Physics 202, Lecture 14

Similar documents
Physics 202, Lecture 13. Today s Topics

Physics 202, Lecture 14

Physics 202, Lecture 14

Physics 3323, Fall 2016 Problem Set 7 due Oct 14, 2016

Physics 202, Lecture 13. Today s Topics. Magnetic Forces: Hall Effect (Ch. 27.8)

in a uniform magnetic flux density B = Boa z. (a) Show that the electron moves in a circular path. (b) Find the radius r o

Magnetic forces on a moving charge. EE Lecture 26. Lorentz Force Law and forces on currents. Laws of magnetostatics

Homework Assignment 9 Solution Set

- 5 - TEST 2. This test is on the final sections of this session's syllabus and. should be attempted by all students.

Chapter 7 Steady Magnetic Field. september 2016 Microwave Laboratory Sogang University

Magnetic Fields! Ch 29 - Magnetic Fields & Sources! Magnets...! Earth s Magnetic Field!

Summary of equations chapters 7. To make current flow you have to push on the charges. For most materials:

Unique Solutions R. All about Electromagnetism. C h a p t e r. G l a n c e

Homework Assignment 6 Solution Set

Potential Formulation Lunch with UCR Engr 12:20 1:00

#6A&B Magnetic Field Mapping

Version 001 HW#6 - Electromagnetism arts (00224) 1

This final is a three hour open book, open notes exam. Do all four problems.

Sources of the Magnetic Field

Problems for HW X. C. Gwinn. November 30, 2009

F is on a moving charged particle. F = 0, if B v. (sin " = 0)

Candidates must show on each answer book the type of calculator used.

200 points 5 Problems on 4 Pages and 20 Multiple Choice/Short Answer Questions on 5 pages 1 hour, 48 minutes

Physics 2135 Exam 3 April 21, 2015

Physics Jonathan Dowling. Lecture 9 FIRST MIDTERM REVIEW

Physics 1402: Lecture 7 Today s Agenda

PHYSICS ASSIGNMENT-9

Week 10: Line Integrals

Physics Graduate Prelim exam

Math 8 Winter 2015 Applications of Integration

Physics 202, Lecture 10. Basic Circuit Components

Problem Set 4: Mostly Magnetic

Lecture 1: Electrostatic Fields

Reading from Young & Freedman: For this topic, read the introduction to chapter 24 and sections 24.1 to 24.5.

Reference. Vector Analysis Chapter 2

Electricity and Magnetism

ragsdale (zdr82) HW2 ditmire (58335) 1

Phys 4321 Final Exam December 14, 2009

The Properties of Stars

Physics 212. Faraday s Law

Problem Solving 7: Faraday s Law Solution

Chapter 4 Syafruddin Hasan

Conducting Ellipsoid and Circular Disk

Lecture 13 - Linking E, ϕ, and ρ

ECE 470 Electric Machines Review of Maxwell s Equations in Integral Form. 1. To discuss a classification of materials

Energy creation in a moving solenoid? Abstract

Problem 1. Solution: a) The coordinate of a point on the disc is given by r r cos,sin,0. The potential at P is then given by. r z 2 rcos 2 rsin 2

ECE 3318 Applied Electricity and Magnetism. Spring Prof. David R. Jackson Dept. of ECE. Notes 31 Inductance

Homework Assignment 3 Solution Set

JUST THE MATHS UNIT NUMBER INTEGRATION APPLICATIONS 6 (First moments of an arc) A.J.Hobson

7.6 The Use of Definite Integrals in Physics and Engineering

Data Provided: A formula sheet and table of physical constants is attached to this paper. SOLID STATE PHYSICS

THREE-DIMENSIONAL KINEMATICS OF RIGID BODIES

Physics 2135 Exam 1 February 14, 2017

Physics Lecture 14: MON 29 SEP

A REVIEW OF CALCULUS CONCEPTS FOR JDEP 384H. Thomas Shores Department of Mathematics University of Nebraska Spring 2007

EMF Notes 9; Electromagnetic Induction ELECTROMAGNETIC INDUCTION

Exam 1 Solutions (1) C, D, A, B (2) C, A, D, B (3) C, B, D, A (4) A, C, D, B (5) D, C, A, B

2. VECTORS AND MATRICES IN 3 DIMENSIONS

APPLICATIONS OF THE DEFINITE INTEGRAL

KINEMATICS OF RIGID BODIES

Electromagnetism Answers to Problem Set 10 Spring 2006

We divide the interval [a, b] into subintervals of equal length x = b a n

Forces from Strings Under Tension A string under tension medites force: the mgnitude of the force from section of string is the tension T nd the direc

Today in Physics 122: work, energy and potential in electrostatics

Physics 121 Sample Common Exam 1 NOTE: ANSWERS ARE ON PAGE 8. Instructions:

p(t) dt + i 1 re it ireit dt =

Phys102 General Physics II

Electric Potential. Concepts and Principles. An Alternative Approach. A Gravitational Analogy

Jackson 2.26 Homework Problem Solution Dr. Christopher S. Baird University of Massachusetts Lowell

