Approximate solution of second-order fuzzy boundary value problem

NTMSCI 5, No 3, 7-21 (2017) 7 New Trends in Mathematical Sciences http://dxdoiorg/1020852/ntmsci2017180 Approximate solution of second-order fuzzy boundary value problem Mine Aylin Bayrak Kocaeli University, Department of Mathematics, Kocaeli,Turkey Received: 21 February 2017, Accepted: 15 July 2017 Published online: 17 August 2017 Abstract: In this paper, a new approach is proposed based on the Adomian Decomposition Method(ADM) with Green s function in order to find a solution for the second-order fuzzy boundary value problem under generalized H-differentiability The proposed technique divides the domain and builds on Green s function before installing the modified recursive scheme Some examples are presented to illustrate the efficiency of the proposed technique Keywords: Fuzzy second-order boundary value problem, Adomian decomposition method, Green function s, Generalized differentiability 1 Introduction The fuzzy differential, integral equations and integro-differential equations are play very important roles in the fuzzy analysis theory In many physical problems some quantities of the boundary values can be uncertain and they can be modeled by fuzzy numbers or fuzzy functions The concept of fuzzy numbers was introduced by Zadeh [11, 30] By using H-derivative, several articles [26, 12, 13] have demonstrated the solution to the fuzzy differential equations However, Bede and Gal [7] introduced a generalized definition for fuzzy derivative and a fuzzy-number-valued function Recently, some mathematicians have become interested in finding the solutions to the fuzzy linear and nonlinear differential equation,and fuzzy integral equation [19, 18, 15, 5, 3, 25,, 2, 8] The goal of this paper is to introduce an new approach by using generalized concepts [2,21,23,22,20,1,16,9,1] for the solution of second-order fuzzy boundary value problem ỹ = F(x,ỹ(x),ỹ (x)) (1) with the boundary conditions ỹ ( )=A,ỹ (x 2 )=B, (2) where,x 2 has constant values, A,B are fuzzy functions The structure of this paper is as follows: In Section 2, basic notations and definitions of fuzzy calculus are given In Section 3, Eqs (1) (2) is solved using the Adomian decomposition method and Green s function under generalized differentiability Convergence of the proposed technique is proven in Section Finally, in Section 5 The efficiency of the technique is shown by solving some numerical examples and a brief conclusion is given in Section 6 2 Preliminaries There are various definitions for the concept of fuzzy numbers [6, 10] Corresponding author e-mail: aylin@kocaeliedutr

8 Mine Aylin Bayrak: Approximate solution of second-order fuzzy boundary value problem Definition 1 A fuzzy number is a function u : R [0,1] which satisfies the following properties: (i) u is normal; (ii) u is convex fuzzy set; (iii) u is upper semi-continuous on R; (iv) [A] 0 =supp(a)=x R A(x) 0} is compact, where Ā denotes the closure of A Definition 2 An arbitrary fuzzy number ũ in the parametric form is represented by an ordered pair of functions(u, u) of functions(u(r), u(r)), which satisfy the following requirements: (i) u(r) is a bounded non-decreasing left continuous function in (0, 1], and right continuous at 0; (ii) u(r) is a bounded non-increasing left continuous function in (0, 1], and right continuous at 0; (iii) u(r) u(r) for all 0 r 1 The set of all fuzzy numbers is denoted by F and it is a convex cone Definition 3 For arbitrary ũ =(u(r), u(r)) and ṽ =(v(r), v(r)), 0 r 1, and scalar k, addition, subtraction, scalar product by k, and multiplication is defined as following Addition: (u+v)(r)=u(r)+v(r), (u+v)(r)=u(r)+v(r), Subtraction: (u v)(r)=u(r) v(r), (u v)(r)=u(r) v(r), Scalar Product: (ku(r),ku(r)), k 0, kũ= (ku(r),ku(r)), k<0 Multiplication: uv(r) = minu(r)v(r), u(r)v(r), u(r)v(r), u(r)v(r)} uv(r) = maxu(r)v(r), u(r)v(r), u(r)v(r), u(r)v(r)} Definition For arbitrary fuzzy numbers ũ,ṽ F, the distance (Hausdorff metric) is used [17] D(u(r),v(r))=max sup u(r) v(r), sup u(r) v(r) }, r [0,1] r [0,1] and it is shown [27] that(f,d) is a complete metric space and the following properties are known: D(ũ+ w,ṽ+ w)=d(ũ,ṽ), ũ,ṽ F, D(kũ,kṽ)= k D(ũ,ṽ), k R,ũ,ṽ F, D(ũ+ṽ, w+ẽ) D(ũ, w)+d(ṽ,ẽ), ũ,ṽ, w,ẽ F Definition 5 If the fuzzy function f(t) is continuous in the metric D, then definite integral exists [17], and also, ( b a f(t,r)dt)= b a f(t,r)dt ( b a f(t,r)dt)= b a f(t,r)dt Definition 6 Let be x,ỹ F If there exists z F such that x=ỹ z, then z is called the H-difference of x and ỹ and is denoted by x ỹ [7] Proposition 1 If f : (a,b) F is a continuous fuzzy valued function, then g(x) = x a f(t)dt is differentiable using a derivative g (x)= f(x) [7] Definition 7[7] Let f :(a,b) F and (a,b) f is a generalized differentiable in (Bede-Gal differentiability), if there exists an element f ( ) F, such that

