Problems 1 to 6 of the Rhind Mathematical Papyrus R. J. GILL I N G S

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- Problems to 6 of the Rhind Mathematical Papyrus R. J. GILL I N G S WHEN THE RHIND MATHEMATICAL PAPYRUS was received by the British Museum,in 864, it was broken in some places, and portions of the brittle fragments were missing. Subsequently the papyrus roll was unrolled and mounted in two glass frames, the first portion, called the Recto (reading from right to left), having a jagged break because of these missing fragments. The whole papyrus was originally 8 feet long and a little over a root in width, the second half, called the Verso, having a blank space about 0 feet long towards the left-hand end, upon which nothing is written. Section I of the papyrus []' consists of an introduction, followed by the division of the number 2 by all the odd numbers from 3 to 0, 50 separate divisions in all, with the answers expressed as unit fractions except for the quite common use of the special fraction 2/3 [2] for which the scribe had a particular liking, so that he used it whenever it was possible. This takes up about one-third of the Recto. Section II, which is relatively much smalleroccupying only about nine inches of the papyrusconsists of a short table giving the answers in unit fractions of the divisions of the numbers to 9 by 0, followed by Problems to 6 [] on the division of certain numbers ofloaves ofbread equally among ten men, in which problems the scribe uses, for his answers, the values given in his table of reference, '"Numbers in brackets refer to the notes at the end of the article. Reprinted from Mathematics Teacher 56 Gan., 962): 6-69; with permission of the National Council ofteachers of Mathematics. and then proves arithmetically that they are correct. (This table and an explanatory version are shown on the following page.) One observes that as soon as it is possible to introduce the fraction 2/3 into his table, the scribe does so, even though for 7 divided by 0 he could have used the simpler value /2 + 5, and for 8 divided by 0, 2 + /5 + /0, and for 9 divided by 0, /2 + 3 + /5 [3]. The problems on the division of loaves are available to us for examination and discussion as a result of the restoration of the missing fragments of the papyrus, which, while in the possession of the New York Historical Society, were recognized as such by the English archaeologist Professor Newberry in 922, and were brought to the British Museum by Edwin Smith to allow them to be put in their appropriate places on the Recto. In the text of the R. M. P. itself, no statement occurs giving the title, or describing the purpose, of the table. The scribe clearly regarded these as self-evident The table occurs as if (for example) a student about to solve a group of problems which would require multiplications and divisions of numbers by 7 (let us say) were to write down first of all the 7 times table, for ready reference in the operations which were to follow. The scribe now sets down the divisions of, 2, 6, 7, 8, and 9 loaves among 0 men, using the values he has already given in his table. These constitute Problems to 6. He omits the division of 3, 4, and 5 loaves among 0 men, but in this 35

