ECONOMETRICS II (ECO 2401S) University of Toronto. Department of Economics. Winter 2014 Instructor: Victor Aguirregabiria

Similar documents
ECONOMETRICS II (ECO 2401S) University of Toronto. Department of Economics. Spring 2013 Instructor: Victor Aguirregabiria

ECONOMETRICS II (ECO 2401S) University of Toronto. Department of Economics. Winter 2016 Instructor: Victor Aguirregabiria

i=1 y i 1fd i = dg= P N i=1 1fd i = dg.

ECONOMETRICS II (ECO 2401) Victor Aguirregabiria. Winter 2017 TOPIC 3: MULTINOMIAL CHOICE MODELS

ECONOMETRICS FIELD EXAM Michigan State University May 9, 2008

Wageningen Summer School in Econometrics. The Bayesian Approach in Theory and Practice

Simple Estimators for Semiparametric Multinomial Choice Models

Introduction: structural econometrics. Jean-Marc Robin

ECONOMETRICS II (ECO 2401) Victor Aguirregabiria. Winter 2018 TOPIC 3: MULTINOMIAL CHOICE MODELS

Testing for Regime Switching: A Comment

ECONOMETRICS II (ECO 2401) Victor Aguirregabiria. Spring 2018 TOPIC 4: INTRODUCTION TO THE EVALUATION OF TREATMENT EFFECTS

Simple Estimators for Monotone Index Models

MC3: Econometric Theory and Methods. Course Notes 4

ECON 594: Lecture #6

Nonparametric Estimation of Wages and Labor Force Participation

GMM-based inference in the AR(1) panel data model for parameter values where local identi cation fails

ECONOMET RICS P RELIM EXAM August 24, 2010 Department of Economics, Michigan State University

1. The Multivariate Classical Linear Regression Model

Estimation of Dynamic Nonlinear Random E ects Models with Unbalanced Panels.

ECONOMET RICS P RELIM EXAM August 19, 2014 Department of Economics, Michigan State University

Economics 241B Review of Limit Theorems for Sequences of Random Variables

Chapter 2. Dynamic panel data models

xtunbalmd: Dynamic Binary Random E ects Models Estimation with Unbalanced Panels

Chapter 6: Endogeneity and Instrumental Variables (IV) estimator

h=1 exp (X : J h=1 Even the direction of the e ect is not determined by jk. A simpler interpretation of j is given by the odds-ratio

Exercises Chapter 4 Statistical Hypothesis Testing

Chapter 2. Review of basic Statistical methods 1 Distribution, conditional distribution and moments

2014 Preliminary Examination

Instrumental Variables. Ethan Kaplan

Lecture Notes on Measurement Error

MLE and GMM. Li Zhao, SJTU. Spring, Li Zhao MLE and GMM 1 / 22

Max. Likelihood Estimation. Outline. Econometrics II. Ricardo Mora. Notes. Notes

Control Functions in Nonseparable Simultaneous Equations Models 1

Rank Estimation of Partially Linear Index Models

Economics 241B Estimation with Instruments

AAEC/ECON 5126 FINAL EXAM: SOLUTIONS

Economics 620, Lecture 18: Nonlinear Models

Chapter 1. GMM: Basic Concepts

Economics 620, Lecture 19: Introduction to Nonparametric and Semiparametric Estimation

Applied Health Economics (for B.Sc.)

Fall 2017 STAT 532 Homework Peter Hoff. 1. Let P be a probability measure on a collection of sets A.

HEC Lausanne - Advanced Econometrics

Expectation Maximization (EM) Algorithm. Each has it s own probability of seeing H on any one flip. Let. p 1 = P ( H on Coin 1 )

Economics 620, Lecture 9: Asymptotics III: Maximum Likelihood Estimation

Solution and Estimation of Dynamic Discrete Choice Structural Models Using Euler Equations

Lecture Notes based on Koop (2003) Bayesian Econometrics

Lecture 14 More on structural estimation

Structural Econometrics: Dynamic Discrete Choice. Jean-Marc Robin

Estimating the Number of Common Factors in Serially Dependent Approximate Factor Models

A Course in Applied Econometrics Lecture 18: Missing Data. Jeff Wooldridge IRP Lectures, UW Madison, August Linear model with IVs: y i x i u i,

ECON Introductory Econometrics. Lecture 11: Binary dependent variables

Lecture # 1 - Introduction

Nonparametric Identi cation and Estimation of Truncated Regression Models with Heteroskedasticity

Contents. University of York Department of Economics PhD Course 2006 VAR ANALYSIS IN MACROECONOMICS. Lecturer: Professor Mike Wickens.

