SBI PO 2015 PRELIM (TIER I) EXAM MODEL PAPER SOLUTIONS Part 1 SOLUTIONS ENGLISH LANGUAGE Answers (1-10) 1. (5) 2. (1) 3. (2) 4. (3) 5. (4) 6. (4) nurturing 7. (1) drive 8. (4) hurdle 9. (2) manageable 10. (4) differ from Explanations (11-15) 11. (2) Use on in place of by. (lack of interest on the part of the public) 12. (2) Use booming in place of boom. (a booming business fuelled) 13. (5) No error. 14. (4) Use among in place of between. (among the public) 15. (5) No error Answer (16-20) 16. (4) 17. (4) 18. (5) 19. (5) 20. (1) Answers (21-30) 21. (2) 22. (3) 23. (5) 24. (3) 25. (4) 26. (5) 27. (4) 28. (2) 29. (1) 30. (1) Part 2 SOLUTIONS QUANTITATIVE APTITUDE Solutions (31-35) 31. (2) 32. (2) 33. (3) 34. (4) 35. (1) Solutions (36-40) 36. (2) I. 12x 2 + 11x + 12 = 10x 2 + 22x 2x 2-11x + 12 = 0 2x 2-8x 3x + 12 = 0 2x (x 4) 3 (x 4) = 0 (x 4) (2x 3) x = 4, x = 1.5 II. 13y 2 18y + 3 = 9y 2 10y 4y 2 8y + 3 = 0 4y 2 6y 2y + 3 = 0 4y 2 2y 6y + 3 = 0 2y (2y 1) 3 (2y -1) = 0 (2y 1) (2y 3) = 0 y = 1/2, y = 3/2 y = 1.5, y = 3/2 So x > y
37. (3) I. 18/x 2 + 6/x 12/x 2 = 8/x 2 18 + 6x - 12/ x 2 =8/x 2 6 + 6x = 8 6x = 2 X = 2/6 = 0.33 II. y 3 + 9.68 + 5.64 = 16.95 y 3 = 16.95 15.32 y 3 = 1.63 y = 1.63 y ~ 1.18 x < y 38. (1) I. 1225 x + 4900 = 0 35x + 70 = 0 x = - 70/35 x = - 2 II. (81) 1/4 y + (343) 1/3 = 0 3y + 7 = 0 y = - 7/3 y = - 233 x > y 39. (1) I. (2) 5 + (11) 3 / 6 = x 3 32 + 1331 / 6 = x 3 x 3 = 1363/6 = 227.167 II. 4y 3 = - (589 4) + 5y 3 y 3 = (589 4) y 3 = 147.25 x > y 40. (4) I. (x 7/5 9) = 169 x 3/5 X 10/5 = 9 x 169 X 2 = 9 x 169 X = ± 3 x 13 X = ± 39 II. y 1/4 X y 1/4 X 7 = 273 y 1/2 y = 273/7 = 39 x < y Solutions (41-45) 41. (5) 29, 37, 21, 43, 13, 53, 5 29 8 = 21, 21 8 = 13, 13 8 = 5 37 +8 = 45, 45 + 8 = 53 So wrong number in the series is 43. 42. (3) 600, 125, 30, 13, 7.2, 6.44, 6.288 6.288 x 5 (5x5) = 6.44 6.44 x 5 (5x5) = 7.2 7.2 x 5 (5x5) = 11 11 x 5 (5x5) = 30 30 x 5 (5x5) = 125 125 x 5 (5x5) = 600 So wrong number in the series is 13. 43. (3) 80, 42, 24, 13.5, 8.75, 6.375, 5.1875 5.1875 x 2 (2x2) = 6.375 6.375 x 2 (2x2) = 8.75 8.75 x 2 (2x2) = 13.5 13.5 x 2 (2x2) = 23 24 x 2 (2x2) = 42 42 x2 (2x2) = 80 So wrong number in the series is 24. 44. (2) 10, 8, 13, 15, 35, 135, 671, 4007 10 x1 2 = 8 8 x2 3 = 13 13 x3 4 = 35 35 x4 5 = 135 135 x 5 6 = 669 669 x 6 7 = 4007 So wrong number in the series is 671 45. (5)150, 290, 560, 1120, 2140, 4230, 8400 150 x2 10 = 290 290 x 2 20 = 560 560 x 2 30 = 1090 1090 x2 40 = 2140 So wrong number in the series is 1120. Solutions (46 55) 46. (1) Let the amount be Rs. x According to the question: (3/9) x (2/14) x = 40 x (1/3 1/7) = 40 x = (21 X 40)/4 x = 210 Rs. 47. (3) According to the question, Rachita buys highest number of pastries than cookies and then ice cream She has to buy 9 units of each. But she has to buy total 32 units and each item of one is must. Pastries > Cookies > Ice cream 13 or 12 10 or 11 9 Hence, she can buy either 10 or 11 units of cookies. 48. (3) Bus fare of first 5 km is = Rs. x So bus fare of 1 km is = Rs. x/5 According to the question:
