.55 0 4 Volume of dichromate = moles/concentration (mark is for this method) (= (7.55 0 4 000)/0.0200 ) V = 37.75 (cm 3 ) (allow 37.7 to 37.8, allow no units but penalise wrong units) (allow conseq on moles of dichromate) (if value of 3.63 0 3 used answer is 30.2 to 30.3, otherwise ans = moles Fe 2+ /0.0002) (if mole ratio wrong and candidate does not divide by 6, max score is ONE for volume method) (iii) (KMnO 4 ) will also oxidise (or react with) Cl (or chloride or Cl) Total 4 2

AQA A2, Mark Scheme, 2006 June series Chemistry, CM5 Question 2 (a) Particles are in maximum state of order (or perfect order or completely ordered or perfect crystal or minimum disorder or no disorder) ( entropy is zero at 0 k by definition) (b) (Ice) melts (or freezes or changes from solid to liquid or from liquid to solid) (c) Increase in disorder () Bigger (at T 2 ) Second mark only given if first mark has been awarded (d) (i) Moles of water =.53/8 (= 0.085 ) eat change per mole = 3.49/0.085 = 4. (kj mol ) (allow 4 to 4., two sig. figs. ) (penalise 4 (negative value), also penalise wrong units but allow kj only) (ii) G = T S (iii) = T S or S = /T (penalise if contradiction) S = 4./373 = 0.0 kj K (mol ) (or 0 (J K (mol )) (allow 2 sig. figs.) (if use value given of 45, answer is 0.2 (or 20 to 2) (if is negative in (d) (i), allow negative answer) (if is negative in (d) (i), allow positive answer) (if is positive in (d) (i), penalise negative answer) Correct units as above (mol - not essential) Total 0 3

Chemistry, CM5 AQA A2, Mark Scheme, June 2006 series Question 3 (a) A Cr( 2 O) 3 (O) 3 (or Co(O) 3 B CO 2 2[Cr( 2 O) 6 ] 3+ +3CO 2 3 2[Cr( 2 O) 3 (O) 3 ] + 3CO 2 +3 2 O ( or gives 2Cr(O) 3 + 3CO 2 + 9 2 O) (b) (i) NaO (or KO) (ii) +6 (or 6 or +VI or VI) (iii) 2 O 2 (orna 2 O 2 or BaO 2 ) [Cr(O) 6 ] 3 + 2O CrO 2 4 +4 2 O + 3e (or [Cr(O) 6 ] 3 CrO 2 4 +2 2 O + 2 + + 3e ) (c) (i) 2 N N 2 2 N Cr 2 N N 2 N 2 3+ At least one 2 NC 2 C 2 N 2 with correct structure and bonding to Cr via N 6 co-ordination with 3 en drawn correctly Correct 3+ charge (Mark independently but must not have 6 monodentate ligands) (ii) Same (or similar) type of bonds broken and made Same number of bonds broken and made (or same co-ordination number) (iii) Entropy change (or S ) is positive (or increase in disorder) Because there are more product particles than reactant particles (d) [Cr( 2 O) 6 ] 2+ Reducing agent (mark independently) (e) (i) Ethanal (or C 3 CO) (not C 3 CO) (ii) Ethanoic acid (or correct formula) Total 8 4

AQA A2, Mark Scheme, 2006 June series Chemistry, CM5 Question 4 (a) (i) ( K p ) = (p z ) 2 /(p x )(p y ) 3 (penalise use of square brackets, allow ( ) ) (ii) X (22 6)/4 = 4 (MPa) (mark is for value 4 only, ignore units) Y obtained by multiplying value for X by 3 (allow conseq on wrong value for X ) Y 4.0 3 = 2 (MPa) ( mark is for value 2 only) (iii) K p = 6.0 2 /4.0 2.0 3 = 5.2 0 3 (allow conseq on wrong values for X and Y e.g.6 2 /3 9 3 = 0.65) (if K p wrong in (a)(i) CE) MPa 2 (allow any unit of P -2 provided ties to P used for K p value) (b) high pressure expensive (due to energy or plant costs) (Rate is) slow (at lower temperatures) Total 8 5

Chemistry, CM5 AQA A2, Mark Scheme, June 2006 series Question 5 (a) (i) Fe 2+ (ii) F 2 O (iii) Fe 2+ Cl Use list principle if more than two answers (b) (i) e.m.f. = E(rhs) E(lhs) =.52 0.77 = 0.75 (0.75 scores first mark also) (ii) Fe 2+ Fe 3+ + e (iii) Decrease (Increase is CE, no further marks) Equilibrium (or reaction) shifts to R (or L if refers to half equation in table) (or in favour of more Fe 3+ ) (or more Fe 3+ formed) (or more electrons formed) Electrode potential (for Fe 3+ /Fe 2+ ) less positive (or decreases) Total 0 6

