Elementary Differential Equations

Similar documents
Math 266: Ordinary Differential Equations

Boyce/DiPrima/Meade 11 th ed, Ch 1.1: Basic Mathematical Models; Direction Fields

SMA 208: Ordinary differential equations I

Boyce/DiPrima 10 th ed, Ch 1.1: Basic Mathematical Models; Direction Fields

It is convenient to think that solutions of differential equations consist of a family of functions (just like indefinite integrals ).

MA 102 Mathematics II Lecture Feb, 2015

MATH 308 Differential Equations

Elementary Differential Equations

Mathematical Models. MATH 365 Ordinary Differential Equations. J. Robert Buchanan. Spring Department of Mathematics

Mathematical Models. MATH 365 Ordinary Differential Equations. J. Robert Buchanan. Fall Department of Mathematics

Introduction. 1.1 Some Basic Mathematical Models; Direction Fields

The Fundamental Theorem of Calculus: Suppose f continuous on [a, b]. 1.) If G(x) = x. f(t)dt = F (b) F (a) where F is any antiderivative

Calculus II. George Voutsadakis 1. LSSU Math 152. Lake Superior State University. 1 Mathematics and Computer Science

Outline. Calculus for the Life Sciences. What is a Differential Equation? Introduction. Lecture Notes Introduction to Differential Equa

EAD 115. Numerical Solution of Engineering and Scientific Problems. David M. Rocke Department of Applied Science

y0 = F (t0)+c implies C = y0 F (t0) Integral = area between curve and x-axis (where I.e., f(t)dt = F (b) F (a) wheref is any antiderivative 2.

Math 315: Differential Equations Lecture Notes Patrick Torres

Modeling with differential equations

Sample Questions, Exam 1 Math 244 Spring 2007

First and Second Order Differential Equations Lecture 4

College Trigonometry

Calculus III. George Voutsadakis 1. LSSU Math 251. Lake Superior State University. 1 Mathematics and Computer Science

Solutions to Homework 1, Introduction to Differential Equations, 3450: , Dr. Montero, Spring y(x) = ce 2x + e x

Homework #5 Solutions

Systems of Differential Equations: General Introduction and Basics

Chapter 2 Notes, Kohler & Johnson 2e

Homework Solutions:

Homogeneous Equations with Constant Coefficients

Final Exam Review. Review of Systems of ODE. Differential Equations Lia Vas. 1. Find all the equilibrium points of the following systems.

Motivation and Goals. Modelling with ODEs. Continuous Processes. Ordinary Differential Equations. dy = dt

Integral Curve (generic name for a member of the collection of known as the general solution)

Definition of differential equations and their classification. Methods of solution of first-order differential equations

Graded and supplementary homework, Math 2584, Section 4, Fall 2017

144 Chapter 3. Second Order Linear Equations

ENGR 213: Applied Ordinary Differential Equations

Lecture 1, August 21, 2017

MATH 251 Week 6 Not collected, however you are encouraged to approach all problems to prepare for exam

Practice Midterm 1 Solutions Written by Victoria Kala July 10, 2017

MATH 4B Differential Equations, Fall 2016 Final Exam Study Guide

34.3. Resisted Motion. Introduction. Prerequisites. Learning Outcomes

Old Math 330 Exams. David M. McClendon. Department of Mathematics Ferris State University

Math 308 Exam I Practice Problems

Solutions to the Review Questions

Section 11.1 What is a Differential Equation?

1.1. BASIC ANTI-DIFFERENTIATION 21 + C.

Computers, Lies and the Fishing Season

Solutions to the Review Questions

Lecture 1. Scott Pauls 1 3/28/07. Dartmouth College. Math 23, Spring Scott Pauls. Administrivia. Today s material.

Section 3.1 Second Order Linear Homogeneous DEs with Constant Coefficients

Math 128A Spring 2003 Week 12 Solutions

MATH 23 EXAM 1 REVIEW PROBLEMS

Math 308, Sections 301, 302, Summer 2008 Review before Test I 06/09/2008

كلية العلوم قسم الرياضيات المعادالت التفاضلية العادية

Differential Equations Spring 2007 Assignments

Differential and Difference LTI systems

Calculus I. George Voutsadakis 1. LSSU Math 151. Lake Superior State University. 1 Mathematics and Computer Science

