ELEG 205 Fall Lecture #13. Mark Mirotznik, Ph.D. Professor The University of Delaware Tel: (302)

Similar documents
Chapter 8 The Complete Response of RL and RC Circuits

Lecture 13 RC/RL Circuits, Time Dependent Op Amp Circuits

EE40 Summer 2005: Lecture 2 Instructor: Octavian Florescu 1. Measuring Voltages and Currents

First Order RC and RL Transient Circuits

mywbut.com Lesson 11 Study of DC transients in R-L-C Circuits

Voltage/current relationship Stored Energy. RL / RC circuits Steady State / Transient response Natural / Step response

Capacitance and Inductance. The Capacitor

Notes 04 largely plagiarized by %khc

( ) ( ) if t = t. It must satisfy the identity. So, bulkiness of the unit impulse (hyper)function is equal to 1. The defining characteristic is

(b) (a) (d) (c) (e) Figure 10-N1. (f) Solution:

ES 250 Practice Final Exam

AC Circuits AC Circuit with only R AC circuit with only L AC circuit with only C AC circuit with LRC phasors Resonance Transformers

Chapter 8 The Complete Response of RL and RC Circuits

B Signals and Systems I Solutions to Midterm Test 2. xt ()

EECE 301 Signals & Systems Prof. Mark Fowler

ELEG 205 Fall Lecture #10. Mark Mirotznik, Ph.D. Professor The University of Delaware Tel: (302)

ECE 2100 Circuit Analysis

Laplace transfom: t-translation rule , Haynes Miller and Jeremy Orloff

Homework-8(1) P8.3-1, 3, 8, 10, 17, 21, 24, 28,29 P8.4-1, 2, 5

INDEX. Transient analysis 1 Initial Conditions 1

Chapter 7 Response of First-order RL and RC Circuits

RC, RL and RLC circuits

( ) ( ) ( ) () () Signals And Systems Exam#1. 1. Given x(t) and y(t) below: x(t) y(t) (A) Give the expression of x(t) in terms of step functions.

CHAPTER 12 DIRECT CURRENT CIRCUITS

Lab 10: RC, RL, and RLC Circuits

8. Basic RL and RC Circuits

Direct Current Circuits. February 19, 2014 Physics for Scientists & Engineers 2, Chapter 26 1

Mon Apr 9 EP 7.6 Convolutions and Laplace transforms. Announcements: Warm-up Exercise:

ECE 2100 Circuit Analysis

EE 224 Signals and Systems I Complex numbers sinusodal signals Complex exponentials e jωt phasor addition

The ZCS Boost Converter

Basic Circuit Elements Professor J R Lucas November 2001

Math 334 Fall 2011 Homework 11 Solutions

i L = VT L (16.34) 918a i D v OUT i L v C V - S 1 FIGURE A switched power supply circuit with diode and a switch.

EECE 301 Signals & Systems Prof. Mark Fowler

EECS 2602 Winter Laboratory 3 Fourier series, Fourier transform and Bode Plots in MATLAB

To become more mathematically correct, Circuit equations are Algebraic Differential equations. from KVL, KCL from the constitutive relationship

Analysis of Tubular Linear Permanent Magnet Motor for Drilling Application

[Kalita*, 4.(6): June, 2015] ISSN: (I2OR), Publication Impact Factor: (ISRA), Journal Impact Factor: 2.114

6.302 Feedback Systems Recitation 4: Complex Variables and the s-plane Prof. Joel L. Dawson

Linear Time-invariant systems, Convolution, and Cross-correlation

ECE-205 Dynamical Systems

Guest Lectures for Dr. MacFarlane s EE3350 Part Deux

Sample Final Exam (finals03) Covering Chapters 1-9 of Fundamentals of Signals & Systems

dt = C exp (3 ln t 4 ). t 4 W = C exp ( ln(4 t) 3) = C(4 t) 3.

Linear Circuit Elements

EE 301 Lab 2 Convolution

LAPLACE TRANSFORM AND TRANSFER FUNCTION

EECE.3620 Signal and System I

Section 7.4 Modeling Changing Amplitude and Midline

Delhi Noida Bhopal Hyderabad Jaipur Lucknow Indore Pune Bhubaneswar Kolkata Patna Web: Ph:

ME 452 Fourier Series and Fourier Transform

Book Corrections for Optimal Estimation of Dynamic Systems, 2 nd Edition

Q1) [20 points] answer for the following questions (ON THIS SHEET):

Linear Quadratic Regulator (LQR) - State Feedback Design

R =, C = 1, and f ( t ) = 1 for 1 second from t = 0 to t = 1. The initial charge on the capacitor is q (0) = 0. We have already solved this problem.