( PART III/HUMAN IMPACT AND THE SOCIETAL STRUCTURING OF MATHEMATICS discussion of the Egyptian division of loaves we shall include them, following exacdy the methods he uses for the others. divided by 0 is /0 2 3 4 5 6 7 8 9 " 0 " 5 " 0 " 5 /0 " 0 " /3 /5 " 0 " /2 " 0 " 2 /0 0 " 2/3 /30 0 " 2/3 /0 /30 0 " 2/3 5 /30 i\ / i{ A / ~ ~,/ /30 2/3 /30 /0 2/3 /30 /5 2/3 Table ofd vision of to 9 by 0!\ I ' ;\ i;/ 7 /\ 7 /0 /5 /0 /5 /5 /3 /2 /0 /2 Problem Division of lloaf among 0 men. [Each man receives /0.] (From his reference table.) For proof multiply /0 by 0. [If] [part is] /0 [then] -- 2 [parts are]/5 4 /3 + 5 (From the Recto, 2 + 5= -- 8 " 3+5.) 23+ /0+ /30 (From the Recto, 2 + 5 = /0 + 30.) [Add the fractions on the lines with check marks (since 2 + 8 = 0): 5 + 2/3 + /0 + /30 =.] T otallloaf which is correct. Those portions enclosed within square brackets are not given by the scribe, but are included here to explain his methods. He does not prove that divided by 0 is /0. His readers are supposed to know this by referring to his table which precedes his problems. Further, the steps in his proof that /0 multiplied by 0 is in fact one loaf may be verified by referring to his more elaborate table of"2 divided by all the odd numbers from 3 to 0," with which the R.M.P. begins [4]. Thus when it is required to multiply the fraction /5 by 2, it is only necessary to look in his table, for 2 divided by 5, to find the answer /3 + /5. And similarly for /5 multiplied by 2, he finds from his table that 2 divided by 5 is /0 + /30. For the addition of the fractions, the standard method, used elsewhere in the R.M.P., was analogous to our modern concept of Least Common Multiple. Taken as parts of (say) the abundant number 30, /5 is 6, 2/3 is 20, /0 is 3, and /30 is, so that 6 + 20 + 3 + = 30, and thus the whole. We may fairly assume that the Egyptian loaves were long and regular in cross-section, either cylindrical or rectangular, so that the actual cutting up of a loaf into uuit fractions (and of course 2/3) did not present real difficulties. The sign in hieroglyphics for a loaf is 0.Q. which permits us to make this assumption. The division of one loaf among ten men would be done, therefore, as in Figure. Problem2 Division of 2loaves among 0 men. [Each man receives /5.] (From his reference table.) 36

PROBLEMS I TO 6 OF THE RHINO MATHEMATICAL PAPYRUS FIGURE I Loaf I I I FIGURE 2 2 Loaves Each man gets 0 For proof multiply /5 by 0. [If] [part is] /5 [then] --/ 2 [parts are] /3 + /5 (From the Recto, 2 + 5 = (From the Recto, 2 + 5 "' 4 /3 + /5.) 2/3 + /0 + /30 /0 + /30.) -- 8 /3+/5+/5 [Add the fractions on the lines with check marks (since 2 + 8 = 0): /3 + /5 + /3 + /5 + /5 = 2.] Total 2 loaves which is correct. The steps in Problem 2 are practically the same as those for Problem, and the division of two loaves among ten men would he done therefore as in Figure 2. If the scribe had included the division of three loaves among ten men as his next problem, he would have set it down as follows (if we adopt the same procedure shown in the other problems). Each man gets 5 [Add the fractions on the lines with the check marks (since 2 + 8 = 0): /3 + /5 + 5 + /3 + /5 + /5 + 2/3 + /0 + /30 = 3.] Total 3 loaves which is correct. The addition of the row of fractions is merely ( + 2), from the additions in Problems and 2. The division of three loaves among ten men would therefore be as shown in Figure 3. It now becomes clear to us why the scribe omitted this division. It is merely a repetition of his first two examples, whose answers were /0 and /5, giving his answer /0 + /5. A glance at Figures, 2, and 3 also shows this. Now in the case of the division of one and two loaves equally among ten men, there is no difference whatever between what an Egyptian would have done following the R.M.P. and what would be done in the present day. But in the case of the division of three loaves ' Division of 3 loaves among 0 men. Each man receives /5 + /0. (From his reference table.) For proof multiply /5+ /0 by 0. If part is /5 + /0 then --/ 2 part>; are /3 + /5 + /5 (From the Recto, 2 + 5 = /3 + /5.) FIGURE 3 %] 3 Loaves then 4 parts are 2/3 + /0 + /30 + /3 + /5 (From the Recto, 2 + 5 = /0 + /30.) then --/ 8 parts are /3 + /5 + /5 + 2/3 + /0 + /30 Each man gets 5 /0 37

