Instant download Test bank for Chemistry The Central Science 10th Edition by Brown, LeMay, Bursten CLICK HERE

Chemistry, 10e (Brown) Chapter 9, Molecular Geometry and Bonding Theories Instant download Test bank for Chemistry The Central Science 10th Edition by Brown, LeMay, Bursten CLICK HERE http://testbankair.com/download/test-bank-for-chemistry-the-central-science-10th-edition-by-brown-lemay-bursten/ http://testbankair.com/download/test-bank-for-chemistry-the-central-science-10th-edition-by-brown-lemay-bursten/ Multiple-Choice and Bimodal 1) For a molecule with the formula linear or bent linear or trigonal planar linear or T-shaped T-shaped trigonal planar Diff: 1 Page Ref: Sec. 9.1 AB the molecular shape is. ) According to VSEPR theory, if there are five electron domains in the valence shell of an atom, they will be arranged in a(n) geometry. octahedral linear tetrahedral trigonal planar trigonal bipyramidal Answer: E ) According to VSEPR theory, if there are four electron domains in the valence shell of an atom, they will be arranged in a(n) geometry. octahedral linear tetrahedral trigonal planar trigonal bipyramidal 4) The electron-domain geometry and molecular geometry of iodine trichloride are and, reectively. trigonal bipyramidal, trigonal planar tetrahedral, trigonal pyramidal trigonal bipyramidal, T-shaped octahedral, trigonal planar T-shaped, trigonal planar 5) The molecular geometry of is square planar. CCl 4 XeF 4 PH XeF ICl 1

Diff: Page Ref: Sec. 9.

6) The molecular geometry of the linear tetrahedral bent trigonal pyramidal octahedral Diff: Page Ref: Sec. 9. + HO ion is. 7) The molecular geometry of the linear bent tetrahedral trigonal planar T-shaped CS molecule is. 8) The molecular geometry of the trigonal planar tetrahedral trigonal pyramidal octahedral T-shaped SiHCl molecule is. 9) The molecular geometry of the PHCl molecule is. bent trigonal planar trigonal pyramidal tetrahedral T-shaped Diff: Page Ref: Sec. 9. 10) The molecular geometry of the CHCl molecule is. bent trigonal planar trigonal pyramidal tetrahedral T-shaped 11) The molecular geometry of the SF molecule is. linear bent trigonal planar tetrahedral octahedral Diff: Page Ref: Sec. 9.

1) The molecular geometry of the octahedral tetrahedral trigonal pyramidal trigonal planar trigonal bipyramidal + PF ion is. 1) The F B F bond angle in the BF - ion is approximately. 90 109.5 10 180 60 14) The Cl Si Cl bond angle in the 90 109.5 10 180 60 SiClF molecule is approximately. 15) The F B F bond angle in the 90 109.5 10 180 60 Diff: Page Ref: Sec. 9. BF molecule is. 16) The O S O bond angle in 90 109.5 10 180 60 SO is slightly less than. 17) The F N F bond angle in the NF molecule is slightly less than. 90 109.5 10 180 60 4

18) According to valence bond theory, which orbitals on bromine atoms overlap in the formation of the bond in? s p 4s 4p d Diff: 1 Page Ref: Sec. 9.4 Br 19) The electron-domain geometry of a sulfur-centered compound is trigonal bipyramidal. The hybridization of the central nitrogen atom is. d d 0) The hybridization of orbitals on the central atom in a molecule is. The electron-domain geometry around this central atom is. octahedral linear trigonal planar trigonal bipyramidal tetrahedral 1) The hybridization of orbitals on the central atom in a molecule is. The electron-domain geometry about this central atom is. octahedral linear trigonal planar trigonal bipyramidal tetrahedral ) The hybridization of the carbon atom in carbon dioxide is. d d 5