Physics 9 Fall 2011 Homework 2 - Solutions Friday September 2, 2011

Prof. Anchordoqui. Problems set # 4 Physics 169 March 3, 2015

NOT TO SCALE. We can make use of the small angle approximations: if θ á 1 (and is expressed in RADIANS), then

2. THE HEAT EQUATION (Joseph FOURIER ( ) in 1807; Théorie analytique de la chaleur, 1822).

Section 14.3 Arc Length and Curvature

4E : The Quantum Universe. Lecture 25, May 14 Vivek Sharma

Phys 6321 Final Exam - Solutions May 3, 2013

Line Integrals. Chapter Definition

IMPORTANT. Read these directions carefully:

ES.182A Topic 32 Notes Jeremy Orloff

Review: Velocity: v( t) r '( t) speed = v( t) Initial speed v, initial height h, launching angle : 1 Projectile motion: r( ) j v r

Solution From Ampere s law, the magnetic field at point a is given by B a = µ 0I a

DIRECT CURRENT CIRCUITS

CAPACITORS AND DIELECTRICS

Space Curves. Recall the parametric equations of a curve in xy-plane and compare them with parametric equations of a curve in space.

Partial Derivatives. Limits. For a single variable function f (x), the limit lim

BME 207 Introduction to Biomechanics Spring 2018

Data Provided: A formula sheet and table of physical constants is attached to this paper. SOLID STATE PHYSICS

13.4 Work done by Constant Forces

Method of Localisation and Controlled Ejection of Swarms of Likely Charged Particles

The Wave Equation I. MA 436 Kurt Bryan

1.1. Linear Constant Coefficient Equations. Remark: A differential equation is an equation

CHM Physical Chemistry I Chapter 1 - Supplementary Material

Analytically, vectors will be represented by lowercase bold-face Latin letters, e.g. a, r, q.

10/25/2005 Section 5_2 Conductors empty.doc 1/ Conductors. We have been studying the electrostatics of freespace (i.e., a vacuum).

Module 1. Energy Methods in Structural Analysis

Light and Optics Propagation of light Electromagnetic waves (light) in vacuum and matter Reflection and refraction of light Huygens principle

6. Intermediate state

Physics 207 Lecture 5

l 2 p2 n 4n 2, the total surface area of the

Transcription:

Physics 202, Lecture 14 Tody s Topics Sources of the Mgnetic Field (Ch. 28) Biot-Svrt Lw Ampere s Lw Mgnetism in Mtter Mxwell s Equtions Homework #7: due Tues 3/11 t 11 PM (4th problem optionl) Mgnetic Force: Mgnetic Forces nd Fields F = Id l B Mgnetic Field: Biot-Svrt Lw: B = µ 0 4 Ampere s Lw: # " Id l " ˆr r 2 Bid s " = µ 0 I enclosed θ r dl P R I I µ 0 = 4πx10-7 T m/a: permebility of free spce Direction of integrtion long pth: use right-hnd rule 1

B Field of Stright Wire, length L (Text exmple 28-13) B field t point P is: B = µ 0 I (cos 1 # cos 2) 4" When L=infinity (text exmple 28-11): B = µ 0I 2 θ 1 θ 2 (return to this lter with Ampere s Lw) Text: 28.43 Question y A current I flows in the +y direction in n infinite wire; current I lso flows in loop. Wht is F x, the net force on the loop in the x-direction? I F left F top X I F right () F x < 0 (b) F x = 0 (c) F x > 0 F bottom x 2

B Field of Circulr Current Loop on Axis Use Biot-Svrt Lw (text exmple 28-12) µ0 IR 2 Bx = 2( x 2 + R 2 ) 3 / 2 Bcenter = µ0 I 2R See lso: center of rc (text exmple 28-13) Text: 28.37 B of Circulr Current Loop: Field Lines B 3

Mgnetic Fields (Biot-Svrt): Summry Current loop, distnce x on loop xis (rdius R): B x = µ 0 IR 2 B 2(x 2 + R 2 ) 3/2 center = µ I 0 2R Center of rc (rdius R, ngle θ): Stright wire: finite length µ I B = (cos 1 # cos 4" infinite wire: 0 2 µ 0I B = 2 ) B center = µ 0 I 4" R θ 1 θ 2 Ampere s Lw: Ampere s Lw I " ny closed pth Bid l = µ 0 I encl dl pplies to ny closed pth, ny sttic B field useful for prcticl purposes only for situtions with high symmetry 4

Ampere s Lw: B-field of Stright Wire Use symmetry: I Choose loop to be circle of rdius R centered on the wire in plne to wire. Why? Mgnitude of B is constnt (function of R only) Direction of B is prllel to the pth. # B id l " = # Brd = 2"rB = µ 0 I encl = µ 0 I B = µ 0 I 2r Text exmple: 28-6 B Field Inside Long Wire Totl current I flows through wire of rdius into the screen s shown. Wht is the B field inside the wire? By symmetry -- tke the pth to be circle of rdius r: " Bid l = B2r Current pssing through circle: I encl = r 2 Bid l = B2r = µ o I encl x x x x x x x x x x x x x x x x x x x x x x r x x x x x x x x x x x x x 2 I " B in = µ Ir 0 2 2 5