Notes on Generalized Method of Moments Estimation

Econometrics Lecture 5: Limited Dependent Variable Models: Logit and Probit

DEPARTMENT OF ECONOMICS DISCUSSION PAPER SERIES

PSC 504: Dynamic Causal Inference

Information in a Two-Stage Adaptive Optimal Design

Classification. Chapter Introduction. 6.2 The Bayes classifier

We begin by thinking about population relationships.

MA 8101 Stokastiske metoder i systemteori

Final Exam. Economics 835: Econometrics. Fall 2010

University of Toronto Department of Economics. Solution and Estimation of Dynamic Discrete Choice Structural Models Using Euler Equations

Ninth ARTNeT Capacity Building Workshop for Trade Research "Trade Flows and Trade Policy Analysis"

Statistics & Data Sciences: First Year Prelim Exam May 2018

A Course in Applied Econometrics Lecture 14: Control Functions and Related Methods. Jeff Wooldridge IRP Lectures, UW Madison, August 2008

Online Appendix to: Marijuana on Main Street? Estimating Demand in Markets with Limited Access

Recent Advances in the Field of Trade Theory and Policy Analysis Using Micro-Level Data

Non-linear panel data modeling

Binary Models with Endogenous Explanatory Variables

Economics 620, Lecture 5: exp

Dynamic Semiparametric Models for Expected Shortfall (and Value-at-Risk)

Math 494: Mathematical Statistics

Environmental Econometrics

x i = 1 yi 2 = 55 with N = 30. Use the above sample information to answer all the following questions. Show explicitly all formulas and calculations.

Introduction to Nonparametric and Semiparametric Estimation. Good when there are lots of data and very little prior information on functional form.

Lecture 6: Discrete Choice: Qualitative Response

ECON2285: Mathematical Economics

Economics Introduction to Econometrics - Fall 2007 Final Exam - Answers

First Year Examination Department of Statistics, University of Florida

Econometric Analysis of Cross Section and Panel Data

Discrete Dependent Variable Models

Analogy Principle. Asymptotic Theory Part II. James J. Heckman University of Chicago. Econ 312 This draft, April 5, 2006

Dynamic Semiparametric Models for Expected Shortfall (and Value-at-Risk)

Lecture Stat Information Criterion

Final Examination Statistics 200C. T. Ferguson June 11, 2009

STAT331. Cox s Proportional Hazards Model

Econometrics Lecture 1 Introduction and Review on Statistics

Föreläsning /31

Estimation of Dynamic Nonlinear Random E ects Models with Unbalanced Panels

Parametric Inference on Strong Dependence

ERSA Training Workshop Lecture 5: Estimation of Binary Choice Models with Panel Data

Lecture 1- The constrained optimization problem

Jeffrey M. Wooldridge Michigan State University

Economics 620, Lecture 7: Still More, But Last, on the K-Varable Linear Model

A Course on Advanced Econometrics

Unbiased Estimation. Binomial problem shows general phenomenon. An estimator can be good for some values of θ and bad for others.

