Tanssts essn #10 Chapte 4 BM 372 lectncs 154
Hmewk Ps. 4.40, 4.42, 4.43, 4.45, 4.46, 4.51, 4.53, 4.54, 4.56 BM 372 lectncs 155
Hmewk Answes #20 Ps. 4.40 See fgue 4.33 BM 372 lectncs 156
Ps. 4.42 Hmewk Answes #22 g m βv T CQ β V CQ T CQ g m 1.0003 2.6003 1.0004 2.6004 1.0006 2.6006 3.8502 3.8503 3.8505 BM 372 lectncs 157
Hmewk Answes #23 Ps. 4.43 Cuplng capacts ae ften used n dscete amplfes s that suce and lad d nt hae dc cuents flwng thugh them and s the as pnts n the amplfe ae ndependent f the suces and the lad. We must nt use cuplng capacts f t s necessay t amplfy dc sgnals ecause the cuplng capacts act as pen ccuts f dc. BM 372 lectncs 158
Hmewk Answes #24 Ps. 4.45 Fst DC analyss, then AC analyss V BQ 0.7V β 100 V CC 15V 1 10k C S 100 4.7k 2 n 0.001snωt BM 372 lectncs 159
Ps. 4.45 DC Analyss Hmewk Answes #25 β 100 V CC 15V V BQ 0.7V 1 10k C S 100 4.7k 2 Theenns equalent at the ase: 4.7 VBth 15 4.8 14.7 4.7 k 10k 3.2k Bth The ase ccut: V V V (1 β ) Bth BQ Bth BQ Q BQ Bth BQ BQ BQ CQ VBth VBQ 4.8 0.7 0.0393mA (1 β ) 3.2 k (301)1 k Bth β 3.93mA BQ V V 15 3.93 3.94 7.12 C CC CQ C Q N ACTV GON βvt 661Ω CQ BM 372 lectncs 160
Ps. 4.45 AC Analyss S β 100 1 10k Hmewk Answes #26 C β 100 4.7k 2 S Z 661 k ut C 1 β 100 2 1 10k 4.7k C A Z A n β C B A Z β β β n 0.5k 548 75.6; A 41.4; G β Z A A n 3132 β A Z n C 151 n 0.001snωt BM 372 lectncs 161
Hmewk Answes #27 P 4.46 Hgh mpedance w mpedance cq 3.9309305 0.003930926 p 66142 661 A 76 76 A 151 151 Zn 54805 548 A 41 41 G 3132 3132 Z 100000 1000 BM 372 lectncs 162
Hmewk Answes #28 Ps. 4.51 Fst DC analyss, then AC analyss V BQ 0.7 V β 100 V CC 15V 1 10k S n 10k 2 500 BM 372 lectncs 163
V TH n S Hmewk Answes #29 V CC 15V 1 10k V BQ 0.7 V β 100 10k 2 500 è TH V CC 15V β B èv TH V B TH V CC 15V eme the ccut elements whch ae nt affects y the DC ltages Openng the cuplng capacts edaw the ccut and eplace the ase ccut wth ts Thenen s equalent 5k V Next, use the DC equalent ccut f the acte egn and then wte KV f the ase ccut V V TH BQ CQ CQ BQ β V V BM 372 lectncs T TH TH V (1 β ) CC TH BQ TH 1 2 2 2 V 6.42mA; V Q BQ BQ Q 1 8.5V ; 100k CC (1 β ) 7.5V 7.5 0.7 5k (1 100) Q BQ V T BQ TH BQ V BQ 64.2µ A 6.48mA (1 β ) 26m 405 64.2µ 164 BQ
Hmewk Answes #30 n S V BQ 0.7 V β 100 1 10k 10k 2 β 500 The next step s t pefm the AC analyss y Shtng any DC ltage suces Openng any DC cuent suces Shtng the capacts Cnnectng the suce, suce esstance, and lad esstance eplace the tansst wth ts small sgnal equalent ccut. And edaw t smplfy BM 372 lectncs 165
Hmewk Answes #31 n n S 1 2 10k 10k S B Z n 5k e (1β) β β e (1β) 333 O 500 BM 372 lectncs A A Z Z A B t 1 2 (1 100) 333.988 (1 100) 333 405 G A B Z A 5k (1 β ) 4.36k ; 8.51 333 (1 β ) (1 β ) (1 β ) A t (1 β ) A Z Z 8.62 34. 166
BM 372 lectncs 167 Hmewk Answes #32 12.1 1 ) ( ) (1 1 1 β β Z S S B S 50k β e (1β) Z O x x S ) ) ( ) (1 1 1 ( ) (1 ) ( 833 ) (1 β β β Z S x x S x x x S x B S S x e x x x x
Hmewk Answes #33 P 4.53 V CC 15V β 100 V BQ 0.7V B 270k C S s 100 BM 372 lectncs 168
Hmewk Answes #34 s P 4.53 S β 100 C β 100 B 270k 100 β Z [ n C ( ( [ c β β (1 β ) ) ) (1 β ) ] (1 β ) ] B BM 372 lectncs 169
Hmewk Answes #35 P 4.54 V CC 15V β 100 V BQ 0.7V B 270k C S s 100 BM 372 lectncs 170
Hmewk Answes #36 β 100 P 4.54 DC analyss s V BQ 0.7V S B 270k C V CC 15V 100 Base Ccut V V ( ) CC BQ B BQ BQ CQ V ( β ) BQ CQ BQ B BQ BQ BQ BQ V B β VT CC BQ (1 β ) BQ V Cllect Ccut V V CC C CQ B Q V V ( ) C CC CQ B Q BM 372 lectncs 171
s Hmewk Answes #37 P 4.54 AC Analyss S β 100 C β 100 B 270k 100 β Z [ n C ( ( [ c β β (1 β ) ) ) (1 β ) ] (1 β ) ] B BM 372 lectncs 172
P. 4.54 Hmewk Answes #38 esults 100 0 BQ 5.1105 5.3005 CQ 0.005105 0.005296 Q 5.1603 5.3503 VCQ 9.3800 9.7000 p 5.0902 4.9102 AV 4.71286 101.852 Zt 1.0604 4.9102 Zn 1.0204 4.9002 V/VS 9.9001 8.3101 AVS 4.66714 84.5894 BM 372 lectncs 173
Hmewk Answes #39 P 4.56 V CC B 1 e (1β) n C 1 B 2 C 2 n β 2 1 BM 372 lectncs 174
Hmewk Answes #40 P 4.56 B f B e (1β) n e (1β) n β 2 1 n β BM 372 lectncs 175
n n P 4.56 f B e (1β) β Hmewk Answes #41 mtte nde f e n B nput Mesh (1 β) n ; n n (1 β) n B B (1 β) (1 β) n n Zn n n B B [ 1 1 1 B / (1 β) ] [ 1 n / (1 β) 1 ] B B A n 1 / (1 β) 1 B 1 1 B 1 / (1 β) [ B / (1 β)] B / (1 β) / (1 β) B Base nde n n n n f n f A ; n 1 A B / (1 β) B / (1 β) B / (1 β) / (1 β) B n B n B / (1 β) n(1 A ) B ; f n B B n BM 372 lectncs 176