Auchmuty High School Mathematics Department Advanced Higher Notes Teacher Version

Similar documents
(n 1)n(n + 1)(n + 2) + 1 = (n 1)(n + 2)n(n + 1) + 1 = ( (n 2 + n 1) 1 )( (n 2 + n 1) + 1 ) + 1 = (n 2 + n 1) 2.

Solution to HW 3, Ma 1a Fall 2016

Motithang Higher Secondary School Thimphu Thromde Mid Term Examination 2016 Subject: Mathematics Full Marks: 100

Chapter Eight Notes N P U1C8S4-6

Permutations and Combinations

A proof of the binomial theorem

Chapter 3: Theory of Modular Arithmetic 38

Algebra. Substitution in algebra. 3 Find the value of the following expressions if u = 4, k = 7 and t = 9.

Physics 2A Chapter 10 - Moment of Inertia Fall 2018

Markscheme May 2017 Calculus Higher level Paper 3

3.6 Applied Optimization

2 x 8 2 x 2 SKILLS Determine whether the given value is a solution of the. equation. (a) x 2 (b) x 4. (a) x 2 (b) x 4 (a) x 4 (b) x 8

of the contestants play as Falco, and 1 6

Math 301: The Erdős-Stone-Simonovitz Theorem and Extremal Numbers for Bipartite Graphs

F-IF Logistic Growth Model, Abstract Version

Appendix A. Appendices. A.1 ɛ ijk and cross products. Vector Operations: δ ij and ɛ ijk

radians). Figure 2.1 Figure 2.2 (a) quadrant I angle (b) quadrant II angle is in standard position Terminal side Terminal side Terminal side

Δt The textbook chooses to say that the average velocity is

6 PROBABILITY GENERATING FUNCTIONS

Question 1: The dipole

working pages for Paul Richards class notes; do not copy or circulate without permission from PGR 2004/11/3 10:50

TANTON S TAKE ON CONTINUOUS COMPOUND INTEREST

Solutions to Problem Set 8

MATH 220: SECOND ORDER CONSTANT COEFFICIENT PDE. We consider second order constant coefficient scalar linear PDEs on R n. These have the form

1) (A B) = A B ( ) 2) A B = A. i) A A = φ i j. ii) Additional Important Properties of Sets. De Morgan s Theorems :

Practice Integration Math 120 Calculus I Fall 2015

5.61 Physical Chemistry Lecture #23 page 1 MANY ELECTRON ATOMS

The Substring Search Problem

Method for Approximating Irrational Numbers

CALCULUS II Vectors. Paul Dawkins

Practice Integration Math 120 Calculus I D Joyce, Fall 2013

On a quantity that is analogous to potential and a theorem that relates to it

ON INDEPENDENT SETS IN PURELY ATOMIC PROBABILITY SPACES WITH GEOMETRIC DISTRIBUTION. 1. Introduction. 1 r r. r k for every set E A, E \ {0},

Berkeley Math Circle AIME Preparation March 5, 2013

A generalization of the Bernstein polynomials

When two numbers are written as the product of their prime factors, they are in factored form.

Version 1.0. General Certificate of Education (A-level) June Mathematics MM04. (Specification 6360) Mechanics 4. Final.

Nuclear and Particle Physics - Lecture 20 The shell model

Section 8.2 Polar Coordinates

9.1 The multiplicative group of a finite field. Theorem 9.1. The multiplicative group F of a finite field is cyclic.

SUPPLEMENTARY MATERIAL CHAPTER 7 A (2 ) B. a x + bx + c dx

arxiv: v1 [math.co] 4 May 2017

A Bijective Approach to the Permutational Power of a Priority Queue

Numerical approximation to ζ(2n+1)

In statistical computations it is desirable to have a simplified system of notation to avoid complicated formulas describing mathematical operations.

