AP Calculus AB. Sample Student Responses and Scoring Commentary. Inside: Free Response Question 1. Scoring Guideline.

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218 AP Calculus AB Sample Student Responses and Scoring Commentary Inside: Free Response Question 1 RR Scoring Guideline RR Student Samples RR Scoring Commentary 218 The College Board. College Board, Advanced Placement Program, AP, AP Central, and the acorn logo are registered trademarks of the College Board. AP Central is the official online home for the AP Program: apcentral.collegeboard.org

AP CALCULUS AB/CALCULUS BC 218 SCORING GUIDELINES Question 1 3 (a) r( t) dt = 27 According to the model, 27 people enter the line for the escalator during the time interval t 3. 3 3 (b) 2 + ( r( t).7) dt = 2 + r( t) dt.7 3 = 8 According to the model, 8 people are in line at time t = 3. (c) Based on part (b), the number of people in line at time t = 3 is 8. 1 : integral 2 : 1 : answer 1 : considers rate out 2 : 1 : answer 1 : answer The first time t that there are no people in line is 8 3 + = 414.286 (or 414.285) seconds..7 (d) The total number of people in line at time t, t 3, is modeled by t 2 + r ( x ) dx.7 t. rt ( ).7 = t1 = 33.13298, t2 = 166.574719 1 : considers rt ( ).7 = 1 : identifies 33.13 4 : t = 1 : answers 1 : justification t People in line for escalator 2 t 1 3.83 t 2 158.7 3 8 The number of people in line is a minimum at time t = 33.13 seconds, when there are 4 people in line. 218 The College Board.

1 1 l 1 1 1. People enter a line for an esalator at a rate modeled by the function r given by r(t) = j44l J 3 (i - 3 f for o t 3 for t > 3, where r(t) is measured in people per second and t is measured in seconds. As people get on the escalator, they exit the line at a constant rate of.7 person per second. There are 2 people in line at time t =. (a) How many people enter the line for the escalator du1ing the time interval O t 3? ioo ( t \ 3 ( 6 ) 7 J o qq ic)5 I I - 3 db =QJD l (b) During the time interval t 3, there are always people in line for the escalator. How many people are in line at time t = 3?.7 l 3; = 11 '7D r 'lfo::: 2qo Unauthorized copying or reuse of any part of this page Is Illegal. -4- Continue question l on page 5. 218 The College Board.

1 1 1-1 1 (c) For t > 3, what is the first time t that there are no people in line for the escalator? (b -oo)(.7)- 1' =.7(; - 21-&O=Q.11; =+1qo ft= lt2zb8 (d) For s; t s; 3, at what time t is the number of people in line a minimum? To the nearest whole number, find the number of people in line at this time. Justify your answer. O:: dt)-.7 t::11,g,;;75' b=--s3.l3 L) 2. 3. 83 1571 &O mit11mv/yl al- Hme t=- 33,13 s whqfl people. otft, i fl Ii ne. Unauthorized copying or reuse of -5- GO ON TO THE NEXT PAGE. any part ol this page Is Illegal. 218 The College Board.

1-1 rl 1 1 1. People a line for an escalator at a rate modeled by the function r given by 1,,_,z r(t) = 144( lo n 1-3 f for O t:;; 3 for t > 3, where r(t) is measured in people per second and tis measured in seconds. As people get on the escalator, they the line at a constant rate of.7 person per second. Ther:e are 2 people in Hne at time t =...::: _.;... - (a) How many people enter the line for the escalttor during the time interval O :::; t $ 3? s! 44ct S (i- too) 'l== - :1-6: o \t tu" t1,u_!1 1 )\t \OT - e Sea \ojor dlff{y\j f1a1, -h"mt t }e rvo. I O -L- t -L-)fJO (b) During the time interval O $ t $ 3, there are always people in Hne for the escalator. How many people are in line at time t = 3? oo C 1 \' JO.s + r l 1-) d + - Jo_.1 y D 1 } )- ]-q;' 'J_(, H + 1'fu b 3o o: S r_,c611j s, e-&r')i ' \ <t ()' 1, fe of l.f: f Yl (,'nt fer es/u<tor. Unauthorized copying or reuse ot -4- Continue question 1 on page 5. any part of this page is Illegal. 218 The College Board.