5 X (x/5) + 182 X 13 = 2402 x + 2366 = 2402 x = 36 x = Rs. 36 49. (1) Let three even numbers are x, (x + 2), (x + 4) According to the question: x (x + 2) (x + 4) = 4032 x (x + 4) = 252 Eq (I) (x + 2) 252 = 4032 Eq (II) (x + 2) = (4032/252) = 16 x = 16-2 = 14 x = 14 So numbers are 14, 16 and 18. Now five times of the second number will be = 16 x 5 = 80 50. (1) Sum of ages of 4 members of a family 5 yr ago = 94 yr Their present age with daughter = 94 + 4 x 5 = 114 yr Now, their present age with daughter in law = 92 yr Difference between daughter and daughter in law = 114 92 = 22 yr 51. (4) Total ball in the bag = 13 + 7 = 20 n(s) = 20 C 2 = (20!/2! 8!) = (20 x 19 x 18!!)/ 2 x 18! = 190 and for same colour of ball n(e 1) = 13 C 2 = (13!/2! 11!) = (13 x 12 x 11!)/ 2 x 11! = (13 x 12)/2 = 78 and n(e 2) = 7 C 2 = (7!/2! 5!) = (7x 6 x 5!)/ 2 x 5! = (7x6)/ 2 = 21 Required probability for same colour ball = P(E) = [n(e 1) + n(e 2) ]/ n(s) = (78 + 21)/190 = 99/190 52. (2) Akash scored in subject A = 73 marks Akash scored in subject B = 56% of 150 = 84 Akash scored in subject C = x marks Maximum marks in all the three subject is = 150 Total marks = 150 x 3 = 450 Now according to the question: Marks obtained in subject (A + B + C) = 54% of total marks 73 + 84 + x = 54% of 450 x = 86, hence Akash scored 86 marks in subject C. 53. (4) Area of Square = 1444m 2 Side of the square = 1444 = 38m Now, according to the question, Breadth of the rectangle = 38 x 1/4 Length of the rectangle = 38 x 3/4 Area of rectangle = Length x Breadth = 38 x 1/4 X 38 x 3/4 = 1444 x (3/16) m 2 Now, difference between the Area of Square and rectangle = 1444-1444 x (3/16) = 1444 (1 3/16) = 1173.25 m 2 54. (5) Share of A = 4/11 x 73689 = Rs. 26796 Share of B = 7/11 x 73689 = Rs. 46893 Required difference = 2 x share of B 3 x share of A = 2 x 46893 3 x 26796 = Rs. 13398 55. (4) In one day, work done by: A + B = 1/20 (i) B + C = 1/30 (ii) A + C = 1/40 (iii) Adding (i) and (ii) above, work done by A + 2B + C = 1/20 + 1/ /30 2B = 1/20 + 1/30 1/ /40 B = 7/240 putting (B = 7/240) in (i) A does 5/240 work in one day, similarly putting the same value in (ii) C does 1/240 work in one day. Required ratio = (1/240) : (5/240) = 1:5 Solutions (56-60) 56. (3) Number of mobiles phones sold in the month of July = 45000 x 17/1000 = 7650 company A = (8/15) x 7650 = 4080 company B = 7650 4080 = 3570 Now number of mobiles phones sold in the month of December = 45000 x (16/100) = 7200 Company A = (7/16) x 7200 = 3150 Mobile phone sold by company B = 7200 3150 = 4050 So required ratio = 3570 : 4050 = 357 : 405 = 119 : 135 57. (3) Number of mobile phones sold in the month of November = 45000 x (12/100) = 5400 Mobile phone sold by company A = (7/15) x 5400 = 2520 company A at a discount = 35% of 2520 = 882 company A without a discount = 2520 882 = 1638 58. (4) Number of mobile phones sold in the month of October = 45000 x (8/100) = 3600 Mobile phone sold by company B = (5/12) x 3600 = 1500 Total profit earned by company B = 1500 x 433 = Rs. 649500