NTMSCI 5, No 3, 7-21 (2017) / wwwntmscicom 9 (i) for all h>0 sufficiently small, f( + h) f( ), f( ) f( h) and the following limits hold f(x lim 0 +h) f( ) f(x h = lim 0 ) f( h) h = f ( ) or (ii) for all h>0 sufficiently small, f( ) f( + h), f( h) f( ) and the following limits hold f( ) f( +h) h f(x lim = lim 0 h) f( ) h = f ( ) or (iii) for all h>0 sufficiently small, f( + h) f( ), f( h) f( ) and the following limits hold f( +h) f( ) h f(x lim = lim 0 h) f( ) h = f ( ) or (iv) for all h>0 sufficiently small, f( ) f( + h), f( ) f( h) and the following limits hold: f(x lim 0 ) f( +h) f(x h = lim 0 ) f( h) h = f ( ) Definition 8 Let f :(a, b) F f is (i)-differentiable in (a, b) if f is differentiable in the sense (i) of Definition(7) and similar in(ii),(iii) and(iv) differentiability Lemma 1[7] For R, the fuzzy differential equation ỹ = f(x,y), ỹ( )=ỹ 0 F, where f : R F F is supposed to be continuous, if is equivalent to one of the integral equations ỹ(x)=ỹ 0 + x f(t,ỹ(t))dt, x [, ], or ỹ(x)=ỹ 0 +( 1) x f(t,ỹ(t))dt, x [, ], On some interval(, ) R, under the differentiability condition,(i) or(ii), respectively Remark In the case of a strongly generalized H-differentiability, as to the fuzzy differential equation ỹ = f(x,y), then two different integral equations may be attached, while in the case of H-differentiability, only one may be attached The second integral equation in Lemma(1) can be written in the form [7]: ỹ(x)=ỹ 0 ( 1) x f(t,ỹ(t))dt Theorem 1[7] Suppose that the following conditions hold (a) Let R 0 =[, + p] B(,q), p,q>0,ỹ 0 F, where B(,q)=y F : D(y, ) qdenotes a closed ball in F and let f : R 0 F be a continuous function such that D( 0, f(x,y))= f(x,y) M is used for all (x,y) R 0 (b) Let g :[, + p] [0,q] R such that g(x,0) 0and 0 g(x,u) M 1, x [, + p], 0 u q Such that g(x,u) is non-decreasing in u and g and such that the initial value problem u = g(x,u(x),u( )) = 0 has the only solution u(x) 0 on[, + p] (c) D( f(x,y), f(x,z)) g(x,d(y,z)), (x,y),(x,z) R 0 and D(y,z) q (d) There exists d > 0 such that for x [, + d] the sequence y n :[, + d] F given by ỹ 0 (x) = ỹ 0, ỹ n+1 (x)= ỹ 0 ( 1) x x f(t,ỹn 0 (t))dt is defined for any n N Then the fuzzy initial value problem ỹ = f(x,y), ỹ( ) = ỹ 0, has two solutions (one (i)-differentiable and the other one (ii)-differentiable) ỹ,ỹ : [, + r] B(,q) where r= minp, q M, q M 1,d} and the successive iterations ỹ 0 (x)=ỹ 0,ỹ n+1 (x)=ỹ 0 + x f(t,ỹ n (t))dt or ỹ 0 (x)=ỹ 0,ỹ n+1 (x)=ỹ 0 ( 1) x f(t,ỹ n (t))dt converge to these two solutions, respectively 3 The basic idea of the technique The proposed technique comprises of the Adomian Decomposition Method and the Green s function In order to solve second-order fuzzy boundary value problem (1) and (2) via the ADM, the original problem has to be divided into two sub-problems is divided Firstly, the domain [,x 2 ] is divided into two sub-domains then the [, ] [,x 2 ] is decomposed,then set the ỹ( )=γ, (,x 2 ) where the γ is an unknown fuzzy constant value

