You try: What is the equation of the line on the graph below? What is the equation of the line on the graph below?

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1 What is the equation of the line on the graph below? 2 3 1a What is the equation of the line on the graph below? y-intercept Solution: To write an equation in slope-intercept form, identify the slope and y-intercept and substitute these values into the equation. The slope-intercept form of a linear equation is: y = mx + b. To identify the slope from a graph, locate two points and use the ratio or subtract with the slope formula. 1b Match the equation with its graph. OR 1) 3x + 4y = 12 The y-intercept is the y-coordinate of the point on the line that crosses the y-axis, which is at 1. Substitute the values of the slope and y-intercept into the equation. 2) 3x + 4y = 12 For Standard Form (Ax + By = C): 3) 3x 4y = 12 A-REI.10 Page 1 of 16 MCC@WCCUSD 01/14/15

2a Given the linear function 3x 4y = 6 Find the x- and y-intercepts The x-intercept is the point where the graph crosses the x-axis (or where y is zero). To find this from the equation, substitute y = 0 & solve for x. The y-intercept is the point where the graph crosses the y-axis (or where x is zero). To find this from the equation, substitute x = 0 & solve for y. 2a Find the x- and y-intercepts and the rate of change of 2x + y = 5 Find the rate of change One method to find the rate of change/slope is to put the equation in slope-intercept form. From this, we can tell that the rate of change is. Because this rate is positive, the graph is increasing everywhere. F-IF.9 2b Given a linear function and the graph of a linear function below, select all of the following statements that are true. Linear Function 1 Linear Function 2 2b Given the graph of the linear function below y = 3x + 1 Find the x- and y-intercepts The x-intercept is ( 3, 0) and the y-intercept is (0, 3). Find the rate of change One method to find the rate of change/slope is to use the slope formula with the x- and y- intercepts. From this, we can tell that the rate of change is 1. Because this rate is positive, the graph is increasing everywhere. F-IF.9 A) These functions have the same x-intercept. B) These functions have the same y-intercept. C) Both functions are increasing on all intervals. D) The rate of change for Function 1 is faster than the rate of change for Function 2. E) The solution to the system containing both equations is (0, 1). Page 2 of 16 MCC@WCCUSD 01/14/15

3 Determine the slope/rate of change for each of the following. 3a Determine the rate of change for a) The equation y = 5 This equation is in slope-intercept form (y = mx + b), but there is no x-term. Therefore, y = 5 can be rewritten as y = 0x + 5. From this we can determine that the slope is zero. b) The equation 3x 2y = 8 1) The equation 2x y = 4 2) The table x y 3 5 5 5 7 5 This equation is in standard form. To find the rate of change, we can rewrite it in slopeintercept form. 3b Select all of the following that have the same slope or rate of change as the graph of the linear function y = 2x 1. From this we can determine that the slope is. A) (6, 2), ( 1, 9) B) 4x 2y = 8 C) y = 1 c) The points (3, 9) and ( 2, 9) To find the rate of change, we can use the slope formula. D) x y 4 6 2 10 0 14 E) Therefore, the slope is 0. F-IF.6 Page 3 of 16 MCC@WCCUSD 01/14/15

4 Write an equation of the line that passes through the point (6, 3) with a slope of 1, in slope-intercept 2 form, point-slope form, AND standard form. Solution: To write an equation in slope-intercept form, identify the slope and y-intercept and substitute these values into the equation. The slope-intercept form of a linear equation is: y = mx + b We are given the slope, but need to find the y-intercept. Substitute the slope m and the coordinates of the point (x, y) in y = mx + b. Then solve for b. 4a Write an equation of the line that passes 3 through the point ( 8, 3) with a slope of, 4 in slope-intercept form, point-slope form, AND standard form. Solution: To write an equation in point-slope form, identify the slope and a point and substitute the values into the equation. The point-slope form of a linear equation is: where are the coordinates of one point. Solution: To write an equation in standard form, collect the variable terms on one side and the constants on the other. The standard form of a linear equation is: Ax + By = C, where A, B, & C are real numbers and A and B are not both zero, and A is usually positive. 4b Select all of the following equations of a line that have a slope of 5 and pass through the point ( 3, 7). A) y + 7 = 5(x 3) B) 5x + y = 8 C) y = 5x 8 D) 3x + 7y = 5 A-CED.2 Page 4 of 16 MCC@WCCUSD 01/14/15