Intermediate Algebra

Introductory Differential Equations

( ) ( ). ( ) " d#. ( ) " cos (%) " d%

First-order transient

Chapter1. Ordinary Differential Equations

Differential Equations

ENGI 3424 First Order ODEs Page 1-01

Chapter 1: Introduction

Chapter 3: Second Order ODE 3.8 Elements of Particle Dy

Chapter 2: First Order ODE 2.4 Examples of such ODE Mo

1. (10 points) Find the general solution to the following second-order differential equation:

Chapter 6. Second order differential equations

First Order Differential Equations Lecture 3

Math 2a Prac Lectures on Differential Equations

Math 106 Answers to Exam 3a Fall 2015

Math 2373: Linear Algebra and Differential Equations

Lecture 6, September 1, 2017

1 The pendulum equation

Math 2214 Solution Test 1D Spring 2015

Use separation of variables to solve the following differential equations with given initial conditions. y 1 1 y ). y(y 1) = 1

Second Order Linear Equations

01 Harmonic Oscillations

Exam 1 Review SOLUTIONS

Review for the Final Exam

Traveling Harmonic Waves

PhysicsAndMathsTutor.com 1

a k 0, then k + 1 = 2 lim 1 + 1

2.1 How Do We Measure Speed? Student Notes HH6ed. Time (sec) Position (m)

Applied Calculus. Review Problems for the Final Exam

MATH 353 LECTURE NOTES: WEEK 1 FIRST ORDER ODES

Taylor polynomials. 1. Introduction. 2. Linear approximation.

Differential Equations & Separation of Variables

MAT 285: Introduction to Differential Equations. James V. Lambers

Math 215/255 Final Exam (Dec 2005)

Differential Equations and Modeling

) # ( 281). Give units with your answer.

1 Differential Equations

Applications of Second-Order Differential Equations

Solutions to Math 53 First Exam April 20, 2010

2.2. THE PRODUCT AND QUOTIENT RULES 179. P dv dt + V dp. dt.

Math 113 Final Exam Practice

First Order Systems of Linear Equations. or ODEs of Arbitrary Order

Math Exam 02 Review

we get y 2 5y = x + e x + C: From the initial condition y(0) = 1, we get 1 5 = 0+1+C; so that C = 5. Completing the square to solve y 2 5y = x + e x 5

Transcription:

Elementary Differential Equations George Voutsadakis 1 1 Mathematics and Computer Science Lake Superior State University LSSU Math 310 George Voutsadakis (LSSU) Differential Equations January 2014 1 / 20

Outline 1 Introduction Basic Mathematical Models: Direction Fields Solutions of Some Differential Equations George Voutsadakis (LSSU) Differential Equations January 2014 2 / 20

Basic Mathematical Models: Direction Fields Subsection 1 Basic Mathematical Models: Direction Fields George Voutsadakis (LSSU) Differential Equations January 2014 3 / 20

Basic Mathematical Models: Direction Fields Differential Equations and Models Equations containing derivatives are differential equations; A differential equation that describes some physical process is called a mathematical model of the process; Example: Suppose that an object is falling in the atmosphere near sea level. Formulate a differential equation that describes the motion. Typically, the variable t denotes time; Let v be the velocity of the falling object; We measure time t in seconds and velocity v in meters/second and assume v is positive in the downward direction; Newtons second law states: F = ma; Moreover, a = dv dt ; Total force acting on the falling object is F = mg }{{} gravity γv; }{{} drag The previous two equations yield m dv dt = mg γv; George Voutsadakis (LSSU) Differential Equations January 2014 4 / 20

Basic Mathematical Models: Direction Fields Direction Fields Consider a differential equation of the form dy dt = f(t,y); The function f(t,y) is called the rate function; A direction field for the differential equation is constructed by evaluating f(t,y) at each point of a rectangular grid; At each point of the grid, a short line segment is drawn whose slope is the value of f at that point; Each line segment is tangent to the graph of the solution passing through that point; Direction fields provide a good picture of the overall behavior of solutions of a differential equation; In constructing a direction field, we do not have to solve the equation, but merely to evaluate the given function f(t,y) many times; George Voutsadakis (LSSU) Differential Equations January 2014 5 / 20

Basic Mathematical Models: Direction Fields Another Application: Field Mice Population Consider a population of field mice inhabiting a certain rural area; In the absence of predators we assume that the mouse population increases at a rate proportional to the current population; Denoting time by t and the mouse population by p(t), we get dp dt = rp, where r is a proportionality constant called the rate constant or growth rate; If we assume, in addition, that owls live in the same neighborhood and that they kill field mice at a rate of k, then the new equation modeling the mouse population would be dp dt = rp }{{} rate of increase k; }{{} rate of decrease George Voutsadakis (LSSU) Differential Equations January 2014 6 / 20

