MA 201 Complex Analysis Lecture 6: Elementary functions

Similar documents
Chapter 3 Elementary Functions

CHAPTER 3 ELEMENTARY FUNCTIONS 28. THE EXPONENTIAL FUNCTION. Definition: The exponential function: The exponential function e z by writing

3 Elementary Functions

CHAPTER 4. Elementary Functions. Dr. Pulak Sahoo

Math Spring 2014 Solutions to Assignment # 6 Completion Date: Friday May 23, 2014

4.1 Exponential and Logarithmic Functions

Section 7.2. The Calculus of Complex Functions

Exercises involving elementary functions

(1) Let f(z) be the principal branch of z 4i. (a) Find f(i). Solution. f(i) = exp(4i Log(i)) = exp(4i(π/2)) = e 2π. (b) Show that

Syllabus: for Complex variables

Solutions to Exercises 1.1

MATH 417 Homework 4 Instructor: D. Cabrera Due July 7. z c = e c log z (1 i) i = e i log(1 i) i log(1 i) = 4 + 2kπ + i ln ) cosz = eiz + e iz

Lecture 9. = 1+z + 2! + z3. 1 = 0, it follows that the radius of convergence of (1) is.

Exercises involving elementary functions

MTH3101 Spring 2017 HW Assignment 4: Sec. 26: #6,7; Sec. 33: #5,7; Sec. 38: #8; Sec. 40: #2 The due date for this assignment is 2/23/17.

Exponential and Trigonometric functions

1 z n = 1. 9.(Problem) Evaluate each of the following, that is, express each in standard Cartesian form x + iy. (2 i) 3. ( 1 + i. 2 i.

Considering our result for the sum and product of analytic functions, this means that for (a 0, a 1,..., a N ) C N+1, the polynomial.

18.04 Practice problems exam 1, Spring 2018 Solutions

Solution for Final Review Problems 1

Solutions to Selected Exercises. Complex Analysis with Applications by N. Asmar and L. Grafakos

Topic 2 Notes Jeremy Orloff

1 Discussion on multi-valued functions

Complex Variables. Cathal Ormond

1 Holomorphic functions

Math 715 Homework 1 Solutions

Physics 307. Mathematical Physics. Luis Anchordoqui. Wednesday, August 31, 16

Chapter 9. Analytic Continuation. 9.1 Analytic Continuation. For every complex problem, there is a solution that is simple, neat, and wrong.

= x iy. Also the. DEFINITION #1. If z=x+iy, then the complex conjugate of z is given by magnitude or absolute value of z is z =.

2.5 Exponential Functions and Trigonometric Functions

Functions of a Complex Variable (Zill & Wright Chapter 17)

10.3. The Exponential Form of a Complex Number. Introduction. Prerequisites. Learning Outcomes

Complex Homework Summer 2014

Math Spring 2014 Solutions to Assignment # 8 Completion Date: Friday May 30, 2014

M361 Theory of functions of a complex variable

Exercises for Part 1

Math 417 Midterm Exam Solutions Friday, July 9, 2010

Inverse Trig Functions

1. COMPLEX NUMBERS. z 1 + z 2 := (a 1 + a 2 ) + i(b 1 + b 2 ); Multiplication by;

Introduction to Complex Variables Class Notes Instructor: Louis Block

MATH 106 HOMEWORK 4 SOLUTIONS. sin(2z) = 2 sin z cos z. (e zi + e zi ) 2. = 2 (ezi e zi )

EEE 203 COMPLEX CALCULUS JANUARY 02, α 1. a t b

Fourth Week: Lectures 10-12

Math 411, Complex Analysis Definitions, Formulas and Theorems Winter y = sinα

Complex Analysis Homework 1: Solutions

Chapter 3 Differentiation Rules (continued)

Hyperbolics. Scott Morgan. Further Mathematics Support Programme - WJEC A-Level Further Mathematics 31st March scott3142.

Chapter 2: Complex numbers

Test one Review Cal 2

Analyse 3 NA, FINAL EXAM. * Monday, January 8, 2018, *

MAT389 Fall 2016, Problem Set 6

MATH243 First Semester 2013/14. Exercises 1

In this chapter we study several functions that are useful in calculus and other areas of mathematics.

Exercises for Part 1

MATH Complex Analysis. Charles Walkden

Lecture Notes Complex Analysis. Complex Variables and Applications 7th Edition Brown and Churchhill

Math 120 A Midterm 2 Solutions

1. DO NOT LIFT THIS COVER PAGE UNTIL INSTRUCTED TO DO SO. Write your student number and name at the top of this page. This test has SIX pages.

