PHYSICS 1050 Mid-term Test 1 University of Wyoming 8 February 2007

Similar documents
PHYSICS 1210 Exam 2 University of Wyoming 14 March ( Day!) points

b) (5) What is the magnitude of the force on the 6.0-kg block due to the contact with the 12.0-kg block?

c) (6) Assuming the tires do not skid, what coefficient of static friction between tires and pavement is needed?

EN40: Dynamics and Vibrations. Midterm Examination Thursday March

F g. = G mm. m 1. = 7.0 kg m 2. = 5.5 kg r = 0.60 m G = N m 2 kg 2 = = N

AP-C WEP. h. Students should be able to recognize and solve problems that call for application both of conservation of energy and Newton s Laws.

Spring 2001 Physics 2048 Test 3 solutions

PHYS Summer Professor Caillault Homework Solutions. Chapter 5

Midterm Exam #2, Part A

Between any two masses, there exists a mutual attractive force.

Recap. Centripetal acceleration: v r. a = m/s 2 (towards center of curvature)

Uniform Circular Motion

ω = θ θ o = θ θ = s r v = rω

OSCILLATIONS AND GRAVITATION

Gravitation. AP/Honors Physics 1 Mr. Velazquez

Extra notes for circular motion: Circular motion : v keeps changing, maybe both speed and

Voltage ( = Electric Potential )

Conflict Exam Issue. Sorry, Can t do it. Please see Kevin Pitts if you have any additional questions or concerns about this. Office is 231 Loomis

Ch 13 Universal Gravitation

Quiz 6--Work, Gravitation, Circular Motion, Torque. (60 pts available, 50 points possible)

1. A stone falls from a platform 18 m high. When will it hit the ground? (a) 1.74 s (b) 1.83 s (c) 1.92 s (d) 2.01 s

Physics 1114: Unit 5 Hand-out Homework (Answers)

Physics C Rotational Motion Name: ANSWER KEY_ AP Review Packet

Phys 201A. Homework 6 Solutions. F A and F r. B. According to Newton s second law, ( ) ( )2. j = ( 6.0 m / s 2 )ˆ i ( 10.4m / s 2 )ˆ j.

SAMPLE QUIZ 3 - PHYSICS For a right triangle: sin θ = a c, cos θ = b c, tan θ = a b,

AP * PHYSICS B. Circular Motion, Gravity, & Orbits. Teacher Packet

Circular Orbits. and g =

kg 2 ) 1.9!10 27 kg = Gm 1

PHYS 1410, 11 Nov 2015, 12:30pm.

Chapter 5 Force and Motion

Chapter 5 Force and Motion

Physics 11 Chapter 4: Forces and Newton s Laws of Motion. Problem Solving

Force can be exerted by direct contact between bodies: Contact Force.

to point uphill and to be equal to its maximum value, in which case f s, max = μsfn

Uniform Circular Motion

Chapter 5: Uniform Circular Motion

Chap 5. Circular Motion: Gravitation

10. Force is inversely proportional to distance between the centers squared. R 4 = F 16 E 11.

Physics 107 TUTORIAL ASSIGNMENT #8

m1 m2 M 2 = M -1 L 3 T -2

Chapter 5. Applying Newton s Laws. Newton s Laws. r r. 1 st Law: An object at rest or traveling in uniform. 2 nd Law:

Physics Fall Mechanics, Thermodynamics, Waves, Fluids. Lecture 6: motion in two and three dimensions III. Slide 6-1

AP Physics Electric Potential Energy

21 MAGNETIC FORCES AND MAGNETIC FIELDS

20-9 ELECTRIC FIELD LINES 20-9 ELECTRIC POTENTIAL. Answers to the Conceptual Questions. Chapter 20 Electricity 241

Circular Motion & Torque Test Review. The period is the amount of time it takes for an object to travel around a circular path once.

HW #5 Hints. Today. HW #5 Hints. HW #5 Hints. Announcements:

PHYS 1114, Lecture 21, March 6 Contents:

( ) ( ) Review of Force. Review of Force. r = =... Example 1. What is the dot product for F r. Solution: Example 2 ( )

Unit 6 Practice Test. Which vector diagram correctly shows the change in velocity Δv of the mass during this time? (1) (1) A. Energy KE.

b) (5) What average force magnitude was applied by the students working together?

