SBI ASSOCIATE JUNIOR ASST - 2 [PH-I] (SOLUTION) MATHS 3. (2) (2 9) + (3 8) = (5 4) +? 228 + 04 = 20 + x 332 = 20 + x x = 22 32. (3) 5% of 524 2% of 985 +? = 20% of 423 5 2 20 524 985 x 423 00 00 00 78.6 9.7 + x = 84.6 9.7 + x = 84.6 78.6 x = 84.6 78.6 + 9.7 x = 25.7 33. (3) 52 225? 2 2 (39) (5) x 39 + 5 = x 54 = x 34. () (7) 8.9 (343).7 (49) 4.8 = 7? (7) 8.9 (7 3 ).7 (7 2 ) 4.8 = 7 x (7) 8.9 (7) 5. (7) 9.6 = 7 x (7) (7) 8.9 5. 9.6 x (7) 7 (7) 8.9 (7) 5. (7) 9.6 = 7 x (7) 3.4 = (7) x x = 3.4 35. () 52 8 = (228 9) 2 =? 228 229 26 + = x 9 9 26 + 44 = x x = 360 36. (2) 47.25 4.72 4.53 =? 47.25 46.25 = x 37.00 = x x = 37 37. (4) 7 2 + 3 4 4 3 =? 2 49 + 8 64 = x 2 30 64 = x 2 66 + 2 = x x = 87 38. () (504.4 4) 3) =? 504.4 x 4300 x = 277 00 x = 2.77 39. (5) 342 6 28 = 099 +? 40. (5) 4. (3) 342 6 28 = 099 + x 596 = 099 + x x = 8497 5 of 2 7 of 8 3 of 4095 =? 5 2 7 8 3 4095 = x x = 624 Hence, the wrong number is 38. Right number = 2 3 + 3 = 36 + 3 = 39 42. (3) 43. (5) Hence, the wrong number is 56. Right number = 32 + (5) 2 = 32 + 25 = 57 Hence, the wrong number is 78. Right number = 59 + 9 = 78
44. (4) 49. (2) Let sum = P, then for 20 yr, SI = (3P P) = 2P 45. (2) So, the wrong number is 32. Right number = 9 2 + 2 6 = 8 + 2 = 30 So, the wrong number is 34650. Right number = 7325 3 = 5975 46. () According to the question, Average age of man and his twin sons = 30 Total age = 30 3 = 90 yr According to the question, Ratio of father and one son = 5 : 2 Ratio of father and both the sons = 5 : 2 : 2 (As sons are born on the same day) 5x + 2x + 2x = 90 or 9x = 90 x = 0 Age of father = 5 0 = 50 yr 47. (4) Let usual speed and usual time taken by the jogger are x and t, respectively. Let his new speed x. Then xt = x' 3 4 t x = 3 4 x' x = 4 3 x Thus, he has to increase his speed by 4 x x 3 00% i.e. 33 % x 3 48. (4) Let quantitites of two types of tea costing ` 8 per kg and ` 20 per kg be 5x kg and 3x kg respectively. Then, CP of tea SP of tea Profit per cent = 68 x 50 x 00% 50x = 8 00% = 2% 50 = 8 5x + 20 3x = 90x + 60x = 50x = 2 8x = 68x 2P = P R 20 00 2 = R 5 R = 0% Again, for another time (T), SI = (2P P) = P P = P 0 T 00 T = 0 yrs Fast track methed:- Here, n = 3, m = 2, T = 20 yr T 2 = m n T = 2 20 = 0 yr 3 50. (3) Given, P = 85220, R = 5% (increases) and n = 3 yr Acording to the formula, P Population n yr ago = 2 R + 00 (by Technique 5) 85520 = 3 5 00 = 85220 2 2 2 20 20 20 85220 20 2020 = 222 = 20 20 20 20 = 60000 5. (4) 4 leaps of cat = 3 leaps of dog leap of cat = 3 leap of dog 4 Cat takes 5 leaps feor every 4 leaps of dog Required ratio = (5 Cat's leap) : (4 Dog's leap) 3 = 5 dog's leap 4 : (4 Dog's leap) = 5 : 6 Direct Approach 2
52. (3) Let the container initally contains 55. (2) Let the certain distance be d and 6L of liquid. time t. Let a L of liquid be compressing water. Now, by given condition, Quantity of water in the new mixture d (t +5) = (t + 5) min = 6a = 6 + a 6 L 3 60 h 20d = t + 5 Quantity of milk in the new mixture t = 20d 5 0a = 0 6 L According to the question, 6 6a 6 + a = 0 0a 6 96 6a + 6a = 60 0a 96 + 0a = 60 0a 20a = 64 a = 64 20 = 6 5 Part of mixture replaced = 6 = 6 5 5 53. (2) Let age of Purvi = x yr Then, age of Anil =.5x yr According to the question,.5x 8 25 x 8 8 27x + 44 = 25x + 200 x = 56 2 = 28 54. (4) Given, M = 20, M 2 = 20 x D = 64, D 2 = 60 W = 2 3 and W 2 = 3 According to the formula, MD M2D2 W W 2 2064 (20 x) 60 2 3 3 20 64 (20 x ) 260 (20 x) = 64 x = 20 64 = 56 Now, 56 men can discharged to finish the work in time. and d = (t 5) min 4 = (t 5) 60 h 5d = t 5 t = 5d + 5 From Eqs (i) and (ii), we get 20d 5 = 5d + 5 5d = 30 d = 6 km 56. (3) Relative speed of train = Speed of train + Speed of car 90 = Speed of train + 5 Speed of train = 90 5 = 75 km/hr 57. () Given, Summer's speed in still water = x = 9 km/h Rate of stream = y = 6 km/h Speed of downstream = x + y = 9 + 6 = 5 km/h 58. (3) There is a 7 digit telephone number but exreme right and extreme left positions are fixed. i.e. 6 5 i.e. Required number of ways = 8 7 6 5 4 = 6720 59. (2) Required probability Given, n = 5 and r = 3 Then, success P = 3 4 Failure, q = 3 4 = 4 Man hit the target thrice 3 2 3 3 = 5 C 3 4 4 + 3 5 C 4 4 4 + 5 5 C 3 5 4 = 270 024 + 405 024 + 243 024 = 98 024 = 459 52 3