1-1 1 1 1 I 1 (c) Fort > 3, what is the first time t that there are no people in line for the escalator? for + / J&o, +le+; r)-1- -l-l /'l'u -f +Li{ 1L,r e {)_fle. YI.J? r Of /1? in \,rl,( r (.J.{,J. SUI f,,jo f. I)+:: ;25 (d) For $ t $ 3, at what time tis the number of people in line a minimum? To the nearest whole number, find the number of people in line at this time. Justify your answer. + 44 / \) / \ -.:t-\ -. 1 \...loo} \.. 3} 4( \ > ( \-±- )7- \ J 5 - _: Q,7- AJ +-1'Mt + = 3). al 3 Se.ond) il,e- ls -!'\1ittil'ftfl1J o JJa) fe_af le OV\,!Lescala-lor. Unauthorized copying or reuse of any part of this page Is Illegal. -5- GO ON TO THE NEXT PAGE. 218 The College Board.

1 1 1 1 1. People enter a line for an escalator at a rate modeled by the function r given by,(t)j44(1o)'[1-3 ) ' fo<osts3o lo for t > 3, where r(t) is measured in people eer second and t is measured in seconds. As people get on the escalator, they exit the line at a constant rate of.7 person per second. There are 2 p eople in line at time t =. (a) How many people enter the line for the escalator during the time interval 5 t 5 3? laoo. t ) peof& = 't t (lbo J ( \ - 3 -\:: )7 dt l 5t,p7() p.eap (b) During the time interval 5 t 5 3, there are always -- people in line for the escalator. How many people are in line at tie t = 3? ch)) - s.jo. 7 Unauthorized copying or reuse of any part of this page is illegal. -4- Continue question 1 on page 5. 218 The College Board.

1 1 1 1 1 ( c) For t > 3, what is the first time t that there are no people in line for the escalator? -- -t > '?,,o o l''nq,,ve, o..re.. r.o.. f".,lllf in \\v\j {ov tl,ui ftrst -.t -tiri-.e. k.-::: oo.- (d) For :s; t $; 3, at what time t is the number of people in line a minimum? To the nearest whole er, find the number of people in line at this time. Justify your answer. ::J \ (_ -\:::) :,. trj( :L)? - 4 4 ( I - 3<, - o re.-¼ e..x,-\:: -,r - Q. >( I 't ;: ('- 'd -l-= t5 SU Unauthorized copying or reuse of any part of this page is Illegal. -5- GO ON TO THE NEXT PAGE. 218 The College Board.

