Study on Thermal Load Calculation for Ceiling Radiant Cooling Panel System

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Study on Thermal Load Calculation for Ceiling Radiant Cooling Panel System Sei Ito, Yasunori Akashi, Jongyeon Lim Shimizu Corporation, Tokyo, Japan University of Tokyo, Tokyo, Japan Abstract The ceiling radiant cooling panel (CRCP) system affords a comfortable environment for occupants with reduced cooling energy consumption. However, it seems that the thermal load calculation for CRCP systems is unconfirmed. Therefore, this study was conducted to propose a thermal load calculation method for the CRCP system based on the thermal network simulation model using Nets. The case study results show that the cooling load on the CRCP system is higher than the general air conditioning system because the CRCP removes not only the room s cooling load but also the ceiling plenum s cooling load. Finally, this study clarifies the necessity of considering the ceiling plenum when calculating the thermal load for the CRCP system. Introduction Energy conservation technology has been in high demand regarding efforts to realize (net) zero-energy buildings (ZEB). Ceiling radiant cooling panel (CRCP) systems represent a key energy conservation technology that can yield high efficiency, since it uses moderately chilled water ( C) and does not require energy to propel a fan to remove the cooling load. Generally, a CRCP system provides a high degree of comfort to occupants because it does not induce any draughts. There are several examples of CRCP system applications, however it seems that the thermal load calculation for CRCP systems is unconfirmed. The design procedure for the CRCP system described in the ASHRAE handbook (ASHRAE ()) shows how to determine a CRCP specification that satisfies the design conditions. However, the method of determining the design condition, i.e. the thermal load, was not referenced in the design procedure. Previous research (J. Feng (3)) compared the sensible cooling load for a radiant system calculated using the heat balance (HB) method with one using the radiant time series (RTS) method. They concluded that the HB method was more accurate than RTS in terms of calculating the thermal load for a radiant system. However, the target system in the previous study was limited to radiant systems without ceiling plenums, such as a radiant cooling panel with insulation on the panel, an embedded surface cooling system and a thermally activated building system. Therefore, this study was conducted to propose a proper method of calculating the thermal load for a CRCP system with a ceiling plenum. This study uses the thermal network model simulation program Nets (H. Okuyama (999)); a form of HB. This paper has three sections: () Evaluation of Nets, () Modeling method for a ceiling radiant model, and (3) Case study of thermal load calculations for CRCP systems. In the first section, comparative testing, namely the ASHRAE Standard - (ASHRAE ()) is conducted for Nets. Also, AS is used to compare the simulation program with the standard building simulation tools to evaluate the validity of Nets. The second section presents the results of the experiment to evaluate the heat transfer phenomena in the CRCP system, as well as determine the thermal conductivity of the CRCP. The necessity to consider not only the influence of cooling load caused by the room, but also the plenum, is shown. Furthermore, we identified thermal conductivity between chilled water and the CRCP surfaces. Therefore, these values are available for the simplified CRCP modeling method for the thermal network model. The third section presents a case study that was conducted to clarify the difference between the thermal load calculation for the CRCP system and the general airconditioning system. Finally, this study shows the necessity of a thermal load calculation for the CRCP system. Evaluation of simulation program Outline of Nets simulation program Figure shows an example model of Nets. The model is constructed to simulate air, surface and solid temperatures of the building with a single room and an airhandling unit. The thermal network model consists of nodes and thermal resistances connecting each node. There are three types of node: () thermal mass node is Ceiling W indow RA SA Slab AHU : Thermal resistance (Conduction, Radiation, Convection) : Thermal resistance (Advection) : Thermal mass node : Surface node : Fixed temperature Node Figure : Network model in Nets San Francisco, CA, USA, Aug. 7-9, 7 555 https://doi.org/./57.7.

