Minimum and maximum values *

OpenStax-CNX module: m17417 1 Minimum and maximum values * Sunil Kumar Singh This work is produced by OpenStax-CNX and licensed under the Creative Commons Attribution License 2.0 In general context, a function may have multiple minimum and maximum values in the domain of function. These minimum and maximum values are local minimum and maximum, which belongs to nite sub-intervals within the domain of function. The least minimum and greatest maximum in the domain of function are global minimum and maximum respectively in the entire domain of the function. Clearly, least and greatest values are one of the local minimum and maximum values. The minimum and maximum, which are not global, are also known as relative minimum and maximum. Note : This module contains certain concepts relating to continuity, limits and dierentiation, which we have not covered in this course. The topic is dealt here because minimum, maximum, least, greatest and range are important attributes of a function and its study is required to complete the discussion on function. 1 Important observations and denitions Let us consider a very general graphic representation of a function. Following observations can easily be made by observing the graph : * Version 1.6: Sep 9, 2008 8:38 am -0500 http://creativecommons.org/licenses/by/2.0/

OpenStax-CNX module: m17417 2 Graph of a function Figure 1: There are multiple minimum and maximum values. 1: A function may have local minimum (C, E, G, I) and maximum (B,D,F,H) at more than one point. 2: It is not possible to determine global minimum and maximum unless we know function values corresponding to all values of x in the domain of function. Note that graph above can be dened to any value beyond A. 3: Local minimum at a point (E) can be greater than local maximum at other points (B and H). 4: If function is continuous in an interval, then pair of minimum and maximum in any order occur alternatively (B,C), (C,D), (D,E), (E,F), (F,G), (G,H), (H,I). 5: A function can not have minimum and maximum at points where function is not dened. Consider a rational function, which is not dened at x=1. f (x) = 1 x 1 ; x 1 Similarly, a function below is not dened at x=0. x=1; x>0 f(x) = x = -1; x<0

OpenStax-CNX module: m17417 3 Graph of function Figure 2: Function is not at x=0. Minimum and maximum of function can not occur at points where function is not dened, because there is no function value corresponding to undened points. We should understand that undened points or intervals are not part of domain - thus not part of function denition. On the other hand, minimum and maximum are consideration within the domain of function and as such undened points or intervals should not be considered in the rst place. Non-occurance of minimum and maximum in this context, however, has been included here to emphasize this fact. 6: A function can have minimum and maximum at points where it is discontinuous. Consider fraction part function in the nite domain. The function is not continuous at x=1, but minimum occurs at this point (recall its graph). 7: A function can have minimum and maximum at points where it is continuous but not dierentiable. In other words, maximum and minimum can occur at corners. For example, modulus function x has its only minimum at corner point at x=0 (recall its graph). 1.1 Extreme value or extremum Extreme value or extremum is either a minimum or maximum value. A function, f(x), has a extremum at x=e, if it has either a minimum or maximum value at that point. 1.2 Critical points Critical points are those points where minimum or maximum of a function can occur. We see that minimum and maximum of function can occur at following points :

OpenStax-CNX module: m17417 4 (a) Points on the graph of function, where derivative of function is zero. At these points, function is continuous, limit of function exists and tangent to the curve is parallel to x-axis. (b) Points where function is continuous but not dierentiable. Limit of function exits at those points and are equal to function values. Consider, for example, the corner of modulus function graph at x=0. Minimum of function exist at the corner point i.e at x=0. (c) Points where function is discontinuous (note that discontinuous is not undened). A function has function value at the point where it is discontinuous. Neither limit nor derivative exists at discontinuities. Example : piece-wise dened functions like greatest integer function, fraction part function etc. We can summarize that critical points are those points where (i) derivative of function does not exist or (ii) derivative of function is equal to zero. The rst statement covers the cases described at (b) and (c) above. The second statement covers the case described at (a). We should, however, be careful to interpret denition of critical points. These are points where minimum and maximum can exist not that they will exist. Consider the graph shown below, which has an inexion point at A. The tangent crosses through the graph at inexion point. In the illustration, tangent is also parallel to x-axis. The derivative of function, therefore, is zero. But A is neither a minimum nor a maximum. Graph of function Figure 3: A is neither a minimum nor a maximum. Thus, minimum or maximum of function occur necessarily at critical points, but not all critical points correspond to minimum or maximum. Note : We need to underline that concept of critical points as explained above is dierent to the concept of critical points used in drawing sign scheme/ diagram.