PART III/HUMAN IMPACT AND THE SOCIETAL STRUCTURING OF MATHEMATICS FIGURE 4 3/0 3/0 3/0 ~ 3/0 3/0 3/0 0 3/0 3/0 3/0 ~0 a modern division would result in nine men getting 3/0 of a loaf each in one whole piece, and the tenth man getting thtee smaller pieces each /0 of a loaf, as in Figure 4. The Egyptian foreman charged with the duty of sharing the food fairly and equally among his gang of ten men, would give each man exactly the same share both in quantity (i.e., size) and number of pieces, and thus to the uneducated and ignorant laborers, not only is justice done, but justice also appears to have been done. In our modem division it could be supposed that one man had received more than his share, because he had three pieces, to_ the others' one piece. We proceed now to the next case, the division of 4loaves among 0 men. It might have appeared as follows. The addition of the long row of fractions to give 4 is much simpler than it appears at ftrst glance. The scribe would observe that, fraction by fraction, the array is exactly twice the summation he has already made in Problem 2. Thus, 2x3=2/3 2 X /5 = 0 + /30 2xll/3=2 2/3 2 X /5 = /3 + /5 2 X /5 = /0 + /30. The division of four loaves among ten men is therefore as shown in Figure 5. One again notices that not only is justice done in the Egyptian system, but justice also appears to be done. A modem division would result in eight men getting each one portion, namely 2/5 of a loaf, and two men getting each two smaller pieces of /5 of a loaf, an apparent inequity perhaps to the ignorant members of the working gang. This is shown in Fignre 6. Continuing we have: Division of Sloaves among 0 men. Each man receives /2. {From his reference table.) For proof multiply /2 by 0. Division of 4loaves among 0 men. Each man receives /3 + /5. {From his reference table.) For proof multiply /3 + /5 by 0. If part is /3 + /5 then -! 2 parts are 2/3 + /0 + /30 (From the Recto, 2 + 5 = /0 + /30.) then 4 parts are /3 + /5 + /5 then.j 8 parts are 2 2/3 + /3 + /5 + /0 + /30 (From the Recto, 2 + 5 = /3 + /5.) [Add the fractions on the lines with the check marks (since 2 + 8 = 0): 2/3 + /0 + /30 + 2 2/3 + /3 + /5 + /0 + /30 = 4.] FIGURE 5 ~I ITa 4Loaves I I I I I I I I I T otal4 loaves which is correct. Each man gets /3 5 38

PROBLEMS I TO 6 OF THE RHINO MATHEMATICAL PAPYRUS FIGURE 6 25 25 25 25 If then ~ then then ~ part is 2 parts are 4parts are 8 parts are 25 25 25 2/5 /2 2 4 /5 /5 /5 /5 [Add the numbers on the lines with check marks (since 2+ 8 = 0): +4=5.] TotalS loaves which is correct. This is the simplest of all the divisions, and it was omitted by the scribe as were the divisions of three and four loaves. The actual cutting up of the five loaves is shown in Figure _7 and, of course, is the same it would be done today. Problem] Division of 6 loaves among 0 men. [Each man receives /2 + /0.] (From his reference table.) For proof multiply /2 + /0 by 0. [If] [part is] /2 + /0 [then] ~ 2 [parts are]!+ 5 4 2+ /3+ /5 (From the Recto, 2 + 5 = /3 + /5.) ~ 8 4+ 2/3 + /0 + /30 (From the Recto, 2 + 5 = /0 + /30.) [Add the fractions on the lines "'!Nith check marks (since 2 + 8 = 0): + /5 + 4 + 2/3 + /0 + + /30 = 6.] Total 6 loaves which is correct. One notes, en passant, that the addition of the row of fractions in this problem is, except fur the integers, exactly the same as that for Problem. The actual cutting up is shown in Figure 8. This is perhaps the best example to show the efficiency of the Egyptian unit fraction system in the cutting up of loaves, for here again each man FIGURE 8 6 Loaves FIGURE J SLoaves I I I I I I I Each man gets 2 Each man gets 2 /0 39