10 Mine Aylin Bayrak: Approximate solution of second-order fuzzy boundary value problem For[, ]: Consider the following second-order fuzzy boundary value problem ỹ = F(x,ỹ(x),ỹ (x)),ỹ ( )=A,ỹ( )=γ (3) Integrating twice the problem(3) and applying ỹ ( )=A, allows for the Volterra integral equation to be obtained Using conditions from ỹ( )=γ, ỹ( ) is found as an x ỹ(x)=ỹ( )+A(x )+ (x η) f(η,ỹ(η)),ỹ (η))dη () x1 ỹ( )=γ A( )+ ( η) f(η,ỹ(η)),ỹ (η))dη (5) Substituting ỹ( ) in Eq(), the Fredholm integral equation is obtained as this while, the Green s function G(x, η) become this x1 ỹ+ A(x )+ G(x,η) f(η,ỹ(η)),ỹ (η))dη (6) ỹ(x)= G(x,η)= η, x η, x, η x (7) ỹ j (x), f(x,ỹ(x)),ỹ (x))= is an infinite series where à j has decomposed Adomian polynomials Substituting(8) into(6), x1 ỹ j + A(x )+ à j (8) G(x,η) [ ] à j dη (9) is obtained Comparing both sides of(9), ỹ 0 (x,γ)=γ+ A(x ), ỹ j (x,γ)= G(x,η)à j 1 dη, j = 1,2, is obtained and then the modified recursive scheme is defined as an ỹ 1 (x,γ)=a(x )+ G(x,η)à 0 dη, ỹ j (x,γ)= G(x,η)à j 1 dη, j = 2,3, (10) (11) which allows a complete determination of the components in the ỹ j (x) Followed by the n-terms series solution of the sub-problem(3) is given by Φ n (1) n (x)= ỹ j (x,γ) (12)

