M-Theory and Matrix Models

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Department of Mathematical Sciences, University of Durham October 31, 2011

1 Why M-Theory? Whats new in M-Theory The M5-Brane 2

Superstrings Outline Why M-Theory? Whats new in M-Theory The M5-Brane There are 5 different superstring theories which describe open and closed strings

D-Branes Outline Why M-Theory? Whats new in M-Theory The M5-Brane There are dualities between the 5 different theories, for example T-duality describes how we can relate IIA to IIB theories. Open strings have end points that live on D-branes D-p-branes are (p+1)-dimensional objects that move through D dimensional spacetime, they can have open/closed bc s

D-Branes Outline Why M-Theory? Whats new in M-Theory The M5-Brane A bosonic brane action would typically look like the following S DBI = T p d p+1 σ detp(g + 2πα F ) These branes have a tension which is some power of g s and l s A p-brane couples to a p+1 form potential, you can add these potentials to the D-brane action S = S DBI + A p+1

The Discovery of M-Theory Why M-Theory? Whats new in M-Theory The M5-Brane M-theory was discovered as a strongly coupled limit to IIA theory This comes from a Kaluza Klein argument where M 2 11 = p mp m = 0, p 11 = N/R 11, where M 11 is the mass of the graviton in 11D SUGRA/M-Theory The D0-brane has mass (l s g s ) 1 and KK modes have N units of U(1) charge

The Discovery of M-Theory Why M-Theory? Whats new in M-Theory The M5-Brane Matching up the two masses gives R 11 = l s g s, gives us extra large dimension Eleven dimensional SUGRA has a 3-form potential g s M-theory has the same potential, yielding an electrically coupled M2 and a magnetically coupled M5 brane. Worldvolume theories for these branes would be 3 and 6 dimensional CFTs

Why M-Theory? Whats new in M-Theory The M5-Brane AdS/CFT... Because no strings talk is complete without it We can look at the AdS/CFT correspondence here too! The correspondence tells us that a stack of M2-branes has bulk background AdS 4 S 7, this was known from the 11-dimensional supergravity result of the M2. Bagger and Lambert discovered the theory of multiple M2-branes in 2007 In 11 dimensions N = 8 is the maximal supersymmetry we could have.

Whats new in M-Theory Why M-Theory? Whats new in M-Theory The M5-Brane BL proposed that the N = 8, SO (8) R theory of multiple M2 branes is a Chern-Simons gauge theory of level k. The revolutionary idea was that the scalars X I took values in a 3-algebra [,, ] : V V V V. L = 1 2 Dµ X I D µ X I + i 2 ΨΓ µ D µ Ψ + i 4 ΨΓ IJ [X I, X J, Ψ] where V (X) + k 2 εµνλ (õ ν à λ + 2 3õÃνÃλ) V (X) = 1 12 Tr([X I, X J, X K ], [X I, X J, X K ])

Whats new in M-Theory Why M-Theory? Whats new in M-Theory The M5-Brane Using the notation õ c d = A µab f abc d, we can write the susy transforms: δx I = i ɛγ I Ψ δψ = D µ X I Γ µ Γ I ɛ 1 6 [X I, X J, X K ]Γ IJK ɛ δãµ = i ɛγ µ Γ I X I Ψ, M2-branes are 1/2 BPS and so we choose Γ 012 ɛ = ɛ Let s discuss a bit more about Lie 3-algebras

Whats new in M-Theory Why M-Theory? Whats new in M-Theory The M5-Brane A Lie 3-algebra is a vector space with a basis T a, a = 1,..., N endowed with a trilinear product [T a, T b, T c ] = f abc d T d, We can derive a generalised Jacobi Id called the fundamental identity by using a derivation on this product. The N = 8 theory required f abc d = f [abc] d, only solution prop to ɛ abcd. So BL theory has an SO(4) = SU(2) SU(2) gauge symmetry. Reformulate as a bi-fundamental gauge theory.

Whats new in M-Theory Why M-Theory? Whats new in M-Theory The M5-Brane BL theory only describes two coincident branes! Also the Chern-Simons level is restricted to k = 1, 2 ABJM wrote down a bifundamental SCCS matter theory which has only N = 6 susy, but this described N coincident branes for any integer k. The moduli space of the ABJM theory is R 8 /Z k, k Z for a U(N) U(N) gauge theory. ABJM theory does not need to use 3 algebras, the potential of the theory is calculated from a superpotential in the usual manner.

Whats new in M-Theory Why M-Theory? Whats new in M-Theory The M5-Brane It is possible to enhance the N = 6 ABJM theory to get the full N = 8 theory by the use of monopole operators. The M2-brane picture is pretty well understood now. On to the M5-brane...

Whats new in M-Theory Why M-Theory? Whats new in M-Theory The M5-Brane Much less is known about the M5-brane. Gravity side has AdS 7 S 4. Field theory is given by an N = (2, 0) supermultiplet (B µν, X I, Ψ), I = 6,..., 10. Difficult to write a gauge kinetic term for the field strength H 3 = db 2. Σ 6 H 3 H 3 = 0 Possible to write down a non-covariant action for a single M5-brane which is gauge fixed, (PST 1997).

