Math 5705: Enumerative Combinatorics, Fall 2018: Homework 3

Similar documents
Math 4707 Spring 2018 (Darij Grinberg): homework set 4 page 1

Math 155 (Lecture 3)

(ii) Two-permutations of {a, b, c}. Answer. (B) P (3, 3) = 3! (C) 3! = 6, and there are 6 items in (A). ... Answer.

14 Classic Counting Problems in Combinatorics

Math 140A Elementary Analysis Homework Questions 1

NAME: ALGEBRA 350 BLOCK 7. Simplifying Radicals Packet PART 1: ROOTS

In number theory we will generally be working with integers, though occasionally fractions and irrationals will come into play.

Homework 3. = k 1. Let S be a set of n elements, and let a, b, c be distinct elements of S. The number of k-subsets of S is

A q-analogue of some binomial coefficient identities of Y. Sun

PROBLEMS ON ABSTRACT ALGEBRA

Solutions to Math 347 Practice Problems for the final

Homework 1 Solutions. The exercises are from Foundations of Mathematical Analysis by Richard Johnsonbaugh and W.E. Pfaffenberger.

Math 2112 Solutions Assignment 5

(A sequence also can be thought of as the list of function values attained for a function f :ℵ X, where f (n) = x n for n 1.) x 1 x N +k x N +4 x 3

1 Generating functions for balls in boxes

Sequences, Series, and All That

1 Counting and Stirling Numbers

Exercises 1 Sets and functions

Week 5-6: The Binomial Coefficients

Zeros of Polynomials

The Boolean Ring of Intervals

Enumerative & Asymptotic Combinatorics

Theorem: Let A n n. In this case that A does reduce to I, we search for A 1 as the solution matrix X to the matrix equation A X = I i.e.

Math 4707 Spring 2018 (Darij Grinberg): midterm 2 page 1. Math 4707 Spring 2018 (Darij Grinberg): midterm 2 with solutions [preliminary version]

Section 5.1 The Basics of Counting

PROBLEM SET 5 SOLUTIONS 126 = , 37 = , 15 = , 7 = 7 1.

and each factor on the right is clearly greater than 1. which is a contradiction, so n must be prime.

3 Gauss map and continued fractions

SEQUENCES AND SERIES

Chapter 0. Review of set theory. 0.1 Sets

Different kinds of Mathematical Induction

1.3 Convergence Theorems of Fourier Series. k k k k. N N k 1. With this in mind, we state (without proof) the convergence of Fourier series.

[ 11 ] z of degree 2 as both degree 2 each. The degree of a polynomial in n variables is the maximum of the degrees of its terms.

Review Problems 1. ICME and MS&E Refresher Course September 19, 2011 B = C = AB = A = A 2 = A 3... C 2 = C 3 = =

4 The Sperner property.

arxiv: v1 [math.co] 23 Mar 2016

Math 61CM - Solutions to homework 3

It is always the case that unions, intersections, complements, and set differences are preserved by the inverse image of a function.

Math 4400/6400 Homework #7 solutions

MATH 324 Summer 2006 Elementary Number Theory Solutions to Assignment 2 Due: Thursday July 27, 2006

Ma 530 Introduction to Power Series

CSE 191, Class Note 05: Counting Methods Computer Sci & Eng Dept SUNY Buffalo

Intermediate Math Circles November 4, 2009 Counting II

3.2 Properties of Division 3.3 Zeros of Polynomials 3.4 Complex and Rational Zeros of Polynomials

TEACHER CERTIFICATION STUDY GUIDE

MA541 : Real Analysis. Tutorial and Practice Problems - 1 Hints and Solutions

MAT1026 Calculus II Basic Convergence Tests for Series

THE KENNESAW STATE UNIVERSITY HIGH SCHOOL MATHEMATICS COMPETITION PART II Calculators are NOT permitted Time allowed: 2 hours

(3) If you replace row i of A by its sum with a multiple of another row, then the determinant is unchanged! Expand across the i th row:

Assignment 5: Solutions

Algorithms and Data Structures 2014 Exercises and Solutions Week 13

1. n! = n. tion. For example, (n+1)! working with factorials. = (n+1) n (n 1) 2 1

Axioms of Measure Theory

Math 104: Homework 2 solutions

Course : Algebraic Combinatorics

Math 299 Supplement: Real Analysis Nov 2013

n=1 a n is the sequence (s n ) n 1 n=1 a n converges to s. We write a n = s, n=1 n=1 a n