NTMSCI 5, No 3, 7-21 (2017) / wwwntmscicom 11 From(7) Definition, it is possible to obtain the approximate solution of Eq (1)-(2) in the following cases [8] Case (a): If ỹ and ỹ are (i)-differentiable, Eq(11) becomes ỹ 1 (x,γ)=a(x )+ G(x,η)Ã 0 dη, ỹ j (x,γ)= G(x,η)Ã j 1 dη, η = 2,3, Case (b): If ỹ and ỹ are (ii)-differentiable, Eq(11) becomes ỹ 1 (x,γ)= ( 1)[A(x ) ( 1) G(x,η)Ã 0 dη], ỹ j (x,γ)= ( 1)[ ( 1) G(x,η)Ã j 1 dη], η = 2,3, Case (c): If ỹ is the(i)-differentiable and ỹ is the (ii)-differentiable, Eq(11) becomes ỹ 1 (x,γ)= ( 1)[A(x )+ G(x,η)Ã 0 dη], ỹ j (x,γ)= ( 1)[ G(x,η)Ã j 1 dη], η = 2,3, Case (d): If ỹ is the(ii)-differentiable and ỹ is the (i)-differentiable, Eq(11) becomes ỹ 1 (x,γ)=a(x ) ( 1)[ G(x,η)Ã0dη], ỹ j (x,γ)= ( 1)[ G(x,η)Ã j 1 dη], η = 2,3, For[,x 2 ]: Let us consider the following fuzzy boundary value problem ỹ = F(x,ỹ(x),ỹ (x)),ỹ( )=γ,ỹ (b)=b (13) Integrating twice the problem(13) and applying an ỹ( )=γ, the Volterra integral equation is obtained x ỹ+ B(x )+ (x η) f(η,ỹ(η)),ỹ (η))dη (1) Using the other boundary condition ỹ (x 2 )=B, the following is yilded x2 ỹ ( )=B f(η,ỹ(η)),ỹ (η))dη (15) Combining Eqs(1) and(15), the Fredholm integral equation is obtained as x2 ỹ+ B(x )+ G(x,η) f(η,ỹ(η)),ỹ (η))dη (16) where G(x, η) is given by By substituting(8) into(16), G(x,η)= x2 ỹ j + B(x )+ x, x η, η, η x x 2 (17) G(x,η)[ Ã j ]dη (18)

12 Mine Aylin Bayrak: Approximate solution of second-order fuzzy boundary value problem the above equation is obtained From(18), the following recursion scheme occurs ỹ 0 (x,γ)=γ+ B(x ), ỹ j (x,γ)= x 2 G(x,η)Ã j 1 dη, j = 1,2, and the modified recursive scheme as ỹ 1 (x,γ)=b(x )+ x 2 x 1 G(x,η)Ã 0 dη, ỹ j (x,γ)= x 2 G(x,η)Ã j 1dη, j = 2,3, (19) (20) is defined Denote the n-terms approximant of the series solutions by using this Φ n (2) (x)= n From Definition(7), following cases exist [8] Case (a): If ỹ and ỹ are (i)-differentiable, Eq(20) becomes ỹ 1 (x,γ)=b(x )+ x 2 G(x,η)Ã 0 dη, ỹ j (x,γ)= x 2 G(x,η)Ã j 1 dη, j = 2,3, Case (b): If ỹ and ỹ are (ii)-differentiable, Eq(20) becomes ỹ 1 (x,γ)= ( 1)[B(x ) ( 1) x 2 x 1 G(x,η)Ã 0 dη], ỹ j (x,γ)= ( 1)[ ( 1) x 2 G(x,η)Ã j 1 dη], j = 2,3, Case (c): If ỹ is the(i)-differentiable and ỹ is the(ii)-differentiable, Eq(20) becomes ỹ 1 (x,γ)= ( 1)[B(x )+ x 2 G(x,η)Ã0dη], ỹ j (x,γ)= ( 1)[ x 2 G(x,η)Ã j 1 dη], j = 2,3, Case (d): If ỹ is the(ii)-differentiable and ỹ is the (i)-differentiable, Eq(20) becomes ỹ 1 (x,γ)=b(x ) ( 1)[ x 2 x 1 G(x,η)Ã 0 dη], ỹ j (x,γ)= ( 1)[ x 2 G(x,η)Ã j 1dη], j = 2,3, ỹ j (x,γ) (21) From Eqs(12) and(21), the continuity condition to determine this γ is used as follows: d Φ n (1) (x, γ) d Φ n (2) (x, γ) = 0, n=1,2, (22) dx dx x=x1 x=x1