Outline Expect Riemannian geometry to break down at Plank scales. Spacetime becomes quantised and coordinates become quantum operators. Open strings ending on D-branes with a B-field turned on give a noncommutative geometry [X µ, X ν ] = iθ µν.

Outline M2-branes end on M5-branes. Has been shown that M5-brane geometry in the presence of 3-form C-field is [X µ, X ν, X λ ] = iθ µνλ. Lie 3-bracket given by fundamental identity: [[f, g, h], k, l] = [[f, k, l], g, h] + [f, [g, k, l], h] + [f, g, [h, k, l]] Constraint is too strong and we do not understand the representation theory.

Outline We propose the Quantum Nambu Bracket : [f, g, h] := fgh + ghf + hfg fhg gfh hgf We will show that the quantum geometry [X µ, X ν, X λ ] = iθ µνλ is given by the QNB. Refer to the above geometry as the Quantum Nambu Geometry.

A IIB Background Outline Consider background AdS 5 S 5. Background has a dilaton, axion, C 2, C 4. Turn on 3-form Flux for a D1-brane in the AdS 5 sector only. It has been shown that consistency requires the spacetime to take the form R 3 AdS 2 S 5. Note for later that the RR 2-form potential is given by C 2 = f ɛ ijk X i dx j dx k.

D1 MM in a Large Flux N parallel D1-branes action given by DBI + CS action Myers proposed a generalisation of the CS term given by S CS = µ 1 TrP(e iλi Φi Φ C n )e λf. Here µ 1 = 1/(g s 2πα ), λ = 2πα and X I = 2πα Φ I. Our background has B = 0. n

D1 MM in a Large Flux Expanding S CS gives S CS = µ 1 Tr[λFχ + C 2 + iλ 2 Fi Φ i Φ C 2 := S χ + S C2 + S C4 + iλi Φ i Φ C 4 λ3 2 Fi4 Φ C 4] We will see only S C2 contributes in the double scaling limit of a large field strength.

D1 MM in a Large Flux Substituing our expression for C 2 gives S C2 /µ 1 = f d 2 σtr( 1 2 ɛ ijkx i D α X j D β X k ɛ αβ ) +f d 2 σtr(ifx i X j X k ɛ ijk ) Here α = 0, 1, i = 2, 3, 4, i = 5, 6, 7, 8, 9.

D1 MM in a Large Flux By including a YM term (from DBI), can find EOM contribution of: S C2 i 2 Φ C 4 i 4 Φ C 4 EOM of X i : O( f α ) O( 1 ) 0 f α 2 EOM of X i 1 1 : 0 O( ) O( f 4 α 2 f 4 α 2 ) The YM term is given by S YM /µ 1 = α 2 det G αβ F αβ F α β Gαα G ββ So for large f and taking ɛ 0, we have a double scaling limit α ɛ, f ɛ a, a > 0.

D1 MM in a Large Flux Choice 1/2 < a < 2 gives us lim S D1 = S C2. ɛ 0 So the double scaling limit gives us the low energy action for N D1-branes in a large F 3 background.

Equations of Motion and Quantum Nambu Geometry ε αβ ε ijk [X j, D β X k X i ] + ε αβ ε ijk [D β, X i X j X k ] = 0, 3 2 ε ijkd α X j D β X k ε αβ + ε ijk [F; X j, X k ] = 0, [A; B, C] := [B, C]A + A[B, C] + BAC CAB Tr[A, B, C]D = Tr[D; B, C] A, in analogy to the relation TrD[A, B] = Tr[D, A]B.

Equations of Motion and Quantum Nambu Geometry Solutions: D α X i = 0, F = 0, [X i, X j ] = iθɛ ij is allowed but there is another more interesting solution, [X i, X j, X k ] = iθɛ ijk

A Representation with Z 3 Symmetry Can construct a rep with raising/lowering operators. Look at a different rep, want to consider reps on a 3-dim real space. [X 1, X 2, X 3 ] = iθ Introduce a unitary operator, and assuming one obtains U ω = ρ 2 ω, ρ 3 = 1 C U ω = ρω, X 1 ω = (ω + a) ω + 1, U X 1 U ω = (ρ 2 ω + a) ω + ρ, U 2 X 1 U 2 ω = (ρω + a) ω + ρ 2

A Representation with Z 3 Symmetry If the fields X 1, X 2 and X 3 are unitarily related to each other by then and we see that X 2 = U X 1 U, X 3 = U X 2 U, X 1 ω = (ω + a) ω + 1, X 2 ω = ρ 2 (ω + aρ) ω + ρ, X 3 ω = ρ(ω + aρ 2 ) ω + ρ 2 [X 1, X 2, X 3 ] ω = 3(a 2 a)(ρ ρ 2 ) ω

IIB Matrix Model Outline Expand around the QNG and examine emerging gauge theories Denote the covariant derivative id α = i α + A α, α = 0, 1 as id α = X α We can show that S D1 can be written as S D1 = f g s ls 2 d 2 σ TrX a X b X c X d X e ɛ abcde, Large N reduction gives S IIB = f g s ls 2 TrX a X b X c X d X e ɛ abcde, a, b, c, d, e = 0, 1, 2, 3, 4.