59. (5) From sol. No. 56 Number of mobiles phones sold by company A in the month of July = 4080 Number of mobiles phones sold by company A in the month of December = 3150 : Required % = (4080/3150) x 100 = 129.53% ~ = 130% 60. (1) Number of mobiles phones sold in the month of August = 45000 x (22/100) = 9900 Number of mobiles phones sold by company B in August = (5/9) x 9900 = 5500 Total number of mobiles phones sold in the month of September = 45000 x (25/100) = 11250 Number of mobiles phones sold by company B in September = (2/5) x 11250 = 4500 So total number of phones sold by company B in August and September = 5500 + 4500 = 1000 Solutions (61-65) 61. (1) Required average earning = Rs (3.34 + 5.83 + 1.69)3 = Rs. 3.62 lakhs 62. (2) Required respective ratio = 2.79 : 9.45 = 31 : 105 63. (5) Required increasee percentage = (9.45 8.42/8.42) x 100 = 12.23 ~ 12% 64. (4) D s earning increased consistently from the year 2005 to the year 20100 65. (3) Required percentage = (1.44 + 7.84)/5.53 x 100 = 167.81 ~ 168% Part 3 SOLUTIONS REASONING Solutions (66-69) After carefully study the given input and various steps of arrangement, we may conclude that in each step numbers are arranged in descending order from left to right while words are arranged in opposite English alphabetical order from right to left and the same process is continued till the rearrangement ends. Input: 84 why shit 14 32 not best ink feet 51 27 vain 68 92 Step I: 14 84 why shit 32 not ink feet 51 27 vain 68 92 best Step II: 27 14 84 why shit 32 not ink 51 vain 68 92 best feet Step III: 32 27 14 84 why shit not 51 vain 68 92 best feet ink Step IV: 51 32 27 14 84 why shit vain 68 92 best feet ink not Step V: 68 51 32 27 14 84 why vain 92 best feet ink not shit Step VI: 84 68 51 32 27 14 vain 92 best feet ink not shit why Step VII: 92 84 68 51 32 27 14 best feet ink not shit why vain 66. (5) There is no such step 67. (4) Step V: 68 51 32 27 14 84 why vain 92 best feet ink not shit Hence best would be at 5 th position from right in Step V. 68. (2) Step VII (last step) 92 84 68 51 32 27 14 best feet ink not shit why vain Hence three element (best, 14, 27) are between feet and 32. 69. (3) Step IV: 51 32 27 14 84 why shit vain 68 92 best feet ink not Hence why is sixth from the left in Step IV> Solutions (70 75) 70. (2) 71. (3) 72. (4) 73. (1) 74. (5) 75. (2) Solutions (76-78) 76. (5): From statement I, Deep is sister of Shilpa who has two siblings. From statement II, Kaushal is the only son of Deepa s parents. So by analyzing both the statement we can conclude Shilpa has one brother. 77. (3): From statement I, Hence D is immediatee right of B. From Statement II,
Hence D is immediate right of B. 78. (3): From statement I, 85. (1) Only I follow Hence Sudha is facing South direction. From Statement II, Hence Sudha is facing South direction Solutions (79 80) Answers: (86-90) 86. (4) 87. (4) 88. (4) 89. (2) 90. (5) Solutions (91 95) 79. (4): C 80. (1) ABE Solutions (81-85) 81. (2) Only II & III follow 82. (5) None of these 83. (4) Only I & III follow 91. (4) 92. (5) 93. (1) 94. (4) 95. (3) 96. (5) Either + or 97. (4) Only three pairs in the word AC, AE, CE SEARCHES Solutions (98 100) Codes are as follows: he pa is ro waiting ta there la the ji train zo at ma station fu this bi/vi a vi/bi 98. (2) pa 99. (3) fu ji zo 100.(2) ta ki ro 84. (2) Only III follows
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