Allowable bearing capacity and settlement Vertical stress increase in soil

Similar documents
Outline. Heat Exchangers. Heat Exchangers. Compact Heat Exchangers. Compact Heat Exchangers II. Heat Exchangers April 18, ME 375 Heat Transfer 1

EE 119 Homework 6 Solution

Appendices on the Accompanying CD

Integral Calculus What is integral calculus?

Partial Derivatives: Suppose that z = f(x, y) is a function of two variables.

Handout 30. Optical Processes in Solids and the Dielectric Constant

Coulomb s Law Worksheet Solutions

Th n nt T p n n th V ll f x Th r h l l r r h nd xpl r t n rr d nt ff t b Pr f r ll N v n d r n th r 8 l t p t, n z n l n n th n rth t rn p rt n f th v

Evans, Lipson, Wallace, Greenwood

WEEK 3 Effective Stress and Pore Water Pressure Changes

. This is made to keep the kinetic energy at outlet a minimum.

Equil. Properties of Reacting Gas Mixtures. So far have looked at Statistical Mechanics results for a single (pure) perfect gas

Where k is either given or determined from the data and c is an arbitrary constant.

FH6 GENERAL CW CW CHEMISTRY # BMC10-4 1BMC BMC10-5 1BMC10-22 FUTURE. 48 x 22 CART 1BMC10-6 2NHT-14,16,18 36 X x 22.

(1) Then we could wave our hands over this and it would become:

Trade Patterns, Production networks, and Trade and employment in the Asia-US region

P a g e 3 6 of R e p o r t P B 4 / 0 9

Beechwood Music Department Staff

6. Negative Feedback in Single- Transistor Circuits

Answer Homework 5 PHA5127 Fall 1999 Jeff Stark

Massachusetts Institute of Technology Department of Mechanical Engineering

Course 10 Shading. 1. Basic Concepts: Radiance: the light energy. Light Source:

828.^ 2 F r, Br n, nd t h. n, v n lth h th n l nd h d n r d t n v l l n th f v r x t p th l ft. n ll n n n f lt ll th t p n nt r f d pp nt nt nd, th t

RUTH. land_of_israel: the *country *which God gave to his people in the *Old_Testament. [*map # 2]

PR D NT N n TR T F R 6 pr l 8 Th Pr d nt Th h t H h n t n, D D r r. Pr d nt: n J n r f th r d t r v th tr t d rn z t n pr r f th n t d t t. n

Chapter 2 Linear Waveshaping: High-pass Circuits

The University of Iowa Dept. of Civil & Environmental Engineering 53:030 SOIL MECHANICS Midterm Exam #2, Fall Semester 2005

0 +1e Radionuclides - can spontaneously emit particles and radiation which can be expressed by a nuclear equation.

46 D b r 4, 20 : p t n f r n b P l h tr p, pl t z r f r n. nd n th t n t d f t n th tr ht r t b f l n t, nd th ff r n b ttl t th r p rf l pp n nt n th

:2;$-$(01*%<*=,-./-*=0;"%/;"-*

Executive Committee and Officers ( )

ELEC 372 LECTURE NOTES, WEEK 11 Dr. Amir G. Aghdam Concordia University

,. *â â > V>V. â ND * 828.

The Language of SOCIAL MEDIA. Christine Dugan

Stochastic Heating in RF capacitive discharges

Definition1: The ratio of the radiation intensity in a given direction from the antenna to the radiation intensity averaged over all directions.

GRAPHS IN SCIENCE. drawn correctly, the. other is not. Which. Best Fit Line # one is which?

Lecture 26: Quadrature (90º) Hybrid.