Reading from Young & Freedman: For this topic, read sections 25.4 & 25.5, the introduction to chapter 26 and sections 26.1 to 26.2 & 26.4.

Some Basic Information about M-S-D Systems

e 2t u(t) e 2t u(t) =?

CHAPTER 6: FIRST-ORDER CIRCUITS

6.003 Homework #9 Solutions

6.003: Signals and Systems. Fourier Representations

Complete solutions to Exercise 14(b) 1. Very similar to EXAMPLE 4. We have same characteristic equation:

Problem Set #1. i z. the complex propagation constant. For the characteristic impedance:

Boyce/DiPrima 9 th ed, Ch 6.1: Definition of. Laplace Transform. In this chapter we use the Laplace transform to convert a

EE202 Circuit Theory II , Spring. Dr. Yılmaz KALKAN & Dr. Atilla DÖNÜK

EE100 Lab 3 Experiment Guide: RC Circuits

d 1 = c 1 b 2 - b 1 c 2 d 2 = c 1 b 3 - b 1 c 3

Section 3.5 Nonhomogeneous Equations; Method of Undetermined Coefficients

Traveling Waves. Chapter Introduction

EECE251. Circuit Analysis I. Set 4: Capacitors, Inductors, and First-Order Linear Circuits

Chapter 10 INDUCTANCE Recommended Problems:

SOLUTIONS TO ECE 3084

Dynamic Effects of Feedback Control!

Chapter 1 Fundamental Concepts

h[n] is the impulse response of the discrete-time system:

Laplace Transforms. Examples. Is this equation differential? y 2 2y + 1 = 0, y 2 2y + 1 = 0, (y ) 2 2y + 1 = cos x,

6.003 Homework #9 Solutions

Chapter 2. First Order Scalar Equations

EECE 301 Signals & Systems Prof. Mark Fowler

Two Coupled Oscillators / Normal Modes

Communication System Analysis

Physical Limitations of Logic Gates Week 10a

Spring Ammar Abu-Hudrouss Islamic University Gaza

Today in Physics 218: radiation reaction

Phys1112: DC and RC circuits

2.4 Cuk converter example

L1, L2, N1 N2. + Vout. C out. Figure 2.1.1: Flyback converter

8.022 (E&M) Lecture 16

Week 1 Lecture 2 Problems 2, 5. What if something oscillates with no obvious spring? What is ω? (problem set problem)

6.003: Signals and Systems. Relations among Fourier Representations

EELE Lecture 3,4 EE445 - Outcomes. Physically Realizable Waveforms. EELE445 Montana State University. In this lecture you:

8.022 (E&M) Lecture 9

Math 333 Problem Set #2 Solution 14 February 2003

R.#W.#Erickson# Department#of#Electrical,#Computer,#and#Energy#Engineering# University#of#Colorado,#Boulder#

Embedded Systems and Software. A Simple Introduction to Embedded Control Systems (PID Control)

DEPARTMENT OF ELECTRICAL AND ELECTRONIC ENGINEERING EXAMINATIONS 2008

Number of modes per unit volume of the cavity per unit frequency interval is given by: Mode Density, N

6.01: Introduction to EECS I Lecture 8 March 29, 2011

Designing Information Devices and Systems I Spring 2019 Lecture Notes Note 17

Transcription:

ELEG 205 Fall 2017 Leure #13 Mark Miroznik, Ph.D. Professor The Universiy of Delaware Tel: (302831-4221 Email: mirozni@ee.udel.edu

Chaper 8: RL and RC Ciruis 1. Soure-free RL iruis (naural response 2. Soure-free RC iruis (naural response 3. Driven RL iruis (fored response 4. Driven RC iruis (fored response

Summary: RL and RC Naural and Fored Response Naural Response Fored Response Time onsan RL i L i (0 L e τ i L ( τ i (0 i ( e i ( L L L τ L R eq RC v v (0 e τ v ( τ v (0 v ( e v ( τ R eq C

100 Ω 100 Ω 800 Ω 0 0.1 A 0 100 Ω i ( 1 µf 10 V Find he urren in he apaior for all ime. Is his a naural response or fored response problem?

