U10057 FOREIGN TECHNOLOGY DIVISION. if. AIR FORCE SYSTEMS COMMAND. Fl WRIGHT-PATTERSON AIR FORCE BASE OHIO - 8.

Similar documents
TRANSLATION FOREIGN TECHNOLOGY DIVISION AIR FORCE SYSTEMS COMMAND [RD OHIO WRIGHT-PATTERSON AIR FORCE BASE

UNCLASSIFIED AD ARMED SERVICES TECHNICAL INFORMATION AGENCY ARLINGTON HALL STATION ARLINGT0 12, VIRGINIA UNCLASSIFIED

UNCLASSIFIED AD DEFENSE DOCUMENTATION CENTER FOR SCIENTIFIC AND TECHNICAL INFORMATION CAMERON STATION. ALEXANDRIA, VIRGINIA UNCLASSIFIED

Fluid Dynamics Problems M.Sc Mathematics-Second Semester Dr. Dinesh Khattar-K.M.College

Physics for Scientists and Engineers 4th Edition, 2017

UNCLASSIFIED AD ARMED SERVICES TECHNICAL INFORMATION AGENCY ARLINGTON HALL STATION ARLINGTON 12, VIRGINIA UNCLASSIFIED

V (r,t) = i ˆ u( x, y,z,t) + ˆ j v( x, y,z,t) + k ˆ w( x, y, z,t)

Application of Viscous Vortex Domains Method for Solving Flow-Structure Problems

Physics Mechanics. Lecture 32 Oscillations II

UNCLASSIFIED AD ARMED SERVICES TECHNICAL INFORMATION AGENCY ARLINGTON HALL STATION ARLINGTON 12, VIRGINIA UNCLASSIFIED

The Calculus of Vec- tors

Translational and Rotational Dynamics!

Chapter 14. Oscillations. Oscillations Introductory Terminology Simple Harmonic Motion:

Fundamentals of Fluid Dynamics: Elementary Viscous Flow

AP Physics C Mechanics Objectives

PRACTICE QUESTION PAPER WITH SOLUTION CLASS XI PHYSICS

AO-A FOREIGN TECHNOLOGY.DIV WRIGHT-PATTERSON AFB 0ON F/G 13/7 MEMORY DEVICE U) MAR A2 N A PASHKIN, V N MALYUTIN UNCLASSIFIED FTD-ID(RS)T 0163

AE/ME 339. K. M. Isaac Professor of Aerospace Engineering. 12/21/01 topic7_ns_equations 1

2. FLUID-FLOW EQUATIONS SPRING 2019

Candidates must show on each answer book the type of calculator used. Only calculators permitted under UEA Regulations may be used.

d v 2 v = d v d t i n where "in" and "rot" denote the inertial (absolute) and rotating frames. Equation of motion F =

Chapter 5. The Differential Forms of the Fundamental Laws

expression that describes these corrections with the accuracy of the order of 4. frame usually connected with extragalactic objects.

COURSE NUMBER: ME 321 Fluid Mechanics I 3 credit hour. Basic Equations in fluid Dynamics

Selected Topics in Physics a lecture course for 1st year students by W.B. von Schlippe Spring Semester 2007

arxiv: v2 [math-ph] 14 Apr 2008

EhhhhEE. AD-Ri FERROMRfGNETIC DIELECTRIC SUBSTRNCE(U) FOREIGN 1/- - - TECHNOLOGY DIV WRIGHT-PATTERSON AFB ON

The... of a particle is defined as its change in position in some time interval.

General Solution of the Incompressible, Potential Flow Equations

Rigid bodies - general theory

CHAPTER 7 SEVERAL FORMS OF THE EQUATIONS OF MOTION

Differential criterion of a bubble collapse in viscous liquids

Fundamentals Physics. Chapter 15 Oscillations

Simple and Physical Pendulums Challenge Problem Solutions

Lecture 3. Rotational motion and Oscillation 06 September 2018

Advanced Heat and Mass Transfer by Amir Faghri, Yuwen Zhang, and John R. Howell

CIRCULAR MOTION, HARMONIC MOTION, ROTATIONAL MOTION

Chapter 1 Fluid Characteristics

INFRCNGCAE ELMNSFR. m E-1525CAT(RN LIKE..(U) AG. FOREIGN WRIGHT-PATTERSON AFB OH 0 S RAYNUS ET AL. e8 APR 85 ENOCN

Oscillatory Motion. Solutions of Selected Problems

Vortex motion. Wasilij Barsukow, July 1, 2016

7. The gyroscope. 7.1 Introduction. 7.2 Theory. a) The gyroscope

fll m L31 12 MICROCOPY RESOLUTION TEST CHART f41l BUREAU OF STAI4DAN A mill

2.29 Numerical Fluid Mechanics Fall 2011 Lecture 7

fla'

Fluid Dynamics Exercises and questions for the course

Q1. Which of the following is the correct combination of dimensions for energy?