1 Quantitative Techniques in Practice

Short T Panels - Review

Transcription:

ECONOMETRICS II (ECO 2401S) University of Toronto. Department of Economics. Winter 2014 Instructor: Victor guirregabiria SOLUTION TO FINL EXM Monday, pril 14, 2014. From 9:00am-12:00pm (3 hours) INSTRUCTIONS: This is a closed-book exam. No study aids, including calculators, are allowed. The exam consists of ve sets of questions. Try to answer all the questions. TOTL MRKS = 100 PROBLEM 1 (25 points). Consider the Censored Linear Regression Model (CLRM), Y = maxfx + " ; 0g where " is independent of X and it has a pdf f(:) and a cdf F (:) that is strictly monotonically increasing over the real line. (a) [5 points] Obtain the expression of the selection bias function s(x ) E(maxfX+ "; 0g j X) X. NSWER: For notational simplicity, let z X. Then, s(z) = E(maxf"; zg) = Pr(" > z) E(" j " > z) + Pr(" < z) ( z), such that: s(z) = [1 F ( z)] = z F ( z) + Z +1 z Z +1 z f(") " d" + F ( z) ( z) 1 F ( z) " f(")d" (b) [5 points] Show that the selection bias function s(x ) is a strictly decreasing. NSWER: Given the conditions on the CDF F, the sample selection function s(z) is continuously di erentiable. The derivative function of s(z) is: s 0 (z) = F ( z) + z f( z) z f( z) = F ( z) < 0 (c) [5 points] Suppose that this CLRM is such that X = 0 + 1 X 1, where X 2 2 f0; 1g is a binary variable. Obtain the expression of the parameter E(Y jx 1 = 1) E(Y jx 1 = 0) in terms of 1 and s(:). NSWER: By de nition of the selection function, we have that E(Y jx) = X + s(x). Then, in this speci c model we have that: = E(Y jx 1 = 1) E(Y jx 1 = 0) = [ 0 + 1 + s( 0 + 1 )] [ 0 + s( 0 )] = 1 + s( 0 + 1 ) s( 0 ) 1

(d) [5 points] In the model of question (c), show that the OLS estimator of 1 in the linear regression Y = 0 + 1 X 1 + e (that ignores the selection problem) is a consistent estimator of. NSWER: The OLS estimator of 1 is P n (x 1i x 1 )y i = P n (x 1i x 1 ) 2, that by the LLN converges in probability to E((X 1 E(X 1 ))Y ) = V (X 1 ). Given that X 1 is binary, we have that: (1) E(X 1 ) = p where p Pr(X 1 = 1); (2) V (X 1 ) = p(1 p); and (3) E((X 1 E(X 1 ))Y ) = p (1 p) E(Y jx 1 = 1) (1 p) p E(Y jx 1 = 0). Therefore, E((X 1 E(X 1 ))Y ) = V (X 1 ) = E(Y jx 1 = 1) E(Y jx 1 = 0) =. (e) [5 points] Using the expressions that you have derived in (c) and (d), obtain the sign of the bias of the OLS estimator of 1 when 1 > 0, and when 1 < 0. NSWER: Given that s(:) is strictly decreasing, we have that: (1) if 1 > 0, then s( 0 + 1 ) s( 0 ) < 0 and < 1, i.e., the OLS estimator provides a downward bias estimate of the true 1 ; and (2) if 1 < 0, then s( 0 + 1 ) s( 0 ) > 0 and > 1, i.e., the OLS estimator provides an upward bias estimate of the true 1. In both cases we have that jj < j 1 j, i.e., the OLS estimator implies an attenuation bias. PROBLEM 2 (20 points). Let be a vector S 1 parameters, and let be a vector of R 1 parameters, where R > S. Suppose that an econometric model implies the following relationship between these two vector of parameters =, where is a R S matrix of constants that is full column rank. Let b be a root-n consistent and asymptotically normal estimator of, such that p n( b )! d N(0; V ), and let V b be a root-n consistent estimator of V. (a) [5 points] De ne the Minimum Distance Estimator (MDE) of when the restrictions = are equally weighted. NSWER: b EMD = arg min h b i 0 h b i This a quadratic criterion function that is globally convex in. The estimator is characterized by rst order conditions of optimality 2 0 h b b EMD i = 0, and solving for b EMD we get: b EMD = 0 1 0b (b) [5 points] De ne the MDE of when the restrictions are optimally weighted. NSWER: h i 0 h b EMD = arg min b bv 1 b i 2

