Last Name Due Date First Name Section M W DENSITY CALCULATIONS PRACTICE This is Practice Work. Unless I give this uring lecture, this is not ue for a grae. I i not give you room on this sheet to o your work. You will nee your own paper. RELEANT EXAM INFORMATION (Part of Exam) There are no ensity calculations questions in Part of the Exam. You are responsible for knowing the symbols an units for ensity. You are responsible for knowing (memorize) the general equation for ensity: ρ H2 O = H 2 O = mass volume = m You must be able to rearrange the ensity equation (without numbers or measurements variables only). The ensity of water must be memorize: ρ H2 O = H 2 O = g H 2 O ml H 2 O ρ H2 O = H 2 O = ρ H2 O = H 2 O = cm 3 H 2 O ml H 2 O cc H 2 O ml H 2 O Know how to write unit equations an unit factors when given the ensity of a substance. (Part 2 of Exam) You must show your work accoring to For plug-n-chug equations: You must show at least two steps between the initial equation an the final answer. For equations that require rearranging: You must show at least two steps between the initial equation an the final answer. For calculations using conversion factors: You must use units through each step. The final answer must have units. The answer must be numerically correct. The answer must have the exact number of significant igits correct. The units in the answer must match the units in the work. Page of 9
Max Time: Remember that Max Time is an absolute bottom-line time perio. If you use max time on all questions, you will not finish the Exam. PRACTICE PROBLEMS USING THE DENSITY EQUATION For these questions, you may not use ensity as a conversion factor. You must use the ensity equation. ) The mass of an object is 08.00 grams. The object has a volume is 2.70 cubic centimeters. Determine the ensity of the substance. (8 pt) Max Time: 4 min 2) The ensity of a liqui is 5.00 g/ml. A sample of the liqui has a mass of 20 grams. 2a) Using variables only, write the ensity equation an rearrange it to isolate volume (). (4 pt). Max Time: 3 min 2b) Use your answer to Question 2a to calculate the volume (in ml) of the liqui. (8 pt). Max Time: 4 min Again: you must use the ensity equation/rearrange ensity equation for creit. 3) The ensity of a liqui is 0.85 grams per cubic centimeter. A sample of the liqui has a volume of,000. cubic centimeters. 3a) Using variables only, write the ensity equation an rearrange it to isolate mass (m). (3 pt) Max Time: 2 min. 3b) Use your answer to Question 3a an the ata in the prompt to calculate the mass (in kilograms) of the substance. (0 pt). Max Time: 5 min Again: you must use the ensity equation/rearrange ensity equation for creit. 4) The ensity of a soli is 5.92 grams per cubic centimeter. 4a) Write the conversion factor base upon the ensity of this substance. (4 pt) Max Time: 2 min 4b) A sample of the soli has a volume of 0.000 cm 3. Use imensional analysis to etermine its mass in grams. (0 pt). Max Time: 5 min Again: you may not use the ensity eqn; you must use ensity as a conversion factor for creit 5) The ensity of a liqui is 0.979 grams per milliliter. 5a) Write the conversion factor base upon the ensity of this substance. (4 pt) Max Time: 2 min 5b) A sample of the liqui has a mass of 2.4 kilograms. Use imensional analysis to etermine its volume (in milliliters). (3 pts). Max Time: 7 min Again: you may not use the ensity eqn; you must use ensity as a conversion factor for creit. 6) A -ml sample of Liqui Metal X (LMX) has a mass of 8.5 grams. 6a) Write the conversion factor base upon the information given. (4 pt) Max Time: 3 min 6b) An inustrial vat contains 52,000 L of LMX. Use imensional analysis to calculate the mass of LMX in tons. ( ton = 2000 lbs.) (9 pts). Max Time: 9 min Again: you may not use the ensity eqn; you must use ensity as a conversion factor for creit. Page 2 of 9
Solutions ) The mass of an object is 08.00 grams. The object has a volume is 2.70 cubic centimeters. Determine the ensity of the substance. (8 pt) Max Time: 4 min (or ρ) = mass volume (or m ) ( pt) The initial variables-only equation must be written ρ = 08.00 g 2.70 cm 3 (3 pt) Plug numerical values in correctly with units ρ = s 4.00 g cm 3 s (4 pt) ( pt) correct numerical answer ( pt) correct sigigs ( pt) answer must have units ( pt) units must match work Page 3 of 9
2a) Using variables only, write the ensity equation an rearrange it to isolate volume (). (4 pt). Max Time: 3 min = m ( pt) Initial equation () = m xx Minimum of two Wrote enominator for cross-multiply set up. m () = xx (2 pt) steps between initial equation an cross-multiplication m = xx the answer. Divie both sies by to isolate xx. Cancel. s m s = xx ( pt) Simplify 2b) Use your answer to Question 2a to calculate the volume (in ml) of the liqui. (8 pt). Max Time: 4 min = m (0 pt) rewrite the initial equation. The answer to Question 2a must be correct to receive any creit for Question 2b. = 20 g ( 5.00 g ml ) (3 pt) Plug numerical values in correctly, incluing units. Show work. = ( 20 g ) ( ml ) ( pt) 5.00 g Remember: When there is a fraction in the enominator, flip the bottom guy an multiply. I want to see this step in your work. ρ = s8.0 gs (4 pt) ( pt) correct numerical answer ( pt) correct sigigs ( pt) units must be inclue in the answer ( pt) units must match work Page 4 of 9
