Shippensburg Math & Computer Day 2014 Individual Math Contest Solutions

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Shippensburg Math & Computer Day 2014 Individual Math Contest Solutions 1. The following four statement, and only these, are found on a card: On this card exactly one statement is false. On this card exactly two statements are false. On this card exactly three statements are false. On this card exactly four statements are false. Suppose each statement is either true or false. Among them, the number of false statements is exactly Solution: (d). Since each pair of statements on the card is contradictory, at most one of them is true. The assumption that none of the statements is true implies the fourth statement is true. In fact, it is easy to verify that the third statement is true. 2. If the distinct non-zero numbers x(y z), y(z x), and z(x y) form a geometric progression with common ratio r, then r satisfies the equation Solution: (a). Let a = x(y z) and observe that the identity implies x(y z) + y(z x) + z(x y) = 0 a + ar + ar 2 = 0 1 + r + r 2 = 0. 3. Let a be a positive integer. Consider the set S of all points whose rectangular coordinates (x, y) satisfy all of the following conditions: i. a 2 x 2a iv. x + a y ii. a 2 y 2a v. y + a x iii. x + y a The boundary of set S is a polygon with... Solution: (d). The boundary of the set of points satisfying the conditions is shown below. 1

4. What is the ones digit of 7 2014. Solution: (e). The ones digits of the powers of 7 follow the repeating pattern 7, 9, 3, 1, 7,.... Since 2014 has a remainder of 2 when divided by 4, the ones digit of 7 2014 is 9. 5. My wife and I were invited to a party attended by four other couples, making a total of ten people. As people arrived, a certain amount of handshaking took place in an unpredictable way, subject only to two obvious conditions: no one shook his or her own hand and no husband shook his wife s hand. After the introductions, I became curious and I went around the party asking each person: How many hands did you shake... And you?... And you? I asked nine people (everyone including my own wife), and I find it very curious that I received nine different answers. How many hands did my wife shake? Solution: (e). Since each person can shake between 0 and 8 hands, each of the nine people that I asked corresponds to one of these values. Thus, call the person who shook 0 hands P 0, the person who shook 1 hand P 1, and so on. First, note that P 8 and P 0 are a couple since P 8 shook hands with everyone but his/her spouse. Repeating this argument, with slight modifications, shows that P i and P j are a couple whenever i + j = 8. Of the nine people, this leaves P 4 without a partner. Thus, P 4 is my wife and she shook 4 hands. 6. Cucumbers are assumed to be a substance that is 99% water by weight. If 500 pounds of cucumbers are allowed to stand overnight, and if the partially evaporated substance that remains in the morning is 98% water, how much is the morning weight? Solution: (b). The night before the cucumbers consisted of 5 pounds of solid matter and the rest water. The amount of solid matter stays fixed and, in the morning, it constitutes 2% of the substance that is being asked about. The question becomes: what is the weight that 5 pounds is 2% of? 7. In the diagram below, the radius of each circle is 1/2 the radius of the next largest circle. If a point inside the largest circle is chosen at random, what is the probability that it would lie in the shaded region? Solution: (d). If the largest circle has radius r, then the area of the shaded region is π(r/2) 2 π(r/4) 2 + π(r/8) 2 = (13πr 2 )/64. Thus the probability is (13πr 2 )/64 πr 2 = 13 64. 2

8. A cow is tied with a 30-foot rope to an outside corner of a rectangular barn having dimensions 20 feet by 10 feet. How many square feet of grazing area does the cow have? Solution: (a). The grazing area the cow has is the shaded region in the figure below. It is the following sum: 3 4 π 302 + 1 4 π 202 + 1 4 π 102 = 800π. 9. The three-digit number 2a3 is added to the number 326 to give the three-digit number 5b9. If 5b9 is divisible by 9, then a + b equals... Solution: (c). To begin with, we have 500+10b+9 = 509+10b is divisible by 9. Since the remainder of 509 when divided by 9 is 5 and b is a single digit (between 0 and 9), it follows that b = 4. Next, we know that b = a + 2, and so a = 2. Thus, the a + b = 6. 10. If sin(a) = 2 cos(a), then what is the value of sin(a) cos(a)? Solution: (d). Square both sides to get sin 2 (A) = 4 cos 2 (A). Adding cos 2 (A) to both sides gives 5 cos 2 (A) = 1, and so cos(a) = ± 1/5. From the original equation, we then have sin(a) = ± 4/5, and cos(a) and sin(a) must have the same sign. Therefore, sin(a) cos(a) = 2/5. 11. Kate drives to work at an average speed of 50 miles per hour. On her way home, she drives at an average speed of 60 miles per hour. What was her average speed for the round trip to work and back, to the nearest tenth? Solution: (b). The average speed for the round trip is given by 2D T, where D is the distance from home to work and T is the time elapsed. We have T = D/50 + D/60, and this gives an average speed of 54.54 mph. 12. What is the probability of rolling three fair six-sided dice and having three distinct values, rounded to the nearest tenth. Solution: (d). The probability is 6 5 4 6 6 6 = 5 9 = 0.556. 13. For how many integers n is the expression n2 +n n+4 an integer? Solution: (e) We have n 2 + n n + 4 = n 3 + 12 n + 4. Since 12 has twelve distinct integer divisors, there are twelve values of n that work. 3

14. How many subsets does the set {{1, 2, 3}, {4}, {5}} have? Solution: (c). The set has three element, so it has 2 3 = 8 subsets. 15. In the figure below, three circles are tangent to each other. Find the area of the shaded region if each circle has a radius of 6. Solution: (d). Connecting the centers of the circles, we have an equilateral triangle as shown below. The sides of the equilateral triangle have length 12. The area of the triangle is A 1 = 1 2 (12)2 sin 60 = 36 3. The area of the total three congruent sectors is ( 1 A 2 = 3 2 62 π ) = 18π. 3 The area of the shaded region is A 1 A 2 = 36 3 18π. 16. Solve the rational inequality: 5 x 2 3 x + 2. Solution: (c). The given inequality is equivalent to 2(x + 8) (x 2)(x + 2) 0. The zero of the denominator is x = 8 (inclusive) and the zeros of the denominator are x = 2 and x = 2 (exclusive). They divide the number line into four intervals. In each interval, pick a point and check the inequality. 4

17. Two points are picked at random on the circle x 2 + y 2 = 1. What is the probability that the chord joining the two points has a length of at least 1? Solution: (d). Let A be a point picked on the circle at random. If the length of the chord AB is at least 1, then the point B must lie on the longer arc of CD that does not include A (see picture below). The probability of the point b lying on the longer arc CD is 4 3 π 2π = 2 3. 18. Anne s sock drawer contains 13 blue socks, 6 red socks, and 8 white socks. In the dark, Anne cannot see the colors of the socks. How many socks would she have to take from the drawer to guarantee that she had a matched pair of any color? Solution: (d). Since there are three colors of socks, she must take four socks to guarantee a matched pair. 19. Given a circle of radius r with a rectangle ABCO inscribed in one quadrant, what is the length of the diagonal AC? Solution: (e). AC = BO = r. 5

20. The number of horses and sheep in a certain town is such that the ratio of the difference to the sum is 1 : 7 and the ratio of the sum to the product is 7 : 24. What is the sum of the the number of horses and sheep? Solution: (b). Let x be the number of horses and y the number of sheep. Then we have which is equivalent to x y x + y x + y xy = 1 7 = 7 24, 6x 8y = 0 24x + 24y = 7xy. Solving this system of equations, we have x = 8 and y = 6. Thus, the total sum is x + y = 14. 6