NTMSCI 5, No 3, 7-21 (2017) / wwwntmscicom 13 From this, the approximate value of γ is found Then the approximate series solution of original second-order fuzzy boundary value problem can be found(1) (2) is defined as Φ n (x)= Φ n (1) (x,γ n ) := ỹ j (x,γ n ), x, Φ n (2) (x,γ n ) := (23) ỹ j (x,γ n ), x x 2 where the γ n, n=1,2,3, approximates the values of γ for each of case (a) (d) Convergence analysis In order to prove convergence using the proposed technique following assumptions are necessary [8] For [, ]: Consider f(x) is bounded for all x [, ] and M 1,M 2 > 0 where G(x,η dη M 1, x1 G x (x,η dη M 2 Supposes that the nonlinear operators f(x,y,y ) satisfies the Lipschitz conditions with D( f(x,y,y ), f(x,z,z )) L 1 D(y,z)+L 2 D(y,z ),L 1 > 0,L 2 > 0 If δ :=(L 1 M 1 + L 2 M 2 )<1, then the Eq(6) has a unique solution Lemma 2[8] If ũ,ṽ, w F and λ R, then (1) D(ũ ṽ,ũ w)=d(ṽ, w) (2) D( λ ũ, λ ṽ)= λ D(ũ,ṽ) Theorem 2[8] Let 0 < δ < 1, then Eqs (1) (2) have a unique solution where ỹ (1)-differentiable and ỹ is (2)- differentiable, respectively Proof Let ỹ and ỹ be two different solutions for(1) (2), then D(ỹ(x),ỹ (x))=d(a(x ) ( 1) G(x,η) f(η,ỹ(η),ỹ (η))dη+ γ, A(x ) ( 1) G(x,η) f(η,ỹ (η),ỹ (η))dη+ γ) = D( ( 1) G(x,η) f(η,ỹ(η),ỹ(η))dη, ( 1) G(x,η) f(η,ỹ (η),ỹ (η))dη) = D( G(x,η) f(η,ỹ(η),ỹ(η))dη, G(x,η) f(η,ỹ (η),ỹ (η))dη) D( G(x,η) f(η,ỹ(η),ỹ(η))dη)+d( G(x,η) f(η,ỹ (η),ỹ (η))dη) (L 1 M 1 + L 2 M 2 )D(ỹ(x),ỹ (x))=δd(ỹ(x),ỹ (x)) From which(1 δ)d(ỹ(x),ỹ (x)) 0 is obtained Since 0<δ < 1, then D(ỹ(x),ỹ (x))=0 implies ỹ(x)=ỹ (x) Theorem 3 Let ỹ 0,ỹ 1,ỹ 2, be the solution components that were obtained by using the recursive schemes(10) and(11), and let Φ n = n ỹ j be the n-terms series solution defined by (12) Then Φ n converges to the exact solution ỹ whenever δ < 1 Proof Using(10),(11) and(12), we have Φ n = ỹ 0 + n ỹ j j=1 = γ+ A(x )+ n ( G(x,η)Ã j 1 dη) j=1 = γ+ A(x )+ G(x,η) n 1 Ã j dη

1 Mine Aylin Bayrak: Approximate solution of second-order fuzzy boundary value problem For all n,m N with n>m, consider D( Φ n, Φ m ) max x1 x x G(x,η)[ n 1 Ã j m 1 Ã j ]dη 1 Using the related n 1 Ã j f(η, Φ n 1, Φ n 1 ) in [28,29] D( Φ n, Φ m ) max x1 x x G(x,η)[ f(η, Φ n 1, Φ n 1 ) f(η, Φ m 1, Φ m 1 )]dη 1 Allows for, the following relation to be obtained D( Φ n+1, Φ n ) δd( Φ n, Φ n 1 ) Thus, it becomes D( Φ n+1, Φ n ) δd( Φ n, Φ n 1 ) δ 2 D( Φ n 1, Φ n 2 ) δ n D( Φ 1, Φ 0 ) For any n,m N, with n>m, consider D( Φ n, Φ m ) D( Φ n, Φ n 1 )+D( Φ n 1, Φ n 1 )++D( Φ m+1, Φ m ) [δ n 1 + δ n 2 ++δ m ]D( Φ 1, Φ 0 )=δ m 1 δ n m ( 1 δ )D( Φ 1, Φ 0 ) Since δ < 1, therefore 1 δ n m < 1 and D( Φ 1, Φ 0 )<, follows that D( Φ n, Φ m )<( δ m 1 δ )D( Φ 1, Φ 0 )<, as m This implies that there exists an Φ such that lim Φ n = Φ Since, ỹ= ỹ j = lim Φ n, has that is, ỹ= Φ n n Remark The proof of other cases is similar to the previous theorems Also, similar steps for the recursive schemes (19) and(20) can be applied 5 Numerical results In this section, second-order fuzzy boundary value problem is solved under generalized differentiability using ADM with Green s function All symbolic and numerical computations were created using MATLAB Software Package Example 1 Consider the following second-order fuzzy boundary value problem ỹ (x)= (2 x 2 )ỹ, x [0,1], ỹ (0)=[0,0], ỹ (1)=[ 2exp( 1)(α 1), 2exp( 1)(1 α)] (2) where the exact solution is ỹ(x)=[(α 1)exp( x 2 ),(1 α)exp( x 2 )] To obtain approximate solution of above example, the ADM with Green s function is applied Firstly, the domain[0, 1] is divided into domains[0, 05] and[05, 1] Suppose that ỹ(05) =[γ, γ], where γ is an unknown fuzzy constant Solve the following sub-problems ỹ (x)= (2 x 2 )ỹ, ỹ (0)=[0,0],ỹ(05)=[γ,γ], x [0,05] (25) and ỹ (x)= (2 x 2 )ỹ, ỹ(05)=[γ,γ],ỹ (1)=[ 2exp( 1)(α 1), 2exp( 1)(1 α)], x [05,1] (26) Consider the following cases Case (a): If ỹ and ỹ are(i)-differentiable, For[0, 05]: According to the recursive scheme(11), the sub-problem(25) is transformed into (x)= 1 8 γ(16x 8x 2 + 11) (x)= 1 8 γ(16x 8x 2 + 11)

