THE MINIMUM NUMBER OF GENERATORS FOR INSEPARABLE ALGEBRAIC EXTENSIONS 1

Similar documents
MAXIMAL SEPARABLE SUBFIELDS OF BOUNDED CODEGREE

55 Separable Extensions

Notes on Field Extensions

Math 603, Spring 2003, HW 6, due 4/21/2003

GALOIS THEORY. Contents

RUDIMENTARY GALOIS THEORY

Fields and Galois Theory. Below are some results dealing with fields, up to and including the fundamental theorem of Galois theory.

A CONSTRUCTION FOR ABSOLUTE VALUES IN POLYNOMIAL RINGS. than define a second approximation V 0

A THEOREM ON VALUATION RINGS AND ITS APPLICATIONS

SOLVING SOLVABLE QUINTICS. D. S. Dummit

A Harvard Sampler. Evan Chen. February 23, I crashed a few math classes at Harvard on February 21, Here are notes from the classes.

Fields. Victoria Noquez. March 19, 2009

50 Algebraic Extensions

FIELD THEORY. Contents

Section V.6. Separability

1 Rings 1 RINGS 1. Theorem 1.1 (Substitution Principle). Let ϕ : R R be a ring homomorphism

AN ALTERNATIVE APPROACH TO THE CONCEPT OF SEPARABILITY IN GALOIS THEORY arxiv: v1 [math.ac] 27 Sep 2017

Field Theory Problems

APPROXIMATION TO REAL IRRATIONALS BY CERTAIN CLASSES OF RATIONAL FRACTIONS 1

Dimension Theory. Mathematics 683, Fall 2013

NOTES ON FINITE FIELDS

Theorem 5.3. Let E/F, E = F (u), be a simple field extension. Then u is algebraic if and only if E/F is finite. In this case, [E : F ] = deg f u.

Galois theory of fields

A finite universal SAGBI basis for the kernel of a derivation. Osaka Journal of Mathematics. 41(4) P.759-P.792

MATH 101A: ALGEBRA I, PART D: GALOIS THEORY 11

An Algebraic Interpretation of the Multiplicity Sequence of an Algebraic Branch

Mathematical Induction Assignments

x by so in other words ( )

CONSTRUCTIBLE NUMBERS AND GALOIS THEORY

School of Mathematics and Statistics. MT5836 Galois Theory. Handout 0: Course Information

Notes on graduate algebra. Robert Harron

1 Separability and splitting fields

Course 311: Michaelmas Term 2005 Part III: Topics in Commutative Algebra

4. Noether normalisation

Math 145. Codimension

\ABC (9) \AX BI Ci\ = 0, r; vi -iv ~*i -n*yi -o

Math 203A - Solution Set 3

Galois Theory, summary

SIMPLE RADICAL EXTENSIONS

(dim Z j dim Z j 1 ) 1 j i

Rings and groups. Ya. Sysak

CHEVALLEY S THEOREM AND COMPLETE VARIETIES

x by so in other words ( )

4.4 Noetherian Rings

Math 429/581 (Advanced) Group Theory. Summary of Definitions, Examples, and Theorems by Stefan Gille

AN EXPOSITION OF THE RIEMANN ROCH THEOREM FOR CURVES

FOUNDATIONS OF ALGEBRAIC GEOMETRY CLASS 41

Math 418 Algebraic Geometry Notes

Field Theory Qual Review

Algebraic function fields

Galois theory (Part II)( ) Example Sheet 1

Chapter V. Solvability by Radicals

Chapter 8. P-adic numbers. 8.1 Absolute values

Homework 4 Algebra. Joshua Ruiter. February 21, 2018

The Galois group of a polynomial f(x) K[x] is the Galois group of E over K where E is a splitting field for f(x) over K.

THE ARTIN-SCHREIER THEOREM KEITH CONRAD

Galois theory. Philippe H. Charmoy supervised by Prof Donna M. Testerman

A short proof of Klyachko s theorem about rational algebraic tori

SUBSPACE LATTICES OF FINITE VECTOR SPACES ARE 5-GENERATED

Algebraic Cryptography Exam 2 Review

Practice problems for first midterm, Spring 98

Math 203A, Solution Set 6.

Infinite Continued Fractions

P. ERDÖS 2. We need several lemmas or the proo o the upper bound in (1). LEMMA 1. { d ( (k)) r 2 < x (log x)c5. This result is due to van der Corput*.