Physics 505 Homework No. 9 Solutions S9-1

C/CS/Phys C191 Shor s order (period) finding algorithm and factoring 11/12/14 Fall 2014 Lecture 22

Chapter 6 Balanced Incomplete Block Design (BIBD)

763620SS STATISTICAL PHYSICS Solutions 2 Autumn 2012

Qualifying Examination Electricity and Magnetism Solutions January 12, 2006

Physics 121 Hour Exam #5 Solution

Related Rates - the Basics

As is natural, our Aerospace Structures will be described in a Euclidean three-dimensional space R 3.

Surveillance Points in High Dimensional Spaces

B da = 0. Q E da = ε. E da = E dv

Double-angle & power-reduction identities. Elementary Functions. Double-angle & power-reduction identities. Double-angle & power-reduction identities

18.06 Problem Set 4 Solution

Random Variables and Probability Distribution Random Variable

Physics 521. Math Review SCIENTIFIC NOTATION SIGNIFICANT FIGURES. Rules for Significant Figures

A Short Combinatorial Proof of Derangement Identity arxiv: v1 [math.co] 13 Nov Introduction

Σk=1. g r 3/2 z. 2 3-z. g 3 ( 3/2 ) g r 2. = 1 r = 0. () z = ( a ) + Σ. c n () a = ( a) 3-z -a. 3-z. z - + Σ. z 3, 5, 7, z ! = !

MASSACHUSETTS INSTITUTE OF TECHNOLOGY Physics Department Physics 8.07: Electromagnetism II September 15, 2012 Prof. Alan Guth PROBLEM SET 2

Lecture 8 - Gauss s Law

H.W.GOULD West Virginia University, Morgan town, West Virginia 26506

Phys 201A. Homework 5 Solutions

Graphs of Sine and Cosine Functions

A Hartree-Fock Example Using Helium

Voltage ( = Electric Potential )

ST 501 Course: Fundamentals of Statistical Inference I. Sujit K. Ghosh.

PDF Created with deskpdf PDF Writer - Trial ::

Class #16 Monday, March 20, 2017

Pascal s Triangle (mod 8)

Introduction and Vectors

EXTRA HOTS PROBLEMS. (5 marks) Given : t 3. = a + (n 1)d = 3p 2q + (n 1) (q p) t 10. = 3p 2q + (10 1) (q p) = 3p 2q + 9 (q p) = 3p 2q + 9q 9p = 7q 6p

New problems in universal algebraic geometry illustrated by boolean equations

Single Particle State AB AB

-Δ u = λ u. u(x,y) = u 1. (x) u 2. (y) u(r,θ) = R(r) Θ(θ) Δu = 2 u + 2 u. r = x 2 + y 2. tan(θ) = y/x. r cos(θ) = cos(θ) r.

Physics 11 Chapter 3: Vectors and Motion in Two Dimensions. Problem Solving

S7: Classical mechanics problem set 2

THE NUMBER OF TWO CONSECUTIVE SUCCESSES IN A HOPPE-PÓLYA URN

f h = u, h g = v, we have u + v = f g. So, we wish

arxiv: v1 [math.nt] 12 May 2017

On the ratio of maximum and minimum degree in maximal intersecting families

n 1 Cov(X,Y)= ( X i- X )( Y i-y ). N-1 i=1 * If variable X and variable Y tend to increase together, then c(x,y) > 0

A Relativistic Electron in a Coulomb Potential

Physics 161 Fall 2011 Extra Credit 2 Investigating Black Holes - Solutions The Following is Worth 50 Points!!!

7.2. Coulomb s Law. The Electric Force

Australian Intermediate Mathematics Olympiad 2017

HOW TO TEACH THE FUNDAMENTALS OF INFORMATION SCIENCE, CODING, DECODING AND NUMBER SYSTEMS?

PROBLEM SET #1 SOLUTIONS by Robert A. DiStasio Jr.