C3 Interactions transfer momentum. C4 - Particles and Systems. General Physics 1

PHYS 2135 Exam I February 13, 2018

Chapter 4. Newton s Laws of Motion

Physics 4A Chapter 8: Dynamics II Motion in a Plane

PS113 Chapter 5 Dynamics of Uniform Circular Motion

Physics 111. Ch 12: Gravity. Newton s Universal Gravity. R - hat. the equation. = Gm 1 m 2. F g 2 1. ˆr 2 1. Gravity G =

Sections and Chapter 10

QUESTION 1 [25 points]

Physics 181. Assignment 4

Chapter 4. Newton s Laws of Motion. Newton s Law of Motion. Sir Isaac Newton ( ) published in 1687

- 5 - TEST 1R. This is the repeat version of TEST 1, which was held during Session.

HW Solutions # MIT - Prof. Please study example 12.5 "from the earth to the moon". 2GmA v esc

Chapter 8. Accelerated Circular Motion

Objective Notes Summary

15 B1 1. Figure 1. At what speed would the car have to travel for resonant oscillations to occur? Comment on your answer.

Physics 235 Chapter 5. Chapter 5 Gravitation

Describing Circular motion

PHYS 172: Modern Mechanics. Summer Lecture 4 The Momentum Principle & Predicting Motion Read

Physics: Work & Energy Beyond Earth Guided Inquiry

Momentum is conserved if no external force

. Using our polar coordinate conversions, we could write a

Section 26 The Laws of Rotational Motion

1) Consider a particle moving with constant speed that experiences no net force. What path must this particle be taking?

When a mass moves because of a force, we can define several types of problem.


Potential Energy and Conservation of Energy

PHYSICS Final Exam University of Wyoming 11 December 2013

Physics 111 Lecture 5 Circular Motion

DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS

A car of mass m, traveling at constant speed, rides over the top of a circularly shaped hill as shown.

PHYSICS NOTES GRAVITATION

Our Universe: GRAVITATION

SPH4U Unit 6.3 Gravitational Potential Energy Page 1 of 9

Teachers notes. Beyond the Thrills excursions. Worksheets in this book. Completing the worksheets

= 4 3 π( m) 3 (5480 kg m 3 ) = kg.

Physics 121 Hour Exam #5 Solution

Chapter 5. Uniform Circular Motion. a c =v 2 /r

From Newton to Einstein. Mid-Term Test, 12a.m. Thur. 13 th Nov Duration: 50 minutes. There are 20 marks in Section A and 30 in Section B.

DYNAMICS OF UNIFORM CIRCULAR MOTION

Physics 11 Chapter 3: Vectors and Motion in Two Dimensions. Problem Solving

Lab #0. Tutorial Exercises on Work and Fields

Centripetal Force. Lecture 11. Chapter 8. Course website:

Chapter 5. really hard to start the object moving and then, once it starts moving, you don t have to push as hard to keep it moving.

Easy. r p 2 f : r p 2i. r p 1i. r p 1 f. m blood g kg. P8.2 (a) The momentum is p = mv, so v = p/m and the kinetic energy is

Physics 201 Homework 4

PROJECTILE MOTION. At any given point in the motion, the velocity vector is always a tangent to the path.

06 - ROTATIONAL MOTION Page 1 ( Answers at the end of all questions )

TAMPINES JUNIOR COLLEGE 2009 JC1 H2 PHYSICS GRAVITATIONAL FIELD

Algebra-based Physics II

Transcription:

Name: PHYSICS 1050 Mid-tem Test 1 Univesity of Wyoming 8 Febuay 2007 This test is open-note and open-book. This means that any efeence mateial is pemitted duing the test. Calculatos also ae pemitted. Howeve, no collaboation, consultation, o communication with othe people (othe than the administato) is allowed by any means, including but not limited to vebal, witten, o electonic methods. If you have a question about the test, please aise you hand. If that does not wok, pehaps you should just give up. Please do not open this test booklet until eveyone has eceived a booklet and the test administato has indicated fo you to begin. While you ae waiting, make sue that you name is witten at the top of this page. Convesion Factos and Constants: 100 cm = 1 m 1000 mm = 1 m 1000 m = 1 km 1000 g = 1 kg 3.2804 ft = 1 m 1 lb = 4.4482 N gavitational acceleation at eath s suface: g = 9.8 m/s 2 = 9.8 N/kg Compound Units: 1 day = 24 h 1 h = 60 min 1 min = 60 s velocity: m/s acceleation: m/s 2 foce: N = kg m/s 2 Fomulas: Aveage velocity: v = x t Instantaneous velocity: v = lim x t t 0 Aveage acceleation: a = v t Instantaneous acceleation: a = lim v t t 0 Velocity change duing constant acceleation: v = a t Distance taveled duing constant acceleation: x = v 0 t + 1 2 a ( t) 2 Acceleation fom net foce F : a = F /m momentum, impulse: kg m/s wok, enegy: J = N m = kg m 2 /s 2 powe: W = J/s = N m/s = kg m 2 /s 3 Gavitational foce on eath: F = mg Fiction: F = µn Momentum: p = mv Impulse: p = F t Wok: w = F d = E Powe: P = E t = w / t = F v Kinetic enegy: KE = 1 mv 2 2 Gavitational potential enegy: PE = mgh