Please Visit us at:

Differential relations for fluid flow

Cams. 774 l Theory of Machines

c) LC=Cl+C2+C3; C1:x=dx=O; C2: y=1-x; C3:y=dy=0 1 ydx-xdy (1-x)~x-x(-dx)+ = Jdldx = 1.

Theoretical physics. Deterministic chaos in classical physics. Martin Scholtz

18.02 Multivariable Calculus Fall 2007

Vector Calculus, Maths II

MATH20411 PDEs and Vector Calculus B

For a rigid body that is constrained to rotate about a fixed axis, the gravitational torque about the axis is

In this section, mathematical description of the motion of fluid elements moving in a flow field is

Tutorial-1, MA 108 (Linear Algebra)

7 Pendulum. Part II: More complicated situations

2007 Problem Topic Comment 1 Kinematics Position-time equation Kinematics 7 2 Kinematics Velocity-time graph Dynamics 6 3 Kinematics Average velocity

Physics C: Mechanics

MATH 32A: MIDTERM 2 REVIEW. sin 2 u du z(t) = sin 2 t + cos 2 2

LANMARK UNIVERSITY OMU-ARAN, KWARA STATE DEPARTMENT OF MECHANICAL ENGINEERING COURSE: MECHANICS OF MACHINE (MCE 322). LECTURER: ENGR.

MAT389 Fall 2016, Problem Set 4

Classical Mechanics III (8.09) Fall 2014 Assignment 3

M04M.1 Particles on a Line

Homework 1. Due whatever day you decide to have the homework session.

Therefore, the control volume in this case can be treated as a solid body, with a net force or thrust of. bm # V

Classical Mechanics Comprehensive Exam Solution

0J2 - Mechanics Lecture Notes 4

PHYS 1114, Lecture 33, April 10 Contents:

28. Pendulum phase portrait Draw the phase portrait for the pendulum (supported by an inextensible rod)

Chapter 9 Global Nonlinear Techniques

UNIVERSITY OF OSLO. Faculty of Mathematics and Natural Sciences. MEK4300/9300 Viscous flow og turbulence

A L A BA M A L A W R E V IE W

q 1 F m d p q 2 Figure 1: An automated crane with the relevant kinematic and dynamic definitions.

Final Examination Thursday May Please initial the statement below to show that you have read it

Introduction. Nature of Mass

DIVIDED SYLLABUS ( ) - CLASS XI PHYSICS (CODE 042) COURSE STRUCTURE APRIL

Problem Solving Session 10 Simple Harmonic Oscillator Solutions

Physics Waves & Oscillations. Mechanics Lesson: Circular Motion. Mechanics Lesson: Circular Motion 1/18/2016. Spring 2016 Semester Matthew Jones

θ + mgl θ = 0 or θ + ω 2 θ = 0 (2) ω 2 = I θ = mgl sinθ (1) + Ml 2 I = I CM mgl Kater s Pendulum The Compound Pendulum

INSTITUTE OF AERONAUTICAL ENGINEERING (Autonomous) Dundigal, Hyderabad

PRACTICE PROBLEMS. Please let me know if you find any mistakes in the text so that i can fix them. 1. Mixed partial derivatives.

Angles and Applications

UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS General Certificate of Education Advanced Level

2.25 Advanced Fluid Mechanics Fall 2013

PHYSICS. Course Structure. Unit Topics Marks. Physical World and Measurement. 1 Physical World. 2 Units and Measurements.