Annual Cooling Load[MWh] Annual Heating Load[MWh] Annual Heating Load[MWh]...5.7 set as the heat capacity of each material, which enables the inside of the material to be calculated, () surface node is set as the surface and border of materials, which should be set in order to calculate the surface and border temperature of materials properly, and (3) fixed temperature node is set as a boundary condition, such as weather data. There are four types of thermal resistance: () conduction, () convection, (3) radiation, and () advection. Heat balance equations for each node are determined using this modeling. Therefore, each node temperature is calculated by solving the equations. Simulation case based on AS For the purpose of evaluating the validity of Nets, comparative testing was conducted as per the ASHRAE Standard - (AS) (ASHRAE ()). AS was developed to validate the building energy simulation program, determined in many test cases. The building models for the test cases are very simple, as shown in Fig. for example. The calculated results of many simulation programs are prepared for comparison with the results calculated by the target program. Then the target program can be validated comparatively. In this study, basic tests were conducted on the building thermal envelope and fabric load for Nets. Table 5 shows the input conditions for the test cases. The variable input parameters are window orientation, sunshade, heat capacity and the thermal insulation performance of 3 the building. Table : Building conditions for test cases Low mass basic test Heavy mass basic test Case Sunshade Case Sunshade south - 9 south - south Overhang 9 south Overhang east, west - 9 east, west - 3 east, west Overhang Overhang 93 east, west Fin Fin south - 9 south - 5 south - 95 south - Table : Control strategies for test cases Case Heating Cooling Ventilating,,, :~: :~: :~: 3, 9, 9, 9, 93 < C: on Otherwise: off >7 C: on Otherwise: off Off 3:~7: :~: :~: < C: on >7 C: on Off, 9 Otherwise: off Otherwise: off 7:~3: < C: on Otherwise: off :~: :~: :~7: 5, 95 Off >7 C: on Otherwise: off On 7:~: Off Table shows the thermostat control strategies for the test cases. It is assumed that the control strategies for Cases,,, 3, 9, 9, 9 and 93 are continuous operation, Cases and 9 are thermostat 7 7 5 3..5 3.. 3..5 Unit: m Figure : Isometrics for Case Plan Figure 3: Thermal network model for test case Figure : Annual heating and cooling load setback and Cases 5 and 95 are night ventilation respectively. A thermal network model was developed for Nets to meet the building conditions of the test cases as shown in Fig. 3. In addition to these conditions, operational conditions were set to meet control strategies of the test cases. Then heating and cooling loads are calculated using the models for each case. Evaluation results Figure shows the results for all cases calculated by Nets. The annual heating and cooling loads are within the range of results calculated by other programs. Therefore, Nets is shown to be valid as a thermal load calculation tool. N Ground Elevation ESP BLAST DOE SRES/SUN SERIRES S3PAS TRNSYS TASE Nets 3 5 9 9 39 93 9 95 5 5 3 5 3 9 9 9 93 9 95 San Francisco, CA, USA, Aug. 7-9, 7 55

Heat flux, Load [W ] 57 Modeling method for ceiling radiant panel Fundamental experiment for CRCP A fundamental experiment was conducted to understand how the CRCP removes the cooling load and to identify the thermal conductivity of the CRCP. Figure 5 shows the device for the fundamental experiment. In order to simulate the actual build environment of the CRCP system, an insulated box was divided into two chambers: a room and plenum chamber. The CRCPs, as shown in Fig., were set between the two chambers and assumed to be the actual ceiling. The CRCP is composed of an aluminum punched panel, metal-reinforced polyethylene pipes and heat sinks. The heat sink promotes heat transfer between the chilled water in the pipe and the panel surface. The chilled water was supplied by the water chiller to keep the water temperature within certain parameters. There were heating elements in each chamber to simulate the actual cooling load in the room and plenum. Water chiller 5 Ceiling plenum chamber Corrugated plastic 7 chamber 5 Heating element Ceiling radiant panel 3 Numeric values show inside dimensions Figure 5: Experimental device 77 53 Heating element Units: mm No. Supply water temp. Table 3: Experimental patterns Flow rate [L/min] chamber temp. Cooling load distribution rate (plenum : room) :. : 3 : Items Air temp. Panel surface temp. Water temp. Radiant heat flux Flow rate Heating value of heating element Table : Measurement items Sensor Number of measurement points : 3 Type T thermocouple : 3 side: side: 3 Platinum resistance thermometer (Inlet, outlets of each panel) Net pyrradiometer : : Electromagnetic flow meter Watt meter : : Table 3 shows the conditions for the experimental patterns. The supply water temperature and flow rate were fixed and the cooling load was adjusted in order to bring the air temperature of the room chamber to C. Table shows the measurement items for the experiment. In order to clarify the convection heat flux from the CRCP, air and panel surface temperatures were measured in detail. The radiant heat flux was measured directly using a net pyrradiometer. The outlet water temperatures of each panel were measured to confirm each panel s removed cooling loads. Results of CRCP heat balance analysis Figure 7 shows the heat flux measurement results for the experiment. The values of a in Fig. 7 indicate the heat flux from the walls including the heating element to the CRCP surfaces. This a is composed of four parts: () Metal-reinforced polyethylene pipe (diameter mm) Heat sink (width mm) 57 Punched panel (pore size: mm@5.5mm) Figure : Detail of ceiling radiant cooling panel 5 5 Radiant room Radiant Advection room Cooling load room Removed by chilled water Convection room Convection Conduction Cooling load plenum a b c d a b c d a b c d : : : Cooling Load distribution rate (: ) Figure 7: Heat flux measurement results q tra q bp q pas q ras q br q ad q pw Figure : Heat balance diagram for CRCP system San Francisco, CA, USA, Aug. 7-9, 7 557

q pw /L p [W/m] radiant heat flux from room surfaces except the CRCPs to the room-side surface of the CRCPs, () convective heat flux from the room air to room-side surface of the CRCPs, (3) radiant heat flux from the plenum surface except the CRCPs to the plenum-side surface of the CRCPs, and () convective heat flux from the plenum air to plenum-side surface of the CRCPs. The radiant heat fluxes are measured directly using a net pyrradiometer. The convective heat flux was calculated from the convective heat transfer coefficient obtained by Wilkes experiment (G. B. Wilkes (93)). The equation for the convective heat flux is as follows: q q ras, c r, cs p ra () rs ras c p cs p pa (),, ps. 7 r, c 5.9. (3) ra rs p, c. () The value of b in Fig. 7 shows the heat flux, which contributes to removing the cooling load in the room chamber. The equations for the advection and conductive heat transfers from room to plenum are as follows: q ad = ρ ac aq a (θ ra θ pa), (5) q tra = K cs c (θ ra θ pa). () The Q a in Equation (5) was measured using the tracer gas method. The value of c in Fig. 7 shows the cooling load, which consists of the room and plenum cooling loads. The value of d in Fig. 7 indicates the amount of cooling load removed by chilled water in the pipe as calculated by the followed equation: q pw = ρ wc wq w (θ pw,out θ pw,in). (7) The results can be explained by the following equations: q ras + q pas =q br+q bp =q pw (i.e. a = c =d) () q pas + q tra + q ad = q br (i.e. b =q br) (9) Equation () represents the general heat balance relation, and previous CRCP modeling methods are based on this equation (ISO (), M. Shioya (3), ()). Equation (9) shows that not only the heat flux from the roomside CRCP surface, but also the ceiling plenum air, contribute to removing the cooling load in the room. These results show that not only the heat balance represented by Equation () should be considered, but also Equation (9) to correctly solve the thermal environment for the CRCP system. Determination of thermal conductivity of CRCP Figure 9 shows the CRCP modeling method in this study. Using the thermal network modeling approach, the heat capacities of the materials used in the CRCP are set as nodes. Furthermore, thermal resistance connects each node. A detailed model, as shown in Fig. 9(a), is the thermal network model. A simplified model, as shown in Fig. 9(c), can be obtained by contracting the detailed model. The simplified model consists of three nodes and thermal resistance, and enables the thermal load calculation for the CRCP system to be simplified. The thermal conductivities for CRCP, K r and K p, are determined by the following equation: q pw/l p = K r (θ rs θ pw)+ K p (θ ps θ pw). () Metal-reinforced polyethylene pipe Contact thermal resistance Aluminum heat sink Aluminum punched panel (a) Detailed model contract w R rs ps (b) Sub-simplified model for identifying R contract w K p K r rs ps K rps (c) Simplified model Figure 9: Modeling method for CRCP Measurement data Calculated data q pw /L p [W/m] q pw /L p [W/m] θ sr θ w,ave θ sp θ w,ave Figure : Identification of thermal conductivity for CRCP San Francisco, CA, USA, Aug. 7-9, 7 55