Shot Multiple choice 4 questions, 4 points each. Please cicle the most coect answe fom the choices given. 1. In this class we mostly use mks units, in which compound units fo physical quantities ae expessed in tems of metes, kilogams, and seconds. Anothe popula system of units is temed cgs, in which units ae based on centimetes, gams, and seconds. The cgs unit of foce is the dyne, whee 1 dyne = 1 g cm/s 2. What is the value of 1 dyne expessed in newtons? (1000 g = 1 kg; 100 cm = 1 m.) a. 1 dyne = 1/100,000 N. b. 1 dyne = 1/1000 N. c. 1 dyne = 1/100 N. d. 1 dyne = 100 N. e. 1 dyne = 1000 N. f. 1 dyne = 100,000 N. 2. Which one of the following physical quantities is a vecto? a. Mass. b. Enegy. c. Time. d. Momentum. e. Speed. f. Distance. 3. Which one of the following statements is always tue about a scala multiple of vecto a (that is, the poduct of multiplying vecto a by a non-vecto)? a. A scala multiple of vecto a is anothe vecto eithe in the same diection as a o in the opposite diection fom a. b. A scala multiple of vecto a is anothe vecto in the same diection as vecto a. c. A scala multiple of vecto a is anothe vecto pependicula to vecto a. d. A scala multiple of vecto a is anothe vecto that can be in any diection. e. A scala multiple of vecto a is a scala. page 2 of 10

4. The foce of kinetic fiction between two sufaces sliding past each othe depends on which one facto listed? a. The coefficient of fiction µ. b. The speed at which the sufaces slide past each othe. c. The diection that the sufaces slide past each othe. d. The aea of contact between the sufaces. Matching 1 question, 4 points. 5. The diagams on the left depict the cuent velocity of an object (vecto v, line aow) and the net foce (vecto F, block aow) acting on the object. The text desciptions on the ight descibe the object's motion ove time. Match each diagam on the left with the text desciption that descibes the same pocess. F v Slowing down while changing diection. v v v F F F Slowing down without changing diection. Speeding up while changing diection. Speeding up without changing diection. page 3 of 10

Moe involved Multiple Choice 10 questions, 6 points each. Please cicle the most coect answe fom the choices given. 6. A tugboat pushes a bage along a canal at constant velocity. The only foces pushing back on the bage ae dag fom the wate and ai. How ae the foces of dag and the fowad push fom the tugboat elated to each othe? a. The (fowad) push is geate in magnitude than the (backwad) dag. b. Dag exactly equals the (fowad) push. c. Dag is exactly the opposite of the (fowad) push. d. The (backwad) dag is geate in magnitude than the (fowad) push. 7. Which one phase below coectly descibes the motion depicted in the velocity-time gaph to the ight? (Positive velocity means motion in the fowad diection.) a. Moving fowad with deceasing speed. b. Moving fowad at constant speed. c. Moving fowad with inceasing speed. d. Moving backwad deceasing speed. e. Moving backwad at constant speed. f. Moving backwad with inceasing speed. velocity 0 time 8. If the only foce acting on an object is gavity, in what diection will it acceleate? a. It will always acceleate in an upwad diection. b. It will always acceleate in a hoizontal diection. c. It will always acceleate in a downwad diection. d. It will always acceleate in the same diection as its velocity. e. It will always acceleate in the diection pependicula to its velocity. f. It will always acceleate in the diection opposite its velocity. page 4 of 10

9. When a ca tuns a cone at constant speed, so that its final diection of tavel is diffeent than its initial diection, but its speed is unchanged, how ae its momentum and kinetic enegy affected? a. Neithe its kinetic enegy no its momentum change. b. Its kinetic enegy changes, but its momentum does not. c. Its momentum changes, but its kinetic enegy does not. d. Both its momentum and its kinetic enegy change. 10. A cute fuy animal is fied fom a catapult so that flies though the ai and lands softly in a flowebed. Duing its tajectoy, the only foce acting on it is gavity. Which of the following statements coectly descibes the effect of gavity duing the animal s upwad and downwad acs? a. Gavity does positive (> 0) wok on the animal thoughout its tajectoy. b. Gavity does positive (> 0) wok on the animal duing its upwad ac, and negative (< 0) wok on the animal duing its downwad ac. c. Gavity does negative (< 0) wok on the animal duing its upwad ac, and positive (> 0) wok on the animal duing its downwad ac. d. Gavity does negative (< 0) wok on the animal thoughout its tajectoy. 11. When a commute tain moving at cuising speed applies a steady, modeate foce by its bakes, it stops in 60 s. If it bakes hade, so that its stopping foce is doubled, how long will it take to stop fom the same cuising speed? a. 240 s. b. 60 s. c. 30 s. d. 15 s. page 5 of 10

