INDIA Sec: Sr. IIT_IZ Jee-Advanced Date: 8--7 Time: 9: AM to : Noon 5_P MDEL Max.Marks:64 KEY SHEET PHYSICS 3 3 5 4 9 5 8 6 5 7 9 8 4 9 ABC ACD BD BC 3 ABD 4 BC 5 BCD 6 ABC 7 ABC 8 CD 9 A-PRST B-PST C-PRS D-PS A-QR B-S C-S D-PQ CHEMISTRY 3 6 3 4 9 5 4 6 4 7 9 8 6 9 ABCD 3 ABCD 3 ABD 3 ABD 33 BCD 34 BCD 35 ABC 36 ABC 37 ACD 38 ACD 39 A-PQRT B-QRT C-PQST D-PQST 4 A PT B QRT C PRS D R MATHS 4 9 4 43 44 45 46 47 48 4 49 BCD 5 AC 5 ABC 5 ABCD 53 BCD 54 ACD 55 ABCD A-PRS A-RS 56 ACD 57 BC 58 D 59 B-QRS C-RS 6 B-RS C-PQ D-PRS D-PQ
8--7_Sr.IIT_IZ_JEE-ADV (5_P)_CTA-5_Key & Sol s SLUTINS PHYSICS. From decay equation, we know Heat generated Putting the values,. Let the piston be displaced by x PA PA 3. (5) q P A A A A L x P A n P P P P L x L L I mr mr 5 4. Ans. 9 Given : Fringe width, Y =. mm =. mm d =.4 mm, W =. ev, D =. m y D d or d D 3 3.4 7 4 m. 5 8 hc 4.4 3 E 3.5 ev 7 4 Stopping potential ev = 3.5. =.95 ev.95 9 V.6 V.95 V 9.6 Sec: Sr. IIT_IZ Page
8--7_Sr.IIT_IZ_JEE-ADV (5_P)_CTA-5_Key & Sol s 5. sin i sin r R d R d R d h R d h h R d R d R d R d R d 6. Conceptual R R 3 7. Regular frequency of oscillation / LC 3 rad s Charge on capacitor changes with time according to q q t At t=, q=...sin sin / 6 or 5 / 6 5 We take as charge on the capacitor is initially decreasing (look at the direction 6 of current initially) 5 q.sin t 6 Sec: Sr. IIT_IZ Page 3
5 Q is zero when t 6 8--7_Sr.IIT_IZ_JEE-ADV (5_P)_CTA-5_Key & Sol s t / 6 3 3.4.73 t.9ms 3 3t 6 6 8. Conceptual 9. rder of maxima are 3,,,,,,3 Along x-axis : hence also. According to Newton s second law of motion t dl or dt L L f i dt a 4qE dt L qa B ma f Sec: Sr. IIT_IZ Page 4
qb m. Ans: B,D 8--7_Sr.IIT_IZ_JEE-ADV (5_P)_CTA-5_Key & Sol s V XL R I rms 3 XL R 3 Similarly. XC R 3 So, XL XC And VL VR VC VR 4volt = V V V R. The diagram is balanced wheat stone bridge 3. Let they fall with speed. m m m u and m m m. u is the speed of the top ball after collision. 4. Conceptual 5. Conceptual 6. Conceptual 7. Conceptual u 8. A dv dr = constant dv dr rl 9. If a conductor is grounded, the potential of the grounded surface becomes zero and charge flow takes place from the conductor to the earth or from earth to the conductor to make potential of that surface equal to zero. The charge on a capacitor will change only if the potential distribution of the circuit changes. In a time varying magnetic field, potential difference is not defined as induced electric field is non-conservative. A q, r B s C s D-p,q Sec: Sr. IIT_IZ Page 5
8--7_Sr.IIT_IZ_JEE-ADV (5_P)_CTA-5_Key & Sol s CHEMISTRY. Mg3N with D gives ND 3 having M.wt Al4C 3 and BeC gives CD 4 having M.wt 4. P Q H C CH C C C H 5º C C C 3 3. 965 eq 965 After deliver the current Ag Initial M.59.59 E E log E.3 After.59.5.59 E E log E.3999 E 4. Due to larger different between K h and 5. Conceptual 6. 7. CH3 CH CH H CH C CH 3 H CH CH CH Sec: Sr. IIT_IZ Page 6