Galois Theory TCU Graduate Student Seminar George Gilbert October 2015

INDRANIL BISWAS AND GEORG HEIN

Some generalizations of Abhyankar lemma. K.N.Ponomaryov. Abstract. ramied extensions of discretely valued elds for an arbitrary (not

ALGEBRA PH.D. QUALIFYING EXAM September 27, 2008

THE GROUP OF UNITS OF SOME FINITE LOCAL RINGS I

The Kummer Pairing. Alexander J. Barrios Purdue University. 12 September 2013

Math 203, Solution Set 4.

CHAPTER 0 PRELIMINARY MATERIAL. Paul Vojta. University of California, Berkeley. 18 February 1998

Valuation bases for generalized algebraic series

54.1 Definition: Let E/K and F/K be field extensions. A mapping : E

MATH 8254 ALGEBRAIC GEOMETRY HOMEWORK 1

UNDERSTANDING RULER AND COMPASS CONSTRUCTIONS WITH FIELD THEORY

Math 762 Spring h Y (Z 1 ) (1) h X (Z 2 ) h X (Z 1 ) Φ Z 1. h Y (Z 2 )

FINITELY GENERATED SIMPLE ALGEBRAS: A QUESTION OF B. I. PLOTKIN

Matsumura: Commutative Algebra Part 2

I ƒii - [ Jj ƒ(*) \'dzj'.

Jean-Pierre Escofier. Galois Theory. Translated by Leila Schneps. With 48 Illustrations. Springer

IRREDUCIBILITY OF 1-CLASSES ON ANTICANONICAL RATIONAL SURFACES AND FINITE GENERATION OF THE EFFECTIVE MONOID. Mustapha Lahyane and Brian Harbourne

PERFECT POLYNOMIALS OVER F p WITH p + 1 IRREDUCIBLE DIVISORS. 1. Introduction. Let p be a prime number. For a monic polynomial A F p [x] let d

Math 711: Lecture of September 7, Symbolic powers

GALOIS THEORY : LECTURE 12

INVERSES AND ZERO-DIVISORS

Peano Arithmetic. CSC 438F/2404F Notes (S. Cook) Fall, Goals Now

ON THE CHIEF FACTORS OF PARABOLIC MAXIMAL SUBGROUPS IN FINITE SIMPLE GROUPS OF NORMAL LIE TYPE

ADVANCED TOPICS IN ALGEBRAIC GEOMETRY

D-MATH Algebraic Geometry FS 2018 Prof. Emmanuel Kowalski. Solutions Sheet 1. Classical Varieties

Math 201C Homework. Edward Burkard. g 1 (u) v + f 2(u) g 2 (u) v2 + + f n(u) a 2,k u k v a 1,k u k v + k=0. k=0 d

Chakravala - a modern Indian method. B.Sury

MATH 631: ALGEBRAIC GEOMETRY: HOMEWORK 1 SOLUTIONS

SEPARABILITY II KEITH CONRAD

GALOIS GROUPS OF CUBICS AND QUARTICS (NOT IN CHARACTERISTIC 2)

1 Flat, Smooth, Unramified, and Étale Morphisms

AN INTRODUCTION TO GALOIS THEORY

Groups of Prime Power Order with Derived Subgroup of Prime Order

DEFORMATION THEORY MICHAEL KEMENY

Inseparable local uniformization. Conference on valuation theory, El Escorial

Transcription:

THE MINIMUM NUMBER OF GENERATORS FOR INSEPARABLE ALGEBRAIC EXTENSIONS 1 M. F. BECKER AND S. MACLANE 1. Finite algebraic extensions of imperfect fields. A finite separable algebraic extension L of a given field K can always be generated by a single primitive element x, in the form L = K(x). If K has characteristic p y while L/K is inseparable, there may be no such primitive element. The necessary and sufficient condition for the existence of such an element is to be found in Steinitz. 2 When there is no such primitive element, there is the question : 3 given K, what is the minimum integer m such that every finite extension L/K has a generation L = K(xi, x 2l, x m ) by not more than m elements? The question can be answered by employing Teichmüller's 4 notion of the "degree of imperfection" of K. In invariant fashion, a field K of characteristic p determines a subfield K p consisting of all pth powers of elements of K. If the extension K/K p is finite, its degree [itlx" 3 '] is a power p m of the characteristic, and the exponent m is called the degree of imperfection of K. For instance, let P be a perfect field of characteristic p and let x y y be elements algebraically independent with respect to P. Form the fields (1) S = P(x), T = P(x,y). so that T is "more im Then S = S»(x), [S:S P ] =ƒ>, while [T:T p ]=p\ perfect" than S. THEOREM 1. If the field K of characteristic p has a finite degree of imperfection m f then every finite algebraic extension LoK can be obtained by adjoining not more than m elements to K. Furthermore f there exist finite extensions LDK which cannot be obtained by adjoining fewer than m elements to K. PROOF. First consider the particular extension K llp consisting of all pth. roots of elements in K. Because of the isomorphism a* *a 1,p, (2) [KU*:K] = [K:K p ] = p. Each element y in K 1,p satisfies over K an equation y p = a of degree p. 1 Presented to the Society, October 28, 1939. 2 E. Steinitz, Algebraïsche Theorie der Körper, Berlin, de Gruyter, 1930, p. 72. 3 This problem was suggested to one of us by O. Ore. 4 0. Teichmüller, p-algebren f Deutsche Mathematik, vol. 1 (1936), pp. 362-388. 182