' PART III/HUMAN IMPACT AND THE SOCIETAL STRUCTURING OF MATHEMATICS FIGURE 9 added in Problem 2) the values 5 /2 + /0. It is not clear at this stage why he should have done this, for while 2 + /0 is equivalent to /3 + /5 3/5 25 + /5, the substitution does not make the summarion to a total of7 any easier, nor in fact does it 3/5 25 make it any more difficult [5]. We shall see later why the scribe preferred to use this alternative 3/5 5 5 form, but the change here made does not in any way alter the general thread of the working of the problem. In the division of seven loaves among ten 3/5 25 men, the scribe comes to his first chance to use the fraction 2/3 for which he has such a great propen- 3/5 5 5 sity [2]. And here it gets him into trouble, if we may use the phrase. His division results in seven 3/5 25 men getting two pieces, 2/3 and /30, while three men get three pieces, two equal pieces /3 each and one piece /30. This is shown in Figure 0. gets exactly the_ same portions, both in quantity FIGURE ro and numbers of pieces ofbread, whereas a modem 7 Loaves division would very likely be as shown in Figure 9. ~ In this case an apparent inequity is even more apparent, since six men each receive a single piece which is 3/5 of a!oat; and four men receive two unequal pieces each, one /5 of a loaf and the other 25 of a loaf. Problem4 Division of7loaves among 0 men. [Each man receives 23+ /30.] (From his reference table.) For proof multiply 2/3+ /30 by 0. [If] [part is] 2/3 + /30 [then] -./ 2 [parts are ] 3 + /5 " 4" 22/3+/0+/30 (From the Recto, 2 + 5 = /0 + /30.) -./ 8 5-/3 + /5 + /5 [Add the fractions on the lines with check marks.] Total 7loaves which is correct. 7menget 23 30 On the last line, in the R.M.P., the scribe has written instead of the simple 5 /3 + /5 + /5 (which together with the fractions /3 + /5 is exacdy the same as the fractions he has already 3 men get 3 3 30 40

PROBLEMS I TO 6 OF THE RHINO MATHEMATICAL PAPYRUS The scribe had at his disposal the simple division of each man getting /2 + /5, and the seven loaves could have been equally distributed with ouly 3 cuts instead of the 6 cuts required for the division which he recommends. It is just another illustration of the Egyptian's des~re to use the non unit fraction 2/3 wherever he possibly could. A modern division, the simplest I can think of, would give seven men each one portion of7/0 of a loaf; and the remaining three men would each receive three pieces, 3/0 of a loaf twice, and a smaller piece, /0 of a loaf. This is just about as complicated as the scribe's division, but would require only nine cuts. FIGURE II 8 Loaves Problem 5 Division of8loaves among 0 men. [Each man receives 2/3 + /0 + /30.] (From his reference table.) For proof multiply 2/3 + /0 + /30 by 0. [If] [part is] 2/3 + /0 + /30 [then] ~ 2 [parts are] + /2 + /0 (As in Problem 4 [6].) " 4 ~ 8 3+/5 6+ /3 + /5 (From the Recto, 2 + 5 = /3 + /5.) [Add the fractions on the lines with check marks.] Total 8 loaves which is correct. One notes that the summation of the fractions, here /2 + /0 + /3 + /5 =, is exacdy the same as the summation of the fractions /3 + /5 + /2 + /0 = in Problem 4, as the scribe wrote it. And now the efficacy of using this alternative form /2 + /0 instead of the conventional/3 + /5 + 5 becomes quite clear to us, and in the subsequent doubling, 3 + /5 is now much simpler that 2 + 2/3 + /3 + /5 + /0 + /30, and the next doubling is simplified as well. The division of eight loaves among ten men as the scribe directs is shown in Figure. Here seven men get three distinct portions, 2/3, /0, /30, and three men get four distinct portions, /3 and /3, 0, /30, which appear to ~ 7menget ~ 23 030 3 men get /3 /3 0 /30 be more or less identical if the two separate /3 pieces are kept together, and so again justice appears to have been done. A modem cutting up of loaves would result in eight men getting each 4/5 of a loaf in one piece, while the remaining two men get each four pieces, each /5 of a loaf; which might be construed as being inequitable. Problem 6 Division of9loaves among 0 men. [Each man receives 2/3 + /5 + /30.] (From his reference table.) For proof multiply 2/3 + /5 + /30 by 0. [If] [part is] 2/3 + /5 + /30 [then] ~ 2 [parts are]2/3 + /0 + /30 4

