Fractional designs and blocking.

Similar documents
ST3232: Design and Analysis of Experiments

Abstract Algebra Homework 6: 1, 2, 9.5, 9.6, 9.7

Fractional Factorials

Soo King Lim Figure 1: Figure 2: Figure 3: Figure 4: Figure 5: Figure 6: Figure 7: Figure 8: Figure 9: Figure 10: Figure 11: Figure 12: Figure 13:

2 k, 2 k r and 2 k-p Factorial Designs

Strategy of Experimentation III

Suppose we needed four batches of formaldehyde, and coulddoonly4runsperbatch. Thisisthena2 4 factorial in 2 2 blocks.

CS 484 Data Mining. Association Rule Mining 2

Fractional Factorial Designs

23. Fractional factorials - introduction

Lecture 3 : Probability II. Jonathan Marchini

Advanced Digital Design with the Verilog HDL, Second Edition Michael D. Ciletti Prentice Hall, Pearson Education, 2011

19. Blocking & confounding

CMPT 882 Machine Learning

Geometry Problem Solving Drill 08: Congruent Triangles

Set Notation and Axioms of Probability NOT NOT X = X = X'' = X

Math for Liberal Studies

TMA4267 Linear Statistical Models V2017 (L19)

Lec 10: Fractions of 2 k Factorial Design

eqr014 Lenth s Method for the Analysis of Unreplicated Experiments

Fractional Factorial Designs

PLC Papers. Created For:

MATH 1823 Honors Calculus I Permutations, Selections, the Binomial Theorem

Session 3 Fractional Factorial Designs 4

arxiv: v1 [math.ra] 11 Aug 2010

Class IX Chapter 7 Triangles Maths. Exercise 7.1 Question 1: In quadrilateral ACBD, AC = AD and AB bisects A (See the given figure).

Unit 2 Boolean Algebra

COM111 Introduction to Computer Engineering (Fall ) NOTES 6 -- page 1 of 12

20g g g Analyze the residuals from this experiment and comment on the model adequacy.

SHW 1-01 Total: 30 marks

Question 1: In quadrilateral ACBD, AC = AD and AB bisects A (See the given figure). Show that ABC ABD. What can you say about BC and BD?

Class IX Chapter 7 Triangles Maths

SOLUTIONS TO EXERCISES FOR. MATHEMATICS 133 Part 4. Basic Euclidean concepts and theorems

21. Prove that If one side of the cyclic quadrilateral is produced then the exterior angle is equal to the interior opposite angle.

Math 5 Trigonometry Fair Game for Chapter 1 Test Show all work for credit. Write all responses on separate paper.

FRACTIONAL FACTORIAL

Aptitude Height and Distance Practice QA - Difficult

Lecture Notes for Chapter 6. Introduction to Data Mining

UNIT 3 BOOLEAN ALGEBRA (CONT D)

Unreplicated 2 k Factorial Designs

The hypergeometric distribution - theoretical basic for the deviation between replicates in one germination test?

PTOLEMY S THEOREM A New Proof

CHAPTER 3 BOOLEAN ALGEBRA

TWO-LEVEL FACTORIAL EXPERIMENTS: REGULAR FRACTIONAL FACTORIALS

Answer Keys to Homework#10

Assignment 9 Answer Keys

Experimental design (DOE) - Design

SOLUTIONS SECTION A [1] = 27(27 15)(27 25)(27 14) = 27(12)(2)(13) = cm. = s(s a)(s b)(s c)

Fractional Replications

Contents. TAMS38 - Lecture 8 2 k p fractional factorial design. Lecturer: Zhenxia Liu. Example 0 - continued 4. Example 0 - Glazing ceramic 3

IE 361 Exam 3 (Form A)

Discrete Probability Distributions

3.4. A computer ANOVA output is shown below. Fill in the blanks. You may give bounds on the P-value.

Vectors 1C. 6 k) = =0 = =17

HOLIDAY HOMEWORK - CLASS VIII MATH

Lecture 6: Manipulation of Algebraic Functions, Boolean Algebra, Karnaugh Maps

2.830J / 6.780J / ESD.63J Control of Manufacturing Processes (SMA 6303) Spring 2008

Chapter 11: Factorial Designs

Design theory for relational databases

GCSE: Congruent Triangles Dr J Frost

Given. Segment Addition. Substitution Property of Equality. Division. Subtraction Property of Equality

CSC 261/461 Database Systems Lecture 13. Spring 2018

Lecture 4: DNA Restriction Mapping

Geometry Problem Solving Drill 07: Properties of Triangles

Homework Solution #1. Chapter 2 2.6, 2.17, 2.24, 2.30, 2.39, 2.42, Grading policy is as follows: - Total 100

