Version : 1.0: General Certificate of Secondary Education November Higher Unit 2. Final. Mark Scheme

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Transcription:

Version : 1.0: 11.11 General Certificate of Secondary Education November 2011 Mathematics Higher Unit 2 43602H Final Mark Scheme

Mark schemes are prepared by the Principal Examiner and considered, together with the relevant questions, by a panel of subject teachers. This mark scheme includes any amendments made at the standardisation events which all examiners participate in and is the scheme which was used by them in this examination. The standardisation process ensures that the mark scheme covers the students responses to questions and that every examiner understands and applies it in the same correct way. As preparation for standardisation each examiner analyses a number of students scripts: alternative answers not already covered by the mark scheme are discussed and legislated for. If, after the standardisation process, examiners encounter unusual answers which have not been raised they are required to refer these to the Principal Examiner. It must be stressed that a mark scheme is a working document, in many cases further developed and expanded on the basis of students reactions to a particular paper. Assumptions about future mark schemes on the basis of one year s document should be avoided; whilst the guiding principles of assessment remain constant, details will change, depending on the content of a particular examination paper. Further copies of this Mark Scheme are available from: aqa.org.uk Copyright 2011 AQA and its licensors. All rights reserved. Copyright AQA retains the copyright on all its publications. However, registered schools/colleges for AQA are permitted to copy material from this booklet for their own internal use, with the following important exception: AQA cannot give permission to schools/colleges to photocopy any material that is acknowledged to a third party even for internal use within the school/college. Set and published by the Assessment and Qualifications Alliance. The Assessment and Qualifications Alliance (AQA) is a company limited by guarantee registered in England and Wales (company number 3644723) and a registered charity (registered charity number 1073334). Registered address: AQA, Devas Street, Manchester 5 6EX.

UMS conversion calculator www.aqa.org.uk/umsconversion The following abbreviations are used on the mark scheme: M M dep A B ft SC [a, b] Method marks awarded for a correct method. A method mark which is dependent on a previous method mark being awarded. Accuracy marks awarded when following on from a correct method. It is not necessary always to see the method. This can be implied. Marks awarded independent of method. Follow through marks. Marks awarded for correct working following a mistake in an earlier step. Special Case. Marks awarded for a common misinterpretation which has some mathematical worth. Or equivalent. Accept values between a and b inclusive. 3

UNIT 2 HIGHER TIER 43602H 1 5(2 9 6) or 5(18 6) or 5 18 5 6 or 12 or 90 30 or 60 their 60 4 or 5 3 or 5 3 1 or 15 1 dep 15 Their 60 can come from only one error 2a 2.56 B1 2b 81.92 B1 3 Any three of a = 2, b = 5 a = 7, b = 2 a = 7, b = 11 a = 11, b = 3 B3 B1 for each correct pair SC1 if no other marks scored for: a = 3, b = 3 (same numbers) a = 3, b = 19 (prime > 12) Listing all primes less than 12 ie 2, 3, 5, 7, 11 Listing the square numbers (1, 4,) 9, 16, 25 4 60 seen B1 their 60 20 their 60 or 48 eg 80 their 60 Yes and 48 seen ft Using 70 and getting 56, hence no scores 56 with no conclusion is A0 SC1 for 12 and Yes 5 6x 2 (=) 2x 6x 2x = 2 or 4x = 2 dep 1 2 Alternative method Input > 0.5 with correct output Input < 0.5 with correct output 0.5 4

6 20 7.50 or 150 their 150 5 or 30 dep Attempt at 429 their 30 or a multiple of their 30 immediately above or below 429 dep 14.3 or 15 (weeks) Alternative method 1 7.50 5 or 1.50 Multiple of their 30 must be correctly evaluated 15 from division (if used) with no errors SC2 for 15 weeks with no working their 1.50 20 or 30 Attempt at 429 their 30 or a multiple of their 30 immediately above or below 429 dep dep 14.3 or 15 (weeks) Alternative method 2 Multiple of their 30 must be correctly evaluated 15 from division (if used) with no errors SC2 for 15 weeks with no working 20 5 or 4 (hours) their 4 7.50 or 30 Attempt at 429 their 30 or a multiple of their 30 immediately above or below 429 dep dep 14.3 or 15 (weeks) Multiple of their 30 must be correctly evaluated 15 from division (if used) with no errors SC2 for 15 weeks with no working 5

7 240 12 (= 20) 15 their 20 + their 20 or 23 8 their 23 184 Correct conclusion from their working with all calculations shown Alternative method 1 Q1 Strand (iii) dep on all M marks and working seen The students have saved enough 240 12 (= 20) their 20 8 (= 160) 15 their 160 + their 160 184 Correct conclusion from their working with all calculations shown Alternative method 2 Q1 Strand (iii) dep on all M marks and working seen The students have saved enough 200 8 (= 25) Average amount saved per student 240 12 (= 20) 15 their 20 + their 20 25 and 23 Correct conclusion from their working with all calculations shown Alternative method 3 15 240 + 240 their 276 12 (= 23) or 23 eg 1.15 their 20 Q1 Strand (iii) dep on all M marks and working seen The students have saved enough or 276 eg 1.15 240 their 23 8 184 Correct conclusion from their working with all calculations shown Q1 Strand (iii) dep on all M marks and working seen The students have saved enough 6