AQA A2, Mark Scheme, 2006 June series Chemistry, CM5 Section B Question 6 (a) (i) N 3 + 2 O N 4 + O (allow N 4 O as product) Ammonia is a proton (or + ) acceptor Shape of the ammonium ion shown correctly as tetrahedral (allow no charge or wrong charge) ( lose mark if wrong angle given) (allow sticks ) (ii) N 3 + BF 3 3 NBF 3 (allow N 3 BF 3 or BF 3 N 3 ) (penalise Fl for F once only) Ammonia is a lone pair donor Shape of 3 NBF 3 shown as tetrahedral about N and B linked by N B bond. (b) 4 () O ion () O- O R () C Cl R C Cl N + R C + N Cl - N 3 arrows and a lone pair on O () Correct name for product (e.g. ethanamide) (c) Further substitution (or reaction) prevented (or 2 o or 3 o amine not formed) Because ammonia is more likely to react with the haloalkane (rather than the amine product) (or all the haloalkane is used up) (or less amine is available) (d) 2N 3 + 2e 2N 2 + 2 2K + 2N 3 2K + 2N 2 + 2 ( or 2KN 2 + 2 ) (e) Van der Waals ( or VdW) forces between methane molecules (or VdW forces in methane) ydrogen bonding in ammonia and water ydrogen bonds are stronger than van der Waals forces ( or VdW forces are the weakest) ydrogen bonds in water more extensive than ammonia because O has two lone pairs (N one) (or Water forms more bonds per molecule (than ammonia)) (or bonds in water stronger because O more electronegative than N) (or bonds in water stronger because O bond more polar than N ) (Note that breaking covalent bond is CE but may not lose all 4 marks) Total 9 7

Chemistry, CM5 AQA A2, Mark Scheme, June 2006 series Question 7 (a) MgCl 2 is ionic SiCl 4 is molecular (or simple covalent) Van der Waals (or VdW) forces between molecules (or intermolecular VdW forces) (QoL mark for forces between molecules clearly indicated) Ionic forces ( or bonds) stronger than VdW (must be a comparison to score the mark) Therefore more energy required (to separate the particles in MgCl 2 ) (b) Charge on oxide ion bigger than on chloride (or oxide ion smaller than chloride) (or charge density on oxide ion greater than chloride) Therefore electrostatic attraction is stronger (QoL mark, can be given independent of first mark) (c) MgO (is a white solid that) forms a suspension (or slightly soluble) MgO + 2 O Mg(O) 2 (or Mg 2+ + 2O ) p is 8 to 0 SO 2 dissolves (or forms (colourless) solution) SO 2 + 2 O 2 SO 3 ( or + + SO 3 ) ( or 2 + + SO 2 3 ) p is to 4 (mark both p values independently of equations) (d) Al(O) 3 + O Al(O) 4 species mark (or forms Al(O) 3 6 etc) Balanced equation Al(O) 3 + 3 + 3+ + 3 2 O Al( 2 O) 6 species mark (or forms [Al( 2 O) 5 (O)] 2+, Al 3+, AlCl 3 (salt + water etc) (Note must start equations with Al(O) 3 or Al(O) 3 ( 2 O) n where n = to 3) Balanced equation Total 7 8

AQA A2, Mark Scheme, 2006 June series Chemistry, CM5 Question 8 (a) Reducing power increases SO 2 S 2 S (Apply list principle to answers that give more than 3 reduction products) 2I + SO 2 4 + 4 + I 2 + SO 2 + 2 2 O species correct (or 6I + SO 2 4 + 8 + 3I 2 + S + 4 2 O) (or 8I + SO 2 4 + 0 + 4I 2 + 2 S + 4 2 O) (Starting materials can be I or NaI instead of I or 2 SO 4 instead of + ) Balanced equation (one only of the above) (b ) Cl 2 2Cl! RC 3 + Cl!! RC 2 + Cl! RC 2 + Cl 2 RC 2 Cl + Cl! (Ignore termination steps and any arrows) (c) Electrophilic substitution RC 2 Cl + AlCl 3 RC + 2 + AlCl 4 (Ignore any arrows) 3 C + 2 R C C 2 R 2 R + + + arrow () intermediate () and arrow () (In intermediate, broken delocalised ring must cover at least 3 carbons and not extend beyond a line between carbons 2 and 6 on the benzene ring) Total 4 9

Chemistry, CM5 AQA A2, Mark Scheme, June 2006 series Question 9 (a) (Initially slow) because reaction is between two negative ions (or between two negative reactants or two negative species) Which repel each other Then Mn 2+ (or Mn 3+ ) (ions) are formed acting as an autocatalyst (QOL mark) (or answer such as Mn 2+ ions formed in the reaction act as a catalyst) 2MnO 4 + 6 + + 5C 2 O 2 4 2Mn 2+ + 8 2 O + 4CO 2 MnO 4 + 4Mn 2+ + 8 + 5Mn 3+ + 4 2 O C 2 O 2 4 + 2Mn 3+ 2Mn 2+ + 2CO 2 (b) (Note these equations may gain credit if they have spectator ions and/or be written as half equations) Active sites are where reactants are adsorbed onto a catalyst surface ( or bind or react on a catalyst surface) ( do not allow absorbed) (Number of active sites increases if) surface area is increased (or catalyst spread thinly) (or on honeycomb) (or powdered) (or decreased particle size) Active sites blocked by another species (or poison) (or species adsorbed more strongly) (or species adsorbed irreversibly) (or species not desorbed) (Note, credit any answer that implies blocked but not just active site poisoned ) Sulphur (compounds) in aber process (or lead in a catalytic converter) (Note do not allow enzymes unless immobilised) Total 0 0