AP PHYSICS 2011 SCORING GUIDELINES (Form B)

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AP PHYSICS 2011 SCORING GUIDELINES (Form B) General Notes About 2011 AP Physics Scoring Guidelines 1. The solutions contain the most common method of solving the free-response questions and the allocation of points for this solution. Some also contain a common alternate solution. Other methods of solution also receive appropriate credit for correct work. 2. Generally, double penalty for errors is avoided. For example, if an incorrect answer to part (a) is correctly substituted into an otherwise correct solution to part (b), full credit will usually be earned. One exception to this may be cases when the numerical answer to a later part should be easily recognized as wrong, e.g., a speed faster than the speed of light in vacuum. 3. Implicit statements of concepts normally earn credit. For example, if use of the equation expressing a particular concept is worth one point, and a student s solution contains the application of that equation to the problem but the student does not write the basic equation, the point is still earned. However, when students are asked to derive an expression it is normally expected that they will begin by writing one or more fundamental equations, such as those given on the AP Physics exam equation sheet. For a description of the use of such terms as derive and calculate on the exams, and what is expected for each, see The Free-Response Sections Student Presentation in the AP Physics Course Description. 2 4. The scoring guidelines typically show numerical results using the value g = 9.8 m s, but use of 2 10 m s is also acceptable. Solutions usually show numerical answers using both values when they are significantly different. 5. Strict rules regarding significant digits are usually not applied to numerical answers. However, in some cases answers containing too many digits may be penalized. In general, two to four significant digits are acceptable. Numerical answers that differ from the published answer due to differences in rounding throughout the question typically earn full credit. Exceptions to these guidelines usually occur when rounding makes a difference in obtaining a reasonable answer. For example, suppose a solution requires subtracting two numbers that should have five significant figures and that differ starting with the fourth digit (e.g., 20.295 and 20.278). Rounding to three digits will lose the accuracy required to determine the difference in the numbers, and some credit may be lost. 2011 The College Board.

AP PHYSICS B 2011 SCORING GUIDELINES (Form B) Question 6 10 points total Distribution of points (a) 3 points For use of correct equation D E = hc l relating transition energy to wavelength 3 1.24 10 evinm DE B 3.1 ev -19 = = (or 5.0 10 J using hc expressed in Jm i ) 400 nm 3 1.24 10 evinm DE C 1.8 ev -19 = = (or 2.8 10 J ) 700 nm For recognition that DEA = DEB + DEC D = 3.1 ev + 1.8 ev = 4.9 ev (or 7.8 10 J ) l E A A 3 ( ) = hc DE = 1.24 10 evi nm 4.9 ev A For a correct answer with units l = 253 nm (or 255 nm using values in J) A The first two points could also be earned for derivation or recall of the relationship 1 1 1 = +, which gives a value of 255 nm. la lb lc -19 (b) 2 points For application of the photoelectric equation to the photon emitted during transition B Kmax = hf - f = DEB - f -19-19 K max = 3.1 ev - 2.46 ev (or 5.0 10 J -( 2.46 ev)( 1.6 10 J ev) ) For a correct answer with units K = 0.64 ev (or 1.06 10 J ) max -19 (c) 3 points For use of the relation l = hp that relates de Broglie wavelength to momentum For use of K = p 2 2m OR p = mu and K = mu 2 2 Solving for p p= 2mKmax Substituting this expression for p into the equation for l above l = h 2mKmax For correct substitutions including the value of K from part (b) ( 6.63 10-34 J s 31 19 ) 2 ( 9.11 10 - kg )( 0.64 ev )( 1.6 10 - i J ev ) max l = -9-19 l = 1.54 10 m = 154 nm (or 151 nm using K max = 1.06 10 J ) 2011 The College Board.

AP PHYSICS B 2011 SCORING GUIDELINES (Form B) Question 6 (continued) Distribution of points (d) 2 points For an answer consistent with part (a) The correct answer is A only if part (a) was worked correctly. If part (a) was not worked correctly, the answer must be consistent with the values calculated in (a), unless the values were correctly recalculated. For an appropriate justification Example: From part (a) D E A = 4.9 ev. This energy is large enough to overcome the 2.46 ev work function, so electrons will be ejected from the metal. From part (a) D E C = 1.8 ev. This energy is not large enough to overcome the 2.46 ev work function, so electrons will not be ejected from the metal. The justification point could also be earned by (1) calculating the longest wavelength photon (505 nm) that could eject an electron from a metal having the given work function and comparing it with the wavelengths of the two transitions A and C, OR 14 (2) calculating the smallest frequency photon ( 5.95 10 Hz ) that could eject an electron from a metal having the given work function and comparing it with the frequencies of the two transitions A and C. 2011 The College Board.

AP PHYSICS B 2011 SCORING COMMENTARY (Form B) Question 6 Sample: B6A Score: 9 All aspects of this response clearly demonstrate the student s understanding. The only point not earned was for not finding the wavelength in part (a). Sample: B6B Score: 6 Parts (a) received full credit. Part (b) used the wrong energy transition and earned no credit. Part (c) earned for recognizing the de Broglie relationship, but no other credit was earned. Part (d) earned full credit. Sample: B6C Score: 3 Part (a) received no credit. Part (b) received full credit. Part (c) earned for recognizing the de Broglie relationship, but no other credit was earned. Part (d) earned no credit. 2011 The College Board.