) The hybridization of the central atom in the XeF 4 molecule is. d d Answer: E Diff: Page Ref: Sec. 9.5 4) The electron-domain geometry of the atom for bonding are orbitals. d d d Diff: Page Ref: Sec. 9.5 AsF6 - ion is octahedral. The hybrid orbitals used by the As 5) In order to produce hybrid orbitals, s atomic orbital(s) and p atomic orbital(s) must be mixed. one, two one, three one, one two, two two, three 6) The angles between 45 180 90 109.5 10 Answer: E orbitals are. 7) There are σ and π bonds in the H C C H molecule. and and 4 4 and and 5 and 0 6

8) There are σ and π bonds in the HC=C=CH molecule. 4, 6, 4,, 6 6, Answer: E 9) The total number of π bonds in the H C C C C C N molecule is. 4 6 9 1 0) There is/are σ bond(s) in the molecule below. 1 1 1 18 7

1) There is/are π bond(s) in the molecule below. 0 1 4 16 ) There is/are π bond(s) in the molecule below. 7 6 1 0 ) The Lewis structure of carbon monoxide is given below. The hybridizations of the carbon and oxygen atoms in carbon monoxide are and, reectively.,, : C O :,,, Diff: Page Ref: Sec. 9.6 8

Multiple-Choice 4) The basis of the VSEPR model of molecular bonding is. regions of electron density on an atom will organize themselves so as to maximize s-character regions of electron density in the valence shell of an atom will arrange themselves so as to maximize overlap atomic orbitals of the bonding atoms must overlap for a bond to form electron domains in the valence shell of an atom will arrange themselves so as to minimize repulsions hybrid orbitals will form as necessary to, as closely as possible, achieve herical symmetry 5) According to VSEPR theory, if there are three electron domains in the valence shell of an atom, they will be arranged in a(n) geometry. octahedral linear tetrahedral trigonal planar trigonal bipyramidal Diff: Page Ref: Sec. 9. 6) In counting the electron domains around the central atom in VSEPR theory, a is not included. nonbonding pair of electrons single covalent bond core level electron pair double covalent bond triple covalent bond 7) The electron-domain geometry of is tetrahedral. CBr 4 PH CCl BR XeF 4 all of the above except Answer: E Diff: Page Ref: Sec. 9. XeF 4 8) The O C O bond angle in the CO - ion is approximately. 90 109.5 10 180 60 Diff: Page Ref: Sec. 9. 9

9) The Cl C Cl bond angle in the greater than 90 less than 109.5 less than 10 greater than 10 greater than 109.5 CClO molecule (C is the central atom) is slightly. 40) Of the following ecies, will have bond angles of 10. PH ClF NCl All of these will have bond angles of 10. BCl 41) The molecular geometry of the trigonal pyramidal trigonal planar bent tetrahedral T-shaped Diff: Page Ref: Sec. 9. BrO- ion is. 4) The molecular geometry of the left-most carbon atom in the molecule below is. trigonal planar trigonal bipyramidal tetrahedral octahedral T-shaped 10

4) The molecular geometry of the right-most carbon in the molecule below is. trigonal planar trigonal bipyramidal tetrahedral octahedral T-shaped 44) The bond angles marked a, b, and c in the molecule below are about,, and, reectively. 90, 90, 90 10, 10, 90 10, 10, 109.5 109.5, 10, 109.5 109.5, 90, 10 Diff: Page Ref: Sec. 9. 45) The bond angles marked a, b, and c in the molecule below are about,, and, reectively. 109.5, 109.5, 109.5 10, 109.5, 10 109.5, 109.5, 10 90, 180, 90 109.5, 109.5, 90 Diff: Page Ref: Sec. 9. 11

46) The bond angle marked a in the following molecule is about. 90 109.5 10 180 60 ICl - 47) The central iodine atom in the ion has nonbonded electron pairs and bonded electron pairs in its valence shell.,, 4 1,,, 4 Answer: E 4 48) The central iodine atom in electron pairs in its valence shell. 1, 5 0, 5 5, 1 4, 1 1, 4 IF 5 has unbonded electron pairs and bonded 49) The central Xe atom in the XeF4 molecule has unbonded electron pairs and bonded electron pairs in its valence shell. 1, 4, 4 4, 0 4, 1 4, 1