Basic Mathematical Models: Direction Fields Guidelines to Constructing Mathematical Models Steps for constructing a model for a physical problem or phenomenon: 1 Identify the independent and dependent variables and assign letters to represent them; 2 Choose the units of measurement for each variable; 3 Articulate the basic principle that underlies or governs the physical problem under investigation; To do this, we must often be familiar with the field in which the problem originates; 4 Express the principle or law of the previous step in terms of the variables chosen for the modeling process; 5 A quick check that the equation is not fundamentally inconsistent is that both terms in the equation have the same physical units; In more complicated problems the mathematical model may not be just a single differential equation. George Voutsadakis (LSSU) Differential Equations January 2014 7 / 20

Solutions of Some Differential Equations Subsection 2 Solutions of Some Differential Equations George Voutsadakis (LSSU) Differential Equations January 2014 8 / 20

Solutions of Some Differential Equations A Specific Initial Value Problem Consider the following: Initial Value Problem {}}{ dy dt = ay b, y(0) = y 0; }{{} Initial Condition To solve it (i.e., find y = y(t)) we work as follows: dy dt dy = ay b dt = a(y b a ) dy = adt y b a dy = adt ln y b a = at +C y b a y b a = eat+c y = b a +ceat y b a = ec e at (General Solution); y(0) = y 0 b a +c = y 0 c = y 0 b a ; Thus, we get y(t) = b a +(y 0 b a )eat (Particular Solution); George Voutsadakis (LSSU) Differential Equations January 2014 9 / 20

Solutions of Some Differential Equations Free Falling Object: General Solution Recall the equation describing the free fall of an object of mass m: m dv dt = mg γv dv dt = g γ m v; Suppose m = 10 Kg, and the drag coefficient γ = 2 Kg/s; Finally, recall g = 9.8( 10) m/s 2 ; dv dt = g γ m v dv dt = 10 2 10 v 5dv dt = 50 v dv 50 v = 1 5 dt dv 50 v = 1 5 dt ln(50 v) = 1 5t +C 50 v = ce t/5 v = 50 ce t/5 ; George Voutsadakis (LSSU) Differential Equations January 2014 10 / 20

Solutions of Some Differential Equations An Initial Condition and a Particular Solution We found that v = 50 ce t/5 is the equation describing the velocity of an object in free fall with mass m = 10 Kg, and drag coefficient γ = 2 Kg/s; If it is dropped by a height of h 0 = 300 meters, can we find an equation describing the distance x that the object travels in time t? At time t = 0, v(0) = 0; Therefore, 50 c = 0 c = 50; Thus, the equation becomes: v = 50 50e t/5 ; Now, we get: v = 50 50e t/5 dt = 50 50e t/5 dx = (50 50e t/5 )dt dx = (50 50e t/5 )dt dx x(t) = 50t +50 5e t/5 +C; Since x(0) = 0 (no distance traveled yet), 0 = 50 5+C C = 250; So x(t) = 50t +250e t/5 250; The height of the object at time t will be h(t) = 300 x(t) (dropping by distance x(t)) or h(t) = 550 50t 250e t/5. George Voutsadakis (LSSU) Differential Equations January 2014 11 / 20

Subsection 3 George Voutsadakis (LSSU) Differential Equations January 2014 12 / 20

Ordinary versus Partial Differential Equations Based on the number of independent variables on which the unknown function depends: If only one independent variable is involved, only ordinary derivatives appear in the differential equation and it is said to be an ordinary differential equation; If several independent variables appear, then the derivatives are partial derivatives, and the equation is called a partial differential equation; Some Examples: The charge Q(t) on a capacitor in a circuit with capacitance C, resistance R, and inductance L is given by the ordinary differential equation: L d2 Q(t) dt 2 +R dq(t) dt The heat conduction equation α 2 2 u(x,t) x 2 + 1 Q(t) = E(t); C = u(x,t) t differential equation, as is the wave equation: a 2 2 u(x,t) x 2 is a partial = 2 u(x,t) t 2 ; George Voutsadakis (LSSU) Differential Equations January 2014 13 / 20