Problem 1. Solution: = show that for a constant number of particles: c and V. a) Using the definitions of P

N V R T F L F RN P BL T N B ll t n f th D p rt nt f l V l., N., pp NDR. L N, d t r T N P F F L T RTL FR R N. B. P. H. Th t t d n t r n h r d r

0 t b r 6, 20 t l nf r nt f th l t th t v t f th th lv, ntr t n t th l l l nd d p rt nt th t f ttr t n th p nt t th r f l nd d tr b t n. R v n n th r


Three Concepts: Probability Henry Tirri, Petri Myllymäki

Job No. Sheet 1 of 6 Rev A. Made by JG/AO Date Feb Checked by GZ Date March 2006

n r t d n :4 T P bl D n, l d t z d th tr t. r pd l

A L A BA M A L A W R E V IE W


Lecture 2a. Crystal Growth (cont d) ECE723

Lectur 22. RF and Microwave Circuit Design Γ-Plane and Smith Chart Analysis. ECE 303 Fall 2005 Farhan Rana Cornell University

Lecture 37 (Schrödinger Equation) Physics Spring 2018 Douglas Fields

4 4 N v b r t, 20 xpr n f th ll f th p p l t n p pr d. H ndr d nd th nd f t v L th n n f th pr v n f V ln, r dn nd l r thr n nt pr n, h r th ff r d nd

4037 ADDITIONAL MATHEMATICS

Vr Vr

Physics Chapter 3 Homework

Humanistic, and Particularly Classical, Studies as a Preparation for the Law

Even/Odd Mode Analysis of the Wilkinson Divider

The University of Alabama in Huntsville Electrical and Computer Engineering Homework #4 Solution CPE Spring 2008

AP Calculus BC Problem Drill 16: Indeterminate Forms, L Hopital s Rule, & Improper Intergals

3) Use the average steady-state equation to determine the dose. Note that only 100 mg tablets of aminophylline are available here.

HOMEWORK FOR UNIT 5-2: COMBINING FORCES

SUMMER 17 EXAMINATION

Lecture Outline. Skin Depth Power Flow 8/7/2018. EE 4347 Applied Electromagnetics. Topic 3e

Software Process Models there are many process model s in th e li t e ra t u re, s om e a r e prescriptions and some are descriptions you need to mode

Lecture 4: Parsing. Administrivia

Exhibit 2-9/30/15 Invoice Filing Page 1841 of Page 3660 Docket No

ELECTROMAGNETIC INDUCTION CHAPTER - 38

Source code. where each α ij is a terminal or nonterminal symbol. We say that. α 1 α m 1 Bα m+1 α n α 1 α m 1 β 1 β p α m+1 α n

The Frequency Response of a Quarter-Wave Matching Network

Characteristics of beam-electron cloud interaction

Please pick up your Exam1 Answer Sheets at front

P a g e 5 1 of R e p o r t P B 4 / 0 9

Colby College Catalogue

n

Appendix XVI Cracked Section Properties of the Pier Cap Beams of the Steel Girder Bridge using the Moment Curvature Method and ACI Equation

Exam 1. It is important that you clearly show your work and mark the final answer clearly, closed book, closed notes, no calculator.

Math 34A. Final Review

1. Be a nurse for 2. Practice a Hazard hunt 4. ABCs of life do. 7. Build a pasta sk

Solutions to Supplementary Problems

176 5 t h Fl oo r. 337 P o ly me r Ma te ri al s

4 8 N v btr 20, 20 th r l f ff nt f l t. r t pl n f r th n tr t n f h h v lr d b n r d t, rd n t h h th t b t f l rd n t f th rld ll b n tr t d n R th

CONFINEMENT REINFORCEMENT DESIGN FOR REINFORCED CONCRETE COLUMNS

Why is a E&M nature of light not sufficient to explain experiments?

Solutions to Supplementary Problems

T H E S C I E N C E B E H I N D T H E A R T

Colby College Catalogue

Colby College Catalogue

Text: WMM, Chapter 5. Sections , ,

European Business Confidence Survey December 2012 Positive expectations for 2013

Chemical Physics II. More Stat. Thermo Kinetics Protein Folding...


W A T E R P R O O F I N G S Y S T E M S

Length L 2 l N RS50KU RS08BKU

SAFE HANDS & IIT-ian's PACE EDT-15 (JEE) SOLUTIONS

10.5 Linear Viscoelasticity and the Laplace Transform

Multiple Short Term Infusion Homework # 5 PHA 5127

c. What is the average rate of change of f on the interval [, ]? Answer: d. What is a local minimum value of f? Answer: 5 e. On what interval(s) is f

AS 5850 Finite Element Analysis


STRIPLINES. A stripline is a planar type transmission line which is well suited for microwave integrated circuitry and photolithographic fabrication.