5 Which point appears to be the solution of the linear system graphed below? 5a Which point appears to be the solution of the linear system graphed below? Solution: The solution to a linear system is the point(s) that are solutions to both linear equations. This means that the point that is a solution will be the point that lies on both lines (or the point of intersection). 5b Select all of the statements that are true about the graph of the system shown below. Line 1 Line 2 (4, 1) These lines intersect at the point (4, 1). Therefore the solution to this linear system is the point (4, 1). A) The solution to the system is ( 2, 3). B) There are an infinite number of solutions. A-REI.11 C) The lines intersect at ( 3, 2). D) The slope of Line 1 is negative. E) The slope of Line 2 is negative. Page 5 of 16 MCC@WCCUSD 01/14/15

6 Graph the solution to this system of inequalities. Inequality 1 Inequality 2 1. Graph Inequality 1 6a Graph the solution to this system of inequalities. (0, 0) So, shade the half-plane with the point (0, 0). 2. Graph Inequality 2 (Change to slope-intercept form first) 6b B C E A D ( 1, 4) So, shade the half-plane with the point ( 1, 4). 3. The graph of the system is the intersection of half-planes. Check a point in that intersection. Select all of the points on this coordinate plane that are solutions to the system below. (2, 1) A-REI.12 A) Point A B) Point B C) Point C D) Point D E) Point E Page 6 of 16 MCC@WCCUSD 01/14/15

7 a) Simplify ( 4x 2 y) 3 Method 1: Expansion 7a ( ) 2 1) Simplify 2xy 4 z 2 Method 2: Exponent Properties 2) Simplify 10x3 y 4 25xy 4 b) Simplify 27a3 b 6 18a 5 b Method 1: Expansion 7b Select all of the following expressions that are equivalent to 30a4 b 2 25ab 6 A) 6a 3 b 4 Method 2: Exponent Properties N-RN.2 B) C) D) E) F) 6 5 a4 1 b 2 6 6a 3 5b 4 1 5a 3 6b4 2 3 5 a a a a b b 5 5 a b b b b b b ( 3b 2 )( 3a 2 ) 2 ( ) 3 a 5b Page 7 of 16 MCC@WCCUSD 01/14/15

8 Factor the trinomial x 2 + 3x 70 The trinomial is written in the form, Ax 2 + Bx + C. Find two factors of the product that add up to B. A = 1, B = 3, C = 70 B = 3 8a Factor the trinomial 2x 2 + 13x + 21 Split the middle Bx term with the sum of these factors: 3x = 7x + 10x Solution: Split the middle term. Solution: Generic Rectangle x + 10 x 2 + 3x 70 Write original expression = x 2 7x + 10x 70 Split the middle term x 2 7x +10x 70 x 7 x. x x. 7 2. 5. x 2. 5. 7 = (x 7) (x + 10) Arrange the terms into the rectangle with the Ax 2 term in the top left and the C term in the bottom right. Decompose the terms into prime factors and factor out the GCFs. Solution: If A = 1 the trinomial is written as x 2 + Bx + C. Insert the factors of the product that add up to B. Product: 7. 10 = 70 Sum: 7 + 10 = 3 8b Match each trinomial with its factored form. 1) A Prime 2) x 2 + 14x + 48 B (x 3)(x 16) 3) x 2 19x + 48 C (x + 4)(x + 12) 4) x 2 20x + 48 D (x 2)(x 24) 5) x 2 26x + 48 E (x + 6)(x + 8) (x )(x ) Factors of x 2 (x 7)(x + 10) Factored form of x 2 + 3x 70 A-SSE.2 Page 8 of 16 MCC@WCCUSD 01/14/15