NTMSCI 5, No 3, 7-21 (2017) / wwwntmscicom 15 (1) Thus, the series solution can found using Φ n = n ỹ j For[05,1]:According to the recursive scheme(20), the sub-problem(26) is transforms into (x)=(2x 1)[γ(01667x 3 + 00833x 2 0583x+0102)+03679(1 α)] (x)=(2x 1)[γ(01667x 3 + 00833x 2 0583x+0102)+03679(α 1)] Thus, the series solution can found using Φ n n ỹ j Case (b): If ỹ and ỹ are (ii)-differentiable, For[0,05]: According to the recursive scheme(11), the sub-problem(25) is transformed into (x)= 1 8 γ(16x 8x 2 + 11) (x)= 8 1 γ(16x 8x 2 + 11) Thus, the series solution can becomes Φ n (1) = n ỹ j For[05,1]:According to the recursive scheme(10), the sub-problem(26) is transformed using (x)=(2x 1)[γ(01667x 3 + 00833x 2 0583x+0102)+03679(1 α)] (x)=(2x 1)[γ(01667x 3 + 00833x 2 0583x+0102)+03679(α 1)] Thus, the series solution is found as Φ n n ỹ j Case (c): If ỹ is the(i)-differentiable and ỹ is the (ii)-differentiable, For[0,05]: According to the recursive scheme(11), the sub-problem(25) is transformed using (x)= 8 1 γ(16x 8x 2 + 11) (x)= 1 8 γ(16x 8x 2 + 11) Thus, the series solution is found Φ n (1) = n ỹ j For[05,1]:According to the recursive scheme(10), the sub-problem(26) is transformed using (x)=(1 2x)[γ(01667x 3 + 00833x 2 0583x+0102)+03679(α 1)] (x)=(1 2x)[γ(01667x 3 + 00833x 2 0583x+0102)+03679(1 α)] Thus, the series solution is found as Φ n n ỹ j Case (d): If ỹ is the(ii)-differentiable and ỹ is the (i)-differentiable, For[0,05]: According to the recursive scheme(11), the sub-problem(25) is transformed using