Solutions to Tutorial for Week 3

Complex Numbers and Exponentials

Complex Function. Chapter Complex Number. Contents

SOLUTIONS MANUAL FOR. Advanced Engineering Mathematics with MATLAB Third Edition. Dean G. Duffy

III.2. Analytic Functions

z = x + iy ; x, y R rectangular or Cartesian form z = re iθ ; r, θ R polar form. (1)

1. Solutions to exercises. , Im(

Complex Variables. Instructions Solve any eight of the following ten problems. Explain your reasoning in complete sentences to maximize credit.

MA3111S COMPLEX ANALYSIS I

Math 423/823 Exam 1 Topics Covered

Revision Lectures Trinity Term 2012 Lecturer: F Hautmann CP3

Suggested Homework Solutions

MA 242 Review Exponential and Log Functions Notes for today s class can be found at

e y [cos(x) + i sin(x)] e y [cos(x) i sin(x)] ] sin(x) + ey e y x = nπ for n = 0, ±1, ±2,... cos(nπ) = ey e y 0 = ey e y sin(z) = 0,

Section 4.8 Anti Derivative and Indefinite Integrals 2 Lectures. Dr. Abdulla Eid. College of Science. MATHS 101: Calculus I

Complex Trigonometric and Hyperbolic Functions (7A)

Smalltalk 9/26/13. Is it all in your imagination? Brian Heinold

Part IB. Complex Analysis. Year

u = 0; thus v = 0 (and v = 0). Consequently,

EE2007 Tutorial 7 Complex Numbers, Complex Functions, Limits and Continuity

UNIVERSITY OF SOUTHAMPTON

Topic 1 Notes Jeremy Orloff

Course 214 Section 2: Infinite Series Second Semester 2008

Complex functions, single and multivalued.

Contents. Chapter 1. Complex Numbers 3 1. Basic properties 3 2. The Argand Plane 6 3. Powers of z Loci and Regions in C 13

MTH 3102 Complex Variables Practice Exam 1 Feb. 10, 2017

Functions 45. Integrals, and Contours 55

Cotangent and the Herglotz trick

Mathematics 104 Fall Term 2006 Solutions to Final Exam. sin(ln t) dt = e x sin(x) dx.

Lecture 4. Properties of Logarithmic Function (Contd ) y Log z tan constant x. It follows that

Second Midterm Exam Name: Practice Problems March 10, 2015

CALCULUS II MATH Dr. Hyunju Ban

FINAL - PART 1 MATH 150 SPRING 2017 KUNIYUKI PART 1: 135 POINTS, PART 2: 115 POINTS, TOTAL: 250 POINTS No notes, books, or calculators allowed.

Chapter 2. First-Order Differential Equations

2 Recollection of elementary functions. II

Calculus I Announcements

Math 421 Midterm 2 review questions

8. Solutions to Part 1

NOTES FOR 18.04, Spring 2017

( ) a (graphical) transformation of y = f ( x )? x 0,2π. f ( 1 b) = a if and only if f ( a ) = b. f 1 1 f

If brute force isn t working, you re not using enough of it. -Tim Mauch

Chapter 2: Differentiation

Transcription:

MA 201 Complex Analysis :

The Exponential Function Recall: Euler s Formula: For y R, e iy = cos y + i sin y and for any x, y R, e x+y = e x e y. Definition: If z = x + iy, then e z or exp(z) is defined by the formula e z = e (x+iy) = e x (cos y + i sin y). Image of following sets under exponential function: {(x, y 0) : x R} {(r, θ) : r = e x, x R, θ = y 0}. {(x 0, y) : y R} {(r, θ) : r = e x 0, θ R}. {(x, y) : a x b, c y d} {(r, θ) : e a r e b, c θ d}.

Properties of Exponential Function e 0 = 1 e z = e z, e z e z. e z 0, for all z C. Look at e z = e x e iy = e x 0. For all z, w C, e z+w = e z e w. Indeed, if z = x + iy, w = s + it then, e z+w = e (x+s)+i(y+t) = e (x+s) [cos(y + t) + i sin(y + t)] = e x e s [(cos y cos t sin y sin t) + i(sin y cos t + cos y sin t)] = [e x (cos y + i sin y)][e s (cos t + i sin t)] = e z e w.