MATHEMATICS EXTENSION2

ON LAMINAR FLOW THROUGH A CHANNEL OR TUBE WITH INJECTION: APPLICATION OF METHOD OF AVERAGES*

Mathematics Extension 2

Uniform Circular Motion AP

ONE-DIMENSIONAL TWO-PHASE CONSTANT LAO FOW IN COMBUSTION CHAMBER 0F 50.U) FOREION TECHNOLG 00 IV AD-A

Chapter 9 Circular Motion Dynamics

Analysis of Fluid Film Stiffness and Damping coefficient for A Circular Journal Bearing with Micropolar Fluid

We now begin with vector calculus which concerns two kinds of functions: Vector functions: Functions whose values are vectors depending on the points

Chapter 12 Vibrations and Waves Simple Harmonic Motion page

where x 0 is arbitrary.

INTEGRAL CALCULUS DIFFERENTIATION UNDER THE INTEGRAL SIGN: Consider an integral involving one parameter and denote it as

Week 2 Notes, Math 865, Tanveer

Transcription:

Fl - - 63-511 - 8.TRANSLATION LLcOCLAIN CD FAPYIA EDLMHVN CAVITIES FILLED WITH A VISCOUS FLUID dc~cp. S. Krasnoshchekov By FOREIGN TECHNOLOGY DIVISION AIR FORCE SYSTEMS COMMAND WRIGHT-PATTERSON AIR FORCE BASE OHIO U10057 if.

FTD-T-63-51i/i+2+4 UNEDITED ROUGH DRAFT TRANSLATION OSCILLATIONS OF A PHYSICAL PENDULUM HAVING CAVITIES FILLED WITH A VISCOUS FLUID By: P. S. Krasnoshchekov English Pages: 15 Source: Soviet Periodical, Prikladnaya matematika i mekhanika, Vol. XXVII, Issue 2, pp. 193-202. T-L14 SOV/40-63-27-2 THIS TRANSLATION IS A RENDITION OF THE ORIGI- NAL FOREIGN TEXT WITHOUT ANY ANALYTICAL OR EDITORIAL COMMENT. STATEMENTS OR THEORIES PREPARED BY, ADVOCATEDOR IMPLIED ARE THOSE OF THE SOURCE AND DO NOT NECESSARILY REFLECT THE POSITION TRANSLATION DIVISION OR OPINION OF THE FOREIGN TECHNOLOGY DI- FOREIGN TECHNOLOGY DIVISION VISION. WP-AFB, OHIO. FTD-TT- 6 3-511/1+2+4 Date jo June 1963 P

OSCILLATIONS OF A PHYSICAL PENDULUM HAVING CAVITIES FILLED WITH A VISCOUS FLUID P. S. Krasnoshchekov (Moscow) An asymptotic method has been proposed [i] for investigating the nonstationary motions of viscous incompressible fluids with large Reynolds numbers (NRe), which arise during the oscillation of various solids which either contain a fluid or are emersed in one, and also during the oscillation of liquid volumes having a free surface. In this article the idea of this method is applied to the investigation of small oscillations of a physical pendulum having cavities completely filled with an incompressible viscous fluid. i. The pressure of a fluid contained in the cavity of an oscillating pendulum (Fig. i) is described by the Navier-Stokes equations and the continuity equation: T/T + (V' V') V=''- v (7' x 0') div' =0 (i) Here U is the potential of the mass forces acting on the fluid. At the edge of the cavity the conditions of adhesion of fluid particles to the walls of the cavity should be satisfied. This gives the following boundary conditions: FTD-TT-63-5ii/i+2+4 -I-

U. - Y, = X,, w (1.2) Here e is the deflection angle of the pendulum from the equilibrium position while u', v', w', are the components of the velocity vector V'. We assume that = V + V where Vo is the velocity vector of the center of mass of the cavity, and we convert to a new system of coordinates (x", y, z") with its origin at the center of mass of the cavity and with axes parallel to the axes of the stationary system of coordinates (x', y', z'). In the new system of coordinates we will have ave a-+ (V'.V') V" = V"p - V (V'x Q'), div '=O., Here Q, =v V, " ' --p/p - U - (Vo'.r') assume: At the boundary of the cavity: U,=- VX'6. w=o (1.4) We will refer all quantities to a characteristic scale. Let us t' =t, =Rx, / = Ry, z= Rz, V'= (RV f" T fl = T2 (p, a, N.e = vvt where T is the characteristic period of one oscillation, R is the characteristic dimension of the cavity, a is the characte'istic amplitude, and NRe is the Reynolds number. Equations (1.3) and Boundary Conditions (1.4) are written in independent variables in the form: -+-- a (V.V) V -Y-- (V x 0), divv-0 (1.6) FTD-TT-63-51/i+2+4-2-