B Field of Long Wire Inside the wire: (r < ) B = µ 0 I 2 r 2 Outside the wire: ( r > ) B B = µ 0 I 2 r r Text: 28.31 Ampere s Lw: Toroid Toroid: N turns with current I. B θ =0 outside toroid (Consider integrting B on circle outside toroid: net current zero) B θ inside: consider circle of rdius r, centered t the center of the toroid. Bid l = B2r = µ o I encl = " µ o NI B = µ 0 NI 2r x x x x x x x x r x x x x x x x x B 6

B Field of Solenoid Inside solenoid: source of uniform B field Solenoid: current I flows through wire wrpped n turns per unit length on cylinder of rdius nd length L. L If << L, the B field is pproximtely contined within the solenoid, in the xil direction, nd of constnt mgnitude. In this limit, cn clculte the field using Ampere's Lw Ampere s Lw: Solenoid The B field inside n idel solenoid is: B = µ 0nI n=n/l idel solenoid segment 3 t 7

Solenoid: Field Lines Right-hnd rule: direction of field lines north pole south pole Like br mgnet (except it cn be turned on nd off) Text: 28.68 Mgnetic Fields (Ampere s Lw): Summry Infinite wire: Inside wire, rdius R: B = µ 0 I 2r Axil field inside toroid (N turns) B = µ 0 NI 2"r B field inside long solenoid (L>>R) (n turns/length) Uniform field B = µ ni 0 B = µ 0Ir 2 R 2 R x x x x x x x x x x x x x x x x x x x x x x x r x x x x x x x x x x x x x L R 8

Mgnetism in Mtter The B field produced long the xis of circulr loop (rdius R) by current I is: B µ 0 µ ẑ typicl dipole behviour 3 2"z µ is the mgnetic moment = I # re nd z >> R Mterils re composed of prticles tht hve mgnetic moments -- (negtively chrged electrons circling round the positively chrged nucleus). orbitl ngulr momentum spin ngulr momentum (quntum mechnics) µ B = q e J = 9.27 10 "24 2m e T Bohr mgneton Mgnetiztion Apply externl B field B 0. Field is chnged within mterils by these mgnetic moments. Mgnetiztion:totl mgnetic moment per unit volume The B field in the mteril is Define H (mgnetic field strength): Mgnetic susceptibility: M B = B 0 + µ 0 M µ totl V B = µ 0 ( H + M ) M = H ( H = B 0 µ 0 ) B = µ H = µ 0 (1 + ) H permebility µ ( = m µ 0 ) 9

Mgnetic Mterils Mterils re clssified by mgnetic susceptibilities: Prmgnetic (luminum, tungsten, oxygen, ) Atomic mgnetic dipoles line up with the field, incresing it. Only smll effects due to therml rndomiztion: χ ~ +10-5 Dimgnetic (gold, copper, wter, s well s superconductors) Applied field induces n opposing field; usully very wek χ~ -10-5 Ferromgnetic (iron, coblt, nickel, ) Dipoles prefer to line up with the pplied field (similr to prmgnetic), but tend to ll line up the sme wy due to collective effects: very strong enhncements χ ~ +10 +3-10 +5 Mgnetic susceptibility temperture dependent (bove rnge of typicl vlues t T=20 C) Ferromgnets Dipoles tend to strongly lign over smll ptches domins (even w/o externl mgnetic field). With externl field, the domins lign to produce lrge net mgnetiztion. Soft ferromgnets Domins re-rndomize when mgnetic field is removed Mgnetic Domins Hrd ferromgnets Domins persist even when the field is removed Permnent mgnets Domins my be ligned in different direction in new externl field Domins my be re-rndomized by sudden physicl shock If temperture is rised bove Curie point (770 C for iron), domins will lso rndomize (like prmgnet) 10

Applied field ligns lmost ll the dipoles nd the domins. Mgnetiztion is then sturted : no further increse. Mgnetic Domins Hrd ferromgnets: Domins cn persist even when the field is removed Permnent mgnets Domins my be ligned in different directions by chnging the pplied field.. A memory effect tht requires lrge reverse field to significntly chnge the mgnetiztion of the object: hysteresis. Mxwell s Equtions: Sttics " " " " Eid A = q encl 0 Eid l = 0 Bid A = 0 Bid l = µ 0 I encl Guss s Lw: Electric Fields Conservtive nture of electrosttic force Guss s Lw: Mgnetic Fields Ampere s Lw 11

Mxwell s Equtions: Generl Cse Preview: " Eid A = q encl Bid A = 0 " 0 Eid l = d " Bid A dt " Bid l d " = µ 0 I encl + µ 0 " 0 dt (time-dependent fields) Guss s Lw: Electric Fields Frdy s Lw (next week) Guss s Lw: Mgnetic Fields Eid A Ampere-Mxwell (lter in sem.) (interdependence of E nd B: crucil for wht s next) 12