where θ pw = (θ pw,out θ pw,in)/ A sub-simplified model in Fig. 9(b) allows the thermal conductivity to be determined using the experimental data. Thermal resistance such as for the pipe, heat sink and panel can be set from data in existing literature. On the other hand, the contact thermal resistance between the pipe and heat sink, R, is unknown and should be determined experimentally. The sub-simplified model enables the relationship between K r and R, and between K p and R, to be revealed. The following equations represent these relationships: K r = /(a rr + b r ) () where a r = 7.7, b r =., K p = /(a pr + b p ) + /c p () where a p =., b p =.3, c p =.5 Equations () and () were substituted for Equation (), and R was identified by nonlinear regression analysis to fit the experimental data. The analysis results are as follows: R =.995 (3) K r =.5 () K p =. (5) Figure shows a comparison between the experimental data and data calculated using the identification results of K r and K p. Each value of Equation () is plotted on a three-dimensional scatter diagram. The z-axis is the left side of Equation () while the x- and y-axes are the temperature differences between the surface and water. The calculated data is shown to correspond with the experimental data. Case study of thermal load calculation A case study is conducted by comparing the thermal load, which is calculated using the simulation model based on the CRCP system, against one calculated using the model based on a conventional airflow system: a constant air volume (CAV) system. This chapter shows the modeling specifications. Modeling specifications Since the objective of the case study is to understand the cooling load difference between a CRCP system and an airflow system, a representative single-zone model is adequate. The wall and fenestration specifications of the model are almost the same as Case 9 under AS except for changes noted as follows: Weather data: Expanded AMeDAS Weather Data (Sampling Period: 99-) (Meteorological Data System (3)) Region: Tokyo Simulation period: July st 3 st Operation time schedule: :-: Controlled object: () air temperature () operative temperature (OT) Figure : Case study model for CRCP system Table 5: Simulation case No. Case HVAC Controlled name system object. CAV-A CAV. RAD-A CRCP Air temperature 3. CAV-O CAV Operative. RAD-O CRCP temperature A A Conduction heat transfer resistance Ceiling Plan Plan The OT is assumed using the following equation: OT = (θ ra+mrt)/ () F i i i CRCP (size:..) 3 panels Ground Building model Based on Case 9 under AS Figure : Thermal network model for CRCP system MRT (7) Temperature set point: C Calculation interval: 5 min Ceiling:. m-high ceiling and.5 m-high plenum zone HVAC system: () Constant air volume (CAV) system () Ceiling radiant cooling panel (CRCP) system It is assumed that the CRCP, which is evaluated in the previous chapter, is installed on a. m-high ceiling as.5. CRCP model Unit: m A-A Section Plan Section San Francisco, CA, USA, Aug. 7-9, 7 559

Temp. [ C] Cooling Load [kw] Temp. [ C] Temp. [ C] Temp. [ C] Cooling Load [kw] Cooling Load [kw] Cooling Load [kw] shown in Fig.. Table 5 shows the simulation cases for the case study. CRCP load calculation method The model to calculate the thermal load of the CRCP system (CRCP case model) is constructed on the basis of the experimental results shown in the previous chapter. The experimental data indicated that plenum air contributed to removing the cooling load in the room chamber. Therefore, the plenum zone and the thermal resistance between the room and the plenum are constructed in the model, as shown in Fig.. Then the model could consider the conduction heat transfer between the plenum and room zone. In order to simulate the heat transfer between chilled water and the CRCP surface, the simplified model shown in the previous chapter is introduced. Therefore, the thermal conductivities between chilled water and CRCP surfaces, as obtained in the experiment shown in the previous chapter, are set as the CRCP model s thermal resistances. Twelve circuits of panels were assumed to be installed in the model, with three sequentially connected panels in each circuit, as shown in Fig.. Therefore, there are three simplified CRCP models for each panel and each panel is connected through advection conduction heat transfer by the water flow. Then the chilled water circulation is modeled. Average surface temperatures for three panels are set in the room and plenum sides of the CRCP surfaces, as shown in Fig. 3. CRCP operation conditions are noted as follows: Chilled water flow rate:. l/min for circuits (. l/min for one circuit, which is the same condition as the experiment shown in the previous chapter.) Thermostat control