At the boundary of the cavity: U=-Y4,,= X6, w.=o (1.7) In the system of equations (1.6) the characteristic amplitude a is a factor for nonlinear terms. We will consider oscillations with a small amplitude and later linearize Eqs. (1.6), disregarding magnitudes of the order a. The linearized system of equations appears as follows: Ov 1 (1.8)., "-- 7- V-- (17.x f), div V ---O The object of this article is to investigate those forms of oscillations for which the solution may be represented in the form: ~c = e -t), V =Ce lu (X, Y, z) (1.9) Setting p = cei'( (x, y, z), Q = ce-,tw (z, y, z), we have for such motions: : u=v -l (v x), divu=0 (1.O) At. the boundary of the cavity: Ux=- yor, Uv = x, U, = (1.11) Relationship (i.10) indicates that the Vector Vf is the sum of the potential and solenoidal vectors. Such a presentation makes it possible to separate the equations, having obtained a separate equation for each unknown function. Actually, having taken the div of both sides of the first equation of System (1.10) we obtain: (D= 0 (1.12) i.e., a function of D which is harmonic in a volume filled with a fluid. Having taken the cure of both sides of the same equation we.have: equation. "Re Thus each of the unknown functions 0, 1 satisfies a separate FTD-TT-63-5ii/i+2+4-3-

At the boundary of the cavity these functions are linked by the following boundary conditions: 90,, (ev,,... ',, xo 80. 1 O/ O'P' ) y5 O- -I 'IF. - 6 / ry Fe ax~i Here Yx y't yi'z are components of vector. A fourth boundary condition determined at the limit of the projection of vector ' onto the normal to the surface of the cavity will be introduced later in a specially selected curvilinear system of coordinates. Let us consider cavities which appear as figures of revolution whose axes are perpendicular to the plane of oscillations of the body. We will introduce a curvilinear system of coordinates associated with the surface of the cavity. In the case under consideration it is convenient to introduce the following coordinates: n - distance along the inner normal to the surface of the cavity taken from the surface inward, q - angle which determines the position of the meridian plane, and A - length of arc along the meridian (Fig. 2). The variables in the (x,y,z) coordinate system are associated with the variables n, a, in the curvilinear coordinate system by the following relationships: a x-[r, + Ssin r(v)dp - ni cos y fl)]sin ax= [r(~ n cos O()J siaa 0 Y=[ro+ sin. (0) d - n cos T (P)]cosa - [r (P)- ncos @)I cosa 0 0-4-~

Here, r O = radius of a circle obtained in the cross-section of the cavity by a plane perpendicular to the axis of symmetry and passing through the center of mass of the cavity; r( ) = radius of the circle formed by points on the surface of the cavity having the coordinate f; 7(p) = angle between the tangent to the meridian at thp point with coordinate 0 and the positive direction of the z-axis. We will write Eq. (1.13) and the boundary conditions in the new coordinate system. For simplicity we will use the notation: Then we have in the curvilinear coordinate system: _a 1. Io I + --T'(P) alpt ' [r (3)- n cos 7 (3)] [ + n7' ( a)i[8= \ ( 3 ) - n cos T (.3) 7% + 4--n crs+(a)] [1. + ny'.()] M)] (1.14) - ( 1/, 2, 3) At the edge of the cavity for n-- 0:... o, I, "'!3 '1j~ (1.1.5) O n NRer (P 00t 8(3] '1 oid (P 8(1 +nco (3)) =rt). 8 ap N )-j/ n - ~ OV~jO(1.17) Let us derive the fourth boundary condition. The normal component Tn of the vortex vector Y is defined in terms of the tangential components U a and U of the velocity vector U as follows: ra (I + nt'(r.) -V ) cos cos TrU( (03)) U IrPB-nco0sT(W)[I nt'(p)il da~- At the edge of the cavity the vector U is known; consequently, its components Ua and U are known for n = 0. Differentiation with respect to a and A for n = const is possible, and therefore calculation of the magnitude of Yn for n = 0 presents no particular difficulty After simple calculations we obtain: -5-

