Problem 22: Journey to the Center of the Earth

Similar documents
Lecture 14 (Oct. 30, 2017)

Gradebook & Midterm & Office Hours

Handout 28. Ballistic Quantum Transport in Semiconductor Nanostructures

, an inverse square law.

AP Calculus BC Problem Drill 16: Indeterminate Forms, L Hopital s Rule, & Improper Intergals

Assignment 4 Biophys 4322/5322

The Special Theory of Relativity

Sec 2.3 Modeling with First Order Equations

PHYS-333: Problem set #2 Solutions

Theoretical study of quantization of magnetic flux in a superconducting ring

MA1506 Tutorial 2 Solutions. Question 1. (1a) 1 ) y x. e x. 1 exp (in general, Integrating factor is. ye dx. So ) (1b) e e. e c.

Differential Equations

Math 34A. Final Review

Probability and Stochastic Processes: A Friendly Introduction for Electrical and Computer Engineers Roy D. Yates and David J.

1. (25pts) Answer the following questions. Justify your answers. (Use the space provided below and the next page)

as a derivative. 7. [3.3] On Earth, you can easily shoot a paper clip straight up into the air with a rubber band. In t sec

PHA 5127 Answers Homework 2 Fall 2001

Junction Tree Algorithm 1. David Barber

3 2x. 3x 2. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

Chemical Physics II. More Stat. Thermo Kinetics Protein Folding...

Utilizing exact and Monte Carlo methods to investigate properties of the Blume Capel Model applied to a nine site lattice.

Derivation of Electron-Electron Interaction Terms in the Multi-Electron Hamiltonian

Hydrogen Atom and One Electron Ions

Problem Set #2 Due: Friday April 20, 2018 at 5 PM.

Introduction to the quantum theory of matter and Schrödinger s equation

SAFE HANDS & IIT-ian's PACE EDT-15 (JEE) SOLUTIONS

Practice Exam 2 Solutions

Brief Introduction to Statistical Mechanics

1.2 Faraday s law A changing magnetic field induces an electric field. Their relation is given by:

Coupled Pendulums. Two normal modes.

Physics 506 Winter 2006 Homework Assignment #12 Solutions. Textbook problems: Ch. 14: 14.2, 14.4, 14.6, 14.12

MA 262, Spring 2018, Final exam Version 01 (Green)

Lecture 37 (Schrödinger Equation) Physics Spring 2018 Douglas Fields

Background: We have discussed the PIB, HO, and the energy of the RR model. In this chapter, the H-atom, and atomic orbitals.

Ch. 24 Molecular Reaction Dynamics 1. Collision Theory

5. B To determine all the holes and asymptotes of the equation: y = bdc dced f gbd

MATH 1080 Test 2-SOLUTIONS Spring

Engineering 323 Beautiful HW #13 Page 1 of 6 Brown Problem 5-12

N1.1 Homework Answers

Elements of Statistical Thermodynamics

Magnetic vector potential. Antonio Jose Saraiva ; -- Electric current; -- Magnetic momentum; R Radius.

COHORT MBA. Exponential function. MATH review (part2) by Lucian Mitroiu. The LOG and EXP functions. Properties: e e. lim.

NEWTONIAN TORSION PHYSICS

Chapter 37 The Quantum Revolution

u x v x dx u x v x v x u x dx d u x v x u x v x dx u x v x dx Integration by Parts Formula

Introduction to Condensed Matter Physics

7.4 Potential Difference and Electric Potential

Where k is either given or determined from the data and c is an arbitrary constant.

Chapter 8: Electron Configurations and Periodicity

1973 AP Calculus AB: Section I

Exam 1. It is important that you clearly show your work and mark the final answer clearly, closed book, closed notes, no calculator.

Collisions between electrons and ions

EAcos θ, where θ is the angle between the electric field and

( ) Differential Equations. Unit-7. Exact Differential Equations: M d x + N d y = 0. Verify the condition

Why is a E&M nature of light not sufficient to explain experiments?

