Summer MA Lesson 19 Section 2.6, Section 2.7 (part 1)

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Summer MA 100 Lesson 1 Section.6, Section.7 (part 1) I The Domain of a Function Remember that the domain is the set of x s in a function, or the set of first things. For many functions, such as f ( x, x could be replaced with any real number to find f ( x ). Therefore the domain could be written in set-builder notation as { x x is a real number} or (, ) using interval notation. However, not all functions have domains that are all real numbers. In real life examples, the domain is often limited to numbers that only make sense. For example, if d 0t (distance in miles equals 0 times time in hours), the time can only be 0 or positive numbers. No one would travel negative hours. So the domain would be { t t 0} or [0, ). Examine the following two functions. f( 4 x g( x If x is replaced with a in function f, the result would be 1. While we ve discussed imaginary numbers, when speaking of domains, we only think of real numbers. So we know is not in the domain of f. How do we find the domain? We know that we can only take the square root of a positive number or zero. Therefore 4 x must be greater than or equal to zero. 4 x 0 x 4 The domain of f is { x x 4} or (,4]. x 4 In function g, if x is replaced with, the result would be, which is an undefined 0 number. is not in the domain of function g. We can write the domain as { x x is a real number and x } or (,) U (, ). The above examples illustrate the problems you will encounter possibly when determining domain of functions. Otherwise the domain of functions will probably be all real numbers. 1. If the function has a square root, set the radicand greater than or equal to zero and solve. The result is the domain.. If the function has a denominator, set the denominator to zero and solve. The number(s) that result(s) are excluded from the domain. 1

Ex 1: Find the domain of each function. Write each using set-builder notation and interval notation. a) f( x + x b) g( x+ c) h( x x x+ 6 II The Algebra of Functions Functions can be combined using addition, subtraction, multiplication, or division on the right sides of two given functions. The domain of the function that results will be all real f ( numbers common to both original domains and, in case of, numbers that do not gx ( ) make a zero denominator. Here are the definitions of these functions given two functions f ( and g( x ). 1. Sum Function: ( f + g)( f( + g( Basically, you are. Difference Function: ( f g)( f( g( adding, subtracting,. Product Function: ( fg)( f( g( multiplying, or dividing f f( the function values or y 4. Quotient Function: ( values. g g( Ex : Given: f ( x 4x + and g( x 4, find the following functions. State the domain of each. a) ( f + g)( b) ( g f)( f c) ( g d) ( gf)(

Ex : Given: f ( x + and g( x +, find the following function values. a) ( f + g)() b) ( f g)(8) g c) (10) f f d) ( ) g Note: In the case of the quotient function, determine the domain before trying to simplify the quotient. f( x 4 g( x+ f f( x 4 ( x+ )( x ) ( x g g( x+ x+ While the domain of expression x would be all reals, you must consider there was a denominator and x. The domain of the quotient function is (, ) U (, ). Ex 4: Use the following graph to find ( f + g)( ), ( fg)(), and ( f g)().

III Composite Functions There is another way to combine functions called a composition of the functions. A good way to illustrate this type of function is the following. Suppose that a store is having a sale. There is a computer that regularly cost $600 on sale for $100 off. However, they are also offering a discount of 10% off (pay 0%), even on sale items. So, first $100 is subtracted from the computer, then 0% of that price if determined. If x could be thought of as the price of the computer... original price: P( x 100, then sale price: S(P()0.0(P() 0.0(x 100). Essentially, one function value is put into a second function. The Composition of Functions: The composition of the function f with g is denoted by f o g and is defined by ( f o g)( f( g( ). The domain of the composite function f o g is the set of all x such that 1. x is in the domain of g and. gx ( ) is in the domain of f. For ( f o g)( f( g( ) gx ( ) is called the inner function and f ( x ) is the outer function. The following picture illustrates the composition of two functions. f o g g f x g ( f ( g( ) Domain of g Range of g Range of f Domain of f 4

Ex : Given: f ( x, g( x x, and h( a) ( f o g)( ) x, find the following values. b) ( go f)( ) c) ( go h)(4) ( ho g) d) (1) To find the domain of a composite function f o g, ask yourself these questions? What is the domain of g( (inner function)? For which of these numbers would gx ( ) be in the domain of f? Ex 6: Find the composite functions ( f og)( and ( g o f )( and the domains of the composite functions given... a ) f ( x + 1, g( x + b ) f ( x 4, g( x

c ) f ( x, g( x + IV Decomposing Functions Suppose could write hx ( ) ( ) + x. This function takes + x and raised it to the cube power. We hx f gx f g x f x x gx x ( ) ( ( )) ( o )( ) where ( ) and ( ) +. Ex 7: Find two functions f and g, such that hx ( ) ( fo g)( for the functions below. Note: f is the outer function and g is the inner function. a) h( 8x 1 b) h( (x+ ) c) h( x 4 ) ( ) d h x x+ 6

V Inverse functions These equations represent inverse functions. Examine the temperature formulas below. C ( F ) F C + Replace F in the first equation with 0º. C (0 ) C (18) C 10 Now, replace C in the second with 10º. F F F (10) + 18 + 0 Notice these functions do opposite things. The first equation turned 0 F to 10 C. The second equation turned 10 C back to 0 F. Such functions are called inverse functions. Here are two other functions that are inverses of each other. x y x + and y Notice that in the first function a number is multiplied by, then is added to the result. In the second function is subtracted from a number, then divided by. Begin with as the number in the first function. Multiply by, and then add ; the result is 1. Now, let 1 be the number in the second function. Subtract, divide by ; the result is (the original number selected for the first function). x Let the first equation above be f( x+ and the second be g(. Examine: x x f ( gx ( )) f + x + x x+ x g( f( ) g(x+ ) x The composition of two inverse functions of x will always be x! 7

VI Verifying Inverse Functions As demonstrated above, when two functions are inverses of each other, their composition functions (both f ( gx ( )) and g( f( ) equal x. To verify (or prove) that two functions are inverses, find both compositions and show they equal x. Ex 8: Determine if the following functions are inverses of each other. x a) f( 4x+, g( 4 x 1 1 b) f( +, g( x x + 1 1 c) f(, g( x+ 1 x + 1 8