OpenStax-CNX module: m17417 5 1.3 Graphical view There are mathematical frameworks to describe and understand nature of function with respect to minimum and maximum. We can, however, consider a graphical but eective description that may help us understand occurrence of minimum and maximum values. We need to understand one simple fact that we can have graphs of any nature except for two situations : 1: function is not dened at certain points or in sub-intervals. 2: function can not be one-many relation. In this case, the given relation is not a function in the rst place. Clearly, there exists possibility of minimum and maximum at all points on the continuous portion of function where derivative is zero and at points where curve is discontinuous. This gives us a pictorially way to visualize where minimum and maximum can occur. The gure, here, shows one such maximum value at dicontinuity. Graph of function Figure 4: Maximum value at a discontinuity. 1.4 Relative or local minimum and maximum The idea of local or relative minimum and maximum is clearly understood from graphical representation. The minimum function value at a point is least in the immediate neighborhood where minimum occurs. A function has a relative minimum at a point x=m, if function values in the immediate neighborhood on either side of point are less than the value at the point. To be precise, the immediate neighborhood needs to be innitesimally close. Mathematically,

OpenStax-CNX module: m17417 6 f (m) < f (m + h) and f (m) < f (m h) as h 0 The maximum function value at a point is greatest in the immediate neighborhood where maximum occurs. A function has a relative maximum at a point x=m, if function values in the immediate neighborhood on either side of point are greater than the value at the point. To be precise, the immediate neighborhood needs to be innitesimally close. Mathematically, f (m) > f (m + h) and f (m) > f (m h) as h 0 1.5 Global minimum and maximum Global minimum is also known by least value or absolute minimum. A function has one global minimum in the domain [a,b]. Global minimum, f(l), is either less than or equal to all function values in the domain. Thus, f (l) f (x) for all x [a, b] If the domain interval is open like (a,b), then global minimum, f(l), also needs to be less than or equal to function value, which is innitesimally close to boundary values. It is because open interval by virtue of its inequality does not ensure this. What we mean that it does not indicate how close x is to the boundary values. Hence, f (l) f (x) for all x (a, b) f (l) f (l) lim f (x) x a+0 lim f (x) x b 0 Similarly, global maximum is also known by greatest value and absolute maximum. A function has one global maximum in the domain [a,b]. Global maximum, f(g), is either greater than or equal to all function values in the domain. Thus, f (g) f (x) for all x [a, b] If the domain interval is open like (a,b), then global maximum, f(m), also needs to be greater than or equal to function value, which is innitesimally close to boundary values. It is because open interval by virtue of its inequality does not ensure this. Hence, f (g) f (x) for all x (a, b) f (g) f (g) lim f (x) x a+0 lim f (x) x b 0

OpenStax-CNX module: m17417 7 1.6 Domain interval Nature of domain interval plays an important role in deciding about occurrence of minimum and maximum and their nature. In order to understand this, we need to rst understand that the notion of very large positive value and concept of maximum are two dierent concepts. Similarly, the notion of very large negative value and concept of minimum are two dierent concepts. The main dierence is that very large negative or positive values are not nite but extremums are nite. Consider a natural logarithmic graph of log e x. It extends from negative innity to positive innity, if base is greater than 1. The function is a strictly increasing function in its entire domain. As such, it has not a single minimum or maximum. The extremely large values at the domain ends can not be considered to be extremum as we can always have function values greater or less than one considered to be maximum or minimum. This argument is valid for behavior of functions near end points of an open interval domain. There can always be values greater or smaller than one considered. Denite sub-interval of logarithmic function Figure 5: Denite sub-interval of logarithmic function However, nature of graph with respect to extremum immediately changes when we dene same logarithmic function in a closed interval say [3,4], then log e 3 and log e 4 are the respective local minimum and maximum. Incidentally since function is strictly increasing in the domain and hence in the sub-interval, these extremums are global i.e. end values of function are global minimum and maximum in the new domain of the function. Above argument is valid for all continuous function which may have varying combination of increasing and decreasing trends within the domain of function. The function values at end points of a closed interval are extremums (minimum or maximum) - may not be least or greatest. In the general case, there may be more minimum and maximum values apart from the ones at the ends of closed interval. This generalization,