100 Ω 100 Ω 800 Ω 0 0.1 A 0 100 Ω i ( 1 µf 10 V v Fored Response Find apaior volage firs ( τ v (0 v ( e v ( τ R eq C final value iniial value ime onsan

100 Ω 100 Ω 800 Ω 0.1 A 0 100 Ω i ( 1 µf 0 10 V v ( τ v (0 v ( e v ( τ R eq C Problem #1: Solve for he iniial ondiion (0 -. Nohing is hanging a his ime so his is a seady-sae problem. This means you an replae he apaior by an open irui.

100 Ω 100 Ω 800 Ω 0.1 A 100 Ω v ( 0-10 V Problem #1: Solve for he iniial ondiion (0 -. Nohing is hanging a his ime so his is a seady-sae problem. This means you an replae he apaior by an open irui. v ( 0 0.1 100 10 V v ( 0 v (0 10 V

100 Ω 100 Ω 800 Ω 0.1 A 100 Ω v ( 0-10 V Problem #2: Solve for he final ondiion (infiniy. Nohing is hanging a his ime so his is a seady-sae problem. This means you an replae he apaior by an open irui. 100 v ( 10 1. 11V 100 800

100 Ω 100 Ω 800 Ω 0.1 A 100 Ω i ( 1 µf 10 V Problem #3: Find he ime onsan. Do his a 0. To find he equivalen resisane kill all he soures. C 1 µf τ R C eq R eq 100 800 100 800 88.9 Ω τ 88.9 10 6 se

100 Ω 100 Ω 800 Ω 0.1 A 0 100 Ω i ( 1 µf 0 10 V Now pu i all ogeher. v ( 1. 11V v ( v (0 v e τ v ( ( τ 88.9 10 6 v ( 0 10V

100 Ω 100 Ω 800 Ω 0.1 A 0 100 Ω i ( 1 µf 0 10 V Now pu i all ogeher. v 1.11 ( 10 1.11 e 88.9 10 6 v 1.11 8.89 e 11,249 How do we find I ( now?

100 Ω 100 Ω 800 Ω 0.1 A 0 100 Ω i ( 1 µf 0 10 V v 1.11 8.89 e 11,249 i C dv d 10 6 ( 11,249 11,249 11,249 8.89 e 0.1 e > 0 i 0 < 0

100 Ω 100 Ω 800 Ω 0.1 A 0 100 Ω i ( 1 µf 0 10 V i 0 < 0 i 0.1 e 11,249 > 0

0 500 Ω 10 V 5 V 500 Ω 2 H i( Find he urren in he induor for all ime. Is his a naural response or fored response problem?

0 500 Ω 10 V 5 V 500 Ω 2 H i( Find he urren in he induor for all ime. fored response i L L ( τ i (0 i ( e i ( L L τ L R eq

0 500 Ω 10 V 5 V 500 Ω 2 H i( Firs find iniial ondiion a 0-500 Ω 10 V 5 V 500 Ω 0 ( i

Firs find iniial ondiion a 0-500 Ω 10 V 5 V 500 Ω i ( 0 KVL : 10 5 500i i (0 5 1000 5mA (0 500i (0 i ( 0 i (0 5mA 0

Nex find iniial ondiion a infiniy 500 Ω 10 V 5 V 500 Ω i ( 10 i ( 20 ma 500

0 500 Ω 10 V 5 V 500 Ω 2 H i( Las find he ime onsan 500 Ω 10 V 5 V 500 Ω 2 H

Las find he ime onsan 500 Ω 10 V 5 V 500 Ω 2 H L τ Req 2 500 1 250 τ 1 250 se

0 500 Ω 10 V 5 V 500 Ω 2 H i L L i( ( τ i (0 i ( e i ( L L i L 20 ( 250 5 20 e ma i L 20 15e 250 ma

20 kω 3 kω 5 µf 12 V 5 kω 1 kω v( 0-10 kω Find he volage v( for all ime. Is his a naural response or fored response problem?