50) An electron domain consists of. a) a nonbonding pair of electrons b) a single bond c) a multiple bond a only b only c only a, b, and c b and c 51) According to VSEPR theory, if there are three electron domains on a central atom, they will be arranged such that the angles between the domains are. 90 180 109.5 60 10 Answer: E 5) According to VSEPR theory, if there are four electron domains on a central atom, they will be arranged such that the angles between the domains are. 10 109.5 180 60 90 5) According to VSEPR theory, if there are two electron domains on a central atom, they will be arranged such that the angles between the domains are. 60 10 109.5 180 90 54) The electron-domain geometry and the molecular geometry of a molecule of the general formula AB n are. never the same always the same sometimes the same not related mirror images of one another 1

55) The electron-domain geometry and the molecular geometry of a molecule of the general formula will always be the same if. there are no lone pairs on the central atom there is more than one central atom n is greater than four n is less than four the octet rule is obeyed AB n 56) For molecules of the general formula, n can be greater than four. for any element A only when A is an element from the third period or below the third period only when A is boron or beryllium only when A is carbon only when A is Xe AB n Consider the following ecies when answering the following questions: (i) PCl (ii) CCl 4 (iii) TeCl 4 (iv) XeF 4 (v) SF 6 57) For which of the molecules is the molecular geometry (shape) the same as the VSEPR electron domain arrangement (electron domain geometry)? (i) and (ii) (i) and (iii) (ii) and (v) (iv) and (v) (v) only Diff: Page Ref: Sec. 9. 58) Of the molecules below, only is polar. SbF 5 AsH I SF 6 CH 4 Diff: Page Ref: Sec. 9. 59) Of the molecules below, only is nonpolar. CO HO NH HCl TeCl Diff: 1 Page Ref: Sec. 9. 14

60) Of the molecules below, only is polar. CCl 4 CH 4 SeF 4 SiCl 4 BF 4 Diff: 1 Page Ref: Sec. 9. 61) Of the molecules below, only is nonpolar. BF NF IF PBr Diff: 1 Page Ref: Sec. 9. BrCl 6) Three monosulfur fluorides are observed: SF, SF 4, and SF 6. Of these, is/are polar. SF only SF and SF 4 only SF 4 only SF 6 only SF, SF 4, and SF 6 Diff: Page Ref: Sec. 9. 6) The molecular geometry of the BeCl molecule is, and this molecule is. linear, nonpolar linear, polar bent, nonpolar bent, polar trigonal planar, polar Diff: 1 Page Ref: Sec. 9. 64) The molecular geometry of the PF molecule is, and this molecule is. trigonal planar, polar trigonal planar, nonpolar trigonal pyramidal, polar trigonal pyramidal, nonpolar tetrahedral, unipolar Diff: Page Ref: Sec. 9. 15

65) Of the following molecules, only is polar. BeCl BF CBr 4 SiHCl Cl Diff: 1 Page Ref: Sec. 9. 66) Of the following molecules, only is polar. CCl 4 BCl NCl BeCl Diff: 1 Page Ref: Sec. 9. Cl 67) For molecules with only one central atom, how many lone pairs on the central atom guarantees molecular polarity? 1 1 or 1 or Diff: 1 Page Ref: Sec. 9. 68) The molecular geometry of the trigonal pyramidal, polar tetrahedral, nonpolar seesaw, nonpolar tetrahedral, polar seesaw, polar Diff: 1 Page Ref: Sec. 9. 69) The molecular geometry of the trigonal pyramidal, polar trigonal pyramidal, nonpolar trigonal planar, polar trigonal planar, nonpolar trigonal bipyramidal, polar Diff: 1 Page Ref: Sec. 9. CHF BCl molecule is, and the molecule is. molecule is, and this molecule is. 16

