Module Stud Guide--Linear Functions The rate of change is constant in the table. Find the rate of change. Explain what the rate of change means for the situation.. The table shows the cost of a ski rental package for a given number of people. People Cost ($) 00 0 7 0 What is the slope of the line?. x What are the slope and -intercept of the graph of the given equation?. = 9 x
Write an equation in slope-intercept form for the line.. x. x What equation in slope intercept form represents the line that passes through the two points?. (.,.), (.,.) Write an equation in point-slope form from the given information. 7. (, ); m =. (, ) and (, -9)
Graph the equation. 9. = (x + ) a. c. x x b. d. x x
Match the equation with its graph.. x = a. c. x x b. d. x x Write an equation of a line with the given slope and -intercept.. m =, b =
Graph the equation.. = x a. c. x x b. d. x x Find the x- and -intercept of the line...9x +. =.9. 7 x = 7
What is the graph of the equation?. x = a. c. x x b. d. x x. Write = x + 0 in standard form. 7. Write = 0x + 0 in standard form.. Describe independent and dependent variables and how the relate to the coordinates of an ordered pair. 9. Rate of change is equal to the quotient of 0. Given the parent function f(x)=x, what are the transformation(s) to f(x)=x+7.. Graph the functions =x and =-x-. Identif the transformation(s).
.The cost of internet access at a café is a function of time. The costs for,, and 0 minutes are shown. Write an equation in slope-intercept form that represents the function. What is the cost of surfing the internet for. hours?
Module Stud Guide--Linear Functions Answer Section. ANS: dollars per person; the cost is $0 for each person. PTS: DIF: L REF: - Rate of Change and Slope OBJ: -. To find rates of change from tables NAT: CC F.IF. CC F.LE..b A..a A..b TOP: - Problem Finding Rate of Change Using a Table KEY: find rate of change interpret rate of change. ANS: 0 PTS: DIF: L REF: - Rate of Change and Slope OBJ: -. To find slope NAT: CC F.IF. CC F.LE..b A..a A..b TOP: - Problem Finding Slopes of Horizontal and Vertical Lines KEY: slope. ANS: The slope is 9 and the -intercept is. PTS: DIF: L REF: - Slope-Intercept Form OBJ: -. To write linear equations using slope-intercept form NAT: CC A.SSE..a CC A.SSE. CC A.CED. CC F.IF. CC F.IF.7.a CC F.BF..a CC F.BF. CC F.LE. CC F.LE. A..a A..b TOP: - Problem Identifing Slope and -intercept KEY: linear equation -intercept slope-intercept form. ANS: = x 7 PTS: DIF: L REF: - Slope-Intercept Form OBJ: -. To graph linear equations in slope-intercept form NAT: CC A.SSE..a CC A.SSE. CC A.CED. CC F.IF. CC F.IF.7.a CC F.BF..a CC F.BF. CC F.LE. CC F.LE. A..a A..b TOP: - Problem Writing an Equation From a Graph KEY: slope-intercept form linear equation -intercept. ANS: = x PTS: DIF: L REF: - Slope-Intercept Form OBJ: -. To graph linear equations in slope-intercept form NAT: CC A.SSE..a CC A.SSE. CC A.CED. CC F.IF. CC F.IF.7.a CC F.BF..a CC F.BF. CC F.LE. CC F.LE. A..a A..b TOP: - Problem Writing an Equation From a Graph KEY: slope-intercept form linear equation -intercept. ANS: = x +.9