60. (c) The bells will toll together after 65. (2) One knows that for every % the time in seconds equal to the LCM angle substended is 3.6 degrees of 9, 6, 4, 0 and 8. in a pie-chart. Thus, the LCM of 9, 6, 5, 0 and 8 is proportion of the Urban Roads LCM = 2 2 3 3 5 2 = 360 In one hour, the rings will toll together 3600 times = 0 times 360 6. () Total length of roads in 2006 from the bar garp is 3000,000 kms. From the pie chart the proportion of length of highways in 2006 is 86%. Hence the length of highways in 2006 =3000,00 86%= 2580,000 kms 62. (2) From the pie-chart, it can be seen that the highways constitute 86% and urban roads constitute 7% of the total road lengths. Hence, the ratio of Highways to Urban Roads is 7 86 2 : 63. (3) Assessment value of Highways in 2006 = 0.86 3,0000.5 lakh = ` 3870000 lakh Assessment value of Urban Roads in 2006 =0.07 3,000,000 lakh = ` 20000 lakh Assessment value of Project Roads in 2006 = 0.07 3,000,000 0.75 lakh = ` 57500 lakh Total value = 3870000 + 20000 + 57500 = ` 4237500 lakh 64. () In the year 2003, the total length was 25,00,000 kms and the highways formed 80% of the same, which is equal to 20,00,000 kms. The highways were 25,80,000 kms in the year 2006. Hence, the increase in the length of highways was (25,80,000 20,00,000) = 5,80,000 kms. Thus, the increase in percentage terms = 5,80,000 20,00,000 00 = 29% 72 from the year would be 3.6 = 20%. In the year 2002, the total road length as can be seen from the bar chart = 24,00,000 kms. Thus 20% of 24,00,000 = 480,000 kms. REASONING (66-70): 66. () Find the corresponding letters from the right. 67. (5) The first letter follows +, +2, +3, +4,... The second follows +2, +3, +4, +5,... 68. (2) Move two letters backward in the alphabetical series for each corresponding letter. 69. (5) 70. (3) Hence P is either son or daughter of Q. (7-74): ze lo ka gi = must save some money... (i) fe ka so ni = he made good money... (ii) ni lo da so = he must be good... (iii) we so ze da = be good save grace... (iv) From (i) and (iii), lo = must... (v) From (i) and (iv), ze = save... (vi) From (ii), (iii) and (iv), so = good... (vii) From (i) and (ii), ka = money... (viii) 4
From (i), (v), (vi) and (viii), gi = some 82. (5) None of the teachers have the same... (ix) compulsory and optional subjects. From (ii), (iii) and (vii), ni = he... (x) 83. (3) E and F have Physics and From (ii), (vii), (viii) and (x), fe = made Mathematics as the compulsory... (xi) and optional subjects. From (iii), (v), (vii) and (x), da = be From (iv), (vi), (vii) and (vii), we = grace 84. (4) A, B and C have History as compulsory... (xiii) subject, from the above table. 7. (3) 72. (5) 73. () 74 (4) (85-90): (75-79): 85. (5) All squares are rings + All rings are 75. (5) R < P < U < K U < L triangles = A + A = A = All squares I. K > R is true. are triangles conversion Some II. L > R is true. triangles are squares. Hence 76. (3) H = I < R < M Hence M > I conclusion II ('At least some I. M = I triangles are squares', i.e. ('Some II. M > I triangles are squares') follows. Either I or II is true. Again, No rectangle is a triangles 77. (2) D > H > N H > I < S + Some triangles are rings I. N < S is not true. (converse of 'All rings are triangles') II. I < D is true. = E + I = O* = Some rings are not 78. (2) W < Y < P < O < I I. Y < I is false. rectangle. Now, draw the all II. O > W is true. possible venn diagrams for the 79. (5) A > B > C > F above conclusion as given below: E > D > C > Z I. A > Z is true. II. F < E is true. (80-84): On the basis of the given information we have the following (Some rings are rectangles.) table: We don't need to draw other 80. () From the table C's compulsory subject is History. 8. (4) The female member is the person who teaches English i.e. D. possibilities. Therefore, the possibility, i.e. conclusion I follows. 86.(4) No flat is an appartment + Some apartments are bunglaows (conversion of 'Some bunglaows are apartments) = E + I = O* = Some bungalows are not flats. Therefore neither conclusion I nor conclusion II follows. 5