70) According to valence bond theory, which orbitals overlap in the formation of the bond in HBr? 1s on H and 4p on Br 1s on H and 4s on Br 1s on H and p on Br s on H and 4p on Br s on H and p on Br Diff: 1 Page Ref: Sec. 9.4 71) The combination of two atomic orbitals results in the formation of molecular orbitals. 1 4 0 7) The electron-domain geometry of a carbon-centered compound is tetrahedral. The hybridization of the central carbon atom is. d d Diff: Page Ref: Sec. 9.5 7) Of the following, only has PH - CO ICl I- PF 5 74) Of the following, the central atom is PCl 5 XeF 4 PH Br - BeF d hybridization of the central atom. hybridized only in. 17

75) The d atomic hybrid orbital set accommodates electron domains. 4 5 6 Answer: E 76) The atomic hybrid orbital set accommodates electron domains. 4 5 6 77) The hybridizations of nitrogen in,,,,, NF and NH are and, reectively. 78) The hybridizations of iodine in, d d d,, d d d,, d d IF and IF 5 are and, reectively. 79) The hybridizations of bromine in BrF 5 and of arsenic in AsF 5 are and, reectively., d d, d, d, d d d, d 18

80) The hybrid orbitals used for bonding by the sulfur atom in the d d SF 4 molecule are orbitals. 81) The hybrid orbitals used for bonding by Xe in the unstable d d Diff: Page Ref: Sec. 9.5 XeF molecule are orbitals. 8) The hybridization of the oxygen atom labeled y in the structure below is. The C O H bond angle is., 180, 109.5, 109.5 d, 90, 90 Diff: Page Ref: Sec. 9.5 8) The electron-domain geometry of the AsF 5 molecule is trigonal bipyramidal. The hybrid orbitals used by the As atom for bonding are orbitals. d d d 19

84) hybrid orbitals are used for bonding by Xe in the d d XeF 4 molecule. Consider the following ecies when answering the following questions: (i) PCl (ii) CCl 4 (iii) TeCl 4 (iv) XeF 4 (v) SF 6 85) In which of the molecules does the central atom utilize d orbitals to form hybrid orbitals? (i) and (ii) (iii) only (i) and (v) (iii), (iv), and (v) (v) only Diff: Page Ref: Sec. 9.5 86) Which of the molecules has a see-saw shape? (i) (ii) (iii) (iv) (v) Diff: Page Ref: Sec. 9., 9.5 87) In which of the molecules is the central atom (i) and (ii) (iii) only (iii) and (iv) (iv) and (v) (v) only d hybridized? 88) There are unhybridized p atomic orbitals in an -hybridized carbon atom. 0 1 4 0

89) When three atomic orbitals are mixed to form hybrid orbitals, how many hybrid orbitals are formed? one six three four five 90) The blending of one s atomic orbital and two p atomic orbitals produces. three hybrid orbitals two hybrid orbitals three two hybrid orbitals hybrid orbitals three hybrid orbitals Answer: E 91) A triatomic molecule cannot be linear if the hybridization of the central atoms is. or d or d 9) A typical double bond. is stronger and shorter than a single bond consists of one σ bond and one π bond imparts rigidity to a molecule consists of two shared electron pairs All of the above answers are correct. Answer: E 9) A typical triple bond. consists of one σ bond and two π bonds consists of three shared electrons consists of two σ bonds and one π bond consists of six shared electron pairs is longer than a single bond 1