120~~60 o D 12~0 1500~30O, 15~30 150~30. ..,u 270,,,, ~"~"-4-~qno 240 2~o 300 v 240 ~70O 300

Transcription:

5 Allwabl barg aaity and ttlmnt Vrtial tr ra il - du t nntratd lad: 3 5 r r x y - du t irularly ladd ara lad:. G t tabl 5..6 Fd / by dtrmg th trm: r/(/) /(/) 3- blw rtangular ladd ara: th t i at th rnr th rtangl: G t tabl 5..8-9,d, by dtrmg th trm: m Z L n Z th t i th ntr th rtangl: G t tabl 5.3.30 t d by dtrmg th trm: m L n 4- Arximat Mthd ( V : H).. L ( )( L ) ng. Haytham ai

5- Avrag vrtial tr ra blw th rnr rtangular ladd ara: Avrag vrtial tr ra a layr il ha dth rm =0 t =H a G t igur 5.7.34 t d a by dtrmg th trm: m n H L H Avrag vrtial tr ra ii layr that tart rm dth =H t dth =H, u th llwg rmula: a( H ) a( H) ; ; H a( H ) H H H rm 0 H H / H a a rm 0 H a( H) ttlmnt alulat. lati ttlmnt vr aturatd lay: A A, A = ( H/, L/), A = (D /) and = β. u H : Dth lay layr undr th bttm undat. igur 5.4 t bta A, A tabl 5.7 t gt a tyial valu β = (OR, ). alulat lati ttlmnt bad n latiity thry: ( Flxibl) ( Rigid) 0.93 ( Flxibl, ntr ). 3. mrvd uat r lati ttlmnt = G F / ng. Haytham ai

4. lati ttlmnt andy il ug tra lun atr: 0 0. 5 Tim yar 0. lg 0. D tiv tr at th lvl undat. Q lumn. Lad = Nt undat rur ra. A FundatAra. : tra lun atr, it i givn a hwn blw: ( m) 0.5 0. () Fr uar r irular undat Z 0 0. Z =0.5 (m) Z = 0 Fr undat with L/ 0 Z 0 0. Z = (m) Z =4 0 U tn / t t / t.5 3.5 95.7854 KN / m 4.4484 b N Fr irular r uar tg Fr tri tg 000 b / t ng. Haytham ai 3

5. ttlmnt undat n and bad n T Myrh thry t i dirnt rm th nt all all D dit nt all rntd hatr3 N 60 Fr 4 t... 4 nt N 60 Fr 4 t... 6 Myrh thught h wa t nrvativ whn h alulatd th nt allwabl barg aaity that h ha rad it valu by 50%:. 5 nt ( all) nt ( all) ud alulatd wl thry: F d : Dth atr D Fd 0. 33 nt ( all) N 60 Fd.m 0.05 5 N 60 0.3 Fd.m 0.08 5.64 r rlat nglih unit (U) 6. Ttal rimary nlidat ttlmnt : Fr nrmally nlidatd il: H lg : mr dx 0.009(LL-0) H : Thikn layr undr nidrat. : nitial vid rati. : Ovr burnd rur(tivtr). : Addd vrtial rur. ng. Haytham ai 4

ng. Haytham ai 5 Fr vrnlidatd lay with <= lg H Fr vrnlidatd lay with 0 < < lg lg H H Fild lad tt (lat lad tt) Fr lay il: u u Fr and il: u u Fr lay: Fr and: xaml A ntuu undat n a dit and layr il, Aum 3 / 5 t b and tim yar r = 0yr. U th tra lun atr t d th lati ttlmnt.