Systems of Differential Equations Based on the number of unknown functions that are involved; If there is a single function to be determined, then one equation is sufficient; If there are two or more unknown functions, then a system of equations is required; An example is the Lotka-Volterra, or predator-prey, equations, which are important in ecological modeling: x(t) and y(t) are the populations of the prey and predator species; a,α,c and γ are constants based on empirical observations and depend on the particular species being studied; Then, the equations have the form dx = ax αxy dt dy = cy +γxy dt George Voutsadakis (LSSU) Differential Equations January 2014 14 / 20

Order of a Differential Equation The order of a differential equation is the order of the highest derivative that appears in the equation; The equation F[t,u(t),u (t),...,u (n) (t)] = 0 is an ordinary differential equation of the n-th order; It is convenient and customary in differential equations to write y for u(t), with y,y,...,y (n) standing for u (t),u (t),...,u (n) (t); Example: y +2e t y +yy = t 4 is a third order differential equation for y = u(t); We always assume that it is possible to solve a given ordinary differential equation for the highest derivative, obtaining y (n) = f(t,y,y,y,...,y (n 1) ). George Voutsadakis (LSSU) Differential Equations January 2014 15 / 20

Linear and Nonlinear Equations The ordinary differential equation F(t,y,y,...,y (n) ) = 0 is said to be linear if F is a linear function of the variables y,y,...,y (n) ; A similar definition applies to partial differential equations; The general linear ordinary differential equation of order n is a 0 (t)y (n) +a 1 (t)y (n 1) + +a n (t)y = g(t); An equation that is not of this form is a nonlinear equation; Example: A simple physical problem that leads to a nonlinear differential equation is the oscillating pendulum. The angle θ that an oscillating pendulum of length L makes with the vertical direction satisfies the equation d 2 θ dt 2 + g sinθ = 0; L George Voutsadakis (LSSU) Differential Equations January 2014 16 / 20

Advantages of Linearity and Linearization The mathematical theory and methods for solving linear equations are highly developed; For nonlinear equations the theory is more complicated, and methods of solution are less satisfactory; It is fortunate that many significant problems lead to linear ordinary differential equations or can be approximated by linear equations; Example: For the pendulum, if the angle θ is small, then sinθ = θ and the pendulum equation d2 θ dt 2 + g L sinθ = 0 can be approximated by the linear equation d2 θ dt 2 + g L θ = 0; This process of approximating a nonlinear equation by a linear one is called linearization and constitutes an extremely valuable way to deal with nonlinear equations, when possible; Since, there are many physical phenomena that cannot be represented adequately by linear equations, to study those it is essential to deal with nonlinear equations also; George Voutsadakis (LSSU) Differential Equations January 2014 17 / 20

Solutions of Differential Equations Consider again the equation y (n) = f(t,y,y,y,...,y (n 1) ); A solution of this differential equation on the interval α < t < β is a function φ, such that φ,φ,...,φ (n) exist and satisfy φ (n) (t) = f[t,φ(t),φ (t),...,φ (n 1) (t)], for every t in α < t < β; It is often not very easy to find solutions of differential equations; It is usually relatively easy to check whether a given function is a solution; Example: Check whether y(t) = cost is a solution of y +y = 0; y(t) = cost; y (t) = sint; y (t) = cost; y +y = cost +cost = 0; George Voutsadakis (LSSU) Differential Equations January 2014 18 / 20

Existence and Uniqueness of Solutions Does an equation of the form y (n) = f(t,y,y,y,...,y (n 1) ) always have a solution? NO! Writing down an equation of this form does not necessarily mean that there is a function y = φ(t) that satisfies it; The question of whether some particular equation has a solution is the question of existence; The question of whether a given differential equation that has a solution, has a unique solution is the question of uniqueness; If we find a solution of a given problem, and if we know that the problem has a unique solution, then we can be sure that we have completely solved the problem; If there may be other solutions, then perhaps we should continue exploring the solution space; George Voutsadakis (LSSU) Differential Equations January 2014 19 / 20

Practice of Finding Solutions Knowledge of existence theory serves in avoiding pitfalls, such as using a computer to find a numerical approximation to a solution that does not exist; On the other hand, even though we may know that a solution exists, it is often the case that the solution is not expressible in terms of the usual elementary functions (polynomial, trigonometric, exponential, logarithmic, and hyperbolic functions); We discuss elementary methods that can be used to obtain exact solutions of certain relatively simple problems. George Voutsadakis (LSSU) Differential Equations January 2014 20 / 20