OpenStax-CNX module: m17417 8 as a matter of fact, is the basis of extreme value theorem. 1.7 Extreme value theorem The extreme value theorem of continuous function guarantees existence of minimum and maximum values in a closed interval. Mathematically, if f(x) is a continuous function in the closed interval [a,b], then there exists f(l) f(x) and f(g) f(x) such that f(l) is global minimum and f(g) is global maximum of function. As discussed earlier, there at least exists a pair of minimum and maximum at the end points. There may be more extremums depending on the nature of graph in the interval. 1.8 Range of function If a function is continuous, then least i.e. global minimum, A and greatest i.e. global maximum, B, in the domain of function correspond to the end values specifying the range of function. The range of the function is : [A, B] If function is not continuous or if function can not assume certain values, then we need to suitably analyze function and modify the range given above. We shall discuss application of the concept of least and greatest values to determine range of function in a separate module. 2 Determining minimum and maximum values There are three cases for determining minimum and maximum values. However, we should clearly underline that these methods give us relative minimum and relative maximum values which may or may not be the greatest (global) or least (global) values. We need to interpret minimum and maximum in the context of specied domain to ascertain whether minimum and maximum are least and greatest respectively or not? (i) function is dierentiable in the domain of function. (ii) function is continuous in the domain of function (iii) function is discontinuous at certain points in the domain of function. 2.1 Function is dierentiable The derivative of function exists for all values of x in the domain. In this case, we follow the algorithm given here (without proof- its proof is based on Taylor's expansion) : 1: Determine rst derivative. 2: Equate derivative to zero. 3: Solve equation obtained in the step 2 for x. 4: If there is no real solution of equation, then function has no minimum or maximum. 5: If there is real solution of equation, then determine second derivative. Put root values in the expression of second derivative one after another and see whether second derivative is non-zero. If second order derivative is positive non-zero, then function is minimum at that root value. On the other hand, if second order derivative is negative non-zero, then function is maximum at that root value. We should note that these conclusions are valid for all higher even derivatives, which we might need to evaluate. 6: If second derivative is zero for any root value, then proceed to determine third derivative. If at any root value (which has not been decided in earlier step) third order derivative is non-zero, then function has no minimum or maximum at that root value. We should note that this conclusion is valid for all higher odd derivatives, which we might need to evaluate. 7: Continue with higher order even and odd derivatives till all root values are evaluated for minimum and maximum.

OpenStax-CNX module: m17417 9 Example 1 Problem : Determine minimum and maximum values of function : f (x) = x3 3 x Solution : Dierentiating with respect x, we have : f (x) = 1 3 X3x2 1 = x 2 1 = (x 1) (x + 1) The roots of the corresponding equation are -1 and 1. Now, dierentiating with respect to x again, f (x) = 2x Putting, x = 1, f (x) = 2 < 0. Hence, function has maximum value at x=-1. Putting, x = 1, Maximum value = ( 1)3 ( 1) = 1 3 3 + 1 = 2 3 f (x) = 2 > 0. Hence, function has minimum value at x=1. Minimum value = (1)3 3 1 = 1 3 1 = 2 3 Graph of function Figure 6: Minimum and maximum values of function.