. - 2 sin ( a) (1.18) This relationship closes the system of boundary conditions for the unknown functions 0, T i. The quantities Wa, P, T n in Relationships (i.i5)- i.i8), are components of vector ' in the curvilinear coordinate system. They are connected with the componenets 'i by the relationships: I=v '=_ 1 COS a - T' sin a TO 1 = - 'l sin T ()sin & + sin T (A) Cos a.- 'VS COST P) i cos T (P) sin a - 2 cos T () cos a + T3' sin T () (i.9) We will assume that the parameters of the pendulum guarantee a sufficiently large Reynolds number. We will assume: =(1.20) where e is a small dimensionless parameter. The idea of constructing a solution for large Reynolds numbers which was presented by Moiseyev [I] is analogous to the idea of constructing a boundary layer. It is assumed that the vortices which exist in the oscillating fluid contained within the pendulum cavity are concentrated mainly in a thin laygr at the walls of the cavity. This in turn makes it possible to consider the derivatives of the components of the vector T along the normal to the surface of the cavity to be significantly greater than in the tangential directions. Let us "expand" the independent variable n. We set n= eil Solution of the problem formulated will be sought in the form of series to powers of the small parameter a: (Do + e(d +... 9 -To,+ Tit +.. Y - 1, 2,3) (1.21 ) Substituting Series (1.21) into the equations and boundary -6-

conditions and equating to zero the sum of the coefficients for the zero power of the parameter e, we obtain the following problem for the determination of the functions (0 and Toi: &(Do = 0, 0'0, (1=,2.3) (1.22) At the boundary of the cavity, for n = 0: 1. o + "0o'" r (A 2, "o - 70 0 F= 70, Oa+ all -,, a o = (1.23) From the first relationship of Conditions (1.23) we see that the standard derivative of the harmonic function 00 is zero at the boundary of the cavity. Hence it is possible to consider 0 = const without limiting the generality. The components of the vector Y in the curvilinear system of coordinates are associated with the components of the same vector in - the Cartesian coordinate system by Relationships (i.19). These relationships are linear with regard to Toil y 0 2, T03 and the coefficients of T0oi T02' T03 are independent of q; consequently the functions Tal To0, and T On satisfy the same equations as Toil This: T-704, L270o0 07 =,27o (1. 24) At the boundary of the cavity these functions satisfy the following boundary conditions:,- V=0 p = r (;2. -v- -- 0, (1.25) The general solution of the equation satisfied by YTa, T Ton has the following form: and Let Re VF" > 0. By assumption, far from the walls of the cavity there are no vortices. Just as is done in boundary-layer theory, we will consider the value T = w to be the respective internal points -7-

of the cavity sufficiently far from the boundary. Then, in agreement with the assumption concerning the absence of vortices, for c c we will have c I = 0. The arbitrary constant of integration c 2 is determined from 'Conditions (1.25). Finally, for the functions Toa' Top YOn we obtain: 'o. I = 0, - r p ak ;(. 6 We will limit ourselves to determination of only the first terms of Series (1.21). Within the limits of this accuracy we write the components of the absolute velocity vector V' in a stationary system of coordinates with its origin at the point of suspension of the pendulum: ' c T la - r () a cosa e - ; +- 0 (a)el I- W,. 0 27 V -c r fl o sina + 0 (8)] e, (.27) where I is the distance of the center of gravity of the cavity from the suspension axis, relative to the characteristic dimension of the cavity. The resulting solution (1.27) will be asymptotic. Relative to it, we have the following result, proof of which will not be cited here. The difference modulus IV' - Vo' < 0 (8) Here V' is the exact solution of the linearized problem and V10 is the approximate solution of this problem obtained by us. Thus, if the Reynolds number is sufficiently high, the approximate solution assures good accuracy. 2. For a final solution of the problem it is necessary to determine the as yet unknown constant a. For this it is necessary to use the equation of pendulum oscillations which may be obtained using the theorem concerning t1m variation of angular momentum of a system. We have: -8-