Properties of Exponential function A function f : C C is called periodic if there is a w C (called a period) such that f (z + w) = f (z) for all z C. e z is periodic function with period 2πi. e z is not injective unlike real exponential. Since e z = e x cos y + ie x sin y satisfies C-R equation on C and has continuous first order partial derivatives. Therefore e z is an entire function. In fact d d z ez = x (ex cos y) + i x (ex sin y) = e z.

Trigonometric Functions Define Properties: sin 2 z + cos 2 z = 1 sin z = 1 2i (eiz e iz ); cos z = 1 2 (eiz + e iz ). sin(z + w) = sin z cos w + cos z sin w cos(z + w) = cos z cos w sin z sin w sin( z) = sin z and cos( z) = cos z sin(z + 2kπ) = sin z, and cos(z + 2kπ) = cos z sin z = 0 z = nπ and cos z = 0 z = (n + 1 )π,, n Z. 2

Trigonometric functions sin z, cos z are entire functions. d (sin z) = cos z and d (cos z) = sin z. dz dz sin z and cos z are unbounded functions. Define: tan z = sin z cos z cot z = cos z sin z sec z = 1 cos z csc z = 1 sin z.

Trigonometric functions Hyperbolic Trigonometric functions: Define sinh z = ez e z ; and cosh z = ez + e z. 2 2 Properties: sinh z, cosh z are entire functions. cosh 2 z sinh 2 z = 1. sinh( z) = sinh z, cosh( z) = cosh z, sinh(z + 2kπ) = sinh z, cosh(z + 2kπ) = cosh z, k Z. sinh(iz) = i sin z and cos(iz) = cos z sin z = sin(x + iy) = sin x cosh y + i cos x sinh y, cos z = cos(x + iy) = cos x cosh y i sin x sinh y.

Complex Logarithm Note that e z is an onto function from C to C = C \ {0}. In fact if w C then w = w e iθ where θ ( π, π]. If we set z = log w + iθ then, e z = e log w +iθ = e log w e iθ = w. e z is not an injective function as e z+2πik = e z, k Z. But if we restrict the domain then it becomes injective. In particular if H = {z = x + iy : π < y π} then z e z is a bijective function from H to C \ {0}. Question: What is the inverse of this function?

Complex Logarithm Definition: For z C, define log z = ln z + i arg z. ln z stands for the real logarithm of z. Since arg z = Arg z + 2kπ, k Z it follows that log z is not well defined as a function. (multivalued) For z C, the principal value of the logarithm is defined as Log z = ln z + i Argz. Log : C {z = x + iy : π < y π} is well defined (single valued). Log z + 2kπi = log z for some k Z.

Complex Logarithm If z 0 then e Log z = e ln z +i Argz = z What about Log (e z )?. Suppose x is a positive real number then Log x = ln x + i Argx = ln x. Log i = ln i + i π 2 = iπ 2, Log ( 1) = ln 1 + iπ = iπ, Log ( i) = ln i + i π 2 = iπ 2, Log ( e) = 1 + iπ

Complex Logarithm The function Log z is not continuous on the negative real axis R = {z = x + iy : x < 0, y = 0}. To see this consider the point z = α, α > 0. Consider the sequences {a n = αe i(π 1 n ) } and {b n = αe i( π+ 1 n ) }. Then but and lim an = z = lim n n bn lim Log an = lim ln α + i(π 1 ) = ln α + iπ n n n lim Log bn = ln α iπ. n

Complex Logarithm The function z Log z is analytic on the set C \ R. Let z = re iθ 0 and θ ( π, π). Then Log z = ln r + iθ = u(r, θ) + iv(r, θ) with u(r, θ) = ln r and v(r, θ) = θ. Then u r = 1 r v θ = 1 r and v r = 1 r u θ. The identity Log (z 1z 2) = Logz 1 + Log z 2 is not always valid. However, the above identity is true if and only if Arg z 1 + Arg z 2 ( π, π] (why?).

Complex Logarithm Branch of a multiple valued function: Let F be a multiple valued function defined on a domain D. A function f is said to be a branch of the multiple valued function F if in a domaind 0 D if f (z) is single valued and analytic in D 0. Branch Cut: The portion of a line or a curve introduced in order to define a branch of a multiple valued function is called branch cut. Branch Point: Any point that is common to all branch cuts is called a branch point.

Complex Exponents Let w C. For any z 0, define z w = exp(w log z), where exp is the exponential function and log is the multiple valued logarithmic function. z w is a multiple valued function. i i = exp[i log i] = exp[i(log 1 + i π 2 )] = exp( π 2 ).