Announcements. 1.) The X-mas exam date has been finalized for December 17 th 9 am 12:00 pm. Room to be announced.

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Announcements 1.) The X-mas exam date has been finalized for December 17 th 9 am 12:00 pm. Room to be announced. 2.) This is the week of November 12 th to 16 th : Group 1 is doing the Gases tutorial while Group 2 is doing the Molar Volume lab 1 Again, the cell potential does not tell you the rate of the chemical reaction. Battery makers for automobiles aim for the largest number of Cold Cranking Amps, a measure of how many Coulombs per second can be produced To recharge the battery, the products of the discharge needs to be converted back to starting materials (electrolytic cell) Cathode E o red = -0.36 V PbSO 4 (s) + 2e- Pb(s) + SO 4 2- Anode E o ox = -1.69 V PbSO 4 (s) + 2H 2 O PbO 2 (s) + 4H+ 2e - + SO 4 2- Cell notation: PbSO 4 PbO 2 PbSO 4 Pb Note that in recharge mode (electrolytic cell) the anode and cathode have switched places! Nonetheless, the anode is always the electrode where oxidation occurs E o cell -2V, which indicates the reaction is not spontaneous (expected). Therefore to recharge we must apply an external voltage of at least 2 V to force this undesirable reaction to occur. When a redox reaction is driven by electricity, it is called electrolysis Recharging batteries is just one example of electrolysis but the principle is the same 2 1

Example: Industrial electrolysis of molten (not aqueous) NaCl to generate Na(s) + Cl 2 (g) A battery or power source drives the reaction. A small amount of CaCl 2 is also added to lower the melting point Anode: 2Cl - (l) Cl 2 (g) + 2e - Cathode: 2Na + (l) + 2e - 2Na(l) 3 Challenge for you: Calculate the minimum external voltage needed for this electrolysis Industrial problem: How do you keep Cl 2 (g) from reacting with the Na(s) product? The solution is a cell design that incorporates an inverted funnel to isolate the chlorine gas product ( Downs electrolysis cell) 4 2

Another question: Why use molten NaCl? Why not simply use NaCl dissolved in water? Electrolysis of NaCl in water results in the same oxidation of Cl - to Cl 2, but H 2 O is reduced much more readily than Na + Anode: 2Cl - (aq) Cl 2 (g) + 2e - Possible cathode reactions: 2Na + (aq) + 2e - 2Na(s) 2H 2 O + 2e - H 2 (g) + 2OH - E o red = -2.71 V E o red = -0.83 V reduction of water is much more favourable No Na(s) is formed but that is not so bad because Cl 2, H 2, and NaOH are industrially important. Therefore, the electrolysis of salt water is important 5 Electrolysis cell for this purpose: 6 3

4. Quantitative Analysis In redox reactions, electrons are formed or consumed in stoichiometric ratios. The amount of electrons can be measured by moles or by charge (Coulombs) 1 mole e - = 96480 Coulombs ( Faraday s constant) However, physicists, electricians, and engineers usually measure electric current instead of electrons 1 ampere (A) = 1 Coulomb per second Thus, it is possible to express A in terms of electrons: 1 mole e - = 96480 V 1.036 x 10-5 mol e - = 1 C 6.240 x 10 18 e - = 1 C (using Avogadro number) that is; 1 A = 6.240 x 10 18 e - per second 7 Take home exercise: Calculate how many electrons go through your toaster if it draws 10 A of electricity for 4 minutes. Since redox reactions are stoichiometric it should be possible to calculate how much electric current and what length of time is necessary for a particular reaction Example: Aluminium smelters in Canada electrolytically produce Al metal using a molten mixture of Al 2 O 3 and Na 3 AlF 6. 8 4

Cathode: Al 3+ + 3e - Al(l) Anode: C(s) + 2O 2- CO 2 (g) + 4e - The production of 1 mole Al requires 3 mole e -, so it is possible to calculate the Coulombs needed and CO 2 emissions (knowing the voltage): Current: 1 A = 1 C s -1 Voltage: 1 V = 1 J C -1 Power: 1 W (Watt) = 1 J s -1 Energy: 1 J = power x time = V x C Process is energy intensive and environmentally unfriendly. 9 Example based on #20 of the November 2006 exam. In the silver button cell which generates 1.50 V, the overall cell reaction is Zn(s) + Ag 2 O(s) + H 2 O(l) Zn(OH) 2 (s) + 2Ag(s) Suppose that a small cell of this type contains 0.200 g Ag 2 O which is the (expensive) limiting reagent. Assuming the cell provides a current of 1.00 x 10-6 A, how many hours could the cell operate? The number of moles of Ag 2 O = 0.2/MM = 231.8 gmol -1 =0.00086 mol. Balanced reduction half reaction: Ag 2 O + 2H + + 2e - 2Ag + H 2 O Q reducing one Ag 2 O requires 2 e - s, the reaction requires 2 x 0.00086 mol =0.00172 mol e - The number moles of electrons consumed = 0.00172 mol x 96490 C mol-1 = 165.96 C t = 165.96C/10-6 A = 1.66 x 10 8 s = 4.61 x 10 4 hr = answer E. 10 5

Thermochemistry C020 11 ENERGY When molecules react, there are energy changes, and energy can be released or consumed Energy can appear and be measured as either: Work: the ability to move a mass through a distance or Heat: increased molecular velocities, usually measured as temperature The SI unit of energy is the joule, J Note: 4.184 J = 1 calorie Not to be confused with 1 Calorie = 1000 calories Specific Heat defined as the amount of heat required to raise 1 gram of a substance 1 degree K; units: Jg -1 K -1 Examples Water Specific Heat = 4.184 Jg -1 K -1 Fe Specific Heat = 0.451 Jg -1 K -1 Glass Specific Heat = 0.84 Jg -1 K -1 By knowing the specific heat of a substance one can calculate the amount of heat required to raise a substance from one temperature to a higher one 12 6

Related to specific heats is a substance s heat capacity, C where the amount of material; that is the mass is not factored in. Units = JK -1 The heat capacity is the amount of energy required to raise the system by 1 K. For example, C(H 2 O) = 4.184 JK -1 Heat capacity C = mass x specific heat 13 Heat changes due to Phase Changes Heat energy may be used not only to change the temperature of a system but also to cause phase changes at constant temperature These are called latent heats 14 7