94) In a polyatomic molecule, "localized" bonding electrons are associated with. one particular atom two particular atoms all of the atoms in the molecule all of the π bonds in the molecule two or more σ bonds in the molecule 95) Which of the following molecules or ions will exhibit delocalized bonding? SO SO - SO SO, SO - SO only and SO SO and, and SO - SO - SO None of the above will exhibit delocalized bonding. 96) Which of the following molecules or ions will exhibit delocalized bonding? NO - NO 4 + N- NO 4 + and NO - only N- NO -, NO 4 +, and N- only N- N- NO - and 97) In order to exhibit delocalized π bonding, a molecule must have. at least two π bonds at least two resonance structures at least three σ bonds at least four atoms trigonal planar electron domain geometry 98) In a typical multiple bond, the σ bond results from overlap of orbitals and the π bond(s) result from overlap of orbitals. hybrid, atomic hybrid, hybrid atomic, hybrid hybrid, hybrid or atomic hybrid or atomic, hybrid or atomic

99) The carbon-carbon σ bond in ethylene, hybrid orbitals hybrid orbitals hybrid orbitals s atomic orbitals p atomic orbitals 100) The π bond in ethylene, hybrid orbitals s atomic orbitals hybrid orbitals hybrid orbitals p atomic orbitals Answer: E CHCH CHCH, results from the overlap of., results from the overlap of. 101) In order for rotation to occur about a double bond,. the σ bond must be broken the π bond must be broken the bonding must be delocalized the bonding must be localized the σ and π bonds must both be broken 10) A typical triple bond consists of. three sigma bonds three pi bonds one sigma and two pi bonds two sigma and one pi bond three ionic bonds 10) The N N bond in HNNH consists of. one σ bond and one π bond one σ bond and two π bonds two σ bonds and one π bond two σ bonds and two π bonds one σ bond and no π bonds

104) The hybridization of the terminal carbons in the HC=C=CH molecule is. d d Diff: Page Ref: Sec. 9.6 105) The hybridization of nitrogen in the H C N: molecule is. 106) The hybridization of the carbon atom labeled x in the molecule below is. d d 4

107) The hybridization of the oxygen atom labeled x in the structure below is. d d 108) The Lewis structure of carbon dioxide is given below. The hybridization of the carbon atom in carbon dioxide is. d d Diff: Page Ref: Sec. 9.6 109) Electrons in bonds remain localized between two atoms. Electrons in bonds can become delocalized between more than two atoms. pi, sigma sigma, pi pi, pi sigma, sigma ionic, sigma Diff: Page Ref: Sec. 9.6 110) Valence bond theory does not address the issue of. excited states of molecules molecular shape covalent bonding hybridization multiple bonds Diff: Page Ref: Sec. 9.5 5

111) Structural changes around a double bond in the portion of the rhodopsin molecule trigger the chemical reactions that result in vision. protein opsin retinal cones rods Diff: Page Ref: Sec. 9.6 11) The bond order of any molecule containing equal numbers of bonding and antibonding electrons is. 0 1 1/ Diff: Page Ref: Sec. 9.7 11) In molecular orbital theory, the H the molecule. filled, filled filled, empty filled, half-filled half-filled, filled empty, filled Diff: 4 Page Ref: Sec. 9.7 σ 1s orbital is and the * σ 1s orbital is in 114) Based on molecular orbital theory, the only molecule in the list below that has unpaired electrons is. C N F O Li Diff: Page Ref: Sec. 9.8 115) Based on molecular orbital theory, there are unpaired electrons in the 0 1 1/ Diff: Page Ref: Sec. 9.8 + OF ion. 116) Based on molecular orbital theory, the bond orders of the H H bonds in H, H +, and H - are, reectively 1, 0, and 0 1, 1/, and 0 6

1, 0, and 1/ 1, 1/, and 1/ 1,, and 0 Diff: 4 Page Ref: Sec. 9.7 117) Based on molecular orbital theory, the bond order of the H H bond in the 0 1/ 1 / Diff: 4 Page Ref: Sec. 9.7 H + ion is. 118) Based on molecular orbital theory, the bond order of the N N bond in the. 0 1 5 Diff: 4 Page Ref: Sec. 9.8 N molecule is 119) Based on molecular orbital theory, the bond order of the N N bond in the 0 1 1/ Diff: 4 Page Ref: Sec. 9.8 + N ion is. 10) Based on molecular orbital theory, the bond order of the Be Be bond in the. 0 1 4 Diff: 4 Page Ref: Sec. 9.8 Be molecule is 11) Based on molecular orbital theory, the bond order of the C C bond in the C molecule is. 0 1 4 Diff: 4 Page Ref: Sec. 9.8 7