strategy: The inlet chilled water temperature, which is shown by the chilled water inlet node in Fig. 3, was adjusted by a proportional-integral-derivative (PID) controller in order to bring the room air temperature or OT to the set point at a constant chilled water flow rate. CAV load calculation method The model to calculate the thermal load of the CAV system (CAV case model) is constructed by adding the air-handling unit (AHU) to the CRCP case model shown in the previous section. The thermal network to simulate circulation of the CAV system is shown in Fig.. The AHU consists of the AHU zone node and advection heat transfer resistance. The supply air was assumed to have been introduced by a diffuser in the room, and the return air extracted from the room through an outlet installed in the plenum via openings in the ceiling except for the CRCPs. In order to set the same conditions for thermal resistance as the CRCP pattern, it is assumed that a CRCP is installed in the CAV case model, but chilled water does not circulate in the CRCP. CAV operation conditions are noted as follows: Supply air volume: 7 m 3 /h Thermostat control strategy: The supply air temperature, which is indicated by the supply air node in Fig., is adjusted by the PID controller in order to Chilled water inlet Panel surface on plenum side Panel surface on room side Figure 3: CRCP model for thermal load calculation Ground Supply air node CRCP model AHU Section Figure : Thermal network model for general air conditioning (CAV) system without water flow to CRCP 3 : MRT: Cooling Load: CAV RAD CAV RAD OT: : 3 3 3 3 7: 7: : : 3: 3: : : 9: 9: 7: : 3: : 9: Figure 5: Temperature and cooling load for Case CAV-A vs. Case RAD-A on July 9 th 3 7: : 3: : 9: Figure : Temperature and cooling load for Case CAV-O vs. Case RAD-O on July 9 th (same legend as Fig. 5) San Francisco, CA, USA, Aug. 7-9, 7 5

bring the room air temperature or OT to the set point at a constant supply air volume. Case study results and discussion Air temperature distribution and cooling load Figures 5 and show the trends in the thermal environment and cooling load calculated by the simulation model for each case on the actual day when the average temperature of the day is at its maximum during the simulation period. The trends for controlled objects (room air temperature in Cases CAV-A and RAD-A, OT in Cases CAV-O and RAD-O) are kept constantly at the set point except for the rise time in each case. It seems reasonable to suppose that the PID parameters for each case were set appropriately. Figure 5 shows a comparison of temperatures and cooling load between Cases CAV-A and RAD-A. The trends for room air temperatures, MRT and OT, in Case RAD-A are almost C. The thermal environment is also kept uniform. From these results, it seems that the simulation model can simulate the characteristics of a CRCP system appropriately. On the other hand, the trends for room air temperatures, MRT and OT in Case CAV-A, vary quite considerably between C and 3 C. Meanwhile the plenum air temperature is lower in Case RAD-A than in Case CAV-A. The reason for this phenomenon can be explained by the fact that the CRCP not only cools the room space, but also the plenum space. It seems reasonable to suppose that these two differences between RAD-A and CAV-A were because the cooling load is higher in Case RAD-A than in Case CAV-A. Figure shows a comparison in the temperatures and cooling load between Case CAV-O and Case RAD-O. These cases were conducted in order to keep the general air-conditioning system, i.e. CAV system, in the same thermal condition as the CRCP system. Therefore, the operative temperature was used as a control object in these cases. The results for Case RAD-O are almost the same as RAD-A, thanks to the small difference between the air temperature and MRT. The room air temperature is cooled to C in Case CAV-O in order to keep the OT at C. As a result, the cooling load is higher in Case CAV-O than in Case CAV-A. However, the cooling load is lower in Case CAV-O than in Case RAD-O. A previous study showed that the cooling load for the CRCP system is higher than a general air-conditioning system, because of the direct radiant exchange between the CRCP and the cooling load (F. Bauman (3)). The same results are obtained in this study. Further discussion about why the cooling load for the CRCP system is higher than a general air-conditioning system will be presented in the following sections. Heat flux distribution on room surfaces Figure 7 shows the conduction transfer heat flux distribution on room and plenum surfaces in the case study. The heat flux is an integrated value during the operational time on July 9 th. Heat flux values