D, D D(21 Here Di - volume of the solid; D = volume of cavity; pi and Vi = density and velocity of points of the body; p and V' = density and velocity of a particle of fluid; g = Vector of gravitational acceleration; r' = radius vector from the axis of rotation to the point of the body or fluid. In our case the equation of moments (2.1) yields a projection, which differs from the identical zero, only onto the z' axis. The integrals which enter into (2.1) [returning to dimensional variables according to Formula (1.5)] may be reduced to the following form S(r' x r4v±') d'r}z' = CMVle' a- A (2.2) (x py') d'rij =C (MI"O" + YJ 1 -MQO' 2 ) e"t (MQ n 01d)(.' DD r' - g dc + (r"'g ~l, C '1 +M 1 Here M i - mass of the solid; tj M = mass of the fluid; k = radius of inertia of the solid relative to the axis of suspension of the pendulum; Z' = distance from the axis of suspension to the center of mass of the cavity; I! - distance from the axis of suspension to the center of gravity of the solid; - coordinates of the poles of the cavity. Substituting (2.2), (2.3), and (2.4) into (2.1) we obtain the following equation to define a: + 0 -(Mi k%+,ll's (2.5) We will set a - v% 2 x. Then (2.5) takes the form: -9-

Zwhen y + +q'. (j=y, q') (2.6) We will prove that this equation has only two roots which satisfy the condition Re y> 0. We set y = a.+ ip. After substitution in (2.6), we obtain for the determination of a and A the system (Cgs - 02)t 4' + ' 0 - ' 341 +- qs = 0 (2.(?) 4e 4= - 442 = - P2 = + 3al 0 Determining P2 from the second equation of System (2.7) and substituting it in the first equation we obtain: 640' + 96as'+ 480. + 80 - q' (1&1. + 8a + 1) =0, ' +3.= 3-(2.8) The first equation in (2.8) has only one change of sign of the coefficients. According to Descart's rule this polynomial has one positive root. We are not interested in negative roots since in this case the condition Re /x > 0 is violated. The second equation of (2.8) gives two values of P which differ only in sign. Therefore, Eq. (2.6) has only two roots for the case Re y > 0. We will solve Eq. (2.6) for the two limiting cases: when is large and when. is small. Let us recall that the solution of the problem concerning the motion of a fluid within a pendulum cavity was obtained for a large Reynolds number. In turn, the magnitude of the Reynolds number depends essentially on the characteristic period of one oscillation r/ Im a'l which is determined only after solution of Eq. (2.6). Consequently, of all the possible solutions of Eq. (2.6) which correspond to different parameters of the pendulum it is. possible to use only those which guarantee a sufficiently large Reynolds number. Later we will see that in the limiting cases of large and small & which we examined, it is always possible to select -10-

pendulum parameters such that the Reynolds number remains large. Let us examine the case of large q. We will seek the solution of Eq. (2.6) in the form of a series in powers of i//- Y+ ' ' - (2.9) Substituting (2.9) in (2.6) and equating to zero the sum of the coefficients with identical powers of i/ - the determination of the unknowns Yo, For y 0 we have: whence we obtain: Yi, etc. Yo' + 1 = 0, Reyo>O we obtain equations. For the determination of y. we have - 4y, + I 0 wtan yj 1/ With an accuracy to value of the order of / q- inclusive, we find Y I.. '~ or (a' = 2yl) (2.io) Thus, in the case under consideration the frequency n and amplitude A of the pendulum oscillations will be, respectively, "= "2YY ' A- 2 As v-+ 0, the damping factor approaches zero while the oscillation frequency approaches the frequency c which corresponds to the oscillation of a pendulum with an ideal fluid. We will calculate by what amount the amplitude decreases during each period T - r/lm u'. Denoting this amount by A we have. -ii-

Aiexp Re ex) n Real (2. 11) exp Re (011)0 " exp 1 Determining Re a' and ir a' 'from (2.10) and substituting in (2.11) we obtain: It Is easy to see that the examined case of large _ corresponds to oscillations close to those of a pendulum with an ideal fluid. Let us consider the simplest example. Let the pendulum be a weightless spherical shell filled with a viscous fluid and connected to the suspension axis by a weightless rod (Fg.3). For such a pendulum we will have: 2R Csg q gn k 4v R2 _, (2.12) The characteristic period of one oscillation with an accuracy to values of the order of i/ / is r(2.a3) The magnitude of T increases with an increase in the length I of the pendulum. In this case there is the danger of an inadmissible reduction of the Reynolds number. We will set the Reynolds number NRa L ±0 and evaluate the allowable pendulum lengths I for various values of radius R. By definition NRe = R 2 /vt. In order to keep NRe 0 it is required that T< 7,61or N Suppose that the pendulum is filled with water at a temperature of 20 0 C (v M 1i.011O - 6 m 2 /sec). For R = 0.1 m we have I/R < ±0, i.e., I < im. For R - I m we obtain Z/R < 10, i.e., I < ±0 kmn. With an increase in R the allowable value of 1/R increases as R 3. Thus the range of applicability of solution (2.12) is sufficiently -12-"