A NOTE ON PASCAL S MATRIX. Gi-Sang Cheon, Jin-Soo Kim and Haeng-Won Yoon

Chapter 2. Periodic points of toral. automorphisms. 2.1 General introduction

MT5821 Advanced Combinatorics

INEQUALITIES BJORN POONEN

Ma 530 Infinite Series I

Modern Algebra. Previous year Questions from 2017 to Ramanasri

Chapter 1 : Combinatorial Analysis

ACO Comprehensive Exam 9 October 2007 Student code A. 1. Graph Theory

Math 475, Problem Set #12: Answers

Cardinality Homework Solutions

CHAPTER I: Vector Spaces

CS 336. of n 1 objects with order unimportant but repetition allowed.

ECE-S352 Introduction to Digital Signal Processing Lecture 3A Direct Solution of Difference Equations

Lecture Overview. 2 Permutations and Combinations. n(n 1) (n (k 1)) = n(n 1) (n k + 1) =

Integrable Functions. { f n } is called a determining sequence for f. If f is integrable with respect to, then f d does exist as a finite real number

On the distribution of coefficients of powers of positive polynomials

CSE 1400 Applied Discrete Mathematics Number Theory and Proofs

Combinatorics and Newton s theorem

M17 MAT25-21 HOMEWORK 5 SOLUTIONS

Archimedes - numbers for counting, otherwise lengths, areas, etc. Kepler - geometry for planetary motion

A brief introduction to linear algebra

arxiv: v1 [math.nt] 10 Dec 2014

62. Power series Definition 16. (Power series) Given a sequence {c n }, the series. c n x n = c 0 + c 1 x + c 2 x 2 + c 3 x 3 +

6 Integers Modulo n. integer k can be written as k = qn + r, with q,r, 0 r b. So any integer.

On a Smarandache problem concerning the prime gaps

Stochastic Matrices in a Finite Field

page Suppose that S 0, 1 1, 2.

SEQUENCES AND SERIES

M A T H F A L L CORRECTION. Algebra I 1 4 / 1 0 / U N I V E R S I T Y O F T O R O N T O

Math 61CM - Solutions to homework 1

MATH10212 Linear Algebra B Proof Problems

The Binomial Theorem

Dupuy Complex Analysis Spring 2016 Homework 02

(b) What is the probability that a particle reaches the upper boundary n before the lower boundary m?

What is Probability?

A Note on the Symmetric Powers of the Standard Representation of S n

A Combinatorial Proof of a Theorem of Katsuura

Lecture 10: Mathematical Preliminaries

TR/46 OCTOBER THE ZEROS OF PARTIAL SUMS OF A MACLAURIN EXPANSION A. TALBOT

1 Last time: similar and diagonalizable matrices

Math 680 Fall Chebyshev s Estimates. Here we will prove Chebyshev s estimates for the prime counting function π(x). These estimates are

LECTURE NOTES, 11/10/04

Introduction To Discrete Mathematics

Transcription:

Uiversity of Miesota, School of Mathematics Math 5705: Eumerative Combiatorics, all 2018: Homewor 3 Darij Griberg October 15, 2018 due date: Wedesday, 10 October 2018 at the begiig of class, or before that by email or cavas. Please solve at most 4 of the 6 exercises! 1 Exercise 1 1.1 Problem Let A ad B be two sets, ad let f : A B be a map. A left iverse of f shall mea a map g : B A such that g f id A. We say that f is left-ivertible if ad oly if a left iverse of f exists. (It is usually ot uique.) Assume that the sets A ad B are fiite. (a) If the set A is oempty, the prove that f is left-ivertible if ad oly if f is ijective. 1 (b) Assume that f is ijective. Prove that the umber of left iverses of f is A B A. 1.2 Solutio 1 This holds eve whe A ad B are ifiite. eel free to prove this if you wish. 1

