Dr.Salwa Alsaleh fac.ksu.edu.sa/salwams

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Transcription:

Dr.Salwa Alsaleh Salwams@ksu.edu.sa fac.ksu.edu.sa/salwams

Lecture 5 Basic Ideas of Statistical Mechanics General idea Macrostates and microstates Fundamental assumptions A simple illustration: tossing coins Simple paramagnetic solid: the statistics of exceedingly big numbers Gaussian Distribution 2

Statistical Mechanics: why? We want to describe/explain/predict the properties of systems containing unimaginably large numbers of objects (eg ~10 23 atoms in a typical lump of solid material Impossible to do this in terms of the equations of motion of individual particles: there are just far, far, too many. Two approaches: Not to worry about microscopic behaviour, just consider relationships between macroscopic variables.thermodynamics Try to understand macroscopic behaviour on the basis of the averaged microscopic behaviour of the particles, using the laws of statistics..statistical Mechanics (But you should think of these as complementary, rather than competing approaches: see later) 3

Macrostates & Microstates Definitions Macrostate (macroscopic state): A state of a system described by a set of macroscopic variables, eg sample of gas in a container with a fixed pressure, volume, temperature and pressure. (In fact, any macrostate can be specified by the internal energy (E), volume (V), number of particles (N) and appropriate parameters to take account of external influences (eg magnetic, electric fields)). Microstate (microscopic state): A particular arrangement of the microscopic constituents of a system. For example, a specification of the positions and momenta of all the atoms or molecules of the above gas. 4

Fundamental Assumption of Statistical Physics All accessible microstates of a given system are equally likely to occur The most probable macrostate is the one with the most microstates. 5

Statistical Weight, or Multiplicity The number of microstates corresponding to a given macrostate is called the STATISTICAL WEIGHT or MULTIPLICITY of the macrostate Usually given the symbol A given macrostate is often defined by having some number n particles with a particular state or configuration out of a total number of N particles Number of microstates then given by the number of ways of selecting these n particles from the total set of N particles: ( n ) n C N ( N N! n )! n! (2-state system) 6

Illustration of concepts: tossing coins Consider, for example, a set of 4 coins, each of which can be tossed to give a head or a tail : Head Tail The set of coins has five possible macrostates : 4 heads 4 tails 3 heads, 1 tail 3 tails, 1 head 2 heads, 2 tails 7

4 heads (4H) macrostate 1 microstate ( (4) = 1) 4 tails (4T) macrostate 1 microstate ( (0) = 1) 8

3 heads, 1 tail (3H1T) macrostate 4 microstates ( (3) = 4) 9

3 tails, 1 head (3T1H) macrostate 4 microstates ( (1) = 4) 10

2 heads, 2 tails (2H2T) macrostate 6 microstates ( (2) = 6) 11

Probability Probability of an event occurring = number of ways the event can occur total number of possible outcomes Probability of a given macrostate M occurring is given by: Total number of microstates for all possible macrostates of a 2-state (binary) system of N particles 12

(n h ) Tossing coins : effect of increasing N (n h ) N=4 N=10 1.60E+008 1.40E+008 1.20E+008 1.00E+029 N=30 N=100 8.00E+028 1.00E+008 8.00E+007 6.00E+028 6.00E+007 4.00E+028 4.00E+007 2.00E+007 2.00E+028 0.00E+000 0 5 10 15 20 25 30 Number of heads (n h ) 0.00E+000 0 10 20 30 40 50 60 70 80 90 100 Number of heads (n h ) 13

As N gets bigger, the probability of observing a deviation from the most likely macrostate (n h =n t =N/2) gets smaller How small does the probability of deviation get for REALLY big numbers, eg number of atoms in a macroscopic solid??? Can t evaluate numerically for N>~100: so try to derive an analytical expression.. Investigate this by taking our first look at the simple paramagnetic solid. 14

Simple Paramagnetic Solid (SPS) In an SPS, each atom or molecule of the solid behaves like a microscopic magnetic dipole (bar magnet). Dipoles are assumed to be independent of one another. Because of quantization of orbital angular momentum (spin) of electrons, dipoles have only 2 possible orientations with respect to an externally applied magnetic field (B): up (parallel to field direction) or down (antiparallel to field direction). At very low temperatures, all dipoles are aligned with field direction ( ); as temperature is increased, thermal energy of crystal randomises the dipole orientation, so we have some aligned up (N ) and some aligned down (N ). Consider hight, low B limit: randomising effect of temperature far outweighs alignment effect of field. 15

High B, low T B Moderate B, T B 16

Low B, high T B 17

Simple Paramagnetic Solid (SPS) To evaluate the number of microstates for a given number of up dipoles (N ) in a total number N we use the standard formula Because we want to work large numbers, it s convenient to use logs We also make use of Stirlings approximation: for large x: ln( x!) x lnx x 18

ln(x) Stirling s Approximation ln(n!) = ln2 + ln3 + ln4 +.. ln(n-1) + ln(n) 3.0 2.5 2.0 Ln(x) Consider, eg N=20 (opposite) 1.5 1.0 0.5 0.0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 X Total area of strips total area under curve y = ln(x) (1 x 20) ln( N!) N ln( N ) N 19

Taylor Expansion Series converges for a <1 20

Simple Paramagnetic Solid: Gaussian Distribution ( N,0) ( N, S ) 2 S 2N e S N = 10 10 Define half width of the distribution from the value of S at which falls to 1/e of its maximum value This is when S 2 = 2N, ie S = (2N) 1/2 So, fractional width of distribution is given by: S 1 ~ N N 21

Simple Paramagnetic Solid: Gaussian Distribution ( N,0) ( N, S ) 2 S 2N e S 1 ~ N N 22

Simple Paramagnetic Solid: Some conclusions We ve considered the case for the weak field, high temperature limit, where thermal energy of crystal completely randomises dipole orientation, or (see later to deal with the situation where ordering due to magnetic field is significant) As expected, the most likely configuration is with equal numbers of dipoles up and down Key point is that this is OVERWHELMINGLY more probable than any other configuration Fractional fluctuations away from N = N = N/2 are exceedingly small, ~ 1/ N ~10-11 for N = 10 22 So, for systems with numbers of particles on this scale, the most likely macrostate (the one with the most microstates), is an entirely well defined, stable thermodynamic state. 23