Date Morning/Afternoon MAXIMUM MARK 100. Final. GCSE (9-1) MATHEMATICS J560/06 Paper 6 (Higher Tier) PRACTICE PAPER (SET 3) MARK SCHEME

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H Date Morning/Afternoon GCSE (9-1) MATHEMATICS J560/06 Paper 6 (Higher Tier) PRACTICE PAPER (SET 3) MARK SCHEME Duration: 1 hour 30 minutes MAXIMUM MARK 100 Final This document consists of 15 pages

Subject-Specific Marking Instructions 1. M marks are for using a correct method and are not lost for purely numerical errors. A marks are for an accurate answer and depend on preceding M (method) marks. Therefore M0 A1 cannot be awarded. B marks are independent of M (method) marks and are for a correct final answer, a partially correct answer, or a correct intermediate stage. SC marks are for special cases that are worthy of some credit.. Unless the answer and marks columns of the mark scheme specify M and A marks etc, or the mark scheme is banded, then if the correct answer is clearly given and is not from wrong working full marks should be awarded. Do not award the marks if the answer was obtained from an incorrect method, i.e. incorrect working is seen and the correct answer clearly follows from it. 3. Where follow through (FT) is indicated in the mark scheme, marks can be awarded where the candidate s work follows correctly from a previous answer whether or not it was correct. Figures or expressions that are being followed through are sometimes encompassed by single quotation marks after the word their for clarity, e.g. FT 180 (their 37 + 16), or FT 300 (their 5 + 7 ). Answers to part questions which are being followed through are indicated by e.g. FT 3 their (a). For questions with FT available you must ensure that you refer back to the relevant previous answer. You may find it easier to mark these questions candidate by candidate rather than question by question.. Where dependent (dep) marks are indicated in the mark scheme, you must check that the candidate has met all the criteria specified for the mark to be awarded. 5. The following abbreviations are commonly found in GCSE Mathematics mark schemes. - figs 37, for example, means any answer with only these digits. You should ignore leading or trailing zeros and any decimal point e.g. 37000,.37,.370, 0.0037 would be acceptable but 3070 or 37 would not. - isw means ignore subsequent working after correct answer obtained and applies as a default. - nfww means not from wrong working. - oe means or equivalent. - rot means rounded or truncated. - seen means that you should award the mark if that number/expression is seen anywhere in the answer space, including the answer line, even if it is not in the method leading to the final answer. - soi means seen or implied.

6. In questions with no final answer line, make no deductions for wrong work after an acceptable answer (i.e. isw) unless the mark scheme says otherwise, indicated by the instruction mark final answer. 7. In questions with a final answer line following working space: (i) If the correct answer is seen in the body of working and the answer given on the answer line is a clear transcription error allow full marks unless the mark scheme says mark final answer. Place the annotation next to the correct answer. (ii) If the correct answer is seen in the body of working but the answer line is blank, allow full marks. Place the annotation next to the correct answer. (iii) If the correct answer is seen in the body of working but a completely different answer is seen on the answer line, then accuracy marks for the answer are lost. Method marks could still be awarded. Use the M0, M1, M annotations as appropriate and place the annotation next to the wrong answer. 8. In questions with a final answer line: (i) If one answer is provided on the answer line, mark the method that leads to that answer. (ii) If more than one answer is provided on the answer line and there is a single method provided, award method marks only. (iii) If more than one answer is provided on the answer line and there is more than one method provided, award zero marks for the question unless the candidate has clearly indicated which method is to be marked. 9. In questions with no final answer line: (i) If a single response is provided, mark as usual. (ii) If more than one response is provided, award zero marks for the question unless the candidate has clearly indicated which response is to be marked. 10. When the data of a question is consistently misread in such a way as not to alter the nature or difficulty of the question, please follow the candidate s work and allow follow through for A and B marks. Deduct 1 mark from any A or B marks earned and record this by using the MR annotation. M marks are not deducted for misreads. 3

11. Unless the question asks for an answer to a specific degree of accuracy, always mark at the greatest number of significant figures even if this is rounded or truncated on the answer line. For example, an answer in the mark scheme is 15.75, which is seen in the working. The candidate then rounds or truncates this to 15.8, 15 or 16 on the answer line. Allow full marks for the 15.75. 1. Ranges of answers given in the mark scheme are always inclusive. 13. For methods not provided for in the mark scheme give as far as possible equivalent marks for equivalent work. If in doubt, consult your Team Leader. 1. Anything in the mark scheme which is in square brackets [ ] is not required for the mark to be earned, but if present it must be correct.