Many Electron Atoms. Electrons can be put into approximate orbitals and the properties of the many electron systems can be catalogued

On the Quasi-inverse of a Non-square Matrix: An Infinite Solution

Hopefully Helpful Hints for Gauss s Law

Research Design - - Topic 17 Multiple Regression & Multiple Correlation: Two Predictors 2009 R.C. Gardner, Ph.D.

Solutions to Problems : Chapter 19 Problems appeared on the end of chapter 19 of the Textbook

Exploration of the three-person duel

0606 ADDITIONAL MATHEMATICS 0606/01 Paper 1, maximum raw mark 80

Current Balance Warm Up

Compactly Supported Radial Basis Functions

Math Section 4.2 Radians, Arc Length, and Area of a Sector

Transcription:

The Binomial Theoem Factoials Auchmuty High School Mathematics Depatment The calculations,, 6 etc. often appea in mathematics. They ae called factoials and have been given the notation n!. e.g. 6! 6!!!!! We also define 0! Combinatoics- Pemutations and Combinations Suppose you ae asked to pick diffeent numbes between and. Thee ae 0 ways of doing this:,,,,,,,,,, The ode in which we pick the numbes is not impotant,,,, e.g.,, is the same as,,.,, This is called a combination.,, It is a selection without aangement.,, n Combinations use the notation n C o, whee you ae selecting components fom a total of n. Fomula n C n!! n!

Auchmuty High School Mathematics Depatment In the above example we ae selecting things fom. This is C o C!! 0 0!!!! 6. Lean how to calculate n! and n C on you calculato. If the ode (aangement) of the numbes is impotant this is a diffeent calculation. Suppose we ae selecting diffeent numbes fom whee the ode does matte. This time thee ae going to be moe possibilities.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,. and so on. Thee ae 60 possibilities altogethe. Think of it like this:- Fo the fist numbe thee ae choices,,, o. Fo the second numbe thee ae choices as you have used one numbe aleady. Fo the thid numbe thee ae choices as you have used numbes aleady. So in total you have 60 possibilities. is the same as doing!! This is known as a pemutation when aangement is impotant. It is denoted n P. Fomula n P n! n! In the above example!! 0 P 60.!!

Auchmuty High School Mathematics Depatment Pemutations ae not pat of the Advanced Highe couse but have been mentioned hee to fom a complete pictue and fo those who will study futhe mathematics. We will concentate on n C. Example people have to be selected fom 8 to fom a committee. How many ways ae thee to do this? 8 7 6 670 This is the same as calculating 8 7 6 8!.! But this includes all the possible aangements. Aangements don t matte hee so we need to divide by! as this is the numbe of ways things can be aanged. 8! So we have!!. It is easie to use ou fomula : Example How many ways can I place discs into empty boxes? C!! 0 0!!!! 6 NB This is also the same as placing empty boxes in. C!! 0 0!!!! 6 This implies that C C o. 8 C 8 8! 8! 00 6! 8!!! 06 Example How many diffeent ways can you place swimmes in 8 lanes? 8 C 8 8! 8! 00 6! 8!!! 60

This is the same as placing gaps in 8 lanes. 8 C 8 8! 8! 00 6! 8!!! 06 So 8 C 8 C o 8 8. Auchmuty High School Mathematics Depatment n n The geneal esult is n Poof n n! n n! n n! n!! n n! n! n!! Pascals Tiangle 6 0 0 Notice that the esults fom combinations occu in Pascal s tiangle. 0 0 0 0 0 0 etc.

Auchmuty High School Mathematics Depatment Fom the tiangle we can see anothe esult: ( n ) + (n ) = (n + ) Poof n n n! n!! n!! n! n! n!!!!! n n n! n! n! n!! n! n! n! n! n! n! n! n! n! n! n! n!! n! common denominato of n since n n n!!!! n as equied. Question fom the 00 pape equied a woking of this poof:- n n n Show that n n n! n!! n!! n! n! n! n n!!!!