OpenStax-CNX module: m17417 10 Example 2 Problem : Determine minimum and maximum values of function : 2x 3 9x 2 + 12x 11 Solution : Dierentiating with respect x, we have : f (x) = 6x 2 18x + 12 = 6 ( x 2 3x + 2 ) = 6 (x 1) (x 2) The roots are 1 and 2. Now, dierentiating with respect to x again, f (x) = 12x 18 Putting, x = 1, f (x) = 6 < 0. Hence, function has maximum value at x=1. Maximum value = 2x 3 9x 2 + 12x 10 = 2X1 3 9X1 2 + 12X1 11 = 6 Putting, x = 2, f (x) = 6 > 0. Hence, function has minimum value at x=2. Minimum value = 2x 3 9x 2 + 12x 11 = 2X2 3 9X2 2 + 12X2 11 = 16 36 + 24 11 = 7 Example 3 Problem : Determine minimum and maximum values of function : Solution : f (x) = x + 1 x f (x) = 1 1 x 2 f (x) = x2 1 x 2 The roots are -1 and 1. Now, dierentiating with respect to x again, f (x) = 2 x 3 At x = 1, f (x) = 2 > 0. Function has minimum value of 2 at x=1. At x = 1, f (x) = 2 < 0. Function has maximum value of -2 at x=-1. Note that minimum value is greater than maximum value. It is possible as function is not dened at x=0. A maximum of smaller value exist left to it and a minimum of higher value exist to the right of it. Example 4 Problem : Determine minimum and maximum values of function : f (x) = x 5 5x 4 + 5x 3 5 Solution : Dierentiating with respect x, we have : Equating to zero, we have : f (x) = 5x 4 20x 3 + 15x 2 5x 4 20x 3 + 15x 2 = 0

OpenStax-CNX module: m17417 11 x 4 4x 3 + 3x 2 = 0 x 2 ( x 2 4x + 3 ) = 0 x 2 (x 1) (x 3) = 0 The roots are 0, 1 and 3. Now, dierentiating with respect to x again, f (x) = 20x 3 60x 2 + 30x Putting, x = 0, f (x) = 0. We need to dierentiate again to evaluate this point. Putting, x = 1, f (x) = 10 < 0. Hence, function has maximum value at x=1, Maximum value = x 5 5x 4 + 5x 3 1 = 15 5X14 + 5X13 5 = 1 5 + 5 5 = 4 Putting, x = 3, f (x) = 90 > 0. Hence, function has minimum value at x=3. Minimum value = x 5 5x 4 + 5x 3 1 = 3 5 5X3 4 + 5X3 3 5 = 243 5X81 + 5X27 5 = 32 In order to determine nature at point x=0, we dierentiate again, f (x) = 60x 2 120x + 30 Putting, x = 0, f (x) = 30 > 0. Hence, function has neither minimum nor maximum value at x=0.

OpenStax-CNX module: m17417 12 Graph of function Figure 7: Minimum and maximum values of function. 2.2 Function is continuous We know that if function is continuous in an interval, then pair of minimum and maximum occur alternatively in any order. We shall use this fact to determine minimum and maximum. This technique being applicable to continuous function allows us to analyze even piece-wise dened functions. A continuous function may or may not be dierentiable. For example, we can theoretically draw a modulus function without lifting pen. As such, it is a continuous function. However, it is not dierentiable at x=0 where we can not draw a tangent. In this case, we follow the algorithm given here: 1: Determine rst derivative. 2: Draw sign diagram of rst derivative. Note that it is slightly a dierent step than the equivalent step given for earlier case. Here, we are required to draw sign diagram - not the roots of rst derivative equation. 3: If function is decreasing to the left and increasing to the right of a critical point of sign diagram, then function value at that point is minimum. 4: If function is increasing to the left and decreasing to the right of a critical point of sign diagram, then function value at that point is maximum. Note : We can use this technique to determine minimum and maximum for function with undened points as well. We shall illustrate this for a case of rational function in the examples given here.