lut 0 D 55 575b / t 575 0.5 0.5 4000 575. 0.96 Tim yar 0 0.lg 0. lg 0. 0. = 5 x 3 = 495 b / t () ( m) 0.5 0. = 0.5 + 0. 0.96.4 () 4000 575 495.4 = 0.65 4000 575 439. 0 0 t b / t t t th ntr ah art at th ntr ah art t 3 / b 6 6,000 3 0.369 5.757 0 50,560 7 0.595 6 4.749 0 50,560 4 0.488 5.337 0 08,800 6 0.63 6 9.368 0 5 5.506 0 b / b / t i givn by trlat. 5 439.5.5060 0.4t 73. 7mm xaml Fd th i th uar tg that arry allwabl lad 000 KN givn that: N 60 0 mm 5 all U wl thry. ng. Haytham ai 6

ttlmnt (mm) lut A th lad i rlativly larg, w will lv aumg >.m nt ( all) nt ( all) N60 0.08 0.3 N 60 0.3 0.08 Fd 5 000 0 0.3.5 0.33 0.08 y trial and rrr, =.3m Fd 5 5 5 xaml3 Frm lat lad tt th llwg rult wr givn: uar lat (305mm x 305mm) Allwabl lad n undat = 500KN. all = 5mm and il. Dtrm th i uar undat. Rlat btwn ttlmnt and tr 0 0 0 30 40 50 60 70 tr (KN/m) 0 00 400 600 800 lut Q 500 A :tr n lat. (m) KN / m (Trial and rrr) mm givn mm givn hk 5mm rm urv rm uat.5 400 4 44 Nt OK 3. 60 7 3. OK that th arriat width undat i 3.m ng. Haytham ai 7

xaml4 Rr t th llwg igur,dtrm th avrag tr ra th lay layr blw th ntr th undat du t th nt undat lad 50 tn. Atr that, dtrm th rimary nlidat ttlmnt r th lay layr. lut: H ah H a H H H `T d blw th ntr th undat, w hav t ubdivid th ara a hwn th igur. 4 r 50 t / t 4409. b / t 55 T d ah :.5 m 0.3.5 n 0.3 = 0. a H T d ah :.5 m 0.83 3.5 n 0.83 3 = 0. a H 0. 3 0. 4409. 4 78.67b / t 3 000 00 4.5 H lg 6.4 3 40 6.4 37.87 0 H 0 lg 859. 0.068 000 0.58 37.87 lg lg 0.37 t.65 0.7 859. 0.7 000 aly at 0, 0.06, 000 and 00 at 0.7, 0.5 ng. Haytham ai 8

xaml5 Rr t th llwg igur,th nt lad r unit ara at th lvl undat i 300 b/t. Aum that th undat i rigid, dtrm th lati ttlmnt that th undat will undrg bad n th thry latiity. 300 0.3 300i artial lut : lv it by yurl and gt n mark bnu ( Rigid) ( Flxibl ) 0.93 ( Flxibl, ntr ). F = 0.5874 F = 0.047 = 0.605 =0.88 ( Rigid ). 0.457 xaml 6 Rr t th llwg igur, dtrm ttlmnt th undat. lut: A A H 3.5 A 0.66 L 3.5 600KN / m aturatdlay D. 0.8 A 0.93.5 50.5 0.66 0.96 0.4m 4m 600 50KN / m ng. Haytham ai 9

xaml 7 Rr t igur 5.6 yur txt bk, th tr n th lvl undat i 300,r th and. = 0.3, =300 b/, D =.95 t, H=3 t,u a tim 5 yar r th r and 0.Aum that th undat i uar 6.5 x 6.5 t,dtrm th lati ttlmnt that th undat will undrg ug lun l atr. lut : 300 D 0.95 34. 5 0 34.5 0.5 0.5 300 34.5 5 0. lg.34 0. = 0 x (3.5+.95) = 68 () ( m) 0.5 0. = 0.705 () Z( t) Z(t) t th ntr layr 0.943 ( ) Z at th ntr th layr 3.5.65 460800(300* ) 0.405 6.839 0 9.75 8.5 460800 0.355 6 7.458 0 5.03 0 5 34.5.030 0.0374t 0. 0.943.34 300 449 xaml 8 Tw lat lad tt with uar lat wr ndutd th ild. At. ttlmnt, th rult wr :- Width lat () Lad (b) 8,070 4 5800 What i uar tg i ruird t arry a nt lad 50,000 b at a ttlmnt. ng. Haytham ai 0

ng. Haytham ai lut: t n m A Q b n i m n m n m A Q n m n A m Q A A 5. 63 4 67.5 33.54 50000 / 67.5 33.54 96 576 5800 48 44 8070 96 4 4 576 4 4 48 4 44