Midterm1 Review. Jan 24 Armita

Unit 9: Confounding and Fractional Factorial Designs

Mathematics 2260H Geometry I: Euclidean geometry Trent University, Winter 2012 Quiz Solutions

Chapter 1 Problem Solving: Strategies and Principles

Two-Level Fractional Factorial Design

DATA MINING - 1DL360

Geometry Regents Practice Midterm

Data Mining Concepts & Techniques

Boolean Algebra and Logic Design (Class 2.2 1/24/2013) CSE 2441 Introduction to Digital Logic Spring 2013 Instructor Bill Carroll, Professor of CSE

CSCI 688 Homework 6. Megan Rose Bryant Department of Mathematics William and Mary

Homework 04. , not a , not a 27 3 III III

Visit: ImperialStudy.com For More Study Materials Class IX Chapter 12 Heron s Formula Maths

THE CYCLIC QUADRANGLE IN THE ISOTROPIC PLANE

ALGORITHMS FOR COMPUTING QUARTIC GALOIS GROUPS OVER FIELDS OF CHARACTERISTIC 0

Strategy of Experimentation II

Answer Key. 9.1 Parts of Circles. Chapter 9 Circles. CK-12 Geometry Concepts 1. Answers. 1. diameter. 2. secant. 3. chord. 4.


Angles of Elevation and Depression

Confounding and Fractional Replication in Factorial Design

Design and Analysis of Multi-Factored Experiments

DATA MINING - 1DL360

SOLUTION. Taken together, the preceding equations imply that ABC DEF by the SSS criterion for triangle congruence.

Vermont Talent Search April 12, 2011 School Year Test 4 Solutions

Geometry Facts Circles & Cyclic Quadrilaterals

STAT451/551 Homework#11 Due: April 22, 2014

Probability Distribution

Class IX - NCERT Maths Exercise (10.1)

NAME: Mathematics 133, Fall 2013, Examination 3

Similarity of Triangle

TWO-LEVEL FACTORIAL EXPERIMENTS: BLOCKING. Upper-case letters are associated with factors, or regressors of factorial effects, e.g.

Reference: Chapter 6 of Montgomery(8e) Maghsoodloo

What if the characteristic equation has complex roots?

The 2 k Factorial Design. Dr. Mohammad Abuhaiba 1

Lecture 12: Feb 16, 2017

1. Prove that for every positive integer n there exists an n-digit number divisible by 5 n all of whose digits are odd.

Transcription:

Fractional designs and blocking Petter Mostad mostad@chalmers.se

Review of two-level factorial designs Goal of experiment: To find the effect on the response(s) of a set of factors each factor can be set by the experimenter independently of the others each factor is set in the experiment at one of two possible levels (- and +) Standard order of factors, 2 n design, calculation of main effects and interaction effects, table of contrasts, standard errors of effect estimates.

Given 2 3 experimental plan, with factors A, B, C. Can we investigate also factor D without increasing number of experiments? Possibility: Give D same signs as interaction ABC. Then: Main effect of D estimated separately from other main effects. Example A B C D= ABC - - - - - - + + - + - + - + + - + - - + + - + - + + - - + + + +

Fractional factorial designs A design with factors at two levels. How to build: Start with full factorial design, and then introduce new factors by identifying with interaction effects of the old. Notation: A 2 3-1 design, 2 4-1 design, 2 5-2 design, etc 2 n-m : n is total number of factors, m is number of factors added identified with interaction effects. The number of experiments is equal to 2 n-m

Example: Biking up a hill Goal of experiment: Determine how various factors influence the time it takes to bike up a hill. Factors: Seat Up/Down, Dynamo Off/On, Handlebars Up/Down, Gear Low/Medium, Raincoat On/Off, Breakfast Yes/No, Tires Hard/Soft. The variance of measurements was estimated from separately collected data. An 8-run experiment was desired, for initial screening of factors.

Experimental plan: 2 7-4 experiment A B C D= E= F= G= AB AC BC ABC - - - + + + - + - - - - + + - + - - + - + + + - + - - - - - + + - - + + - + - + - - - + + - - + - + + + + + + +

Conclusions from biking example Main effects are computed: Dynamo and gear large We saw previously how the standard deviation of the population of effect estimates (the standard error of the effect) could be estimated as 2 2 σ / 4 +σ / 4 where 2 is the variance of the population of observations at a setting. In this example, repeated runs at some setting had sample standard deviation 3. So 2 was estimated with 3 2, and the standard error with 2 2 2 2 σ / 4 +σ / 4 = 3 / 4 + 3 / 4 = 2.1

Drawing conclusions Fractional factorial experiments are great for screening for factors with effect. Assuming factors do not interact, a rough impression of the size of effects of factors can be found quickly. A quick estimate of the standard error can help interpret the numbers. In bicycle example: Effects were 3.5, 12.0, 1.0, 22.5, 0.5, 1.0, 2.5, with st. error 2.1.