Solutios to homewor set #3 page 2 of 5 2 Exercise 2 2.1 Problem Let A ad B be two sets, ad let f : A B be a map. A right iverse of f shall mea a map h : B A such that f h id B. We say that f is right-ivertible if ad oly if a right iverse of f exists. (It is usually ot uique.) Assume that the sets A ad B are fiite. (a) Prove that f is right-ivertible if ad oly if f is surjective. 2 (b) Prove that the umber of right iverses of f is f 1 (b). Here, f 1 (b) deotes the set of all a A satisfyig f (a) b. b B 2.2 Solutio 3 Exercise 3 3.1 Problem (a) Prove that ( ) 1/2 ( 1 4 ) ( ) 2 for each N. (b) Prove that 0 ( 2 )( ) 2 ( ) 4 for each N. [Hit: Part (b) is highly difficult to prove combiatorially. Try usig part (a) istead.] 3.2 Solutio 2 This holds eve whe A ad B are ifiite, if you assume the axiom of choice. But this is ot the subject of our class. Darij Griberg, 00000000 2 dgriber@um.edu

Solutios to homewor set #3 page 3 of 5 4 Exercise 4 4.1 Problem Recall oce agai the iboacci sequece (f 0, f 1, f 2,...), which is defied recursively by f 0 0, f 1 1, ad f f 1 + f 2 for all 2. (1) It is easy to see that f 1, f 2, f 3,... are positive itegers (which will allow us to divide by them soo). ( ) or ay N ad Z, defie the ratioal umber (a slight variatio o the correspodig biomial coefficiet) by ( ) f f 1 f +1, if 0; f f 1 f 1 0, otherwise. (a) Let be a positive iteger, ad let N be such that. Prove that ( ) ( ) ( ) 1 1 f +1 + f 1 1 where we set f 1 1. ( ) (b) Prove that N for ay N ad N., 4.2 Solutio 5 Exercise 5 5.1 Problem Let j N, r R ad s R. Prove that j ( )( ) j r s ( 1) s j. j 0 [Hit: irst, argue that it suffices to prove this oly for s N ad r Z satisfyig r sj. Next, cosider r distict stoes, sj of which are arraged i j piles cotaiig s stoes each, while the remaiig r sj stoes are formig a separate heap. How may ways are there to pic j of these r stoes such that each of the j piles loses at least oe stoe?] 5.2 Solutio Darij Griberg, 00000000 3 dgriber@um.edu

Solutios to homewor set #3 page 4 of 5 Let N. The summatio sig 6 Exercise 6 6.1 Problem shall always stad for a sum over all subsets I of []. (This sum has 2 addeds.) Let A 1, A 2,..., A be umbers or polyomials or square matrices of the same size. (Allowig matrices meas that A i A j is ot ecessarily equal to A j A i, so beware of usig the biomial formula or similar idetities!) (a) Show that ( 1) I ( i I A i ) m (i 1,i 2,...,i m) [] m ; {i 1,i 2,...,i m}[] A i1 A i2 A im for all m N. (Example: If 2 ad m 3, the this is sayig (A + B) 3 A 3 B 3 + 0 3 AAB + ABA + ABB + BAA + BAB + BBA, where we have reamed A 1 ad A 2 as A ad B.) (b) Show that ( 1) I ( i I A i ) m 0 for all m N satisfyig m <. (Example: If 3 ad m 2, the this is sayig (A + B + C) 2 (A + B) 2 (A + C) 2 (B + C) 2 + A 2 + B 2 + C 2 0 2 0, where we have reamed A 1, A 2, A 3 as A, B, C.) (c) Show that ( ) ( 1) I A i A σ(1) A σ(2) A σ(), i I σ S where S stads for the set of all (!) permutatios of []. (Example: If 3, the this is sayig (A + B + C) 3 (A + B) 3 (A + C) 3 (B + C) 3 + A 3 + B 3 + C 3 0 3 ABC + ACB + BAC + BCA + CAB + CBA, where we have reamed A 1, A 2, A 3 as A, B, C.) [Hit: You ca use the product rule, which says the followig: Darij Griberg, 00000000 4 dgriber@um.edu

Solutios to homewor set #3 page 5 of 5 Propositio 6.1 (Product rule). Let m ad be two oegative itegers. Let P u,v, for all u [m] ad v [], be umbers or polyomials or square matrices of the same size. The, (P 1,1 + P 1,2 + + P 1, ) (P 2,1 + P 2,2 + + P 2, ) (P m,1 + P m,2 + + P m, ) P 1,i1 P 2,i2 P m,im. (i 1,i 2,...,i m) [] m (This frighteig formula merely says that a product of sums ca be expaded, ad the result will be a sum of products, with each of the latter products beig obtaied by multiplyig together oe added from each sum. You have probably used this sometime already.) ] 6.2 Solutio Darij Griberg, 00000000 5 dgriber@um.edu