16 Mine Aylin Bayrak: Approximate solution of second-order fuzzy boundary value problem (x)= 1 8 γ(16x 8x 2 + 11) (x)= 1 8 γ(16x 8x 2 + 11) Thus, the series solution is found as Φ n (1) = n ỹ j For[05,1]:According to the recursive scheme(10), the sub-problem(26) is transformed using (x)=(1 2x)[γ(01667x 3 + 00833x 2 0583x+0102)+03679(1 α)] (x)=(1 2x)[γ(01667x 3 + 00833x 2 0583x+0102)+03679(α 1)] Thus, the series solution can be found as Φ n n ỹ j From Eq (12), the numerical values for [γ,γ] are listed in Table 1 when ỹ and ỹ are (i)-differentiable As seen from Table 1, we observe that the numerical values of [γ, γ] approaches the value [(α 1)07788366,(1 α)07788366] The exact value of[γ,γ] is ỹ(05)=[(α 1)exp( 025),(1 α)exp( 025)] In Figure 1, the exact ỹ(x) and the approximate Table 1: Numerical values of[γ n,γ n ], n=2,,6 for α = 0 n 2 3 5 6 γ n 07977789 0785282 0779723 07790055 07788366 γ n 07977789 0785282 0779723 07790055 07788366 solutions Φ n,n=2,,6 for α = 0 when ỹ and ỹ are(i)-differentiable is plotted The numerical values of [γ,γ] are listed in Table 2 when ỹ is (i)-differentiable and ỹ is (ii)-differentiable In Figure Fig 1: Exact ỹ(x) and the approximate Φ n,n=2,,6 solutions 2, the approximate solutions Φ n,n=2,,6 for α = 0 when ỹ is the (i)-differentiable and ỹ is the (ii)-differentiable is plotted

NTMSCI 5, No 3, 7-21 (2017) / wwwntmscicom 17 Table 2: Numerical values of[γ n,γ n ], n=2,,6 for α = 0 n 2 3 5 6 γ n 07977789 0785282 0779723 07790055 07788366 γ n 07977789 0785282 0779723 07790055 07788366 Fig 2: Approximate Φ n,n=2,,6 solutions Example 2 Consider the following second-order fuzzy boundary value problem ỹ (x)=2ỹ 3, xε[0,1], ỹ (0)=[1 α,α 1], ỹ (1)=[ 1 (1 α), 1 )(α 1)] (27) where the exact solution is ỹ(x)=[(α 1) 1+,(1 α) 1+ ] The domain[0,1] is divided into domains[0,05] and[05,1] and use ỹ(05) =[γ, γ] Solve the following problem ỹ (x)=2ỹ 3, ỹ (0)=[1 α,α 1],ỹ(05)=[γ,γ], x [0,05] and ỹ (x)=2ỹ 3, ỹ(05)=[γ,γ],ỹ (1)=[ 1 (1 α), 1 )(α 1)], x [05,1] (29) Consider the following cases Case (a): If ỹ and ỹ are (i)-differentiable, For[0,05]: According to the recursive scheme(11), the sub-problem(28) is transformed using 3 [(2x 1) (2x 1)2 ]+(1 α)(x 2 1) 3 [(2x 1) (2x 1)2 ]+(α 1)(x 1 2 ) (28)

18 Mine Aylin Bayrak: Approximate solution of second-order fuzzy boundary value problem Thus, the series solution can found using Φ (1) n = n ỹ j For[05,1]:According to the recursive scheme(10), the sub-problem(29) is transformed using 3 [(2x 1)(x 1) (2x 1)2 ]+(1 α)( x 1 8 ) 3 [(2x 1)(x 1) (2x 1)2 ]+(α 1)( x 1 8 ) Thus, the series solution is found using Φ n n ỹ j Case (b): If ỹ and ỹ are (ii)-differentiable, For[0, 05]: According to the recursive scheme(11), the sub-problem(28) is transformed using 3 [ (2x 1)2 x(2x 1)]+(α 1)(x 1 2 ) 3 [ (2x 1)2 x(2x 1)]+(1 α)(x 1 2 ) Thus, the series solution can be found using Φ n (1) = n ỹ j For[05,1]:According to the recursive scheme(10), the sub-problem(29) is transformed using 3 [ (2x 1)2 +(x 1)(2x 1)]+(α 1)( x 1 8 ) 3 [ (2x 1)2 +(x 1)(2x 1)]+(1 α)( x 1 8 ) Thus, the series solution is found using Φ n n ỹ j Case (c): If ỹ is the(i)-differentiable and ỹ is the(ii)-differentiable, For[0, 05]: According to the recursive scheme(11), the sub-problem(28) is transformed using 3 [x(2x 1) (2x 1)2 ]+(α 1)(x 1 2 ) 3 [x(2x 1) (2x 1)2 ]+(1 α)(x 1 2 ) Thus, the series solution is found using Φ n (1) = n ỹ j For[05,1]:According to the recursive scheme(10), the sub-problem(29) is transformed using 3 [(x 1)(2x 1) (2x 1)2 ]+(α 1)( x 1 8 ) 3 [(x 1)(2x 1) (2x 1)2 ]+(1 α)( x 1 8 ) Thus, the series solution is found using Φ n n ỹ j Case (d): If ỹ is the(ii)-differentiable and ỹ is the (i)-differentiable, For[0, 05]: According to the recursive scheme(11), the sub-problem(28) is transformed using

