Math Departmental Exit Assessment Review (Student Version)

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Math 008 - Departmental Eit Assessment Review (Student Version) Solve the equation. (Section.) ) ( + ) - 8 = 6-80 - 0 ) + - - 7 = 0-60 - 0 ) 8 + 9 = 9 - - ) - = 60 0-0 -60 ) 0.0 + 0.0(000 - ) = 0.0 0 6000 000 6) 0.80-0.0(0 + ) = 0.70(0) 90 80 0 70 Solve the formula for the specified variable. (Section.6) 7) I = Prt for t t = P - Ir t = P - I + r t = I Pr t = P - Ir 8) P = L + W for L L = P - W L = P - W L = P - W L = P - W Solve the inequalit. Graph the solution set and write it in interval notation. (Section.9) 9) - - -( + 7) [, ) (-, ] 6 7 (-, ) 6 7 (, ) 6 7 6 7

0) -( - 7) < -0 + 0 (-, -) (-, -] - - - - - 0 (-, ) - - - - - 0 [-, ) - - - - - 0 - - - - - 0 ) -7 - + - (, 7) - - 0 6 7 8 9 0 [, 7] - - 0 6 7 8 9 0 [-7, -] - - -0-9 -8-7 -6 - - - - - 0 (-7, -) - - -0-9 -8-7 -6 - - - - - 0 ) 0 ( - ) [6, 8] 6 7 8 9 0 6 [6, 8) 6 7 8 9 0 6 (6, 8] 6 7 8 9 0 6 (6, 8) 6 7 8 9 0 6

Solve. If needed, round mone amounts to two decimal places and all other amounts to one decimal place. (Sections.6 -.9 and.) ) A chemist needs 0 milliliters of a 7% solution but has onl 7% and 77% solutions available. Find how man milliliters of each that should be mied to get the desired solution. 0 ml of 7%; 0 ml of 77% 0 ml of 7%; 0 ml of 77% 00 ml of 7%; 0 ml of 77% 0 ml of 7%; 00 ml of 77% ) The owners of a cand store want to sell, for $6 per pound, a miture of chocolate-covered raisins, which usuall sells for $ per pound, and chocolate-covered macadamia nuts, which usuall sells for $8 per pound. The have a 0-pound barrel of the raisins. How man pounds of the nuts should the mi with the barrel of raisins so that the hit their target value of $6 per pound for the miture? lb 9 lb lb 8 lb ) A motorccle traveling at 70 miles per hour overtakes a car traveling at 0 miles per hour that had a three-hour head start. How far from the starting point are the two vehicles? mi 80 mi 7 mi 76 mi 6) Linda and Dave leave simultaneousl from the same starting point biking in opposite directions. Linda bikes at 6 miles per hour and Dave bikes at 8 miles per hour. How long will it be until the are 0 miles apart from each other? hr 0 hr 7 hr 7 0 hr 7) Kevin invested part of his $0,000 bonus in a certificate of deposit that paid 6% annual simple interest, and the remainder in a mutual fund that paid % annual simple interest. If his total interest for that ear was $900, how much did Kevin invest in the mutual fund? $7000 $000 $6000 $000 8) How can $,000 be invested, part at % annual simple interest and the remainder at 0% annual simple interest, so that the interest earned b the two accounts is equal at the end of the ear? $,000 invested at %; $0,000 invested at 0% $0,000 invested at %; $,000 invested at 0% $,000 invested at %; $0,000 invested at 0% $0,000 invested at %; $,000 invested at 0% 9) Seven less than three times a number is less than ten. Find all such numbers. > - < 7 < < 0) Three-fourths a number decreased b one is between negative four and twelve. Find all such numbers. 0 < < - < < - < < - 9 < < 9

Find three ordered pair solutions b completing the table. Then use the ordered pairs to graph the equation. (Section.) ) = + 0-0 - - - -7 0 0 - - 0 - -0-0 - - -0 0-7 0 7-0 0-0 - 0-0 - 0 - - -0-0

Graph the linear equation b finding and plotting its intercepts. (Section.) ) - - = 0 0-0 - 0-0 - 0 - - -0-0 0 0-0 - 0-0 - 0 - - -0-0

) + = -8 0 0-0 - 0-0 - 0 - - -0-0 0 0-0 - 0-0 - 0 - - -0-0 6

Use the slope-intercept form to graph the equation. (Section.) ) = - - 0 0-0 - 0-0 - 0 - - -0-0 0 0-0 - 0-0 - 0 - - -0-0 7