1) An antibonding π orbital contains a maximum of electrons. 1 4 6 8 Diff: Page Ref: Sec. 9.7 1) According to MO theory, overlap of two s atomic orbitals produces. one bonding molecular orbital and one hybrid orbital two bonding molecular orbitals two bonding molecular orbitals and two antibonding molecular orbitals two bonding molecular orbitals and one antibonding molecular orbital one bonding molecular orbital and one antibonding molecular orbital Answer: E Diff: Page Ref: Sec. 9.7 14) A molecular orbital can accommodate a maximum of electron(s). one two four six twelve Diff: Page Ref: Sec. 9.7 15) Molecular Orbital theory correctly predicts paramagnetism of oxygen gas,. This is because. the bond order in can be shown to be equal to. there are more electrons in the bonding orbitals than in the antibonding orbitals. the energy of the πpmos is higher than that of the σpmo O there are two unpaired electrons in the MO electron configuration of O the O O bond distance is relatively short Diff: 4 Page Ref: Sec. 9.7, 9.8 16) Molecular Orbital theory correctly predicts diamagnetism of fluorine gas, F. This is because. the bond order in F can be shown to be equal to 1. there are more electrons in the bonding orbitals than in the antibonding orbitals. all electrons in the MO electron configuration of F are paired. the energy of the πpmos is higher than that of the σpmo the F F bond enthalpy is very low Diff: 4 Page Ref: Sec. 9.7, 9.8 O 8

17) Of the following, only appears to gain mass in a magnetic field. C N F O Li Diff: 4 Page Ref: Sec. 9.8 18) Of the following, appear(s) to gain mass in a magnetic field. O N B N B B N O only only and and N O O and Answer: E Diff: 4 Page Ref: Sec. 9.8 19) According to MO theory, overlap of two p atomic orbitals produces. two bonding molecular orbitals one bonding molecular orbital and one antibonding molecular orbital two bonding molecular orbitals and two antibonding molecular orbitals two bonding molecular orbitals and one antibonding molecular orbital three bonding molecular orbitals and three antibonding molecular orbitals Diff: Page Ref: Sec. 9.8 10) According to MO theory, overlap of two p atomic orbitals produces. one π MO and one σ* MO one π MO and one σ MO one π MO and one π* MO or one σ MO and one σ* MO one π + MO and one σ* MO two π MOs, two π + MOs, one σ MO, and one σ* MO Diff: Page Ref: Sec. 9.8 11) An antibonding MO the correonding bonding MO. is always lower in energy than can accommodate more electrons than can accommodate fewer electrons than is always higher in energy than is always degenerate with Diff: Page Ref: Sec. 9.8 9