Auchmuty High School Mathematics Depatment n! n! n! n!! n! common denominato of! n! n! n! n! n! n n! n! n! n! since n! n n! n! n n! n! n!! n! n!! n! n as equied. Questions Given that 0 (a) 6 0, 0 0 0 and 0 7 0 0 (b) (c) 8 wite down the value of Find (a) 8 (b) (c) 6 (d) Find anothe n C equivalent to (a) 6 (b) (c) 9 (d) 0 Wite down in n fom (a) 8 8 6 (b) (c) (d) 8 8 8 9 6

Auchmuty High School Mathematics Depatment Equations n Suppose we know that. Can we solve this fo n? n n!! n! n! n! n n! n n n n 0 n n0 0 n 6 n 0 n 6 o n n6, n n 66. What is the value of n? n 66 n! 66! n! n! n! n n! 66 n n 66 n n n n 0 n n 0 n o n n, n 7

Auchmuty High School Mathematics Depatment Solve fo n. n n 8 n n n n 8 using n! 8! n! n nn! n!! 8 n n 6 n n6 0 n 7 n8 0 n 7 o n 8 n7, n Questions n Find the value of n, n. (a) 0 n (b) 6 n (c) 0 n n Solve (a) (b) n n 66 n n (c) 90 The Binomial Theoem The Binomial Theoem helps us to multiply out backets which we would othewise have to complete longhand. x y x xy y x y x y x xy y x x y xy y x y x y x x y xy y x x y 6x y xy y Look at the coefficients and compae with Pascal s Tiangle. 6 x y coefficients of x y coefficients of x y coefficients of 8

Auchmuty High School Mathematics Depatment n So the coefficients ae the same as o n C and ae known as the binomial coefficients. x y x y x y x y xy x y 0 x y x y x y x y x y x y x y 0 So 0 0 0 0 In geneal n n n 0 n n n n n n n 0 n x y x y x y x y xy x y 0 n n fo x, y, n This is known as The Binomial Theoem. n n n n It can also be witten as x y x y fo n,. 0 n n The geneal tem of the expansion is given by x y. n You may choose to use Pascal s tiangle o AH level, Pascal s tiangle is usually sufficient. to find the coefficients it s up to you. At Examples x y x y x y x y x y x y x y 0 0 0 x x y 0x y 0x y x y y Be caeful when thee ae coefficients within the backet! 6 x y x x y x y x y y 6x x y x y 8xy y 9

x y x x y xy y Auchmuty High School Mathematics Depatment x 9x y 7xy 7y a b a a b 0a b 0a b ab b 0a 80a b 760a b 0a b 60ab b Questions Expand using the binomial theoem: (a) x y 7 (b) a b 6 (c) x y 6 (d) a b (e) x y Examples involving negatives and factions Exta cae must be taken hee! x y x x y 6x y xy y x x y 6x y xy y x y x x y xy y 8x x y 6xy y x y 6 x 6x y x y 0x y x y 6x y y 6 6 79x 96x y 860x y 0x y 60x y 76xy 6y 6 6 x x x 6x x y y y y y x 6x x x y y y y 0

Auchmuty High School Mathematics Depatment x x x 0x 0x x y y y y y y x 0x 0x x x y y 8y 6y y x x x x x y y y 6y y 6 x y 6 6 6 x 6x x 0x x 6x y y y y y y 6 76x 60x 0x 860x 96x 79 6x 6 y y y y y y 7 x x x x 0x 0x x x x x x x 80x 080x 70x 0x x x x x x x 70 0 x x x x 80x 080x 8 x y x x y 6x y x y y x x y x y 08x y 8y 8 6 Questions Expand using the binomial theoem. (a) x y (b) 6x y (c) y x (d) a b 6 (e) a b 6 (f) a b (g) x y (h) 6 x x