1 (a) 50 1 1 AO.1a Allow answers in range 175 to 35 (b) (i) 1 750 3 1 AO1.3b 1 AO.1a 1 AO3.1a M for 17 k oe where 75 k 775 Or M1 for 1 [tonne] = [ ]750 soi or 17 their k oe where k is their weight per tonne Allow answers in range 1 35 to 13 175 May be in parts read from the graph, e.g. [tonnes] = [ ]3000 1 [tonne] = [ ]750 17 [tonnes] = 3000 + [1 ] 750 Attempt at unitary method Accept 75 775 (ii) The unit cost is the same for all amounts bought 1 1 AO3.b See Appendix for further examples (a) 0.5 oe 1 AO.1a (b) (i) 9 1 AO.1b (ii) Correct explanation 1 1 AO3.b 3 (a) Position correctly shown on map 3 1 AO.3a 1 AO.3b M1 for 1 (0.3 + 0.5) If 0 scored, SC1 for 0.7 M1 for 0.3 30 oe e.g. May need to play more times or she may not be very good at this game M1 for bearing 130 to 13 drawn at mast Y M1 for bearing 50 to 5 drawn at mast Z Ignore other constructions for M marks For full marks, position of mast X must be unambiguously marked 5

(b) (i) 1 50 000 AO1.3a B1 for [ :] 500 000 (ii) 1 to 15 1 AO.3a 11 100 to 11 00 3 3 AO1.3a M1 for 1.5 their measurement between 9.8 and 10 oe B for 1 00 000 to 1 50 000 seen Method may be seen in stages e.g. Measurement = 9.9 9.9 =.95.95 5 = 13.75 May be in standard form: 1. 10 8 to 1.5 10 8 Or M1 for 11 6.67 10 5.97 10 6. 10 Or B1 for figs 1 seen 6 oe Exact answer: 11 155.1175 5 (a) Crompton, Harwood, Astley nfww AO1.3b 1 AO3.1c 1 AO3.3 M3 for converting all three into comparable forms Or M for converting two into comparable forms Or M1 for correctly manipulating one into an equivalent alternative form Condone C, H, A as abbreviations for school names e.g. Working in decimals: H = 0.8 or 0.3 A = 0.[ ] C = 0. or working in fractions: H = 1350 3150, A= 100 133, C = 3150 3150 See Appendix for further examples (b) If Beechfield has more pupils than Kenwood the number of girls may be more than at Kenwood 1 1 AO.5b Comments must indicate that the pie charts show proportions, not quantity 6

6 (a) 100 3 M for 3500 1 AO.3a 60 oe 1 AO3.1c Or B1 for 60 oe or 36 oe 60 If 0 scored, SC1 for 100 as final answer (b) Different age groups may not have the same opinion 1 1 AO3.5 7 ( x) + ( x + 1) + ( x + ) + ( x + 3) + ( x + ) 5 = 5 x + 10 5 = x +, which is the median AO.a 1 AO3.1a 1 AO3. M1 for x, x + 1, x +, x + 3, x + seen M1 for (x) + (x + 1) + (x + ) + (x + 3) + (x + ) M1 for their (5x + 10) 5 If 0 scored, allow SC for a numerical example of any 5 consecutive numbers with mean clearly evaluated, and median identified as the same value Or SC1 for a numerical example of any 5 consecutive numbers with mean clearly identified, or median clearly identified, or both identified with no conclusion Or equivalent algebraic representation of 5 consecutive numbers Alternative (non-algebraic) arguments also accepted for full marks e.g. M1 for The numbers are the first number, 1 more, more, 3 more and more. M1 for So the mean of the differences is (1 + + 3 + ) 5 =. M1 for So the mean is the first number plus. And the final mark for concluding this with Which is the median. 7