INSEPARABLE ALGEBRAIC EXTENSIONS 183 If K llp had generators yu - - -, y n in number less than m, the degree [K llp :K] could not exceed p n, a contradiction to (2). An explicit generation for K/K p can be found by successively choosing elements Xi of K such that each Xi is not in K p (x\,, #»-i). Then each Xi satisfies an irreducible equation 5 x? = a* over K p (xi,, Xi-i). The adjunction of Xi is an extension of degree p\ so (3) X = J p (*i, s 2,, x m ), [K:K p ] = p m y where m is the degree of imperfection 6 of K. Now let L be any finite extension of K. Because of the isomorphism a +a p, one has [L:K] = [L P :K P ]. Hence (4) [L:L p ] = [L:K]- [K:K P ]/[L P :K P ] = [K:K p ] «*\ Therefore i and L have the same degree of imperfection. But L has an explicit generation L=L p (y h, y m ) like that of (3). If L** denotes the field of all p n th powers of elements of L } the isomorphism a* >a pu yields L pu =L pu pn (yf,, y m ). By an induction on n, (5) L = L pn {y h -..,y m ). Since Z/i is finite, there is an integer n so large that for each y in L the power y pw is separable over K. The separable extension 7 K(L pu )/K has a single generator K(L pn ) =üt(y 0 ). Since y 0 is separable, the usual theorem 8 of the primitive element yields a single element y' such that X(3r 0,3, 1 )=X( 3 ;, ).Thus,by(5), L = Z(^o, 3>i, y i9, y m ) = #(ƒ, 3%, y»). This is a generation by m elements, as required. The degree of imperfection of a field K may be infinite, in the sense that the extension K/K p used in the definition is infinite. Our arguments in this case give the following result. THEOREM 2. If the degree of imperfection of a field K is infinite, then for each integer n >0 there exists a finite algebraic extension Lo K which cannot be obtained by adjoining fewer than n elements to K. 5 For the usual properties of such equations, cf. A. A. Albert, Modern Higher Algebra, chap. 7. 6 The set {xi,, x m ] of independent generators is called a p-basis for K. See O. Teichmüller, loc. cit., 3, or S. MacLane, Modular fields, I. Separating transcedence bases, Duke Mathematical Journal, vol. 5 (1939), pp. 372-393. 7 Here K(L^n) denotes the field obtained from K by adjoining all elements of the field L*> n. 8 B. L. van der Waerden, Moderne Algebra, vol. 1, 1st edition, 34. Cf. also Steinitz, loc. cit., p. 72.

184 M. F. BECKER AND S. MACLANE [February It might be thought that the minimum number of generators for an extension L/K is related to t, the transcendence degree of K over its maximum perfect subfield. However, this degree t may be larger than the degree of imperfection m. For a power series field K, Teichmüller observed that m = 1, while t is infinite. Even when t and m are both finite, they can differ, as one of us showed by a more involved example 9 with t = 2, m = 1. 2. Infinite algebraic extensions of imperfect fields. In applying our criterion for the minimum number of generators one needs to compute the degree of imperfection of a given field. A perfect field contains th roots of all of its elements, hence has degree of imperfection zero. A simple transcendental extension K{t) has a degree of imperfection one greater than the degree of imperfection of K, asteichmiiller has proved (cf. also the examples (1)). On the other hand, the computation (4) proves the following theorem. THEOREM 3. The degree of imperfection of a field is not changed by a finite algebraic extension. There remains the case of an infinite algebraic extension L/K. Such an extension is purely inseparable (or, a "radical" extension) if for each element a of L some power a p lies in K. In this case we have the following result. THEOREM 4. If K has a finite degree of imperfection m, then the degree of imperfection of a purely inseparable infinite extension of K is less than m y the degree of imperfection of K. Let L be a purely inseparable, infinite extension of K. We use a chain of intermediate fields (6) KcLicLtcLzC c.l n c ci, where L n consists of all elements of L with p n th power in K. The field L n+ i is obtained from L n by adjoining pth. roots of a sufficient number of elements of L n. By (4), the degree of imperfection of each L n is m. Hence, L n+ i is a field of degree at most p m over L n. Since [L n 'K] is then finite, each L n+ i is larger than the preceding L n. By the definition of the tower (6), each L n ol p n+i. Since I P DLJ +1, any element a of L n has over LJ+i a degree 10 [a:ln+i]è [a' p ]- In other words, 9 S. MacLane, loc. cit., 10. 10 In fact, [a:z^+1 ] = [<*:!>]. Since a is an element of L n, [a:z^+1 ] =p or 1, hence [a:lp] =p or l L If [a:l*>] -1, a*' 1 is in L and («O pw+1 -«pn is in K > Th us, by definition of Ln+u a? is in L v so [<x'*l* +1 ] =* 1.