Visualization A 3D cube can visualize 3 effects: Take average over other factors. - + Alternative: Visualize 4D data by splitting into two cubes, one for + or of a fourth factor. Possible to visualize 5D data, and even 6D data, by splitting into smaller cubes.

What is lost when using fractional designs? In a 2 3-1 design, an interaction between A and B, and an effect of C, will have same effect on data: A B C - - + - + - + - - + + + A - + - 2 3 + 4 14 Also: The interaction AC is confounded with the effect of B, and the interaction BC is confounced with the effect of A. So, how can we keep track of what we can estimate, and what not?

Theory for fractional designs Formally define the multiplication AB of factors A and B by multiplying the signs at each experiment. The multiplication rule is associative (AB)C=A(BC) and commutative AB=BA It has an identity I consisting of + for every experiment: for any A, AI=A. For any factor A, we have AA=I These rules of calculation can be used to find out which effects and interactions are identified!

Example 2 3-1 design generated by A, B, and C=AB We get ABC=I Also: AC=B and BC=A Conclusions: Main effect A confounded with interaction BC Main effect B confounded with interaction AC Main effect C confounded with interaction AB

Example 2 4-1 design generated by A, B, C, and D=ABC We get ABCD=I Also: A=BCD, B=ACD, C=ABD, D=ABC, AB=CD, AC=BD, and AD=BC. Conclusions: Main effect A confounded with interaction BCD Main effect B confounded with interaction ACD Main effect C confounded with interaction ABD Main effect D confounded with interaction ABC Interactions AB and CD confounded Interactions AC and BD confounded Interactions AD and BC confounded

Example 2 4-1 design generated by A, B, C, and D=BC We get BCD=I In general: BC=D, BD=C, CD=B, ABC=AD, ABD=AC, ACD=AB, BCD=I, ABCD=A. Conclusions: Main effect A confounded with ABCD Main effect B confounded with interaction CD Main effect C confounded with interaction BD Main effect D confounded with interaction BC Interactions ABC and AD confounded Interactions ABD and AC confounded Interactions ACD and AB confounded

Conclusions Different designs will have different properties and abilities to detect interactions. Choice of design should be made based on the context of the experiment.

Classification of designs. The designs above is defined by the defining relations, like ABC=I or ABCD=I. The resolution is the smallest set of letters in an equation identifying effects. It is denoted with Roman numerals: The three examples above can be denoted 3 1 4 1 4 1 2 III 2 IV 2 III

Example: A 5 2 2 design Generated by A, B, C, D=AB, E=AC Resolution: III 16-run 2-way interactions confounded by main effects: AB=D, AC=E, AD=B, AE=C, BD=A, CE=A 2-way interactions NOT confounded by main effects: BC, BE, CD, DE. III

Extending designs Factorial expeirments are often part of explorative research. Next step is often to extend the experiment in a direction suggested by the data. Example:

Example A 2 3-1 design visited before: A B C - - + - + - + - - + + + A A B - + - 2 3 + 4 14 Data indicates either a strong effect of C, or a strong interaction effect AB. Which is it? Run 4 more experiments, but with the sign of C switched compared to the first 4 runs. C and AB can now be estimated independently.

A B C Example, cont. Main effect of C: - - + 2 5.5 - + - 3 + - - 4 Main effect of AB: + + + 14-1 - - - 3 Note: This is a - + + 10 standard 2 3 design, + - + 7 even if rows are permuted + + - 1

Blocking in factorial designs Frequently there are factors we know will influence the result, although we are not particularly interested in estimating this influence; only to avoid that this influence affects other estimates. Then: use blocking. If we are not estimating the effect of the blocking factor, randomization in the order the blocks are run is not important. Otherwise the factor is treated as any other. Blocking is important to reduce noise!

Blocking using replications Sometimes, it pays to repeat experiments in n blocks, instead of using n randomized replications. Example: Biking times dependencies on many factors is investigated. Instead of repeating each experiment 4 times, with a random choice among 4 bikes each time, do each experiment once with each of 4 bikes.

Blocking in fractional designs Sometimes, one can use a blocking factor as one of the factors in a fractional factorial design. Then: The interaction effects between other factors that are confounded with the blocked factor cannot be estimated. Still, it can be valuable to do blocking, in order to reduce noise from the blocked factor.