The pn junction: 2 Current vs Voltage (IV) characteristics

The Matrix Exponential

PHYS ,Fall 05, Term Exam #1, Oct., 12, 2005

u 3 = u 3 (x 1, x 2, x 3 )

VTU NOTES QUESTION PAPERS NEWS RESULTS FORUMS

Lie Groups HW7. Wang Shuai. November 2015

Total Wave Function. e i. Wave function above sample is a plane wave: //incident beam

Electron energy in crystal potential

The Matrix Exponential

ME 321 Kinematics and Dynamics of Machines S. Lambert Winter 2002

HIGHER ORDER DIFFERENTIAL EQUATIONS

Problem Set 6 Solutions

10. The Discrete-Time Fourier Transform (DTFT)

Addition of angular momentum

1 General boundary conditions in diffusion

EEO 401 Digital Signal Processing Prof. Mark Fowler

University of Illinois at Chicago Department of Physics. Thermodynamics & Statistical Mechanics Qualifying Examination

Deepak Rajput

Fr Carrir : Carrir onntrations as a funtion of tmpratur in intrinsi S/C s. o n = f(t) o p = f(t) W will find that: n = NN i v g W want to dtrmin how m

ON THE MOTION OF FREE MATERIAL TEST PARTICLES IN ARBITRARY SPATIAL FLOWS

High Energy Physics. Lecture 5 The Passage of Particles through Matter

Calculus II (MAC )


Unit 7 Charge-to-mass ratio of the electron

Exam 2 Thursday (7:30-9pm) It will cover material through HW 7, but no material that was on the 1 st exam.

A 1 A 2. a) Find the wavelength of the radio waves. Since c = f, then = c/f = (3x10 8 m/s) / (30x10 6 Hz) = 10m.

Zero Point Energy: Thermodynamic Equilibrium and Planck Radiation Law

1997 AP Calculus AB: Section I, Part A

Electromagnetism Physics 15b

2. Background Material

San José State University Aerospace Engineering AE 138 Vector-Based Dynamics for Aerospace Applications, Fall 2016

y cos x = cos xdx = sin x + c y = tan x + c sec x But, y = 1 when x = 0 giving c = 1. y = tan x + sec x (A1) (C4) OR y cos x = sin x + 1 [8]

Pair (and Triplet) Production Effect:

Digital Signal Processing, Fall 2006

AerE 344: Undergraduate Aerodynamics and Propulsion Laboratory. Lab Instructions

Constants and Conversions:

y = 2xe x + x 2 e x at (0, 3). solution: Since y is implicitly related to x we have to use implicit differentiation: 3 6y = 0 y = 1 2 x ln(b) ln(b)

Integration by Parts

Psychoanalysis of Centrally Symmetric Gravitational Field Using a Centrally Symmetric Metric

GRAVITATION 4) R. max. 2 ..(1) ...(2)

TP A.31 The physics of squirt

Unit 6: Solving Exponential Equations and More

The van der Waals interaction 1 D. E. Soper 2 University of Oregon 20 April 2012

ELECTROMAGNETIC INDUCTION CHAPTER - 38


Transcription:

Problm : Journy to th Cntr of th Earth Imagin that on drilld a hol with smooth sids straight through th ntr of th arth If th air is rmod from this tub (and it dosn t fill up with watr, liquid rok, or iron from th or) an objt droppd into on nd will ha nough nrgy to just xit th othr nd aftr an intral of tim Your goal is to find that intral of tim a) Th graitational for on an objt of mass m, loatd insid th arth a distan r < R, from th ntr (R is th radius of th arth), is du only to th mass of th arth that lis within a solid sphr of radius r What is th graitational for as a funtion of th distan r from th ntr? Exprss your answr in trms of g and R Not: you do not nd th mass of th arth to answr this qustion You only nd to assum that th arth is of uniform dnsity b) Using th onpt of for xplain how th objt-arth systm for objts insid th arth is analogous to an objt-spring systm ) What is th potntial nrgy insid th arth as a funtion of r for th objt-arth systm? Can you think of a natural point to hoos a zro point for th potntial nrgy? Find out how long this journy will tak d) How dos this tim ompar to a satllit in low arth orbit (i orbits just abo th surfa of th arth)? ) In ordr to shortn th tral tim, th sndr trals down th hol a distan until sh is only a fration of th radius of th arth, β R, (R is th radius of th arth) from th ntr Th ripint trals down a similar distan from th far nd in ordr to ath th objt By how muh if any is th tral tim thrby rdud (as a funtion of β)?