OpenStax-CNX module: m17417 13 Example 5 Problem : Find minimum value of modulus function Solution : Modulus function is dened as : x ; x 0 f(x) = -x ; x<0 For x>0, f (x) = x f (x) = 1 > 0 Since rst derivative is positive, given function is increasing function for x>0. For x<0, f (x) = x f (x) = 1 < 0 Since rst derivative is negative, given function is decreasing function for x<0. Overall sign diagram of modulus function is as shown here : Sign scheme Figure 8: Sign scheme At x=0, the function is decreasing to its left and increasing to its right. It means function has minimum at x=0. Minimum value = 0 Note that minimum value in this case is also least value as there is only one minimum in the entire domain. Hence, minimum at x=0 is global minimum. Example 6 Problem : The function y = alog e x + bx 2 + x has exteme values at x=-1 and x=2. Find values of a and b. Solution : Here extreme values (maximum or minimum) are given. We know that rst derivative is zero at extreme values. Now, y = ax 1 x + 2bx + 1

OpenStax-CNX module: m17417 14 At x =-1, y = ax 1 1 + 2bX 1 + 1 = 0 At x = 2, a 2b + 1 = 0 y = ax 1 2 + 2bX2 + 1 = 0 a 2 + 4b + 1 = 0 Solving two simultaneous equations, a + 8b + 2 = 0 a = 2 b = 1 2 Example 7 Problem : Find maximum and minimum values of function : y = x2 7x + 6 x 10 Solution : This function is not dened for x=10. The function is continuous except at this point. Thus, minimum and maximum obtained do not belong to a continuous domain. y = (x 10) (2x 7) ( x 2 7x + 6 ) (x 10) 2 = 2x2 27x + 70 x 2 + 7x 6 (x 10) 2 y = x2 20x + 64 (x 10) 2 Now denominator is a positive number for all x. Thus, sign diagram of rst derivative is same as that of numerator. In order to draw sign diagram, we need to factorize numerator. x 2 20x + 64 = (x 4) (x 16) Hence, critical points are 4 and 16. The sign diagram is as shown in the gure. At x=4, the function is increasing to its left and decreasing to its right. It means function has maximum at x=4.

OpenStax-CNX module: m17417 15 Sign scheme Figure 9: Sign scheme Maximum value = x2 7x + 6 = 42 7X4 + 6 = 1 x 10 4 10 At x=16, the function is decreasing to its left and increasing to its right. It means function has minimum at x=16. Minimum value = x2 7x + 6 = 162 7X16 + 6 = 25 x 10 16 10 Note that minimum value is greater than maximum value. Graph of function Figure 10: The minimum and maximum values of a function.

OpenStax-CNX module: m17417 16 3 Exercise Exercise 1 (Solution on p. 17.) Determine maximum value of function : ( ) x 1 f (x) = x

OpenStax-CNX module: m17417 17 Solutions to Exercises in this Module Solution to Exercise (p. 16) The function is not dened for x=0. The function of the form x y is dened for x>0. Comparing, 1 x > 0 The critical point of this rational inequality is zero. The rational function 1/x is positive for x >0. Thus, domain of given function is x>0. In order to dierentiate this function, we need to take logarithm. Let, ( ) x 1 y = x ( ) 1 log e y = xlog e = x (log e 1 log x e x) = xlog e x Dierentiating with respect to x, we have : 1 y X dy dx = log e (x) xx 1 x = (1 + log ex) dy ( ) x 1 dx = y (1 + log ex) = (1 + log x e x) In order to determine sign diagram of rst derivative, we equate it to zero. ( ) x 1 (1 + log e x) = 0 x Now, (1/x) x > 0 as x > 0. Hence sign diagram of rst derivative is same as that of (1 + log e x) : (1 + log e x) = 0 log e x = 1 x = e 1 = 1 e The expression 1/e is less than 1. We put x=1 to test the sign of right side. At x=1, (1 + log e x) = (1 + log e 1) = (1 + 0) = 1 < 0 This means function is increasing in interval (0,1/e] and decreasing in [1/e, ). maximum at x=1/e. Thus, function has Maximum value = (1/x) x = ( 1 1 e ) 1 e = (e) 1/e Note that this maximum value is greatest value as there is only one maximum in the domain of function.