PART III/HUMAN IMPACT AND THE SOCIETAL STRUCTURING OF MATHEMATICS (i.e., /3 + /3 + /5 + /5 as before, = 2/3 + /0 + /30 from 2 + 5 in the Recto.) 4 3+2+/0[6) ~ 8 7/5 [Add the fractions on the lines with check marks.] Total 9 loaves which is correct. Again the use of the equivalent /2 + /0 instead of /3 + /5 + /5 leads to simpler answers, for 2/3 + /0 + /30 + /5 =, exactly as in Problem, and the scribe is to be commended on an elegant arithmetical solution. The division would be performed as in Figure 2, and the apparent equity of the shares is observable if the two separate /3 pieces are placed together to make 2/3. A modem distribution of nine loaves among ten men would result either in nine men receiving 2/0 of a loaf and the tenth man getting nine small pieces each /0 of a loaf, which would be clearly inequitable to the uneducated laborer, or in the ten men getting each /2 a loaf, and then eight of them receiving in addition 2/5 of a loaf while the remaining two men would get four small pieces each /0 of a loaf, which is even worse. As in Problem 4, the scribe had at his disposal simpler divisions in terms of unit fractions, as for example /2 + /5 + /0 for 8 + 0, and /2 + /3 + /5 for 9 + 0, but speculations on these dissections would not serve us. The simple fact is that the Egyptian scribe always preferred to use 2/3 if he could, and then by halving his answer to get /3 of a quantity, "an arrangement," as Neugebauer remarks, which is "standard even if it seems perfectly absurd to us [7]." Problems to 6 of the R.M.P. have had considerable interest for students of Egyptian mathematics, although I know of none who has looked at the practical aspect of the actual cutting up of the loaves, at least in publication. I quote from The Scientific American of952, "The Rhind Papyrus," by James R. NeW!nan, reprinted in The World rf Mathematics (New York: Simon & Schuster, Inc., 956), I, 73. Discussing the division of nine loaves among ten men, that is, Problem 6, Newman says: FIGURE I2 9 Loaves llllllllll 7menget 23 5 /30 3 men get 3 3 5 30 The actual working of the problem is not given. If 0 men are to share 9 loaves, each man, says A'h-mose, is to get 2/3 + /5 + /30 (i.e., 27/30) times 0 loaves (sic. [8]); but we have no idea how the figure for each share was arrived at. The answer to the problem (27/30, or 9/0) is given first and then verified, not explained. It may be, in truth, that the author had nothing to explain, that the problem was solved by trial and error-as, it has been suggested, the Egyptians solved all their mathematical problems. But of course we know how he would have obtained the values he gives in his table! The first part of the Recto of the R.M.P. is filled with 42

PROBLEMS I TO 6 OF THE RHINO MATHEMATICAL PAPYRUS examples of how he would do it. Chace (R.M.P., Vol., p. 23), for example, gives his methods for 2 and 7 divided by 0, but they are so simple from the scribe's point of view that he merely sets the answers down in order, without even a heading let alone any explanations. A'h-mose neither here nor elsewhere indulged in unnecessary detail or verbosity. He was writing a mathematical text! Having "no idea how the figure for each share was arrived at," as Newman puts it, is so far from the truth that I will set down here how the scribe could have performed the divisions of the numbers to 9 by 0. All that is necessary is to note that he performed division by