9 Find the roots (zeros, x-intercepts) of f (x) = x 2 + 2x 24 9a Find the zeros of f (x) = 3x 2 + 7x + 2 Method: Factoring Factors of 24 Sum to 2 24 1 24 + 1 = 23 24 1 24 + ( 1) = 23 6 4 6 + 4 = 2 6 4 6 + ( 4) = 2 x 2 6x 4x 24 x 6 x x 2 6x 4 4x 24 Since we are asked to find the zeros of this function, we want to set the function equal to zero and solve for x. 9b Select all of the following that are true about the function: f (x) = x 2 4x 60 A) f (x) = ( x +10) ( x 6) B) f (x) = ( x 10) ( x + 6) C) f (x) = ( x 10) ( x 6) D) The zeros of this function are at x = 10 and x = 6. E) The zeros of this function are at x = 6 and x = 10. F) The zeros of this function are at x = 10 and x = 6. A-SSE.3a End of Study Guide Page 9 of 16 MCC@WCCUSD 01/14/15

You Try Solutions: 1b Match each equation with its graph. 1a What is the equation of the line on the graph below? 1) 3x + 4y = 12 C 3 4 y-intercept 2) 3x + 4y = 12 B Solution: To identify the slope from a graph, locate two points and use the ratio or subtract using the slope formula. 3) 3x 4y = 12 A OR Write the slope formula Substitute the coordinates of the points Simplify The y-intercept is the y-coordinate of the point on the line that crosses the y-axis, which is at 0. Substitute the values of the slope and y-int. y = mx + b Write the equation Substitute for m and 0 for b. Simplify For Standard Form (Ax + By = C): Write slope-intercept form Inverse operations: zero pairs Simplify Multiply w/ LCD to clear fractions Simplify Page 10 of 16 MCC@WCCUSD 01/14/15

2a Find the x- and y-intercepts and the rate of change of 2x + y = 5 Find the x- and y-intercepts The x-intercept is the point where the graph crosses the x-axis (or where y is zero). To find this from the equation, substitute y = 0 & solve for x. The y-intercept is the point where the graph crosses the y-axis (or where x is zero). To find this from the equation, substitute x = 0 & solve for y. 3a Determine the rate of change for 1) The equation 2x y = 4 This equation is in standard form. To find the rate of change (slope), we can put it in slope-intercept form. From this we can determine that the slope is 2. Find the rate of change One method to find the rate of change/slope is to put the equation in slope-intercept form. From this, we can tell that the rate of change is. Because this rate is negative, the graph is decreasing everywhere. 2) The table x y 3 5 5 5 7 5 To find the rate of change, we can use the slope formula with two points from the table. For this example, lets use (3, 5) and (7, 5). 2b Given a linear function and the graph of a linear function below, select all of the following statements that are true. Linear Function 1 Linear Function 2 y = 3x + 1 Therefore, the slope is 0. A) These functions have the same x-intercept. B) These functions have the same y-intercept. C) Both functions are increasing on all intervals. D) The rate of change for Function 1 is faster than the rate of change for Function 2. E) The solution to the system containing both equations is (0, 1). Page 11 of 16 MCC@WCCUSD 01/14/15

3b Select all of the following that have the same slope or rate of change as the graph of the linear function y = 2x 1. 4a Write an equation of the line that passes through the point ( 8, 3) with a slope of 3, in slope-intercept 4 form, point-slope form, AND standard form. Solution: Slope-Intercept Form A) (6, 2), ( 1, 9) B) 4x 2y = 8 C) y = 1 D) E) x y 4 6 2 10 0 14 Solution: Point-Slope Form Write point-slope form Substitute 3 for, for m, 8 for Simplify Solution: Standard Form Write slope-intercept form Inverse operations: zero pairs Simplify Multiply with LCD Simplify 4b Select all of the following equations of a line that have a slope of 5 and pass through the point ( 3, 7). A) y + 7 = 5(x 3) B) 5x + y = 8 C) y = 5x 8 D) 3x + 7y = 5 Page 12 of 16 MCC@WCCUSD 01/14/15

