Exam 1, Ch September 21, Points

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Chem 130 Name Exam 1, Ch 1-4.2 September 21, 2018 100 Points Please follow the instructions for each section of the exam. Show your work on all mathematical problems. Provide answers with the correct units and significant figures. Be concise in your answers to discussion questions. Part 0: Warmup. 4 points each 1. Which of the following aspects of Dalton s atomic theory remains unchanged in our current understanding: a. Atoms are indivisible. b. All atoms of a particular element are identical. c. Compounds are the result of a combination of two or more different kinds of atoms in fixed ratios. d. None of the above. 2. Which of the elements below DOES NOT exist naturally as a diatomic molecule? a. hydrogen b. helium c. nitrogen d. chlorine Answer Answer 3. An atom of sodium contains 11 protons, 11 electrons and 12 neutrons. Adding the masses of all of the protons, neutrons and electrons in a sodium atom will produce a value that is a. equal to the true mass of a sodium atom. b. greater than to the true mass of a sodium atom. c. less than to the true mass of a sodium atom. d. eleven times the true mass of a sodium atom. Part I: Complete all of problems 4-10 Answer 4. Gallium is solid at 20 o C. There are 1.16 x 10 21 atoms in 134 mg of gallium at this temperature. Above 30 o C, gallium melts (it melts in your hand!). How many atoms are there in 134 mg of gallium at 40 o C? Briefly justify your answer. (4 points) 5. When it ionizes, does aluminum tend to form anions or cations? What is the charge on the ion? Briefly justify your answer. (4 points) 1

6. Complete the following table. (12 points) Symbol 56 Fe 3+ # of protons 34 48 # of neutrons 45 64 # of electrons 48 Charge -2 Name 7. Name the following compounds or provide the correct formula for the given names. (16 points) a. Mo(NO 3) 4 b. B 2Br 4 c. (NH 4) 2S d. Na 2CO 3 10H 2O e. xenon hexafluoride f. magnesium perchlorate g. chromium (VI) cyanide h. strontium hydroxide 8. The atomic mass of fluorine is 18.998 amu and all fluorine atoms in a naturally occurring sample of fluorine have this mass. The atomic mass of chlorine is 35.453 amu, but no chlorine atoms in a naturally occurring sample of chlorine have this mass. Explain this observation. (8 points) 2

9. Write balanced reactions, specifying the state for all reactants and products. (8 points) a. Al(s) + KOH(aq) + H 2O(l) KAl(OH) 4(s) + H 2(g) (2 points) b. BCl 3(l) + H 2(g) B(s) + HCl(g) (2 points) c. Aqueous potassium carbonate reacts with aqueous iron (III) nitrate to produce aqueous potassium nitrate and solid iron (III) carbonate. (4 points) 10. A brand new penny is 19.05 mm in diameter and 1.52 mm thick and is 97.5% zinc and 2.5% copper by mass. Assuming the penny has the same density as zinc (7.13 g/cm 3 ), how many zinc atoms are in a new penny? You may assume the penny is a cylinder with a volume of πr 2 h, where π = 3.14159, r is the radius and h is the thickness.(8 points) 3

Part II. Answer three (3) of problems 11-14. Clearly mark the problem you do not want graded. 10 points each. 11. Glucose, C 6H 12O 6, is used as an energy source by the human body. The overall reaction in the body is described by the unbalanced equation below. If 55.5 grams of glucose is converted to CO 2, what mass of oxygen gas is required? What mass of water is produced? C 6H 12O 6 (s) + O 2(g) CO 2(g) + H 2O (l) Answers 12. There are two isotopes of boron, 10 B (atomic mass 10.01294 amu) and 11 B (atomic mass 11.00931 amu). What are the percent abundances of each of the two isotopes? 4

13. Isobutylene contains only carbon and hydrogen and is an important industrial chemical used in the production of a variety of products, ranging from antioxidants to polymers. Combustion of 1.00 grams of isobutylene results in the production of 3.14 grams of carbon dioxide and 1.28 grams of water. If the molar mass of isobutylene is 56.106 g/mol, what is its molecular formula? 14. A compound that contains only potassium, chromium and oxygen was analyzed. If was found that the compound contained 26.58% potassium and 35.45% chromium by mass. What is the formula for this compound? 5

Possibly Useful Information % by mass= g component 100 g sample d = m/v NA = 6.022 x 10 23 To save some calculation time, you may round all atomic masses to two (2) decimal points. 6