CH CH CH 3 8--7_Sr.IIT_IZ_JEE-ADV (5_P)_CTA-5_Key & Sol s CH C CH 3 3 H CH3 CH CH CH 3 F H NMe Me 8. 9. When N is passed into liquor ammonia NH4N and NH 4N 3 will be formed NH H N NH N NH N 3 4 3 4 It is disproportionation reaction NH N N H 4 3 NH N N H 4 N 3 and N oxidize NH 4 ion 3. C Cl CCl C B H H B C 6 3 C S CS C H CH H Cat 3 Sec: Sr. IIT_IZ Page 7
8--7_Sr.IIT_IZ_JEE-ADV (5_P)_CTA-5_Key & Sol s C CH C CH CH N N -N 3. (A) CH N N H (B) R CH C R CH C H (C) R C CH N H Cl R CH C Ag / H R CH C H CH N N CH N N (D) 3. Presence of with respect to the substituent in elimination addition reactions are must. 33. Conceptual W W 34. All are extension of PV = nrt, n and d M V 35. Conceptual 36. Conceptual 37. :E = w = ncv T = (Cp R) T = (8. 8.34) (-3) = 597 J w = -597 J H = ncp T = 8. (-3) = 846 J Ssys = ncp ln(t/t) nr ln(p/p) Ssurr = 38. Conceptual 39. Conceptual 4. Conceptual = 8. ln(9/) 8.34 ln(/4) = 8. +.53 = 3.4 JK - Sec: Sr. IIT_IZ Page 8
4. USE LMVT for the function f ( x) 43. 8--7_Sr.IIT_IZ_JEE-ADV (5_P)_CTA-5_Key & Sol s MATHS x M N s sin PM PN PS sin PN sin PS sin PN 3 3 sin sin,. 3 3 5 5 44. Let A6 t, t, t & B,, be any points on L, L and PB r L and PA r L and AB r L t t 8 and t t 6 and 3 x 45. Differentiate e f ( x ) three times 46. y f x x f y dx f y dy b a I f y b y f y dy b y f y f y dy b a f y f a dy b I f x f a dx I a b a Sec: Sr. IIT_IZ Page 9
8--7_Sr.IIT_IZ_JEE-ADV (5_P)_CTA-5_Key & Sol s a cos x c bsin x 47. dx dx I I e cos x ecos x I is rational function of sin x & cos x I a cos x c dx. ecos x a cot x cosecx c cosec x I cos ecx ecot x t cosecx ecot x dx dt cosecx cot x cosec x dx dt I is a rational function of sin x, cos x. We have a c e ae c 48. Let be a common root b b 3b ; 4 b 4 b & b b 3b ; 4 b 4 b b or b b 8 b 8 i 3 7 b b 4 5.,,, 5 f f f ve f ve 5. f x x f x if x f x & f x f x x if x f x f x f x x x x e ; x f x x x e ; x 53. Aa cos, a sin, P a cos, bsin B a cos, asin, Q a cos, bsin 3 3 3 3 Sec: Sr. IIT_IZ Page
54. 8--7_Sr.IIT_IZ_JEE-ADV (5_P)_CTA-5_Key & Sol s 4 4 4 4 C a cos, a sin, R a cos, bsin 3 3 3 3 Normals to the ellipse at P, Q, R are. a b L : ax sin bycos sin a b L : ax sin by cos sin 3 3 3 4 4 a b 4 L3 : axsin by cos sin 3 3 3 Since & 4 sin sin sin 3 3 4 cos cos cos 3 3 4 & sin sin sin 3 3 L, L, L are concurrent. 3 5 A 6 7 7 J,5 7 7 7 J B 63 J 63 63 J 8 789 56 56 J 56 J 3,5 9 8,5,5,5 I6,5 7 7 c I7,5 63 63 789 I,5 56 56 55. T a b c cos sin 3,5 a b c cos sin a b c cos sin y a b b c c a 3 a b sin b c sin c a sin y T cos a b c 3 Sec: Sr. IIT_IZ Page
56. N a at, centre of circle 8--7_Sr.IIT_IZ_JEE-ADV (5_P)_CTA-5_Key & Sol s SN SP PN & PNS 6 In le PSR, R 3 tan 3 t 3 t S a, R 3 a, area is 4a 3 a 6 4 57. z z z... z z z 5 5 z z (or) z z (rejected) 5 z 5 z, z, z, z3, z4 are the roots z z z z. 99 99 99 99 3 4 4 3 sin sin 3sin 7 sin 36 5 5 3cos8 cos54 cos 8 3 sin 7 cos8 58. length of the shortest straight beam of the light is 97. feet 37 37, 3 3, 3 3, 4 4 59. for a f x has 4 distinct real roots. For For 37 37 a,, 4 4, f x has distinct real roots 37 37 a, 3,,3 4 4 f x, has 3 distinct real roots. 3 6. a, b, c are the roots of x x x abc & a b c 3 Sec: Sr. IIT_IZ Page