This a quadratic criterion function that is globally h convex ini. The estimator is characterized by rst order conditions of optimality 2 0 V b 1 b b OMD = 0, and solving for b OMD we get: h i 1 b OMD = 0 V b 1 0 V b 1 b (c) [10 points] Derive the asymptotic variance of the estimator of, both for the Equally Weighted and for the Optimally Weighted MDE. NSWER: For the EMD p n( b EMD ) = p n 0 1 0b p n 0 1 0 = p n 0 1 0b p n 0 1 0 = 0 1 0 p n( b ) Therefore, such that p n( b EMD )! d N(0; 0 1 0 V 0 1 ) var( b EMD ) = 0 1 0 V 0 1 For the OMD p n( b OMD ) = p i 1 n h 0 V b 1 0 V b 1 b p i 1 n h 0 V b 1 0 V b 1 = p h i 1 n 0 V b 1 0 V b 1 b p i 1 n h 0 V b 1 0 V b 1 h i 1 = 0 V b 1 0 V b 1p n( b ) Therefore, by the consistency of b V 1 (Slutsky s theorem): p i 1 h i 1) n( b OMD )! d N(0; h 0 V 1 0 V 0 V 1 h i 1) = N(0; 0 V 1 such that var( b OMD ) = h 0 V 1 i 1 PROBLEM 3 (30 points). Consider a random coe cients multinomial choice model with J +1 choice alternatives f0; 1; :::; Jg. The "utility" of alternative j = 0 is normalized to zero. The utility of alternative choice j > 0 for individual i is U ij = + i Z j + " ij, where: is a parameter; Z j is an observable attribute of alternative j; i is a random coe cient with that is i.i.d. over individuals with a normal distribution N( ; 2 ); and " ij is an unobservable that is i.i.d. over i and over j with an extreme value type 1 distribution. The researcher observes product attributes fz 1, Z 2,..., Z J g and a random 3

sample of n individuals with their optimal choices fy i : i = 1; 2; :::; ng with y i 2 f0; 1; :::; Jg. We are interested in using this sample to estimate the parameters of the = f; ; g. (a) [5 points] Write the expression of the choice probability P j () Pr(Y = jj) in terms of the primitives of the model. NSWER: We can write i = + v i, where v i is iid standard normal with pdf (:). Then: Z P j () = exp + + v i Zj 1 + P J k=1 exp + (v i ) dv i + v i Zk (b) [5 points] Write the log-likelihood function of this model and data. NSWER: l() = = nx 1fy i = jg ln P j () n j ln P j () where n j P n 1fy i = jg. (c) [5 points] Show that if we do not impose the model restrictions on the choice probabilities, the MLE of P j is the frequency estimator. NSWER: Without restrictions on the choice probabilities, we have a multinomial model with J free parameters/probabilities P = fp j : j = 1; 2; :::; Jg. The log likelihood function is: l(p) = = nx 1fy i = jg ln P j + 1fy i = 0g ln(1 P 1 ::: P J ) j=1 n j ln P j + n 0 ln(1 P 1 ::: P J ) j=1 The likelihood equations are: l(p) P j = n j bp j n 0 bp 0 = 0 Or n j b P0 = n 0 b Pj. Summing this expression over j > 0, we have that (n n 0 ) b P 0 = n 0 (1 b P0 ), and solving for b P 0, we get b P 0 = n 0 =n. Plugging this expression into the likelihood equations we get that b P j = n j =n, and this is the frequency estimator. (d) [5 points] Propose a simulator of the choice probability P j (). De ne the simulated log-likelihood function of this model, and the simulated MLE. 4

NSWER: Let fv r : r = 1; 2; :::Rg be R independent random draws from a standard normal distribution. Then, the simulator of P j () is: ep R j () = 1 R RX exp + + v r Z j 1 + P J k=1 exp + + v r Z k The simulated log-likelihood function is: e l R () = n j ln e P R j () The simulated MLE is the value of that maximizes e l R (). (e) [5 points] Obtain the simulated likelihood equations with respect to ; ; and. NSWER: The likelihood equations are P J n j e P R j () ep R j 1 () = 0, where e P R j () = e P R j (), P e j R(), P e j R()! 0 and with P e j R() = 1 P R R j(v r ; ) [1 j (v r ; )] P e j R() = 1 P R R j(v r P ; )[Z J j k=1 Z k k (v r ; )] P e j R() = 1 P R R vr j (v r P ; )[Z J j k=1 Z k k (v r ; )] j (v r exp + + v r Z j ; ) 1 + P J k=1 exp + + v r Z k (f) [5 points] Describe a simulated-based version of the BHHH algorithm to compute the simulated MLE. NSWER: We start with an initial vector b 0. Then, we generate the recursively the sequence f b K : K 1g where at iteration K 1, we obtain update b K using the formula: " nx b K = b K 1 + e li R(b K 1 ) e # 1 " li R nx (b K 1 ) e # l R 0 i (b K 1 ) where e l R i () is the simulated score based with e l R i () = 1fy i = jg ln P e j R () 5

such that e l R i () = 1fy i = jg e P R j () 1 ep R j () PROBLEM 4 (5 points). Consider the single-equation econometric model Y = g(x; ";) where g is a known real valued function, X is a vector of observable explanatory variables, " is a vector of unobservables, and is a vector of unknown parameters. Function g is continuous in all its arguments and monotonic in ", though may not be strictly monotonic. The unobservables " are independent of X and have a continuous and strictly increasing CDF over the Euclidean space. The distribution of " is unknown to the researcher, i.e., the model is semiparametric. Let fy i ; x i : i = 1; 2; :::; ng be a random sample of Y and X. (a) [5 points] Propose a consistent estimator of. NSWER: Under the assumption that the unobservables have medians independent of X, the Least bsolute Deviations (LD) estimator provides a consistent estimator of Y = g(x; ";) in a model with non-additively-separable unobservables such as Y = g(x; ";). This estimator is de ned as: nx b LD = arg min jy i g(x i ; 0;)j PROBLEM 5 (15 points). Consider the static linear panel data model Y it = i + i X it +u it, where X it is a explanatory variable that is strictly exogenous with respect to u it. (a) [5 points] Suppose that i and X it are independently distributed, but i and X it are not independent. The researcher does not want to make any assumption about the joint distribution of i and X it. Propose an estimator of E( i ) that is consistent as N! 1 and T is xed. NSWER: De ne the random variable v i i, that by construction has zero mean, and by assumption is independent of X it. We can write the model as Y it = i + X it +e it, where e it u it + v i X it. Note that for any two periods t and s we have that: E(X it e is ) = E (X it [u is + v i X is ]) = E (X it u is ) + E (v i X it X is ) = 0 + 0 = 0 Therefore, X it is strictly exogenous with respect to e it in the model Y it = i + X it +e it. Under this condition, we know that the OLS estimator in the rst di erences transformed equation, or the OLS estimator in the within-groups transformed equation are consistent as N! 1 and T is xed. 6

(b) [5 points] Prove that the estimator proposed in (a) is consistent. NSWER: For instance, in the rst di erences transformed equation, Y it Y it 1 = ( ) + (e it e it 1 ) and E([ ] [e it e it 1 ]) = 0. Under this condition, and given that there are not incidental parameters, the OLS estimator is consistent. (c) [5 points] Suppose that both i and i are NOT independently distributed of X it. The researcher does not want to make any assumption on the joint distribution of ( i ; i ) and X it. Propose an estimator of E( i ) that is consistent as N! 1 and T is xed, and prove its consistency. NSWER: OLS in rst di erence or OLS in within-groups transformed model are inconsistent because now the error term e it u it + v i X it is correlated with X it. However, we can consider the following transformation of the model. First, we take rst di erences: Y it Y it 1 = i ( ) + (u it u it 1 ) nd provided that ( ) 6= 0 (this has zero probability mass if X it is a continuous random variable) we can divide right-hand-side and left-hand-side by ( ) to get: or Y it Y it 1 = i + u it u it 1 Y it Y it 1 = + it where it v i + u it u it 1. It is clear that E( it ) = 0. Therefore, the sample mean of Y it Y it 1 is a consistent estimator of as N! 1 and T is xed, and prove its consistency. For instance, suppose that T = 2: b = 1 N NX Yi2 It is clear that by LLN b converges in probability to E Yi2 Y i1 X i2 X i1 = E( + i2 ) =. X i2 Y i1 X i1 7