87. () Some solids are liquids + All 88. () All XYZ are alphabets (A) liquids are water = I + A = I = conversion Some alphabets are XYZ (I) + No XYZ is a day (E) = Some solids are water. Now, draw I + E = O = Some alphabets are all possible venn diagrams for the not days. Therefore conclusion I above conclusions as given below: does not follow. Again, All ABC Possibility I: are XYZ + All XYZ are alphabets = A + A = A = All ABC are alphabets conversion Some alphabets are ABC (I). Therefore, conclusion II follows. 89. () From the statement 'Some [Some water is solids.] teachers are professors' there are Possibility II: possibility that 'All teachers are professors' and 'All professors are teachers'. Similarly from the statement 'Some lecturers are [All gases are water.] teachers' there is a possibility Possibility III: that 'All teachers are lecturers'. Again, All professors are teachers + All teachers are lecturers = A + A = A = All professors are lecturers is a possibility. But [All water is gas.] conclusion II does not follow. It is clear from the above that 90. (2) From the above conclusion I does conclusion I, i.e. 'All solids being not follow. Again, from the above, water is a possibility' follows. we have the following possibility: Again, from the given premise, 'All lecturers are teachers' and 'All teachers are professors'. Now, All 'some solids are liquid', we can lecturers are teachers + All have the possibility of being 'All teachers are professors = A + A = solids are liquids'. Therefore, All A = 'All lecturers are professors. such solids which are not water Therefore conclusion II, i.e. 'All can be liquids. Hence, Conclusion lecturers being professor is a II does not follow. possibility' follows. 6
(9-95): 97. (5) I is implicit in the very giving of the advice. II is implicit in the condition attached. 98. () I is implicit: when you urge someone to do something, you assume a positive response. For some reason, II is not implicit. 99. (2) If I were implicit, such decision 9. (5) Between P and R is S. 92. (4) T is at the third place, from the would not be taken. II is implicit above. in the purpose of fund-rasing that 93. () P is certainly greater than R. has been mentioned in the 94. (4) U is the tallest, hence he plays statement. basketball. 00. (4)When a warning is given, it is 95. (4) We have not information about S, assumed that it will be heeded hence he can play either cricket to. Hence I is implicit. II is not or badminton. believed to the motive behind a (96-00): warning (even though the police 96. (2) The driver does not have control often create such an impression on what the auto driver will do. Hence I is not implicit. But II is among the people that they are implicit as one assumes the seen as extorionists; well! Let that outcome while taking an action. be on a lighter note.) 7
SBI ASSOCIATE JUNIOR ASST - 2 (PH-I] [ANSWER KEY]. (5) 2. (3) 3. (4) 4. (5) 5. (3) 6. (2) 7. () 8. (5) 9. () 0. (2). (3) 2. (2) 3. (4) 4. () 5. (5) 6. () 7. (5) 8. () 9. (2) 20. (4) 2. () 22. (5) 23. (4) 24. (3) 25. (2) 26. () 27. (5) 28. (2) 29. (5) 30. (3) 3. (2) 32. (3) 33. (3) 34. () 35. () 36. (2) 37. (4) 38. () 39. (5) 40. (5) 4. (3) 42. () 43. (5) 44. (4) 45. (2) 46. (2) 47. (4) 48. (4) 49. (2) 50. (3) 5. (3) 52. (4) 53. (2) 54. (4) 55. (2) 56. (3) 57. () 58. (3) 59. (2) 60. (3) 6. () 62. (2) 63. (3) 64. () 65. (2) 66. () 67. (5) 68. (2) 69. (5) 70. (3) 7. (3) 72. (5) 73. () 74. (4) 75. (5) 76. (3) 77. (2) 78. (2) 79. (5) 80. () 8. (4) 82. (5) 83. (3) 84. (4) 85. (5) 86. (4) 87. () 88. () 89. () 90. (2) 9. (5) 92. (4) 93. () 94. (4) 95. (4) 96. (2) 97. (5) 98. () 99. (2) 00. (4) Note:-. For any question paper related queries call/whatsap/message on 8287900900. 2. For any issue related to RESULT Processing, kindly contact us on 8287200200. 3. If your opinion differs regarding any answer, please message the mock test and question number to 8287500500. 8