12. Fou fatenity membes each oll a keg of bee down a diffeent hill. All fou hills ae 5 m high, but they have diffeent shapes. In which case does gavity do the most wok on the keg as the keg olls downhill? a. Rolling down a steep hill. b. Rolling down a gadual hill. c. Rolling down a hill that is at fist steep, then gadual. d. Rolling down a hill that is at fist gadual, then steep. e. The wok is the same in all fou cases. 13. (We haven t talked about gavity yet, but you aleady know enough to answe this question.) The moon obits the eath instead of flying off into space at a constant velocity because the eath s gavity constantly pulls the moon towad the eath. How does the gavitational foce with which the moon pulls on the eath compae to the gavitational foce with which the eath pulls on the moon? a. The moon pulls on the eath hade than the eath pulls on the moon. b. The eath pulls on the moon hade than the moon pulls on the eath. c. The moon pulls on the eath about as had as the eath pulls on the moon. d. The moon pulls on the eath exactly as had as the eath pulls on the moon. page 6 of 10

14. A small ca (with a small mass) collides with a lage tuck (with a lage mass). The dives of the two vehicles have the same mass, and each dive stays with the vehicle thoughout the collision. How do the magnitudes of the foces expeienced by the vehicles and thei dives compae? a. The foce on the ca is geate than the foce on the tuck. The foce on the ca s dive is geate than the foce on the tuck s dive. b. The foce on the ca is geate than the foce on the tuck. The foce on the ca s dive is equal to than the foce on the tuck s dive. c. The foce on the ca is equal to the foce on the tuck. The foce on the ca s dive is geate than the foce on the tuck s dive. d. The foce on the ca is equal to the foce on the tuck. The foce on the ca s dive is equal to the foce on the tuck s dive. e. The foce on the ca is less than the foce on the tuck. The foce on the ca s dive is equal to the foce on the tuck s dive. f. The foce on the ca is less than the foce on the tuck. The foce on the ca's dive is less than the foce on the tuck's dive. 15. Which pocess equies the most powe? a. Applying a foce of 800 N at a speed of 2 m/s. b. Lifting a 500-N weight 20 m in 10 s. c. Opeating a 1000-watt hai dye. d. Acceleating a 4-kg mass fom est (0 m/s) to a speed of 50 m/s in 5 s. page 7 of 10

Shot answe and calculation 2 questions, 10 points each. Please povide complete answes to each question. Povide units with all numeical answes. Show all wok so that patial cedit can be assigned. 16. The foce diagam below depicts the foces acting on a ball on a amp. What is the diection of the amp? Daw it. Will the ball acceleate? If so, in what diection? nomal foce gavity page 8 of 10

17. A Vogon s 1 100-kg gandmothe finds heself flying though space at a speed of 20 m/s diectly towad the 300-kg Ravenous Bugblatte Beast of Taal, who is floating motionless in space. When she eaches the beast, it of couse immediately devous he. What is the Bugblatte Beasts s speed afte its dinne? 1 [Vogons] ae one of the most unpleasant aces in the Galaxy not actually evil, but bad-tempeed, bueaucatic, officious and callous. They wouldn t even lift a finge to save thei own gandmothes fom the Ravenous Bugblatte Beast of Taal without odes signed in tiplicate, sent in, sent back, queied, lost, found, subjected to public inquiy, lost again, and finally buied in soft peat fo thee months and ecycled as fielightes. The best way to get a dink out of a Vogon is to stick you finge down his thoat, and the best way to iitate him is to feed his gandmothe to the Ravenous Bugblatte Beast of Taal. Douglas Adams, The Hitchhike s Guide to the Galaxy, 1979. page 9 of 10

Exta Cedit 18. (5 points) In class, when I sang Fo acceleation, Newton s once again ou souce: It s diectly in popotion to applied net foce, But invesely to the mass of what you e pushing, of couse. what equation was I descibing? Fo full cedit, you must both name (2 pt) and wite out the equation (3 pt). page 10 of 10