PTS: DIF: L REF: - Slope-Intercept Form OBJ: -. To write linear equations using slope-intercept form NAT: CC A.SSE..a CC A.SSE. CC A.CED. CC F.IF. CC F.IF.7.a CC F.BF..a CC F.BF. CC F.LE. CC F.LE. A..a A..b TOP: - Problem Writing an Equation From Two Points KEY: linear equation -intercept slope-intercept form 7. ANS: + = (x + ) PTS: DIF: L REF: - Point-Slope Form OBJ: -. To write and graph linear equations using point-slope form NAT: CC A.SSE..a CC A.SSE. CC A.CED. CC F.IF. CC F.IF.7.a CC F.BF..a CC F.BF. CC F.LE. CC F.LE. A..a A..b TOP: - Problem Writing an Equation in Point-Slope Form KEY: point-slope form. ANS: PTS: DIF: L REF: - Point-Slope Form OBJ: -. To write and graph linear equations using point-slope form NAT: CC A.SSE..a CC A.SSE. CC A.CED. CC F.IF. CC F.IF.7.a CC F.BF..a CC F.BF. CC F.LE. CC F.LE. A..a A..b TOP: - Problem Writing an Equation in Point-Slope Form KEY: point-slope form 9. ANS: A PTS: DIF: L REF: - Point-Slope Form OBJ: -. To write and graph linear equations using point-slope form NAT: CC A.SSE..a CC A.SSE. CC A.CED. CC F.IF. CC F.IF.7.a CC F.BF..a CC F.BF. CC F.LE. CC F.LE. A..a A..b TOP: - Problem Graphing Using Point-Slope Form KEY: point-slope form. ANS: B PTS: DIF: L REF: - Standard Form OBJ: -. To graph linear equations using intercepts NAT: CC N.Q. CC A.SSE. CC A.CED. CC F.IF. CC F.IF.7.a CC F.IF.9 CC F.BF..a CC F.LE. CC F.LE. A..a A..b TOP: - Problem Graphing a Line Using Intercepts KEY: standard form of a linear equation. ANS: = x + PTS: DIF: L REF: - Slope-Intercept Form OBJ: -. To write linear equations using slope-intercept form NAT: CC A.SSE..a CC A.SSE. CC A.CED. CC F.IF. CC F.IF.7.a CC F.BF..a CC F.BF. CC F.LE. CC F.LE. A..a A..b TOP: - Problem Writing an Equation in Slope-Intercept Form KEY: linear equation slope-intercept form -intercept. ANS: A PTS: DIF: L REF: - Slope-Intercept Form OBJ: -. To graph linear equations in slope-intercept form NAT: CC A.SSE..a CC A.SSE. CC A.CED. CC F.IF. CC F.IF.7.a CC F.BF..a CC F.BF. CC F.LE. CC F.LE. A..a A..b TOP: - Problem Graphing a Linear Function KEY: linear equation -intercept slope-intercept form. ANS: x-intercept is.; -intercept is.
PTS: DIF: L REF: - Standard Form OBJ: -. To graph linear equations using intercepts NAT: CC N.Q. CC A.SSE. CC A.CED. CC F.IF. CC F.IF.7.a CC F.IF.9 CC F.BF..a CC F.LE. CC F.LE. A..a A..b TOP: - Problem Finding x- and -intercepts KEY: x-intercept standard form of a linear equation. ANS: x-intercept is ; -intercept is 7 PTS: DIF: L REF: - Standard Form OBJ: -. To graph linear equations using intercepts NAT: CC N.Q. CC A.SSE. CC A.CED. CC F.IF. CC F.IF.7.a CC F.IF.9 CC F.BF..a CC F.LE. CC F.LE. A..a A..b TOP: - Problem Finding x- and -intercepts KEY: x-intercept standard form of a linear equation. ANS: D PTS: DIF: L REF: - Standard Form OBJ: -. To graph linear equations using intercepts NAT: CC N.Q. CC A.SSE. CC A.CED. CC F.IF. CC F.IF.7.a CC F.IF.9 CC F.BF..a CC F.LE. CC F.LE. A..a A..b TOP: - Problem Graphing Horizontal and Vertical Lines KEY: standard form of a linear equation. ANS: x + = 0 PTS: DIF: L REF: - Standard Form OBJ: -. To write linear equations in standard form NAT: CC N.Q. CC A.SSE. CC A.CED. CC F.IF. CC F.IF.7.a CC F.IF.9 CC F.BF..a CC F.LE. CC F.LE. A..a A..b TOP: - Problem Transforming to Standard Form KEY: standard form of a linear equation 7. ANS: x + = PTS: DIF: L REF: - Standard Form OBJ: -. To write linear equations in standard form NAT: CC N.Q. CC A.SSE. CC A.CED. CC F.IF. CC F.IF.7.a CC F.IF.9 CC F.BF..a CC F.LE. CC F.LE. A..a A..b TOP: - Problem Transforming to Standard Form KEY: standard form of a linear equation. ANS: Dependent varibales depend on the independent variables. The independent variable represents the x coordinate and the dependent variable represents the coordinate. PTS: 9. ANS: The change in /change in x PTS: 0. ANS: Translated up 7. PTS:. ANS:. Translation down units.
. Rotation up.. Reflection over the -axis. PTS:. ANS: =.7x+ cost= $0. PTS: