ID : ae-4-2nd-three-months-in-school [1] Grade 4 2nd three months in school For more such worksheets visit www.edugain.com Answer the questions (1) If 16 kg of corn is required to make food for 688 people, then how many kilograms will be needed to make food for 3010 people? (2) On his 4 th birthday, Bashir decided to distribute candies in his class of 36 students. His mom gave him 235 candies to distribute. If he distributed the candies equally in the class, how many candies did each student get? How many candies are left with Bashir? (3) In the orchards of the northern part of Japan, delicious bananas are packed in boxes of 54 each. How many boxes will be required to pack 30456 bananas? (4) A factory produces 4856 pens every month. It sends 1412 pens to the town market, 1010 pens to the markets in other states and 1010 to the markets in other countries. How many pens are left in the factory? (5) What is the common term for the perimeter of a circle? (6) Akbar's mom made a set of pastries (the set had 20 pastries). She had to throw 1 5 of the pastries as they were over-baked. She made 2 more sets of pastries. How many pastries does she have now? (7) What is the longest chord in a circle known as? (8) Find the product of following A) 5 7 4 4 7 2 7 0 B) 5 9 8 8 5 1 0 6 C) 5 6 3 9 8 3 4 3 D) 2 2 8 1 3 3 6 3 E) 9 7 1 6 3 1 3 9 F) 8 4 1 4 5 2 4 2 (9) On his 10 th birthday, Ansari decided to distribute candies in his class of 25 students. His mom gave him 800 candies to distribute. If he distributed candies equally in the class, how many candies did each student get and how many candies are left with Ansari? (10) An athlete eats 3 dozen mangoes in a day. How many mangoes will he eat in the month of April?
(11) Azra made the input output table given below: Input Output 10 2 35 7 40 8 25 5 20 4 ID : ae-4-2nd-three-months-in-school [2] What rule can be used to find each output number?
ID : ae-4-2nd-three-months-in-school [3] Choose correct answer(s) from the given choices (12) Choose the correct net for the given solid shape. a. b. c. d.
Fill in the blanks ID : ae-4-2nd-three-months-in-school [4] (13) Solve the following: A) = B) = C) = D) = E) = F) = (14) Fill in the blanks: A) 20 = 19R14 B) 199 11 = R C) 17 = 11R7 D) 705 13 = R E) 509 = 25R9 F) 18 = 7R10 (15) The chord of a circle can be larger than its diameter (True/False):. 2017 Edugain (www.edugain.com). All Rights Reserved Many more such worksheets can be generated at www.edugain.com
Answers ID : ae-4-2nd-three-months-in-school [5] (1) 70 kg According to the question, 16 kg corn is required for 688 people. So, the amount of corn required for one person = 16 688 kg Therefore, the amount of corn required for 3010 people = 3010 16 688 kg From the calculation in step 2, we get 70 kg as the product. Hence, 70 kg corn will be required for 3010 people. (2) 6, remaining - 19 Since, 235 candies are to be distributed among 36 students, we need to divide 235 by 36 to get the candies per student as well as the remaining candies. On calculating the above, we get: 235 36 = 6 R 19 Therefore, each student will get 6 candies while 19 candies are left with Bashir.
(3) 564 ID : ae-4-2nd-three-months-in-school [6] Number of bananas in one box = 54 Total number of bananas = 30456 Total number of boxes needed = Total number of bananas Number of bananas in one box = 30456 54 = 564 Step 4 Therefore, 564 boxes are required to pack 30456 bananas. (4) 1424 The factory produces 4856 pens every month. Let us first find out the total number of pens it sends to the markets every month. The total number of pens it sends to the markets every month = The number of pens it sends to the town markets + The number of pens it sends to the markets in other states + The number of pens it sends to the markets in other countries = 1412 + 1010 + 1010 = 3432 pens The number of pens left in the factory = The number of pens produced by the factory - The number of pens sent to the markets = 4856 pens 3432 pens = 1424 pens
(5) Circumference ID : ae-4-2nd-three-months-in-school [7] The perimeter of any shape is the total length of its boundary. The common term for the perimeter of a circle is circumference. The circumference of a circle can be measured by taking a thread and wrapping it around the circle once. Once we do that, the length of the thread wrapped around the circle will be equal to the circumference of the circle. (6) 56 Akbar's mom first made one set of pastries. The number of pastries in one set = 20 Out of the 20 pastries she made, the number of over-baked pastries =1/5 of the 20 pastries = 20 5 pastries = 4 pastries The number of remaining pastries = 20-4 = 16 pastries Step 4 The number of extra sets she made = 2 The number of pastries in these 2 sets = 2 20 = 40 pastries Step 5 Total number of pastries = Remaining pastries from first set + Number of pastries in 2 sets = 16 + 40 = 56 pastries Step 6 Therefore, the total number of pastries she has now is 56.
(7) The diameter ID : ae-4-2nd-three-months-in-school [8] A chord is any line segment that joins any two points on the circumference of a circle. Such a line segment will be longest if it passes through the center of the circle. Hence, the longest chord will be the diameter of the circle. (8) A) 15510690 B) 6347810 C) 19344514 D) 8281119 E) 13505657 F) 20363090 (9) 32, remaining - 0 According to the question, 800 candies are to be distributed equally among 25 students. In order to find the number of candies per student as well as the number of remaining candies, we must divide 800 by 25. On calculating the above, we get: 800 25 = 32 R 0 Hence, each student will get 32 candies while 0 candies remain with Ansari.
(10) 1080 ID : ae-4-2nd-three-months-in-school [9] One dozen mangoes means 12 mangoes. The athlete eats 3 dozen mangoes in a day. This means that the number of mangoes he eats in a day = 12 3 = 36 mangoes We know that there are 30 days in the month of April. Step 4 Hence, the number of mangoes the athlete will eat in the month of April = The number of mangoes he eats in one day The number of days in the month of April = 36 30 = 1080 mangoes (11) Divide by 5 If we observe all numbers carefully, it can be seen that output is equal to input divided by 5: 10 5 = 2 35 5 = 7 40 5 = 8 25 5 = 5 20 5 = 4 Therefore, to get the output, we should divide the input by 5. (12) b. We know that a net of a solid shape is a shape that can be folded along the given lines to form that particular solid shape. Let us look at the given options one by one.
In option a, if we fold the given net along the given lines, we get: ID : ae-4-2nd-three-months-in-school [10] Hence, it is not the correct net for the given solid shape. In option b, if we fold the given net along the given lines, we get: Hence, it is the correct net for the given solid shape. In option c, if we fold the given net along the given lines, we get: Hence, it is not the correct net for the given solid shape. In option d, if we fold the given net along the given lines, we get: Hence, it is not the correct net for the given solid shape. Therefore, option b is the correct answer.
ID : ae-4-2nd-three-months-in-school [11] (13) A) 5 Divisor 18 ) 9 0 ( 5 Quotient 9 0 Remainder 0 B) 2 Divisor 12 ) 2 4 ( 2 Quotient 2 4 Remainder 0 C) 6 Divisor 11 ) 6 6 ( 6 Quotient 6 6 Remainder 0 D) 4 Divisor 11 ) 4 4 ( 4 Quotient 4 4 Remainder 0 E) 6 Divisor 14 ) 8 4 ( 6 Quotient 8 4 Remainder 0
ID : ae-4-2nd-three-months-in-school [12] F) 10 Divisor 18 ) 1 8 0 ( 10 Quotient 1 8 0 0 Remainder 0 (14) A) 394 Here, we have been given the divisor, the quotient and the remainder. We have to find the dividend. We know that dividend = divisor quotient + Remainder. Putting the value of divisor, quotient and remainder, we get: dividend = 20 19 + 14 = 380 + 14 = 394 Therefore, 394 is the correct answer. B) 18 1 On dividing 199 by 11 we get: Divisor 11 ) 1 9 9 ( 18 Quotient 1 1 8 9 8 8 Remainder 1 Thus, the quotient for the division 199 11 will be equal to 18 and the remainder will be equal to 1.
ID : ae-4-2nd-three-months-in-school [13] C) 194 Here, we have been given the divisor, the quotient and the remainder. We have to find the dividend. We know that dividend = divisor quotient + Remainder. Putting the value of divisor, quotient and remainder, we get: dividend = 17 11 + 7 = 187 + 7 = 194 Therefore, 194 is the correct answer. D) 54 3 On dividing 705 by 13 we get: Divisor 13 ) 7 0 5 ( 54 Quotient 6 5 5 5 5 2 Remainder 3 Thus, the quotient for the division 705 13 will be equal to 54 and the remainder will be equal to 3.
ID : ae-4-2nd-three-months-in-school [14] E) 20 Here, we have been given the dividend, the quotient and the remainder. We have to find the divisor. We know that divisor = (dividend remainder) quotient. Putting the value of dividend, quotient and remainder, we get: divisor = (509 9) 25 = 500 25 = 20 Therefore, 20 is the correct answer. F) 136 Here, we have been given the divisor, the quotient and the remainder. We have to find the dividend. We know that dividend = divisor quotient + Remainder. Putting the value of divisor, quotient and remainder, we get: dividend = 18 7 + 10 = 126 + 10 = 136 Therefore, 136 is the correct answer.
ID : ae-4-2nd-three-months-in-school [15] (15) False Let us first understand the definition of a chord and a diameter. A chord is a line segment whose end points lie on the circumference of a circle, whereas diameter is a chord which passes through the center of a circle with end points on the circumference of a circle. In the above figure, AB, CD, PQ, and EF are all chords of the given circle. The longest chord PQ is the diameter as it passes through the center of the circle. Step 4 Hence, the statement "The chord of a circle can be larger than its diameter" is False.