8a y 11 B1 8b w 8 B1 8c y 2 = 3x or 3 y = x + 3 2 or 3x = 2 y y 2 3 = x or x = 2 y 3 SC1 for x = 2 y 3 or x = y + 2 3 9 2 parts = 10 marks A (= 5 parts =) 25 and B (= 3 parts =) 15 A = 25, B = 15, C = 32 Alternative method 1 Attempt to write equivalent ratios eg 10 : 6, 15 : 9 (A)25 : 15(B) 25 : 15 selected eg writing consecutive multiples 5, 10, 15, and 3, 6, 9, A = 25, B = 15, C = 32 Alternative method 2 m + 10 5 = m 3 m = 15, hence m + 10 = 25 A = 25, B = 15, C = 32 eg 5m = 3(m + 10) 10a m 2 + 4m B2 B1 for one term correct 10b 6y(2xy 1) B2 B1 for 6(2xy 2 y) or 3(4xy 2 2y) or 2(6xy 2 3y) or y(12xy 6) or 3y(4xy 2) or 2y(6xy 3) or 6y(??) eg 6y(2xy y) 7

11 3(2x 3) or 4(x 1) Denominator not necessary marks for numerator terms 6x 9 + 4x 4 dep allow one incorrect term their 10x 13 = 2 12 dep eg 20x 26 = 2 24 Do not allow their 10x 13 = 2 37 (x =) 3.7 or 10 All steps clearly shown with M3 awarded Q1 Strand (ii) 12a (n + a)(n + b) Where ab = ±6 (n + 1)(n + 6) 12b Sight of 11 16 11 2 2 2 2 ( 1) 11 2 4 Use of factor tree with one pair of factors of which one is prime or repeated division by primes 13 B or x + y 3 and D or 2y x + 4 B2 B1 for one correct and at most one incorrect 14 Gradient = 2 or y = 2x + c m = 2 earns this mark Substituting x = 250, y = 620 or x = 400, y = 920 dep c = 120 or C = (0, 120) D = ( 60, 0) Alternative method Sight of 150 and 300 or ratio 1 to 2 Finds an intermediate point between B and C eg (, 320), (200, 520) C = (0, 120) dep This point implies M2 D = ( 60, 0) 8

15a 15b 15c Add one more to both top and bottom or n + 1 + 1 = n + 2 n + 1 n n + 2 n + 1 n n + 1 or n +1 n + 2 Numerator of (n + 1) 2 n(n + 2) or n(n + 2) (n + 1) 2 n = 2 9 10 2 + 2n + 1 n 2n ( n + 1)( n + 2) 1 ( n + 1)( n + 2) 10 and 11 B1 B1 Denominator not necessary marks for numerator expression Numerator expansion clearly shown no terms missing or with incorrect signs since answer given Accept 9(th) and 10(th) terms 16 x 2 7x 7x + 49 ( a) or x 2 14x + 49 ( a) a = 14 b = 63 Alternative method Substitutes a value for x in the identity eg x = 1 gives b = 63 a = 14 b = 63 ft a = 14 from no working or an error in the number term of the expansion implies ft for b = 35 from a = 14, if M mark earned 17 (w 2 =) 162 or (h 2 =) 150 Allow for 81 2 25 6 12 2 3 B1 ft ft their 12 if possible 9

18 (x 3)(x 3) = x 2 3x 3x + 9 or x 2 6x + 9 x 2 8x 20 (= 0) (x 10)(x + 2) (= 0) Allow one error For expression of the form ax 2 + bx + c (= 0) Correct ft from their expansion If formula or completing the square used it must be correct x = 10, x = 2 for one correct (x, y) pair eg x = 10, y = 7 for a second correct (x, y) pair eg x = 2, y = 5 y = 7, y = 5 Alternative method y 2 = 2(y + 3) + 29 or y 2 2y = 29 + 6 y 2 2y 35 (= 0) (y 7)(y + 5) (= 0) SC2 for both correct (x, y) pairs by trial and improvement SC1 for one correct (x, y) pair by trial and improvement Allow one error For expression of the form ay 2 + by + c (= 0) Correct ft from their substitution and expansion If formula or completing the square used it must be correct y = 7, y = 5 for one correct (x, y) pair eg x = 10, y = 7 for a second correct (x, y) pair eg x = 2, y = 5 x = 10, x = 2 SC2 for both correct (x, y) pairs by trial and improvement SC1 for one correct (x, y) pair by trial and improvement 10