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GTE 014 Brief nalysis (Based on student test experiences in the stream of ME on 16th February, 014 - Second Session) Section wise analysis of the paper 1 Mark Marks Total No of Questions Engineering Mathematics 4 4 8 Engineering Mechanics 1 4 Strength of Materials 4 Design of Machine Elements 1 4 5 Theory of Machines 1 1 Vibrations 1 1 Fluid Mechanics 4 Thermal Science 4 6 Heat Transfer 5 Manufacturing Science 6 8 Industrial Engineering 4 7 Verbal bility 1 4 Numerical bility 4 6 0 5 65 Questions from the aper 1. Which of the following options is the closest in meaning to the word underlined in the sentence below? In a democracy, everybody has the freedom to disagree with the government. () Dissent (B) descent (C) decent (D) decadent ns:. While receiving the award the scientist said I Feel vindicated. The meaning of the word vindicated is closed to () unished (B) substantiated (C) appreciated 7

. In the sequence of 1 consecutive odd numbers the sum of first 5 numbers is 45 then the sum of last 5 numbers in sequence is. ns: 495 8 th observation is 7 =14 more than 1 st observation 9 th observation is 14 more than nd observation 10 th observation is 14 more than rd observation 11 th observation 14 more than 4 th observation 1 th observation 14 more than 5 th observation Total 14 5=70 Sum of the first five numbers =45 Sum of last five numbers =495 4. et ns: () n m f (x, y) x y. nm If x is doubled and y is halved the new value of f is (B) m n n 1 m ' X y X Y nm n m nm mn (C) (n m) (D) (m n) 5. fter discussion, Tom said to me, please revert He expect me to () Retract (B) get back to him (C) move in reverse (D) retreat 6. If KCFTSB stands for best of luck and SHSWDG stands for good wishes, which of following indicates ace the Exam () MCHTX (B) MXHTC (C) XMHCT (D) XMHTC KCFTSB: BST-Best, F-Of, CK-uck (Reverse order) SHSWDG: GD-Good, WSHS-Wishes (Reverse order) Similarly ace the Exam - C-ce, T-The, XM-Exam 7. firm producing air purifiers sold 00 units in 01. The following ie chart represents the share of raw material, labour cost, transportation, energy, plant and machinery cost in total manufacturing cost of firm 01. The expenditure of labour in 01 is Rs. 4, 50,000. The raw material expenses in 8

01 are increased by 0%. ll other expenses increased by 0%. What is the percentage increase in total cost for company in 01? (e) (a) (d) (b) (c) a transport (10%) b labour (15%) c raw material (0%) d energy (5%) e plant and machinery (0%) ns: 01 01 Transport (10%) 00,000 60,000 abour (15%) 450,000 540,000 Raw material (0%) 750,000 780,000 Energy (5%) 750,000 900,000 lant and Machinery (0%) 900,000 1,080,000 Total,000,000,660,000 ercentage increase in total cost =% 8. Industrial consumption of power doubled from 000-001 to 010-011. ssuming it to be uniform over the year find the annual rate of increase in percentage () 5.6 (B) 7. (C) 10 (D) 1. n 10 r r 1 n 10 years 1 100 100 r 7. 9. Find the next term in the sequence 1M, 17Q, 19S,. () 1W (B) 1V (C) W (D) V ns: C 9

10. five digit is formed using the digits 1,, 5, 7 & 9 without repeating any one of them. What is the sum of all such possible five digit numbers? () 6666660 (B) 6666600 (C) 6666666 (D) 6666606 The digit in unit place is selected in 4! Ways The digit in tens place is selected in 4! Ways The digit in hundreds place is selected in 4! Ways The digit in thousands place is selected in 4! Ways The digit in ten thousands place is selected in 4! Ways Sum of all values for 1 4! 1 10 10 10 10 10 4! 111111 0 1 4 Similarly for 4! (11111) Similarly for 5 4! (11111) 5 Similarly for 7 4! (11111) 7 Similarly for 9 4! (11111) 9 sum of all such numbers 4! (11111) 1 5 7 9 4 (11111) 5 6666600 6 11. Ball bearings are rated by a manufacturer for a life of 10 revolutions. The catalogue rating of particular bearing is 16 KN. If the design load is kn then the life of the bearing will be 10 6 revolutions where is equal to ns: =51 k c 6 10 k (Ball bearing) w 16 10 8 10 10 6 6 51 6 1. In a statically determinate plane truss, no of joints (J), the number of members (M) is represented by () j=m- (B) m=j+1 (C) m=j- (D) m=j-1 ns: C 10