8 (a) 3 B1 for 18 correctly placed 13 7 1 AO.1a AND AO.3b B for 13, 7 and correctly placed Or M1 for 60 (18 + their 13 + their Their 7 must be 1 ) in overlap 18 (b) 0 FT oe 1 AO.1b 1 AO.3a M1 for denominator seen, FT from their 13 + their 7 + their FT from their Venn diagram Look for 10 or 0.76[190 ] 1 Condone 0.7 to 0.8 9 (a) 5 k 1 (b) 9 1m 9 AO1.3a B1 for m or 1 m or m.5 Allow 1 1m or 1m.5 (c) 17 5p 3 B for 17 p seen 3 AO1.3b 1 Or B1 for 5 or p seen 10 (a) 1 1 k + ( 30 1 ) k = 6 k + 18 k = k 3 1 AO.1a 1 AO. 1 AO.3b M1 for 1 1 k AND M1 for (30 1) k Condone missing signs Or M for 1 k (18 + 30) 8

(b) 17.1 3 AO1.3a M for [k =] 10 oe soi by 17.0[83 ] 1 AO.1a Or M1 for k = 10 (c) (i) 0.7 3 1 AO1.3b 1 AO.1a 1 AO3.1c (ii) 1 nfww 5 1 AO1.3b 3 AO3.1d 1 AO3.3 10 13 5 M for oe 1 5 1 Or M1 for 10 = 13 5 + 5 a 1 M1 for 10 = 15t + 0.t oe AND M for [t =] 15 ± 15 0. 10 0. Or M1 for [t =] 15 ± 15 0. 10 with at 0. most 1 sign error AND A1 for [-96. to -96.3 or -96 and] 1. to 1.3 If no relevant working shown, SC3 for -96 and 1 as final answer Or SC for -96. to -96.3 and 1. to 1.3 as final answer May be done in stages Substitutes numbers correctly into formula (or their attempt at a rearranged formula) oe includes 10 = 15t + 0.t or 050 = 75t + t M or M1 are FT from their 3 term quadratic Condone short division line in working if seen correct at least once Would earn M1 only if only + or - used instead of ± Maximum marks if unrounded and/or negative solution not rejected 9

11 (a) x + 6 or 8(3x + 8) M1 for 3x + 6 seen AO1.3a (b) - 3 AO3.1a M1 for 3 x + 6 = 8( x + ) oe M1 for 5 x = -10 Form equation Begin to solve for x 1 50 5 + 5 +.5 +.5 + π.5 360 = 19.36[ ] = 19. [m] AO1.3b 1 AO. 1 AO.3a B1 for 50 or 100 seen AND their 50 M for [ ] π.5 360 Or M1 for π.5 Also allow their 100 π.5 360 13 6.3 to 6. 6 AO1.3a 3 AO3.1b 1 r r sin1 M5 for 1 AO3. [ 100] OR πr May see in stages May see evaluated for a particular radius. Award M marks for method seen with r = their consistent radius M1 for 180 56 oe AND 1 M for r r sin their '1' Or M1 for 1 sin '1' r r their AND M1 for their triangle area πr [ 100] 10

1 (a) Sides = 33, 56, 65 3 B1 for 56 and 65 seen Alternative method 33² + 56² = 5 M1 for 33² + 56² 1 AO.a M1 for ( x + 3) + x = ( x 1) 5 = 65 1 AO3.1a M1 for x 5x 6 = 0 or equivalent quadratic = 0 A1 for x = 33 [and x -8] (b) x 1 = x + 3 x = x 1 = x x = 1 which does not give a triangle x = x + 3 which has no solution M1 B1 M1 A1 M1 A1 3 AO3.1a AO3.b Could be in any order x = 1 must be rejected Needs to be explained 15 3.6 3 AO1.3b 1 AO3.3 B3 for 7.6 to 7.63 OR M for 00 1.03 OR M1 for 76.8[0] or 1.03 soi M1 for their 76.8 1.03 and their 556.05 to 556.06 1.03 and their 637.85 to 637.86 1.03 Steps towards first year calculated Further 3 years calculated 11