MASSACHUSETTS INSTITUTE OF TECHNOLOGY Dpartmnt of Physis Physis 801 TEAL Fall Trm 004 In-Class Problms -4: Harmoni Osillation and Mhanial Enrgy: Solution Problm : Journy to th Cntr of th Earth Imagin that on drilld a hol with smooth sids straight through th ntr of th arth If th air is rmod from this tub (and it dosn t fill up with watr, liquid rok, or iron from th or) an objt droppd into on nd will ha nough nrgy to just xit th othr nd aftr an intral of tim Your goal is to find that intral of tim a) Th graitational for on an objt of mass m, loatd insid th arth a distan r < R, from th ntr (R is th radius of th arth), is du only to th mass of th arth that lis within a solid sphr of radius r What is th graitational for as a funtion of th distan r from th ntr? Exprss your answr in trms of g and R Not: you do not nd th mass of th arth to answr this qustion You only nd to assum that th arth is of uniform dnsity Answr: Choos a radial oordinat with unit tor rˆ pointing outwards Th graitational for on an objt of mass m at th surfa of th arth is gin by two xprssions Gmm F = gra rˆ = mgrˆ R Thrfor w an sol for th graitational onstant alration 1

Gm g = R Whn th objt is a distan r from th ntr of th arth, th mass of th arth that lis outsid th sphr of radius r dos not ontribut to th graitational for Th only ontribution to th graitational for is du to th mass nlosd in th sphr of radius r, Sin th mass dnsity is gin by 4 m nlosd = ρ π r ρ = m (4/)π R, th mass nlosd is m m nlosd = (4/)π r = m r (4/)π R R Thrfor th graitational for on th objt of mass m whn it is a distan r from th ntr of th arth is gin by = Gmm nlosd rˆ = Gmm r Gmm Fgra rˆ = r r r R R W an us our xprssion for th g Gm = / R to find that th graitational for on a mass m at a distan r from th ntr of th arth is gin by F = mg rrˆ gra R b) Using th onpt of for xplain how th objt-arth systm for objts insid th arth is analogous to an objt-spring systm Answr: Th minus sign indiats that th for is always dirtd towards th ntr of th arth (rstoring for) and proportional tot h distan from th ntr of th arth This is analogous to th rstoring for of a spring, F spring = kxxˆ,

whr th spring onstant for graitation is gin by k = mg gra R This mans that th objt will undrgo simpl harmoni motion just lik a spring ) What is th potntial nrgy insid th arth as a funtion of r for th objt-arth systm? Can you think of a natural point to hoos a zro point for th potntial nrgy? Find out how long this journy will tak Answr: W an dfin a potntial nrgy for graitation insid th arth that is analogous to th spring potntial nrgy funtion with zro point for potntial nrgy hosn at th ntr of th arth and 1 Ur () = k gra r = 1 mg r R If w rlas th objt from rst at th surfa of th arth, th initial mhanial nrgy is all potntial nrgy and is gin by \ E = ( ) = 1 mg R = 1 i U R mgr R Whn th objt rahs th ntr of th arth, th mhanial nrgy is all kinti nrgy, E f = K f = 1 m Sin thr ar no xtrnal work ating on th systm, th mhanial nrgy is onstant and E i = E f 1 1 mgr = m Th loity just bfor th objt rahs th ntr of th arth is thn = gr

Not w hoos just bfor so that th loity is radially inward in polar oordinats: thr is no wll dfind dirtion whn th objt is loatd at th origin From Nwton s Sond Law, F = ma, in th radial dirtion boms This simplifis to Th position of th objt satisfis d r rˆ : mg r = m R dt dr g = r dt π rt () = R os( t) T whr T is th priod of osillation Th loity of th objt is R π π t () = R sin( t) T T π π Whn t = T /4, os( t) = os( ) = 0 hn th objt is at th ntr of th arth Also T π π sin sin( t) = sin( ) = 1, th loity at th ntr of th arth is gin by T π = ( T / 4) = R T From th ondition that mhanial nrgy is onstant w found that = gr Thrfor π R = gr T W an sol for th priod and find that T = π ( R / g 1/ ) d) How dos this tim ompar to a satllit s priod in low arth orbit (i orbits just abo th surfa of th arth)? 4

Answr: If an objt undrgos uniform irular motion around th arth th Nwton s Sond Law in th radial dirtion boms π rˆ : mg = mr T W an sol for th priod of th irular orbit and find that th priod is idntial to th priod of osillation, T = π (R / g) 1/ ) In ordr to shortn th tral tim, th sndr trals down th hol a distan until sh is only a fration of th radius of th arth, β R, (R is th radius of th arth) from th ntr Th ripint trals down a similar distan from th far nd in ordr to ath th objt By how muh if any is th tral tim thrby rdud (as a funtion of β)? Answr: If th objt starts losr to th arth th priod is still th sam baus w ha only hangd th initial onditions w ha not hangs th spring onstant of graitation 5