20 kω 3 kω v ( 5 µf 12 V 5 kω 1 kω v( - 0-10 kω v naural response τ v (0 e τ R eq C

20 kω 3 kω - v ( 5 µf 12 V 0 10 kω 5 kω 1 kω - v( Find iniial ondiion a 0-20 kω 3 kω v ( 0 v (0 12V v ( 0 12 V 5 kω 1 kω - 10 kω

20 kω 3 kω v ( 5 µf 12 V 5 kω 1 kω v( - 0-10 kω Find ime onsan 20 kω 3 kω v ( 5 µf 12 V 5 kω 1 kω v( - - 10 kω

20 kω 3 kω - v ( 5 µf 5 kω 1 kω - v( 10 kω τ R eq C C 5 µf R eq 5,000 1,000 5,000 1,000 3,000 10,000 20,000 33,667 Ω τ 0.1683se v τ v (0 e 12 e.1683 0 12 e 5.94

20 kω 3 kω - v ( 5 µf 5 kω 1 kω - v( v i v 12 e dv C d 5.94 5 10 6 10 kω 12 5.94e 5.94 0.3564 e 5.94 i ( i v i KVL ouer loop: 20000 ( 3000 ( ( 10000 0 12 e 5.94 0.3564 e 5.94 ma 33,000 v( 0 ma v( 0.2388 e 5.94 V

Chaper 10: Seady-Sae Sinusoidal Analysis V Aos( ω φ

Chaper 10: Sinusoidal Seady-Sae Review of Sinusoids V Aos( ω φ ime, se ω A radians angular frequeny, se ampliudeor magniude φ phaseangle, radians

Chaper 10: Sinusoidal Seady-Sae ω 2π f V Aos( ω φ V Aos(2π f φ ime, se ω angular frequeny, f frequeny, Hz radians se ( yles / se A ampliudeor magniude φ phase angle, radians

V π φ 5os(2, A 5, f 1Hz, 0 5 1 yle or 2π radians over 1 seond Tperiod

V 2.5os(2π, A 2.5, f 1Hz, φ 0 2.5 1 yle or 2π radians over 1 seond

V 5os(6π, A 5, f 3Hz, φ 0 5 3 yles or 6π radians over 1 seond

π π V π 5os(2, A 5, f 1Hz, φ 2 2 5 1 yle or 2π radians over 1 seond

π φ V 5os(2, A 5, f 1Hz

Oher ways o wrie sinusoids V Aos( ω φ Reall: e jx os( x j sin( x e j ( ω φ j( ω φ e V Aos( ω φ A 2

Oher ways o wrie sinusoids V Aos( ω φ Reall: e jx os( x j sin( x V Aos( ω φ Re [ ( ] A e j ω φ Re [ ] A e jφ e jω Re real par

Before we learn how o solve irui problems using sinusoids Wha is so speial abou sinusoids?

Wha is so speial abou sinusoids? Wha do I ge if I add wo sinusoids of he same frequeny? Aos( ω φ B os( ω φ A B?

Wha is so speial abou sinusoids? Wha do I ge if I add wo sinusoids of he same frequeny? Aos( ω φ B os( ω φ C os( ω A B φ C C φ C [ ( ( ] 2 Aos φ B os φ [ Asin( φ Bsin( φ ] an 1 A Aos Asin A ( φ ( ( ( A B os φa φa Bsin φa A A 2 The resul is a sinusoid of he same frequeny, ω!

Wha is so speial abou sinusoids? Wha do I ge if I subra wo sinusoids of he same frequeny? Aos( ω φ B os( ω φ C os( ω A B φ C C φ C [ ( ( ] 2 Aos φ B os φ [ Asin( φ Bsin( φ ] an 1 A Aos Asin A ( φ ( ( ( A B os φa φa Bsin φa A A 2 The resul is a sinusoid of he same frequeny, ω!

Wha is so speial abou sinusoids? Wha do I ge if I ake he derivaive of a sinusoid? d d ( Aos( ω φ A ω sin( ω φ A ω os( ω φ π 2 The resul is a sinusoid of he same frequeny, ω!

Wha is so speial abou sinusoids? Wha do I ge if I ake he inegral of a sinusoid? ( Aos( ω φ d A ω sin( ω φ A ω os( ω φ π 2 The resul is a sinusoid of he same frequeny, ω!

Wha is so speial abou sinusoids? REASON #1 A os( ω φa Linear Sysem C os( ω φc For any linear sysem if I inpu a sinusoid of frequeny, ω, he oupu is also a sinusoid of he same frequeny.

Wha is so speial abou sinusoids? REASON #2

Wha is so speial abou sinusoids? REASON #2 Any non-sinusoid signal an be onsrued by adding a bunh of sinusoids of differen frequenies. Called Fourier series and Fourier ransforms.

Elerial Symbols Library for Drawing Shemais in PowerPoin For bes resuls: Turn snap-o-grid-on Do no sale he symbols library. Draw enire shemai firs, hen sale o desired size. Afer roaion, press up/down and sideways arrow keys o realign he omponen wih he grid. Aives Passives Soures Disrees