Finding a Paticula Tem Auchmuty High School Mathematics Depatment You may be asked to find a paticula tem in an expansion o obtain its coefficient. This can be done by completing a whole expansion and picking out the equied tem but this can be time consuming and aithmetical eos ae moe likely to occu. n n n n It helps if you emembe the geneal fomula x y x y fo n,. 0 Examples Find the coefficient of the xy tem in the expansion of x y 7. Fo xy, n 7,, n. 7 The tem is x y x y coefficient Find the coefficient of the xy tem in the expansion of x y 6. Fo xy, n 6,, n. 6 The tem is x y 6x y 0x y coefficient 0 Find the tem independent of x in the expansion of Tem independent of x equies n 0,, n x x. 0 x x. 0 The tem is x x x 806 x

Auchmuty High School Mathematics Depatment Find the x tem in the expansion of x tem equies x x. n 6,, n 6 x 6 6x x 80x The tem is x Questions 6 x x. Find the coefficient of the Find the coefficient of the xy tem in the expansion of x y 6. x. 9 x tem in the expansion of Find the y tem in the expansion of y. y Find the tem independent of y in the expansion of Find the tem independent of a in the expansion of 8 y. y 9 a a. Witing down the Geneal Tem in an Expansion Remembe the geneal tem of the expansion of x y n n is given by x Examples Wite down and simplify the geneal tem in the expansion of x x. Hence o othewise obtain the tem in x. 0 x 0 0 x x 0 0 x 0 0 so tem is x x The th tem is given by x 0 0. n 0 y.

Auchmuty High School Mathematics Depatment Wite down and simplify the geneal tem in the expansion of Hence o othewise obtain the tem independent of x. 9 x x. The th tem is given by 9 9 0 9 x x 9 9 x x 9 9 9 x x 9 9 9 x 9 9 76. so tem is 6 6 Questions Wite down and simplify the geneal tem in the expansion of Hence o othewise obtain the tem in 0 x. Wite down and simplify the geneal tem in the expansion of Hence o othewise obtain the tem independent of x. 8 x x. x x. Applications of the Binomial Theoem We can use the binomial theoem to tackle othe types of poblems. Using the binomial theoem find 0 0 0 0. 0 0 6 0 0 0 0 0 0 008 000 00000 0 0000006 086 Using the binomial theoem find 06 0 06. 0 0 0 08 0 06 0 6

Expand x y x y Auchmuty High School Mathematics Depatment The tick hee is to notice it s a diffeence of squaes. x y x y x yx y x y Now use the binomial theoem. x x y x y y x x y x y y 6 6 Questions Calculate (a) 0 (b) 98 (c) 99 Expand the following (a) a b a b (b) a b a b (c) y y x x

Auchmuty High School Mathematics Depatment Past Pape Questions 00 A6 Expand 00 Q x x, x 0 and simplify as fa as possible. ( maks) Obtain the binomial expansion of a. ( maks) 007 Q Expess the binomial expansion of fo integes a, b, c, d and e. x x in the fom d e ax bx c x x ( maks) 008 Q8 Wite down and simplify the geneal tem in the expansion of x x. Hence o othewise, obtain the tem in x. (, maks) 009 Q8 (a) Wite down the binomial expansion of x. (b) Hence show that 09 is 0 909. (, maks) 0 00 Q Show that n n n whee the intege n is geate than o equal to. ( maks) 0 Q Use the binomial theoem to expand x and simplify you answe. ( maks) 0 Q Wite down and simplify the geneal tem in the expansion of Hence, o othewise, obtain the tem independent of x. 9 x x. (, maks) 6

Auchmuty High School Mathematics Depatment 0 Q Wite down the binomial expansion of x x and simplify you answe. ( maks) 0 Q Wite down and simplify the geneal tem in the expession Hence, o othewise, obtain the tem in x 0 Q Use the binomial theoem to expand and simplify 0 x x.. ( maks) Show that n n n x. ( maks) x, fo all integes, n, whee n. ( maks) 06 Q Wite down and simplify the geneal tem in the binomial expansion of x x. Hence, o othewise, find the tem in x 9. ( maks) 07 Q Wite down the binomial expansion of ( y y) and simplify you answe. ( maks) 7