1) The more effectively two atomic orbitals overlap,. the more bonding MOs will be produced by the combination the higher will be the energy of the resulting bonding MO and the lower will be the energy of the resulting antibonding MO the higher will be the energies of both bonding and antibonding MOs that result the fewer antibonding MOs will be produced by the combination the lower will be the energy of the resulting bonding MO and the higher will be the energy of the resulting antibonding MO Answer: E Diff: 4 Page Ref: Sec. 9.8 1) The bond order of a homonuclear diatomic molecule can be decreased by. removing electrons from a bonding MO or adding electrons to an antibonding MO adding electrons to a bonding MO or removing electrons from an antibonding MO adding electrons to any MO removing electrons from any MO The bond order of a homonuclear diatomic molecule cannot be decreased by any means. Diff: 4 Page Ref: Sec. 9.8 14) The order of MO energies in B, C, and N (σ p > π p ), is different from the order in O, F, and Ne (σ p < π p ) This is due to. O less effective overlap of p orbitals in, F, and Ne the more metallic character of boron, carbon and nitrogen as compared to oxygen, fluorine, and neon greater s-p interaction in,, and greater s-p interaction in O B, F C less effective overlap of p orbitals in Diff: 5 Page Ref: Sec. 9.8 Short Answer, and B, Ne N C, and 1) The 1s hydrogen orbital overlaps with the iodine orbital in HI. Answer: 5p Diff: Page Ref: Sec 9.5 ) A covalent bond in which overlap regions lie above and below an internuclear axis is called a(n). Answer: π bond Diff: Page Ref: Sec 9.6 ) The sensation of vision results from a nerve impulse that is triggered by the separation of retinal from. Answer: opsin Diff: Page Ref: Sec 9.6 4) In molecular orbital theory the stability of a covalent body is related to its. Answer: bond order Diff: Page Ref: Sec 9.7 5) Each molecular orbital can accommodate, at most, two electrons with their ins paired. This is called the. Answer: Pauli principle Diff: 4 Page Ref: Sec 9.8 N 0

6) The more unpaired electrons in a ecies, the stronger is the force of magnetic attraction. This is called. Answer: paramagnetism Diff: 1 Page Ref: Sec 9.8 True/False 1) Possible shapes of molecules are linear, trigonal planar, and T-shaped. Answer: FALSE Diff: Page Ref: Sec 9.1 AB ) Boron trifluoride has three bonding domains and its electron domain geometry is trigonal planar. Answer: TRUE Diff: Page Ref: Sec 9. ) Electron domains for single bonds exert greater force on adjacent domains than the electron domains for multiple bonds. Answer: FALSE Diff: 1 Page Ref: Sec 9. 4) The quantitative amount of charge separation in a diatomic molecule contributes t o the dipole moment of that molecule. Answer: TRUE Diff: 1 Page Ref: Sec 9. 5) Hybridization is the process of mixing atomic orbitals as atoms approach each other to form a bond. Answer: TRUE Diff: 1 Page Ref: Sec 9.5 6) Electrons in core orbitals contribute to atom bonding. Answer: FALSE Diff: 1 Page Ref: Sec 9.6 Algorithmic Questions 1) Using the VSEPR model, the electron-domain geometry of the central atom in BF is. linear trigonal planar tetrahedral trigonal bipyramidal octahedral ) Using the VSEPR model, the electron-domain geometry of the central atom in SF is. linear trigonal planar tetrahedral trigonal bipyramidal octahedral 1

) Using the VSEPR model, the electron-domain geometry of the central atom in ClF is. linear trigonal planar tetrahedral trigonal bipyramidal octahedral 4) Using the VSEPR model, the electron-domain geometry of the central atom in BrF4 - is. linear trigonal planar tetrahedral trigonal bipyramidal octahedral Answer: E 5) Using the VSEPR model, the molecular geometry of the central atom in XeF is. linear trigonal planar tetrahedral bent trigonal pyramidal 6) Using the VSEPR model, the molecular geometry of the central atom in BCl is. linear trigonal planar tetrahedral bent trigonal pyramidal 7) Using the VSEPR model, the molecular geometry of the central atom in CF4 is. linear trigonal planar tetrahedral bent trigonal pyramidal 8) Using the VSEPR model, the molecular geometry of the central atom in SO is. linear trigonal planar tetrahedral bent trigonal pyramidal

9) Using the VSEPR model, the molecular geometry of the central atom in NCl is. linear trigonal planar tetrahedral bent trigonal pyramidal Answer: E 10) Using the VSEPR model, the molecular geometry of the central atom in PF5 is. tetrahedral square planar trigonal bipyramidal seesaw square pyramidal 11) The hybrid orbital set used by the central atom in NO - is. d d 1) The hybrid orbital set used by the central atom in BF4 - is. d d 1) The hybrid orbital set used by the central atom in KrF is. d d