broad. Let us now examine the case of extremely small A. We note tht + it is possible to realize small _q not only by increasing the klnem-- viscosity v, which might lead to a reduction in NRe. Actually, ii. the case of the pendulum just considered it is apparent that this.-. '. be achieyed by decreasing the length of the pendulum I or increasing the radius of the cavity R. Let us represent Eq. (2.6) in the following form: Y' (y + 1) - q (2.14) From this it follows that I Y'Y + 1=1-q'l=,q The product IyI ly+il decreases with decreasing _. In this process the factor ly+i cannot approach zero, otherwise the condition Re y > 0 is violated. Consequently the modulus of the unknown root has an order of smallness q Starting from this we will seek the solution of Eq. (2.6) in the form of the following series: Y = q%/ (Yo + q11-yj +.. For the determination of the unknowns yo and y, we obtain Yo,+ I 0, Yo" + 3 y, = 0 From this we find: With an accuracy to values of the order q2/3 inclusive, we have: Y = 9. "t + 23-.) ( -31 q".) For a' we obtain the expression: i;' 7= =' r- 4.V,. ] (2-15) - 3 1, 2,../ 4 /,. -T,../. or, limiting ourselves to magnitudes of the order q /': Just as in the preceding case, we determine by what amount the amplitude drops from its original value during the characteristic period T. FTD-TT-63-5ii/i+2+4-13-

We have A I -expn Reoa/jIrMa, I Using Eq. (2.15) to determine Re a' and lim a', we obtain YT T (2.16) It is apparent that this case differs greatly from the case of osillations of a pendulum "with an ideal fluid. It turns out that it is possible to select a pendulum cavity so large or a pendulum length so small that the influence of Viscosity on the motion of the pendulum cannot be neglected despite large Reynolds numbers. In the case of,extremely small % the amplitude may drop on the order of 84% from its original value during a single swing. We will demonstrate, using as our example the pendulum shown in Fig. 3, that by increasing the radius of the cavity R while keeping I and v constant it is possible to reach as large NRe and as small as desired. For this pendulum we have: R 2'L 2 (2-(7) --- I /..T - (2.08) It is easily seen from (2.18) that N,,-+ w and q-+ 0 as R-+ -. Oscillations of the pendulum in this case are extremely different from oscillations of a similar pendulum with an ideal fluid. Thus, a pendulum filled with water at 200C (v - Li.iO - 6 m 2 /sec) with a cavity radius R - 0. m and a length Z - 0.00016 m will complete 5 oscillations per second, while the same pendulum with an ideal fluid will make 25 oscillations per second. For the pendulum parameters indicated above we will have:?td-tt-63-5ii/i+2+4-14-

q -:, 0.0012, IV, ~.. 101 which completely justifies the use of Solution (2.A7) in this case. Submitted January 29, 1962 Fig.. Fig. 2. Fig. 3. REFERENCES i. N. N. Moiseyev. 0 krayevykh zadachakh dlya lineyarizovanykh uravneniy Nav'ye-Stoksa v sluchaye, kogda vyazkost' mala. Zhurnal vychislit. matemat. i matemat. fiziki, vol. i, No. 3, 196i. FTD-TT-63-5±i/i+2-. -15-

DISTRIBUTION LIST DEPARITMNT OF DEFENSE Nr. Copies MAJOR AIR OOM Nb. CopS.U AFSC SCFDD1 DDC 25 TDBTL 5 HEADQUARTERS USAF TDBDP 2 TDEED (Minahafl)1 AFOIN-3D2 1 AFKTC (i4tw)1 ARL CARD) 1 AFWL (WLF)1 APGC (PG?)1 ASD (ASYIM) 2 ESD (35!) 1 OTHER AGENCIES SSD (SDF) 2 CIA 1 NSA 6 DIA 9 AID 2 OTS 2 AEC 2 PWS 1 NASA 1 ARMY (FSTC)3 NAVY 3 NAPEC 1 RAND1 &i'cm. (C~RXi) 11 POE 12 MT-TT-63-513/1+2 +4 16