NTMSCI 5, No 3, 7-21 (2017) / wwwntmscicom 19 Fig 3: Exact ỹ(x) and the approximate Φ n,n=2,,5 solutions 3 [ (2x 1)2 x(2x 1)]+(α 1)(x 1 2 ) 3 [ (2x 1)2 x(2x 1)]+(1 α)(x 1 2 ) Thus, the series solution is found using Φ n (1) = n ỹ j For[05,1]:According to the recursive scheme(10), the sub-problem(29) is transformed using 3 [ (2x 1)2 (x 1)(2x 1)]+(α 1)( x 1 8 ) 3 [ (2x 1)2 (x 1)(2x 1)]+(1 α)( x 1 8 ) Thus, the series solution is Φ n n ỹ j As seen from Table 3, the numerical values of [γ, γ] approaches the value[(α 1)06673067,(1 α)006673067] when ỹ and ỹ are (i)-differentiable Note that the exact value of [γ,γ] is ỹ(05)=[(α 1) 3 2,(1 α) 3 2 ] In Figure 3, the exact Table 3: Numerical values of[γ n,γ n ], n=2,,5 for α = 0 n 2 3 5 γ n 06825986 06382310 06789988 06673067 γ n 06825986 06382310 06789988 06673067 ỹ(x) and the approximate solutions Φ n,n=2,,5 for α = 0 when ỹ and ỹ are(i)-differentiable is plotted The numerical values of [γ,γ] are listed in Table α = 0 when ỹ is the (i)-differentiable and ỹ is the (ii)-differentiable In Figure, the approximate solutions Φ n,n = 2,,5 for α = 0 when ỹ is the (i)-differentiable and ỹ is the (ii)- differentiable is plotted

20 Mine Aylin Bayrak: Approximate solution of second-order fuzzy boundary value problem Table : Approximate value of[γ n,γ n ], n=2,,5 for α = 0 n 2 3 5 γ n 06825986 06382310 06789988 06673067 γ n 06825986 06382310 06789988 06673067 Fig : Approximate Φ n,n=2,,5 solutions 6 Conclusion The ADM with Green s function for the solution of second-order fuzzy boundary value problem under generalized differentiability is presented The proposed technique is interested in dividing the domain and building Green s function before installing the modified recursive scheme The efficiency of the technique is illustrated by two numerical examples Competing interests The authors declare that they have no competing interests Authors contributions All authors have contributed to all parts of the article All authors read and approved the final manuscript References [1] Akın Ö, Oruç Ö A prey-predator model with fuzzy initial values Hacet J Math Stat 2012; 1: 387-395 [2] Allahviranloo T, Abbasbandy S, Sedaghgatfar O, Darabi P A new method for solving fuzzy integro-differential equation under generalized differentiability Neural Comput Appl 2012; 1: 191-196 [3] Allahviranloo T, Amirteimoori A, Khezerloo M, Khezeloo S A new method for solving fuzzy Volterra integro-differential equations Aust J Basic Appl Sci 2011; 5: 15-16 [] Allahviranloo T, Khezerloo M, Ghanbari M, Khezerloo S The homotopy perturbation method for fuzzy Volterra inetgral equations Intern J Comp Cogn 2010; 8: 31-37

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