continually multiplying the divisor until the dividend was reached, usually by doubling and halving, and of course taking 2/3 wherever possible [2]. I follow these by his abbreviated proofs as given in the R.M.P. (except, of course, those for 3, 4, and 5, which I reconstruct) so that one can see the order and regularity with which the Egyptian scribe sets down his work. It is a matter of wonderment to me that an Egyptian scribe could perform such arithmetical operations with the limited tools at his disposal. /0 /2 /0 ~2 /5 ~2 5 4 /3 /5 4 2/3 5 ~8 23 /0 /30 ~8 4 2/3 /0 /30 Total Total6 2 /5 2/3 /30 2 /3 /5 ~2 /3 /5 4 2/3 /0 /30 4 2 2/3 0 /30 ~8 /3 /5 /5 ~8 5 2 /0 Total2 Total 7 ~/0 Ans. /0 0 Ans. 0 ~/2 5 ~/0 /2 /0 6 /5 /0 2/3 /0 /30 ~2 /2 0 ~2 /2 /0 4 /5 4 3/5 ~8 2 /3 /5 ~8 6 /3 /5 Total3 TotalS /0 ~/5 Ans. /5 0 2 2 Ans. 0 ~2/3 6 2/3 ~/30 /3 2/3 /30 7 /3 /5 2/3 /5 /30 ~ 2 2/3 /0 /30 ~2 2/3 /0 /30 4 /2 /0 4 3 /2 /0 ~8 3 /5 ~8 7/5 Total4 Total9 ~/0 ~/5 Ans. /0 /5 0 2 3 Ans. 0 ~ 2/3 6 2/3 ~/0 ~/30 /3 2/3 /0 /308 /2 ~ 2 4 2 ~ 8 4 Total 5 2/3 ~ /3 ~/5 Ans. /3 /5 Ans. 0 6 2/3 3/3 2/3~ 4 ~/2 /2 Ans. 0 ~ 2/3 6 2/3 ~/5 2 ~ /30 /3 2/3 /5 /30 9 0 5 5 SUMMARY OF THE SCRIBE'S ADDITION OF UNIT FRACTIONS From the Recto of the RMP. 2 +5" /3 /5 2 + 5 " /0 /30 2/3 5 /0 /30 = **Written probably as 3 30 /3, meaning that, since 3 X 0 30, then /30 X 0 /3, and hence 5 X 0 2/3. Problem + 0 " (2/3 5 /0 /30) " 43

PART III/HUMAN IMPACT AND THE SOCIETAL STRUCTURING OF MATHEMATICS Problem2 2 + 0 = /3 /3 /5 /5 /5 = 2/3 /5 (2+ 5) = (2/3 /5 /0 /30) = 2 3 + 0 = /3 2/3 /3 /5 /5 /0 5 /5 /30 = 2 /3 (2+5)/0 /5 /5 /30 = 2 /3 (/3 /5) /0 /5 /5 /30 = 2 2/3 (/5 /5 /5) /0 /30 = 2 (2/3 /5 /0 /30) = 3 4 + 0 = 22/3 2/3 /3 (/0 /0) /5 (/30 /30) = (2 2/3 /3) 2/3 /5 /5 /5 = 3 2/3 /5 (2+5) = 3 (2/3 /5 /0 /30) = 4 5 + 0 = 4 = 5 Problem] 6 + 0 = 4 (2/3 /5 /0 /30) = 6 Problem4 7 + 0 = 5 (/3 /3) /5 (/5 /5) = 6 2/3 /5 (2 + 5) = 6 (2/3 /5 /0 /30) = 7 Problem5 8 + 0 = (6) /2 (/3 /0 /5) =7/22=8 Problem 6 9 + 0 = 7 (2/3 /5 /0 /30) = 9 A dispassionate view of this array of unit fractions, with its order and symmetry, and indeed its elegance and simplicity (if one considers the mathematical issues involved), leaves one with a feeling of hopeless admiration and wonderment at what was achieved by the Egyptyian scribe with the rudimentary arithmetical tools at his disposal. NOTES. Following the nomenclature of Chace, Bull, Manning, The Rhz'nd Mathematical Papyrus (Oberlin, Ohio: Mathematical Association of America, 929). 2. See Gillings, ''The Egyptian 2/3 table for fractions," Australian journal of Science, XXII (December, 959), 247. 3. It is convenient to use the plus sign at this stage. The Egyptian scribe had no such notation; mere juxtaposition indicated addition. I also use the signs = and + which also do not have equivalents in the RM.P., although in the Egyptian Leather Roll "' meaning "this is," is repeatedly used. 4. See Gillings, "The division of2 by the odd numbers 3 to 0 from the Recto of the R.M.P. (B.M. 0058)," Australian journal of Science, XVIII (October, 955), 43-49. 5. The scribe is familiar with many alternatives evident throughout the R.M.P., and he uses the values 7 + 0 = /2 + /5 in Problem 54, while in his table, and in Problem 4, he uses 7 + 0 = 2/3 + /30. 6. Here again the scribe writes /2 + /0 as equivalent to /3 + /5 + /5, both arising from the multiplication of2/3 + /0 + /30 by 2. In Problem 4, the scribe does not have any further doubling, so that there is little advantage in using the shorter form there. Thus 2(2/3 + /0 + /30) = 2 + /3 + /5 + /5 = 3 + (/3 + /5 + /5) = 3 + /2 + /0. 7. 0. Neugebauer, The Exact Sciences in Ant quity (Princeton, N.J.: Princeton University Press, 952), p. 76. 8. An error. "Times 0 loaves," should read "of one loa " 44