M-Theory Matrix Model IIB background invariant under KV i, i = 2, 3, 4. Compactify x 2 on circle of radius R 2 and T-dualize S 1 R 2 AdS 2 S 5 D1-brane D2-brane under this T-duality In IIA theory with D2-brane action S D2 = f d 3 σx a X b X c X d X e ɛ abcde g s l s

M-Theory Matrix Model In IIA theory, we have D0, D2, D4, D6, D8-branes. M-theory on a circle in the infinite momentum frame gives us only states with positive D0-charge Under the same double scaling, we are left with S D0 = 1 P(C (1) ) = f dtɛ ij X i D t X j, i, j = 3, 4 g s l s g s l s BFSS model describes M-theory in infinite momentum frame using QM - D0-branes

M-Theory Matrix Model D2-action describes D0-branes too Dimensionally reduce D2-action In the large flux curved background, M-theory action is S M = if dt TrD t X b X c X d X e ɛ bcde, b, c, d, e = 1, 2, 3, 4 g s l s where X 0 = id t

IIA Matrix Model Outline Write constants in terms of M-theory radius R 11, compactify on x 2, perform 11-2 flip The flip changes the M-theory direction on the torus. All this means is R 2 = g s l s, R 11 = N with lightcone momentum p + = 1 Obtain the IIA matrix model S IIA = f d 2 σ TrX a X b X c X d X e ɛ abcde, N where a, b, c, d, e = 0, 1, 2, 3, 4

Multiple D4-branes Outline Consider a fluctuation around the QNG X i = x i 1 K K + A i (σ, x j ) The IIA action becomes S 5 = f trx a X b X c X d X e ɛ abcde N Σ 5 where Σ 5 = d 2 σ x and x is an integral on QNG

Multiple D4-branes Outline Argue this describes K parallel D4-branes Introduce 3-form H where H abc = i[x a, X b, X c ], H de5 = i[x d, X e ], a, b, c, d, e = 0, 1, 2, 3, 4, is the Hodge dual of H ραβ. H µνλ := 1 6 g ɛµνλραβ H ραβ

Multiple D4-branes Outline Claim S 5 = trh abc H de5 ɛ abcde Σ 5 describes the D4 s. To see the connection, we examine an abelian M5-brane theory and dimensionally reduce PST wrote the action for a single M5-brane in 6d by coupling to a scalar.

Multiple D4-branes Outline Gauge fixing gives us the following non-covariant action S PST = 1 ( ) 1 4 d 6 σ 6 ɛ abcdeh abc H de5 + H ab5 Hab5 g After dim reduction on x 5, 1st term is precisely our action! 2nd term comes from a YM term, this is neglected in double scaling limit

Multiple M5-branes Outline Recent proposal that M5-branes on S 1 is equivalent to D4-branes with instantons. There is a precise mapping between instanton states and KK modes Seems natural to promote X 5 = 1 to a general field H µνλ = i[x µ, X ν, X λ ] Different from field strength of 2-form formulation, here in terms of a 1-form Two formulations are related non-trivially

Multiple M5-branes Outline Propose action S M5 = 1 4 Σ 6 tr( 1 6 ɛ abcdeh abc H de5 + ( c 2 H abc H abc + c 3 H ab5 H ab5 ) g) where Σ 6 = Σ 5 S 1 H must satisfy a Bianchi Id. Most natural one is [X [µ, H νλρ] ] = 0 Requiring self-duality solves EOM H ab5 = 1 6 ɛ abcdeh cde

Multiple M5-branes Outline The solution for coefficients are given by 1-parameter family c 2 = 1 18 (c 1/2), c 3 = 5 6 (c 1/2) Moreover, the self-duality condition on H implies that the QNG is self-dual! [x µ, x ν, x λ ] = iθ µνλ 1

Multiple M5-branes Outline The final action for K parallel M5-branes (or K non-abelian 3-form) is S M5,θ = 1 tr( 1 4 x 6 ɛ abcdeh abc H de5 + ( α 1 3 Habc H abc + (1 α)h ab5 ) H ab5 g) where x is determined by the rep of the QNG. Only α = 1/6 gives us the correct Bianchi Id and self-duality condition. The last two terms combine to give the non-abelian generalisation of the gauge fixed PST action!

Conclusion Outline Results: New kind of geometry in string theory D1 s in a large flux non-abelian 3-form on M5 s. Identify C µνλ = θ µνλ Future: More representation theory QFT on a QNG Supersymmetry