) = - 0 0-0 - 0-0 - 0 - - -0-0 0 0-0 - 0-0 - 0 - - -0-0 8

Graph the linear equation. (Horizontal/Vertical Lines - Section.) 6) - = 0 6 6-6 - - - - - 6 - - - - - -6-6 - - - - - 6 - - - - - -6 6 6-6 - - - - - 6 - - - - - -6-6 - - - - - 6 - - - - - -6 9

7) - = 0 6 6-6 - - - - - 6 - - - - - -6-6 - - - - - 6 - - - - - -6 6 6-6 - - - - - 6 - - - - - -6-6 - - - - - 6 - - - - - -6 Problems #6-7 come from Section. Write an equation of the line with the given slope, m, and -intercept (0, b). 8) m = -, b = 6 = - + 6 = + 6 = - - 6 = - 6 Find an equation of the line with the given slope that passes through the given point. Write the equation in the form A + B = C. 9) m = - ; (, ) 9 + 9 = - 9 = 9 + = - + 9 = - Find an equation of the line described. Write the equation in slope-intercept form if possible. 0) Slope -, through (, ) 7 = - 7-9 = - 7-7 = - 7 + 7 = 7-7 0

Find an equation of the line through the pair of points. Write the equation in the form A + B = C. ) (-7, -9) and (0, ) - + = - - 7 = - - = - - - 7 = - ) (-, -6) and (0, -) - - = 6 + = -9 - - = -9 - = 6 Find an equation of the line described. Write the equation in slope-intercept form if possible. ) Through (, -) and (-8, ) = - - 9 = - 77 = - 9 = - - 67 Find an equation of the line. ) Vertical line through (, -0) = = = -0 = -0 ) Horizontal line through (-0, ) = -0 = = -0 = Find an equation of the line described. 6) With undefined slope, through -, -7 = -7 - - 7 = 0 - + = -7 = - 7) With slope 0, through - 9, = - 9 + = - 9 + = 0 = - 9 Solve the sstem of equations b graphing. (Section.) 8) = - 6 = - 8 0-0 - 0 - -0 no solution (-, ) (, -) (-, )

9) + = 7 + = 0-0 - 0 - -0 no solution (, -) (-, ) (-, ) Section. Without graphing, decide: (a) Are the graphs of the equations are identical lines, parallel lines, or lines intersecting at a single point? (b) How man solutions does the sstem have? 0) + = + = 6 lines intersecting at a single point; one solution parallel lines; no solution identical lines; infinite number of solutions ) - 6 = = 0 + identical lines; infinite number of solutions parallel lines; no solution lines intersecting at a single point; one solution Solve the sstem of equations b the substitution method. (Section.) ) = - - = - infinite number of solutions no solution (, ) (, ) ) = - 0 + = 0 (-, ) infinite number of solutions no solution (, -) ) + = 6 + = 60 (, -) no solution (0, ) infinite number of solutions Solve the sstem of equations b the addition method. (Section.) ) - 7 = -7 + = (-, ) (, ) (, -) (-, -)

6) 6-7 = 9 8 - = 6 (, ) no solution (9, 6) 8, - 8 Evaluate the epression with the given replacement values. (Section.) 8 7) ; = - 8 7-8 7-8) -; = and = - 9-768 768 Simplif the epression. Write the result using positive eponents onl. (Sections./.) 9) (ab) a6b a8b 8a6b 8a8b 0) (-6-7)(-) -0 6-0 7 8-6 -08 ) ( ) 9 0 9 ) - - 6 8 6 8 6 6 Perform the indicated operation. (Section.) ) (7 - - ) + ( + + ) 7 + + 8 + + 6-6 - 6 8 + 6 + 6 ) ( 9 + 6 - + ) - (0 9-7 + - 6) 9 + 6-7 - 7 + 7 9 + 6 + 7-7 + 7-9 + 6-7 - 7 + 7-9 + 6 + 7-7 + 7 Multipl (Section./.) ) ( - 8)(6 + 7) - 0 - - 6 0 + 8-6 0-6 6) ( - 6)( - ) - 8-8 - 8 + - + - 8 +

