Stars I. Distance and Magnitude. How Does One Measure Distance? Distances. Stellar Parallax. Distance Equation some examples!

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Stars I Distance and Magnitude Chapter 17 Why doesn t comparison work? Distances The nearest star (Alpha Centauri) is 40 trillion kilometers away(4 ly) Distance is one of the most important quantities we need to measure in astronomy How Does One Measure Distance? The first method uses some simple geometry Parallax Have you ever notice that as you change positions the background of a given object changes? Now we let the Earth move in its orbit Because of the Earth s motion some stars appear to move with respect to the more distant stars Using the apparent motion of stars gives us the method called Stellar Parallax p = r/d if r = 1 A.U. and we rearrange We get: d = 1/p Definition : if p = 1 then d = 1 parsec 1 parsec = 206,265 A.U. 1 parsec = 3.09 x 1013 km 1 parsec = 3.26 lightyears So Alpha Centauri is 1.3 pc away 40 trillion km, 24.85 trillion mi, and 4 ly Distance Equation some examples! Our distance equation is: d = 1/p Example 1: p = 0.1 and d = 1/p d = 1/0.1 = 10 parsecs Example 2 Barnard s Star: p = 0.545 arcsec d = 1/0.545 = 1.83 parsecs Example 3 Proxima Centauri (closest star): p = 0.772 arcsec d = 1/0.772 = 1.30 parsecs 1

Difficulties with Parallax The very best measurements are 0.01 This is a distance of 100 pc or 326 ly (not very far) Space! Improved Distances In 1989 ESA launched HIPPARCOS This could measure angles of 0.001 arcsec This moves us out to about 1000 parsecs or 3260 lightyears HIPPARCOS has measured the distances of about 118,000 nearby stars The U.S. Naval Observatory Interferometer can come close to this level from the ground How do we measure distances beyond 1000 pc? Indirectly! We will now discuss a system that will reappear throughout the semester and it is very critical that you understand how it works. Luminosity, Apparent brightness, and the Inverse square law Luminosity = total amount of power (energy per sec) Measured in L s or Watts Apparent brighntess = power per area (power per square meter) Measured in W/m 2, symbol = b Brightness b=l/4pd 2 b s =3.9 x 10 26 W/4p(1.5 x 10 11 m) 2 = 1370 W/m 2 We measure brightness using a CCD. This method is called photometry. Apparent Magnitudes How bright do the stars appear? 2

Apparent Magnitude Scale It is symbolized by m Brightest Stars in the sky are 1 st magnitude Faintest stars visible to the naked-eye are 6th magnitude each step in magnitude is 2.512 times brighter Apparent Magnitude Scale Magnitude Difference Brightness Ratio 1 2.512 1 2.512 2 2.512 2 6.31 3 2.512 3 15.85 4 2.512 4 39.82 Brightness Ratio 5 2.512 5 100.0 10 2.512 10 10,000 A Modern Magnitude System Now we know some stars are brighter than 1st magnitude Sirius A: -1.46 Canopus: -0.72 Arcturus: -0.06 Alpha Centauri: -0.01 Vega: 0.04 Capella: 0.08 Rigel: 0.14 What Effects Apparent Magnitude? Intrinsic brightness of the object Distance to the object Examples Star Magnitude Distance Sirius A -1.46 8.61 ly Canopus -0.72 313 ly Alpha Centauri -0.01 4.4 ly Rigel 0.14 773 ly Distance and Brightness For nearby stars we know Distance from parallax Apparent magnitude Ratio of apparent brightness when compared to the sun We can calculate the luminosity using that information. M represents absolute magnitude M is the magnitude a star would have if placed at a distance of 10 pc from Earth Now- back to the question of distances 3

How do we measure distances beyond 1000 pc? Indirectly! Here is how it works That looks complicated lets make it simpler m 1 m 2 = (2.5)*(log(b 1 ) - log(b 2 )) b=l/4pd 2 and B=L/4pD 2 m - M = (2.5)*(log(L/ 4pD 2 ) - log(l/ 4pd 2 )) m - M = 5 * log(d/d) Remember the absolute magnitude is the magnitude if the object was at 10 parsecs This gives us : m - M = 5 log(d/10) or m - M = 5 log(d) 5 Remember this is the brightness of an object if it appeared at 10 parsecs Examples of s Sun = +4.8 Faintest Stars = +20.0 Giant Elliptical Galaxies = -23.0 Supernova 1987 A = -15.5 Example of Distance Modulus The Sun: m-m = 5log(d)-5 m = -26.7, M =?, d= 5.011*10-6 pc Remember: m - M = 5 log(d) - 5 Solve for log(d) : log(d) = [(m - M) + 5] / 5 We will use this equation several times during this semester when discussing distance to astronomical objects. m - M is also called the distance modulus (m - M) is (-) then object closer than 10 pc (m - M) is (+) then object farther than 10 pc (m - M) is zero then object is exactly 10 pc away Distances If we know the apparent magnitude and the absolute magnitude we can find the distance To do this we must have a known absolute magnitude Objects which have a known absolute magnitude are called Standard Candles Refinement of the Magnitude Scales We must refine our definition of magnitudes To really understand magnitude we have to talk about filters There are many filter systems used in astronomy Johnson-Cousins Stromgren Infrared Washington Johnson UBV Filters 4

Representation of Magnitudes Apparent magnitude m V is the magnitude in the V filter this is sometimes just V Absolute magnitude M V is the magnitude in the V filter this is also sometimes just V Colors Let s define color in the Astronomical Context Color Indices or a Color Index The difference between two magnitudes taken in two different filters Examples: (B-V) (U-B) (b-y) Example Stars Star B-V U-B Temp appearance Bellatrix -0.23-0.87 21,500 K Blue Regulus -0.12-0.38 12,000 K Blue-White Sirius +0.01-0.05 9,400 K Blue-White Megrez +0.08 +0.07 8,800 K White Altair +0.22 +0.08 7,400 K Yellow Sun +0.62 +0.10 5,800 K Yellow Aldebaran +1.54 +1.90 3,700 K Orange Betelgeuse +1.85 +2.06 2,400 K Red 5