1. The number of independent elastic constant required to define the stressstrain relationship for isotropic elastic solid is. ns: 9 14. If of elastic material is 0.4. The ratio of modulus of rigidity to young s modulus is. ns: 0.57 E=G(1+ ) G 1 1 0.57 E (1 ) (1 0.4) 15. Total number of decision variables in objective function of an assignment problem of size n n is () ns: D n (B) n (C) n-1 (D) n 16. Which of the following is used to convert rotational motion into a translation motion? ns: D () Bevel gear (C) Worm gear (B) Double helical gears (D) Rack and pinion gear 17. oint mass in executing SHM on with amplitude of 10 mm and frequency of 4 Hz, The maximum acceleration (m/s ) of the mass is. ns: 6. Exp. Given =10 mm=0.01 m dx d x v sin t, a cost dt F=4Hz, For maximum, t=0 a 0.01 f x=cost dt Q f 0.01 4 6.m / s 18. bolt of major diameter 1 mm is required to clamp two steel plates. Crosssectional area of the threaded portion of the bolt is 84. mm, length of threaded portion in grip is 0 mm while the length of unthreaded portion in grip is 8 mm. E= 00 Ga. The effective stiffness in (MN/m) of the bolt clamped zone is. 11

ns: 468.9 Exp. d1 l 1 1 mm 8mm 84.mm 1 (d 1) 4 84. mm l 0mm 1 1 1 1 (1) 00 1 E E 84. 00 K ; K 56. l l 0 4 8 87.4 1 1 1 k k k 1 1 87.4 56. K 468.9 MN / m 19. single degree of freedom system has a mass of 8 kg, stiffness 8 N/m and viscous damping ratio is 0.0. The dynamic magnification factor at an excitation frequency of 1.5 rad/sec is. ns: 0.799 C C Damping ratio 0.0 mn 8 8 C 0.0 8 0. 8 Dynamic magnification factor c s S m n 1 1 1 0.799 (0.) (1.5) (1.5) 1 (8) (1) 0. butt weld joint is developed on steel plates having yield and ultimate tensile strength 500 Ma and 700 Ma respectively. The thickness of plates is 8 mm and width is 0 mm. In proper selection of welding parameters caused an undercut of mm depth along the weld. The maximum transverse tensile load (in KN) carrying capacity of the developed weld joint is. 1

ns: 7.5 Yield strength y Force rea b 0 6 mm bt 6 8 147.07 mm F 500147.07 7.5KN 1. Torque and angular speed data over one cycle of shaft carrying a flywheel are shown in the figures. The Moment of Inertia (kg-m ) of fly wheel is. 000 N m T 0 rad / s 0 1500 10 rad / s 0 ns: 0 0 10 0 0 10 E rea of T diagram 000 1500 000 E I C 000 I(10) I 47.1 max min max min Cs s S. If aplace transform of cost S S S () (B) (S ) 16 (S ) 16 then aplace transform of e-t cos4t is S S (C) (D) (S ) 16 (S ) 16 1

. It is desired to avoid interference in a pair of spur gears having a 0 o pressure angle with increase in pinion to gear ratio, the minimum number of teeth on the pinion () Increases (C) First increases then decreases (B) Decreases (D) Remain unchanged 4. The truss shown in figure has the forces F 1 & F are 9kN & kn respectively Force (in kn) in QS is F Q F1 R 1.5 S T () 11.5 T (B) 11.5 C (C) 1.5 T (D) 1.5C ns: By method of sections F 1 Q R FQS sin 5.1 S 5.1 T V 0 F F sin 5.1 1 QS F QS 11.5(T) 14

5. ladder B of length 5 m & weight 600 N is resting against a wall. ssuming frictionless contact at the floor B & wall the magnitude of force (in N) required N maintain equilibrium ladder is..5m m.5m W 4 m B ns: 400 N From free body diagram M 0 B W R R 600 R 400 H 0 R 400 N R B 6. The thin glass cylinder with an internal radius 100 mm subjected to internal pressure of 10Ma. The maximum permissible working stress is restricted to 100Ma. The minimum cylinder wall thickness (in mm) for safe design must be. ns: 10 pd 10 100 1 100 t 10 mm t t 7. shaft is subjected to the torsional moment and the maximum shear stress developed in the shaft is 100Ma. The yield and ultimate strength of the shaft in tension are 00Ma and 450Ma respectively. The factor of safety using maximum distortion energy theory (von-misses) is. ns: 1.5 max s Fos 00 FOS 1.5 100 15

8. wardrobe (mass 100 kg, height 4 m width m depth 1m) symmetric about the Y-Y axis stands on a rough level floor as shown in the figure. force is applied at mid height on the wardrobe so as to tip it about point Q without slipping. What are the minimum values of force (in N) and the static coefficient of friction between the y floor & the wardrobe is. W mg 4m m FF y R N Q () 490.5 & 0.5 (B) 981 & 0.5 (C) 1000.5 & 0.15 (D) 1000.5 & 0.5 M 0 F Q W 1m m 100 9.81 490.5 N, H 0 F 490.5 N, V 0 R mg 981 N N 490.5 Friction Force R N 0.5 981 9. frame is subjected to a load as shown in figure. The frame has a constant flexural rigidity EI. The effect of axial load is neglected. The deflection at pt due to applied load is 16

() ns: D 1 EI (B) EI (C) EI (D) 4 EI SE Mxdx EI 0 0 M dx y EI M X M X Y X 1 (X) dx () dx 6 1 4 X EI EI EI EI EI EI 4 EI 0 0 0 0 0. uniform slender rod (8m length, kg mass) rotates in vertical plane about a horizontal axis 1 m from its end as shown in figure. The magnitude of angular acceleration (in rad/sec ) of the rod at the position shown is 1m 7 m ns: 1.7 m 4m W M 0 W I M 9.81 8 9.81 1.7rad / sec 17