7) (z + ) z + 0z + z + 6z + 6z + 0z + 8) (7a - ) 7a - 70a + 7a + 9a - 70a + 9a + 9) (a - )(a + ) a + a - a - a - a - a - 60) ( + 7)( + 6 - ) + + 7 - + 7 + 6 + 7 - + 6 - + 7 + 7 + 6 + 7 + Perform the division. (Section.6) 6) 68 + 6 + 6 8 6 + + 8 + + 8 + + 8 + + 8 6) m + m - m + m + 7 m + m + m - m + m + 6m + 7 m + m + 6) - + 6 - - + + - - + - - + - - Factor completel. (Chapter 6) 6) 0 + 0 0(6 + ) ( + ) 0(6) (0 + ) 6) 8m8 + 96m6 + 8m 6(8m 8 + 6m 6 + m ) -m (-8m + 96m - 8) 6m(8m + 6m + ) m(8m + 96m + 8) 66) -6 + - -( - + ) -( - - ) -( - - ) -( - + ) 67) + - 9-99 ( + )( - 9) ( + )( - 9) ( - )( + 9) ( - )( + 9) 68) - 9 ( - ) ( + ) ( + )( - ) prime 69) + + 7 + 7 (7 + 7)( + ) ( + )( + 7) ( + 7)( + ) ( + )(7 + 7)

70) - 79 (7 + 9)(9-6 + 8) (7-9)(9 + 6 + 8) ( - 9)( + 6 + 8) (7-9)(9 + 8) 7) + 0 + 9 + 6 ( + )(9 + ) ( + 9)( + ) ( + )( + 9) ( + 9)( + ) 7) + - ( - 9)( + ) ( - 9)( + ) prime ( + 9)( - ) 7) - - 77 ( - 77)( + ) ( + )( - 7) ( - )( + 7) prime 7) 8-9 prime (9 + 7) (9-7) (9 + 7)(9-7) 7) + 6 - ( - )( + ) ( + )( - ) prime ( - )( + ) 76) - 0 + ( - )( - 6) ( - )( - ) ( - 6)( + ) prime 77) 7-7 - 90 prime 9( + )( - ) (7 + 8)( - ) 9( - )( + ) 78) + 9 - ( - )( + ) ( + )( - ) ( + )( - ) ( - )( + ) 79) 6 + - 6 ( + )( - ) prime (6 + )( - ) ( - )( + ) 80) 79 + (9 + 7)(8 + 6 + 9) (9 + 7)(8-6 + 9) (9-7)(8 + 6 + 9) (79-7)( + 6 + 9) 8) 0-7 + 9 prime (0 + )( + ) ( + )( + ) ( - )( - ) 8) - 6 + 6 prime ( + 6) ( - 6) ( + 6)( - 6) 8) -6 + + ( - )(-6 - ) -( - )( + ) (-6 + )( + ) -( - )( + ) 8) 9 - + 9 (7 - )(7 + ) (9 + )( + 9) (7 - ) (7 + ) 8) 6 + 9 (8 + ) Prime (8 - ) (8 + )(8 - )

Identif the correct factor for the given polnomial. 86) + + 7 + 8 + + - Solve the equation. (Section 6.6) 87) - = 0, 0, - - 88) + 6 = 0-8, -, 8, 8, 89) ( + )( + ) =, -, - -, 8-8, 90) 0 + 00 + 0 = 0 0, -, - -, - -, - 0,, Simplif the rational epression. (Section 7.) - 8 9) - -7-7 9) + + + 9 + + + + + 9 + + 9) - 0 - - - 9) + + + 9 + + 9 + - + + + 9 + + 9 + 7 + + 7 Multipl or divide as indicated. Simplif completel. (Section 7.) 9) 6-7 07-6 - 6-0 9-7 6

96) + 7 + + + + 8 + 8 + + + + + + 8 + 97) + - 6-8 - 6 6-6 6( - ) - 6 ( - ) 98) - 8 + 8 - - 8 + 8 ( - 9) - 08 60 ( - 9) 60 99) - + - - - 9-9 9( - + - ) ( + )( - ) 9 ( - ) ( - ) 00) + - 6 + 9 + 8 - + 7 + + - + + + + - + 7

Answer Ke Testname: MATH008REVIEWSTUDENTMC ) D ) A ) D ) B ) C 6) B 7) C 8) C 9) A 0) A ) B ) A ) C ) C ) B 6) C 7) C 8) D 9) B 0) C ) D ) C ) D ) B ) A 6) D 7) C 8) A 9) A 0) C ) B ) D ) A ) A ) D 6) D 7) A 8) C 9) B 0) B ) A ) C ) D ) D ) A 6) B 7) A 8) D 9) C 0) A ) A ) C ) B ) B ) B 6) D 7) D 8 8) C 9) C 60) B 6) A 6) B 6) B 6) A 6) C 66) A 67) A 68) C 69) B 70) B 7) B 7) D 7) C 7) D 7) D 76) B 77) B 78) D 79) A 80) B 8) D 8) A 8) B 8) C 8) B 86) C 87) C 88) D 89) D 90) A 9) C 9) C 9) A 9) D 9) A 96) A 97) A 98) B 99) C 00) C