3a) Using variables only, write the ensity equation an rearrange it to isolate mass (m). (3 pt) Max Time: 2 min. = m ( pt) Initial equation () = xmx ( pt) write the initial equation. Wrote enominator for crossmultiply set up. xmx = ( pt) cross-multiplication, correct answer. As long as you show your work, you can use any metho to solve this problem. You cannot, however, simply write the answer because you can see it in your hea. You coul have also multiplie both sies by. 3b) Use your answer to Question 3a an the ata in the prompt to calculate the mass (in kilograms) of the substance. (0 pt) m = (0 pt) rewrite the rearrange equation. m = ( 0.85 g cm3 ) (000. ) (3 pt) Plug numerical values in correctly, incluing units. cm 3 m = ( 850.0 g ) ( kg 000 g ) (3 pt) Convert to kg; correct conversion factor; incluing units m = s0.8500 kgs (4 pt) ( pt) correct numerical answer ( pt) correct sigigs ( pt) answer must have units ( pt) units must match work Page 5 of 9
4) The ensity of a soli is 5.92 grams per cubic centimeter. 4a) Write the conversion factor base upon the ensity of this substance. (4 pt) Max Time: 2 min 5.92 g = cm 3 pt for number pt for number pt for units pt for units An equals sign must be use. Using a colon or ash = 0.5 pt euction. 4b) A sample of the soli has a volume of 0.000 cm 3. Use imensional analysis to etermine its mass in grams. (0 pt). Max Time: 5 min Again: you may not use the ensity eqn; you must use ensity as a conversion factor for creit 0.000 cm3 ( ) ( 5.92 g ) = x59.200 gx cm3 Point Breakown 0.000 cm3 ( ) ( 5.92 g ) = x59.200 gx cm3 pt: initial value pt: initial value ( pt) correct numerical answer pt: unit inclue pt: unit inclue ( pt) correct sigigs pt: numerator an pt: numerator an ( pt) units match work enominator correct enominator correct ( pt) units through every step Page 6 of 9
5) The ensity of a liqui is 0.979 grams per milliliter. 5a) Write the conversion factor base upon the ensity of this substance. (4 pt) Max Time: 2 min 0.979 g = ml pt for number pt for number pt for units pt for units An equals sign must be use. Using a colon or ash = 0.5 pt euction. 5b) A sample of the liqui has a mass of 2.4 kilograms. Use imensional analysis to etermine its volume (in milliliters). (3 pts). Max Time: 7 min Again: you may not use the ensity eqn; you must use ensity as a conversion factor for creit. 2.4 kg ( ) ( 000 g kg ) ( ml 0.979 g ) = x2.5 0 3 mlx Point Breakown 2.4 kg ( ) ( 000 g kg ) ( ml 0.979 g ) = x2.5 0 3 mlx pt: initial value pt: initial value pt: initial value ( pt) correct numerical answer pt: unit inclue pt: unit inclue pt: unit inclue ( pt) correct sigigs pt: numerator an pt: numerator an pt: numerator an ( pt) units match work enominator correct enominator correct enominator correct ( pt) units through every step The conversion from kg to grams must be shown in imensional analysis. Do not simply slap the ecimal point aroun. Page 7 of 9
5) The ensity of a liqui is 0.979 grams per milliliter. 5a) Write the conversion factor base upon the ensity of this substance. (4 pt) Max Time: 2 min 0.979 g = ml pt for number pt for number pt for units pt for units An equals sign must be use. Using a colon or ash = 0.5 pt euction. 5b) A sample of the liqui has a mass of 2.4 kilograms. Use imensional analysis to etermine its volume (in milliliters). (3 pts). Max Time: 7 min Again: you may not use the ensity eqn; you must use ensity as a conversion factor for creit. 2.4 kg ( ) ( 000 g kg ) ( ml 0.979 g ) = x2.5 0 3 mlx Point Breakown 2.4 kg ( ) ( 000 g kg ) ( ml 0.979 g ) = x2.5 0 3 mlx pt: initial value pt: initial value pt: initial value ( pt) correct numerical answer pt: unit inclue pt: unit inclue pt: unit inclue ( pt) correct sigigs pt: numerator an pt: numerator an pt: numerator an ( pt) units match work enominator correct enominator correct enominator correct ( pt) units through every step The conversion from kg to grams must be shown in imensional analysis. Do not simply slap the ecimal point aroun. Page 8 of 9
6) A -ml sample of Liqui Metal X (LMX) has a mass of 8.5 grams. 6a) Write the conversion factor base upon the information given. (4 pt) Max Time: 3 min Timing: 30 s (all levels) ml LMX = 8.5 g LMX pt for number pt for number pt for units pt for units 6b) An inustrial vat contains 52,000 L of LMX. Use imensional analysis to calculate the mass of LMX in tons. ( ton = 2000 lbs.) Again: you may not use the ensity eqn; you must use ensity as a conversion factor for creit. (9 pts) Max Time: 9 min ( 5.00 05 cm 3 ) ( 8.5 g cm ) ( lb 3 453.59 g ) ( ton ) = x0.2 tonx 2000 lbs POINT BREAKDOWN ( 5.00 05 cm 3 ) ( 8.5 g cm ) ( lb 3 453.59 g ) ( ton ) = x0.2 tonx 2000 lbs pt: initial value pt: initial value pt: initial value pt: initial value ( pt) correct numerical answer pt: unit inclue pt: unit inclue pt: unit inclue pt: unit inclue ( pt) correct sigigs pt: numerator an pt: numerator an pt: numerator an pt: numerator an ( pt) answer inclues units enominator correct enominator correct enominator correct enominator correct ( pt) units must match work Page 9 of 9