5a Which point appears to be the solution of the linear system graphed below? 6a Graph the solution to this system of inequalities. y x + 3 m =, b = (0, 3) Solid line, shaded below. Solution: The solution to a linear system is the point(s) that are solutions to both linear equations. This means that the point that is a solution will be the point that lies on both lines (or the point of intersection). These lines intersect at the point ( 2, 0), therefore the solution to this linear system is the point ( 2, 0). m =, b = (0, 6) Dotted line, shaded below. 5b Select all of the statements that are true about the graph of the system shown below. Line 1 Line 2 The intersection of the shaded half-planes is the solution to the system of inequalities. A) The solution to the system is ( 2, 3). B) There are an infinite number of solutions. C) The lines intersect at ( 3, 2). D) The slope of Line 1 is negative. E) The slope of Line 2 is negative. Page 13 of 16 MCC@WCCUSD 01/14/15

6b B C 7a 1) Simplify ( 2xy 4 z 2 ) 2 Method 1: Expansion E A D Method 2: Exponent Properties Select all of the points on this coordinate plane that are solutions to the system below. A) Point A B) Point B C) Point C D) Point D E) Point E 2) Simplify 10x3 y 4 25xy 4 Method 1: Expansion Method 2: Exponent Properties Page 14 of 16 MCC@WCCUSD 01/14/15

7b Select all of the following expressions that are equivalent to 30a4 b 2 25ab 6 A) 6a 3 b 4 B) 6 5 a4 1 b 2 6 8a Factor the trinomial 2x 2 + 13x + 21 The trinomial is written in the form, Ax 2 + Bx + C. Find two factors of the product that add up to B. A = 2, B = 13, C = 21 B = 13 C) D) E) F) 6a 3 5b 4 1 5a 3 6b4 2 3 5 a a a a b b 5 5 a b b b b b b ( 3b 2 )( 3a 2 ) 2 ( ) 3 a 5b Split the middle Bx term with the sum of these factors: 13x = 6x + 7x Solution: Split the middle term. Solution: Generic Rectangle Write original expression Split the middle term Group the terms Factor out the common factor Factor out the common factor 2x 2 + 13x + 21 Write original expression = 2x 2 + 6x + 7x + 21 Split the middle term 2x 2 + 6x + 7x + 21 Arrange the terms into the rectangle with the Ax 2 term in the top left and the C term in the bottom right. 2x + 7 x + 3 2. x. x 3. 2. x 7. x 3. 7 Decompose the terms into prime factors and factor out the GCFs. = (x + 3)(2x + 7) Page 15 of 16 MCC@WCCUSD 01/14/15

8b Match each trinomial with its factored form. 1) x 2 + 16x + 48 C A Prime 2) x 2 + 14x + 48 E B (x 3)(x 16) 3) x 2 19x + 48 B C (x + 4)(x + 12) 4) x 2 20x + 48 A D (x 2)(x 24) 5) x 2 26x + 48 D E (x + 6)(x + 8) 9a Find the zeros of f (x) = 3x 2 + 7x + 2 Method: Factoring a c = 6 b = 7 f (x) = 3x 2 + 7x + 2 2 3 = 6 2+3 7 = 3x 2 + 6x +1x + 2 ( ) + 1x + 2 = 3x 2 + 6x ( ) 1 6 = 6 1+6 = 7 = 3x(x + 2)+1(x + 2) = (3x +1)(x + 2) We are looking for the zeros. We want to solve for x when f(x) = 0. OR 9b Select all of the following that are true about the function: f (x) = x 2 4x 60 A) f (x) = ( x +10) ( x 6) B) f (x) = ( x 10) ( x + 6) C) f (x) = ( x 10) ( x 6) D) The zeros of this function are at x = 10 and x = 6. E) The zeros of this function are at x = 6 and x = 10. F) The zeros of this function are at x = 10 and x = 6. Page 16 of 16 MCC@WCCUSD 01/14/15