AP CALCULUS AB/CALCULUS BC 218 SCORING COMMENTARY Question 1 Overview The context of this problem is a line of people waiting to get on an escalator. The function r models the rate at 3 7 t t which people enter the line, where 44 1 rt for t 3, and rt for t 3; rt 1 3 is measured in people per second, and t is measured in seconds. Further, it is given that people exit the line to get on the escalator at a constant rate of.7 person per second and that there are 2 people in the line at time t. In part (a) students were asked how many people enter the line for the escalator during the time interval t 3. A correct response demonstrates the understanding that the number of people entering the line during this time interval is obtained by integrating the rate at which people enter the line across the time interval. Thus, this number 3 is the value of the definite integral rt dt. A numerical value for this integral should be obtained using a graphing calculator. In part (b) students were given that there are always people in line during the time interval t 3 and were asked to determine the number of people in line at time t 3. A correct response should take into account the 2 people in line initially, the number that entered the line as determined in part (a), and the number of people that exit the line to get on the escalator. It was given in the problem statement that people exit the line at a constant rate of.7 person per second, so the number of people that exit the line to get on the escalator can be found by multiplying this constant rate times the duration of the interval, namely 3 seconds. In part (c) students were asked for the first time t beyond t 3 when there are no people in line for the escalator. Because no more people join the line after t 3 seconds, and people exit the line at the constant rate of.7 person per second, dividing the answer to part (b) by.7 gives the number of seconds beyond t 3 before the line empties for the first time. Adding this quotient to 3 produces the answer. In part (d) students were asked when, during the time interval t 3, is the number of people in line a minimum, and to determine the number of people in line (to the nearest whole number) at that time, with the added admonition to justify their answer. The Extreme Value t Theorem guarantees that the number of people in line at time t, given by the expression 2 r x dx.7 t, attains a minimum on the interval t 3. Correct responses should demonstrate that the rate of change of the number of people in line is given by rt.7. Solving for rt.7 within the interval t 3 yields two critical points, t 1 and t 2, so candidates for the time when the line is a minimum are t, t 1, t 2, and t 3. t1 The number of people in line at times t 1 and t 2 is computed from 2 r x dx.7 t 1 and t2 2 rx dx.7 t2. The answer is the least of 2, these two computed values (to the nearest whole number), and the answer to part (b), together with the corresponding time t for this minimum value. For part (a) see LO 3.3B(b)/EK 3.3B2, LO 3.4A/EK 3.4A2, LO 3.4E/EK 3.4E1. For parts (b) and (c), see LO 3.4A/EK 3.4A2, LO 3.4E/EK 3.4E1. For part (d) see LO 1.2B/EK 1.2B1, LO 2.3C/EK 2.3C3, LO 3.3B(b)/EK 3.3B2, LO 3.4A/EK 3.4A2, LO 3.4E/EK 3.4E1. This problem incorporates the following Mathematical Practices for AP Calculus (MPACs): reasoning with definitions and theorems, connecting concepts, implementing algebraic/computational processes, building notational fluency, and communicating. Sample: 1A Score: 9 The response earned all 9 points: 2 points in part (a), 2 points in part (b), 1 point in part (c), and 4 points in part (d). In part (a) the response earned the first point for 3 t 3 t 7 44 1 dt. The response earned the 1 3 218 The College Board.

Question 1 (continued) second point for the answer 27. In part (b) the response earned the first point for 21 on the right side of the response area. The response earned the second point for the answer 8. In part (c) the response earned the point for the answer 414.286. What appears to be a fourth digit of 5 is not a digit but the letter s for seconds. Units are not required to earn any points in this question. In part (d) the response earned the first point for rt.7 in line 2. The response earned the second point with t 33.13 in line 4. The response earned the third point for the boxed information. What appears to be a fourth digit of 5 is not a digit but the letter s for seconds. The response earned the fourth point for the candidates test demonstrated with the table. The expression for the function p, identified as total people, supports how the values at 33.13 and 166.575 are produced. Sample: 1B Score: 6 The response earned 6 points: 2 points in part (a), 2 points in part (b), no point in part (c), and 2 points in part (d). In part (a) the response earned the first point for 3 t 3 t 7 44 1 dt. The response earned the second 1 3 point for the answer 27. In part (b) the response earned the first point with the term.7 dt. The response earned the second point for the answer 8. In part (c) the response did not earn the point because what is presented 3 7 t t is incorrect. In part (d) the response earned the first point in line 2 with the equation 44 1.7. 1 3 The response earned the second point with t 33.13 in line 3. The response did not earn the third point for the answers because 3.83 is not rounded to a whole number. The response did not earn the fourth point because it does not have a complete justification. Sample: 1C Score: 3 The response earned 3 points: 1 point in part (a), 2 points in part (b), no point in part (c), and no points in part (d). In part (a) the response earned the first point for 3 t 3 t 7 44 1 dt. The response did not earn the 1 3 second point because 567 is incorrect. In part (b) the response earned the first point with the term 3.7 dt in line 1. The response earned the second point for the answer 8. In part (c) the response did not AP CALCULUS AB/CALCULUS BC 218 SCORING COMMENTARY earn the point because what is presented is incorrect. In part (d) the response did not earn the first point with any of the equations presented. The equation at the top right rate enter rate exit is too formulaic and not specific to the question. The response does not identify t 33.13 and did not earn the second point. As a result, the response is not eligible to earn the remaining 2 points. 3 218 The College Board.