1940J INSEPARABLE ALGEBRAIC EXTENSIONS 185 But L +1 (Z, n ) =L n, while L n +i>l n [L P (L n ):L P ] ^ [L^Lny.LJtx]. and [L +1 :L/]>1. Thus [L (L n ):L J 5i [L n :L n+ ij < [L n :L n +i\' [L n+ i:l n J = [L n :Z n J. p This degree [L n :L n of L n \ so ] is simply p m, with m the degree of imperfection (7) vl*(l n ):Lp] ^p ~K The maximum value of these degrees in (7) thus determines an integer ô S m 1 with (8) p 8 = max [Z>(Z, n ):Z>], 5 < m. We assert that S is the degree of imperfection of L. In the first place, LDZ>(Z, W ); so [L:L p ]a [L p (L n ):L p ] =p 8, where we have so chosen n as to give the maximum in (8). If, however, [L:Z>] exceeds p ô, there must be 5+1 elements a 0, #i,, as in L such that [L p (a 0, a h, tf ô ):I>] = 8+1, contrary to the definition (8) of ô. Thus 5, the degree of imperfection of L, is less than the corresponding degree of imperfection for K. The degrees used in the computation (8) of ô can be expressed explicitly by choosing a ^-basis Xi,, x m for each L n, for then [i>(l w ):2>] = [L p (L n p (x h, x m )):L p ] = [i>oi,, x m ):L*]. Consider now an infinite extension L/K which is not purely inseparable, and let M denote the field of all elements of L separable over K. Even if M/K is infinite, M and K still have the same degree of imperfection, according to a result of Teichmüller. 11 If the exponent of L is taken to be the least integer e such that all powers a p * of elements a in L are separable over K, we then have the following theorem. THEOREM 5. If K has a finite degree of imperfection, then an algebraic extension L of K has the same or a smaller degree of imperfection according as L has a finite or an infinite exponent over K. 3. Generators for given extensions. In 1 we determined the minimum number of generators for all algebraic extensions of a fixed base field. Suppose, however, L is a specific extension of K. We wish to 11 Any -basis for K is also a -basis for an arbitrary separable algebraic extension Moi K; cf. Teichmüller, loc. cit., p. 170.

186 M. F. BECKER AND S. MACLANE get the minimum number of generators for this particular extension. It clearly suffices to consider L a purely inseparable finite extension ofk. Whether the degree of imperfection of L is finite or infinite there is a subset UinL such that L p ( U) =L. By the same argument as in 1 (9) L = L pn (U) for integral n. Consider, now, the field L V (K) between L and K. For L/K finite, L/L P (K) is finite and [L:L p (K)]=p r. Since the pih power of every element in L is contained in L P (K), r elements Xi, -^2,, X r in L can be chosen such that L = L p (K)(X ly, X r ) = L P (K, X h X h, X r ). If e is the exponent of L/K, using (9) we obtain L = L P \K, X l9, X r ) = K(X lf X h, X T ), Hence L/K can be generated by r elements. Moreover, r is the minimum number of generators. For if L = K(Y U, Y s ) where s <r, Lp = K*(Yf,, Yf), L P (K) = K(Y l p f, Yf), p' = [L:L P (K)] = [K(Y l9, F.):*^,, F/»)] ^ ^, and r^s, against assumption. THEOREM 6. /ƒ L is a purely inseparable finite extension of K, the minimum number of generators of L/K is r, the exponent determined by the degree [L:L p (K)]=p r. NEW YORK, N.Y., AND HARVARD UNIVERSITY