Post Graduate Diploma in Mechanical Engineering Computational mechanics using finite element method

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9210-220 Post Graduate Diploma in Mechanical Engineering Computational mechanics using finite element method You should have the following for this examination one answer book scientific calculator No additional data is attached General instructions This examination paper is of three hours duration. This paper contains nine (09) questions. Answer five (05) questions.

Section A 1 Three bars 1, 2 and 3 are connected together, as shown in Figure Q1 and a force of 2.4 N is applied in the x direction at node 2. Consider each element to be 600 mm long, Modulus of Elasticity E = 20 MPa and cross sectional area A = 3 cm 2 for each element 1 and 2, Modulus of Elasticity E = 10MPa and A = 6 cm 2 for element 3, and nodes 1 and 4 are fixed. Determine the following. a) Global stiffness matrix. (7 marks) b) Displacements of nodes 2 and 3. (6 marks) c) Reactions at nodes 1 and 4. (7 marks) Figure Q1 2 a) Considering a basic element in the x y plane (as shown in Figure Q2a) with positive nodal forces, derive an equation to determine the axial stress in a bar if for a bar, the relationship between the local forces and the local displacements in the respective directions is given by Where f { 1x } [ ]{ } = AE 1 1 d 1x f 2x L 1 1 d 2X Where d 1x = d 1x Cosθ + d 1y Sinθ d 2x = d 2x Cosθ + d 2y Sinθ Figure Q2a 2

b) Figure Q2b, shows a bar element for stress evaluation, which makes an angle of 60 degrees with the X axis. If its cross sectional area A = 4 x 10-4 m 2, modulus of elasticity E = 208 GPa, and length L = 2 m, find the axial stress assuming the global displacements have been previously determined to be d 1x = 0.20 mm, d 1y = 0.0, d 2x = 0.40 mm and d 2y = 0.60 mm.` Figure Q2b 3 a) Derive an expression for the stiffness matrix for a 2-D truss element. b) Derive the strain displacement matrix for a 1-D linear element and show that σ = E[B]{u}. 4 Consider the compound bar shown in Figure Q4, which is made of Aluminium (1-2) and Steel (2-3), with length 150 mm and 300 mm respectively and the following cross sectional areas and Moduli of elasticity. Aluminium Steel A 1 = 1000 mm 2 A 2 = 200 mm 2 E 1 = 80 x 109 N/m 2 E 1 = 210 x 109 N/m 2 An axial load of P = 150 N is applied in the x direction. Applying Boundary conditions, determine a) nodal displacements (12 marks) b) stress in each material (4 marks) c) reaction forces. (4 marks) Figure Q4 3 See next page

5 The cantilever beam of length L shown in Figure Q5 is subjected to a concentrated load P at its free end and an uniformly distributed load w per unit length acting over the whole span of the beam. Determine, a) the free end displacements and b) the nodal forces Figure Q5 6 The thin (steel) plate in Figure Q6 has uniform thickness, t = 1 cm. Its material has a Young s Modulus E = 200 GPa and weight density ω = 7850 kg/m 3. In addition to its self-weight, the plate is subjected to a point load P = 100 N at its midpoint. The area at the midpoint of the plate is 3 cm 2. a) Model the plate with two finite elements. (5 marks) b) Write down expressions for the element stiffness matrices and element body force vectors. (4 marks) c) Assemble the structural stiffness matrix K and global load vector F. (4 marks) d) Using the elimination approach, solve for the global displacement vector Q. (7 marks) Figure Q6 4

7 A 45 strain rosette is used to estimate stresses on a beam. The normal strains obtained are as given in Figure Q7. If the Modulus of elasticity and Poisson s ratio of the beam are 5 GPa and 0.25 respectively, determine the major and minor principal stresses. Assume plain strain condition. (20 marks) Figure Q7 8 Briefly explain the following: a) Constant strain triangle (5 marks) b) Serendipity family of element (5 marks) c) Isoparametric element (5 marks) d) The convergence criteria for non-linear solutions (5 marks) 9 a) State the purpose of the Gauss elimination method. (5 marks) b) Solve the simultaneous set of equations using the Gauss elimination method 2x 1 + 2x 2 + 1x 3 = 9 2x 1 + 1x 2 = 4 1x 1 + 1x 2 + 1x 3 = 6 (15 marks) 5