16 (a) 5 1 5 1 815 = 83 = 3 8 = AO. M1 for 815 or 83 (b) 1 3 3 1 AO1.3b 1 AO. 1 AO3.1b B for power Or M1 for 8 3 or equivalent fractional 3 or ( ) 1 3 8 1 1 8 8 3 3 or 7 3 17 BP = PC (P midpoint of BC) Angle MBP = angle NPC (corresponding angles) Angle BPM = angle PCN (corresponding angles) 1 AO1.1 3 AO.b B3 for three facts with conclusion Or B for three facts with missing or unclear conclusion or for two facts with conclusion Or B1 for one fact Accept any correct proof Each fact must be backed up with a reason for full marks Triangles [MBP and NPC] congruent by ASA. 18 (a) 0 000 or 1 000 to 1 100 AO1.3a M1 for 30 000.36 Allow 00 000 provided correct working seen 1

(b) 6 or 5.9[9 ] 3 M for ( 3 1) 100 oe Alternative method using trial and improvement AO3.1a Or B1 for 3 or 1.599 100 + k Or M1 for = 100 oe 3 M for working towards calculating overall percentage increase over 3 years for both 5% and 6% e.g. As a minimum: 1.5 3 = 1.95[3 ] and 1.6 3 =.000[ ] Or M1 for working towards calculating a percentage increase over 3 years where k is between 0 and 30 e.g. 1.5 3 = 1.95[3 ] Allow method marks for working in decimals, percentages or from their initial population k After 3 years k After 3 years 0 7.8 6 100.03 1 77.15 7 10.83 81.58 8 109.71 3 86.08 9 11.66 90.66 30 119.7 5 95.31 13

APPENDIX Exemplar responses for Q1(b)(ii) Response Mark There are no discounts for buying more 1 There is enough aluminium 0 Exemplar responses for Q5(a) Working in fractions: 1 mark 1 mark Still only 1 mark marks marks marks 3 marks H = 3 7 150 1350 7 63 350 3150 A C 9 1 50 9 1 50 8 63 00 50 189 50 17 350 100 3150 133 3150 Working in ratios: 1 mark 1 mark Still only 1 mark marks marks marks marks marks marks 3 marks 3 marks H 3 : 3 : 1 : 16 1 : 8 15 : 0 87 : 116 8 : 11 35 : 580 A = : 5 1 : 15 8 : 105 16 : 0 116 : 15 8 : 105 6 : 580 C 1 : 9 1 : 9 1 : 9 8 : 116 8 : 116 105 : 15 8 : 116 0 : 580 1

J560/06 Mark Scheme Assessment Objectives (AO) Grid Question AO1 AO AO3 Total 1(a) 0 1 0 1 1(b)(i) 1 1 1 3 1(b)(ii) 0 0 1 1 (a) 1 1 0 (b)(i) 1 1 0 (b)(ii) 0 0 1 1 3(a) 1 0 3 3(b)(i) 0 0 3(b)(ii) 1 1 0 3 0 0 3 5(a) 0 5(b) 0 1 0 1 6(a) 1 1 1 3 6(b) 0 0 1 1 7 0 8(a) 0 3 0 3 8(b) 0 0 9(a) 1 0 0 1 9(b) 0 0 9(c) 3 0 0 3 10(a) 0 3 0 3 10(b) 1 0 3 10(c)(i) 1 1 1 3 10(c)(ii) 1 0 5 11(a) 0 0 11(b) 1 0 3 1 0 13 0 6 1(a) 1 1 1 3 1(b) 1 0 5 6 15 3 0 1 16(a) 0 0 16(b) 1 1 1 3 17 1 3 0 18(a) 0 0 18(b) 1 0 3 Totals 0 30 30 100 15