on room walls are higher in the CRCP system than in the air-conditioning system. These results can be explained by the increased radiant heat transfer between the CRCP and other surfaces. As for the plenum heat flux, the same results are obtained. It is clear from these results that the CRCP is cooling the plenum zone. The heat flux directions on the ceiling of the CRCP cases are opposite to the CAV cases. These results show that the model can simulate the contribution of plenum air to removing the room-cooling load. Cooling load classification analysis Figure shows the results of cooling load classification analysis. These values indicate where the cooling load comes from. The summation of heat fluxes from room surfaces to room air is equal to the cooling load of the general air-conditioning system. Then, the summation of heat fluxes from the room surfaces except the CRCP surface and room and plenum air to the CRCP surface is equal to the cooling load of the CRCP system. The results show that the room-cooling load removed by the CRCP is lower than the general air-conditioningsystem-cooling load under the same thermal conditions (i.e. Case CAV-O). On the other hand, the entire cooling load removed by CRCP is higher than that removed by the general air-conditioning system (Case CAV-O) due to heat flux from plenum space. Consequently, it is concluded that the thermal load calculation for the CRCP system should consider the influence of the plenum space in the building..9..5..9.. 3.7....9.9.. 3...9..9.... CAV-A RAD-A CAV-O RAD-O day Unit: kw h Heat flux Figure 7: Heat flux classification analysis on July 9 th San Francisco, CA, USA, Aug. 7-9, 7 5

[kwh] 3 X: Ceiling Equipment Air filtration Floor Wall CRCP contribution to room side X: air Roof wall Equipment Air filtration air Floor Wall From X to room air From X to ceiling surface From X to room air From X to ceiling surface CAV-A RAD-A CAV-O RAD-O X: Ceiling Equipment Air filtration Floor Wall CRCP contribution to room side X: air Roof wall Equipment Air filtration air Floor Wall Figure : Cooling load classification analysis on July 9 th Conclusion This study proposed a thermal calculation method for the CRCP system by validating the Nets simulation program, investigating the influence of the plenum space on removing the cooling load in a room in the CRCP system using a fundamental experiment, and simplified the CRCP by using the thermal network approach. Furthermore, this study clarifies the difference in the thermal load between the CRCP and the general air-conditioning system using case study models based on the simplified model. The cooling load of the CRCP system is shown to be higher than the general air-conditioning system due to the influence of the plenum, even with the same thermal conditions. Finally, it is concluded that in order to consider the thermal load for the CRCP system, one must consider not only the room, but also the influence of the plenum space in the building. Nomenclature q ras,c q pas,c : Convective heat flux from room air to roomside surface of the CRCP [W/m ] : Convective heat flux from plenum air to plenum-side surface of the CRCP [W/m ] S p : Area of CRCP [m ] α r,c α p,c θ ra θ pa θ rs θ ps q ad : Convective heat transfer coefficient of room side-surface of CRCP [W/m K] : Convective heat transfer coefficient of plenum side-surface of CRCP [W/m K] : air temperature : air temperature : -side surface temperature of CRCP : -side surface temperature of CRCP : Heat flux by advection between room and plenum [W/m ] Q a q tra K c : Circulation air volume between room and plenum [m 3 /s] : Conduction heat flux on ceiling except CRCP [W/m ] : Thermal conductivity of the ceiling except CRCP [W/m K] S c : Space of the ceiling except CRCP [m ] q pw : Cooling capacity of CRCP [W/m ] q ras q pas L p K r K p K srp θ pw θ pw,out θ pw,in R OT MRT F i θ i : Heat flux from room space to room-side surface of CRCP [W/m ] : Heat flux from plenum space to plenum-side surface of CRCP [W/m ] : Length of CRCP pipe [m] : Thermal conductivity between room-side surface of CRCP and water in CRCP pipe [W/mK] : Thermal conductivity between plenum-side surface of CRCP and water in CRCP pipe [W/mK] : Thermal conductivity between room-side surface of CRCP and plenum-side surface of CRCP [W/mK] : Average water temperature in CRCP pipe : Outlet water temperature of CRCP : Inlet water temperature of CRCP : Thermal resistance between pipe and heat sink [mk/w] : Operative temperature : Mean radiant temperature : View factor between room center and room surface of plane i [-] : surface temperature of plane i San Francisco, CA, USA, Aug. 7-9, 7 5

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