CONSTRUCTING TRUNCATED IRRATIONAL NUMBERS AND DETERMINING THEIR NEIGHBORING PRIMES

Similar documents
SOME NEW OBSERVATIONS ON MERSENNE NUMBERS AND PRIMES

Round-off Errors and Computer Arithmetic - (1.2)

[ 47 ] then T ( m ) is true for all n a. 2. The greatest integer function : [ ] is defined by selling [ x]

YALE UNIVERSITY DEPARTMENT OF COMPUTER SCIENCE

Confidence Intervals

Sequences A sequence of numbers is a function whose domain is the positive integers. We can see that the sequence

THE INTEGRAL TEST AND ESTIMATES OF SUMS

Solutions to Math 347 Practice Problems for the final

Lecture 2: April 3, 2013

PROPERTIES OF AN EULER SQUARE

A sequence of numbers is a function whose domain is the positive integers. We can see that the sequence

Infinite Sequences and Series

COMPUTING FOURIER SERIES

Nuclear Physics Worksheet

Once we have a sequence of numbers, the next thing to do is to sum them up. Given a sequence (a n ) n=1

is also known as the general term of the sequence

tests 17.1 Simple versus compound

CSE 1400 Applied Discrete Mathematics Number Theory and Proofs

Section 6.4: Series. Section 6.4 Series 413

Putnam Training Exercise Counting, Probability, Pigeonhole Principle (Answers)

1.3 Convergence Theorems of Fourier Series. k k k k. N N k 1. With this in mind, we state (without proof) the convergence of Fourier series.

Lesson 10: Limits and Continuity

Solutions to Problem Sheet 1

MA131 - Analysis 1. Workbook 10 Series IV

PROPERTIES OF THE POSITIVE INTEGERS

Injections, Surjections, and the Pigeonhole Principle

Proposition 2.1. There are an infinite number of primes of the form p = 4n 1. Proof. Suppose there are only a finite number of such primes, say

6.3 Testing Series With Positive Terms

3 Gauss map and continued fractions

Lecture 11: Hash Functions and Random Oracle Model

ACCESS TO SCIENCE, ENGINEERING AND AGRICULTURE: MATHEMATICS 1 MATH00030 SEMESTER / Statistics

(A sequence also can be thought of as the list of function values attained for a function f :ℵ X, where f (n) = x n for n 1.) x 1 x N +k x N +4 x 3

ENGI 4421 Probability and Statistics Faculty of Engineering and Applied Science Problem Set 1 Solutions Descriptive Statistics. None at all!

a. How might the Egyptians have expressed the number? What about?

Confidence intervals for proportions

Find a formula for the exponential function whose graph is given , 1 2,16 1, 6

Complex Numbers Solutions

Revision Topic 1: Number and algebra

PROBLEM SET 5 SOLUTIONS 126 = , 37 = , 15 = , 7 = 7 1.

ON SUPERSINGULAR ELLIPTIC CURVES AND HYPERGEOMETRIC FUNCTIONS

SEQUENCES AND SERIES

Order doesn t matter. There exists a number (zero) whose sum with any number is the number.

The Structure of Z p when p is Prime

6.003 Homework #3 Solutions

4.3 Growth Rates of Solutions to Recurrences

MA131 - Analysis 1. Workbook 2 Sequences I

Lecture 11: Pseudorandom functions

Sequences I. Chapter Introduction

CHAPTER I: Vector Spaces

Bertrand s Postulate

Mathematical Description of Discrete-Time Signals. 9/10/16 M. J. Roberts - All Rights Reserved 1

September 2012 C1 Note. C1 Notes (Edexcel) Copyright - For AS, A2 notes and IGCSE / GCSE worksheets 1

NICK DUFRESNE. 1 1 p(x). To determine some formulas for the generating function of the Schröder numbers, r(x) = a(x) =

Coping with Insufficient Data: The Case of Household Automobile Holding Modeling by Ryuichi Kitamura and Toshiyuki Yamamoto

Discrete Mathematics for CS Spring 2005 Clancy/Wagner Notes 21. Some Important Distributions

1. Hilbert s Grand Hotel. The Hilbert s Grand Hotel has infinite many rooms numbered 1, 2, 3, 4

WHAT COOL MATH! JULY CURRICULUM INSPIRATIONS: Math for America DC:

The Growth of Functions. Theoretical Supplement

COMPUTING SUMS AND THE AVERAGE VALUE OF THE DIVISOR FUNCTION (x 1) + x = n = n.

Cardinality Homework Solutions

The picture in figure 1.1 helps us to see that the area represents the distance traveled. Figure 1: Area represents distance travelled

3.2 Properties of Division 3.3 Zeros of Polynomials 3.4 Complex and Rational Zeros of Polynomials

Analytic Continuation

UNIT #5. Lesson #2 Arithmetic and Geometric Sequences. Lesson #3 Summation Notation. Lesson #4 Arithmetic Series. Lesson #5 Geometric Series

If a subset E of R contains no open interval, is it of zero measure? For instance, is the set of irrationals in [0, 1] is of measure zero?

Discrete Mathematics and Probability Theory Summer 2014 James Cook Note 15

How many prime numbers are there?

First selection test, May 1 st, 2008

Quadratic Functions. Before we start looking at polynomials, we should know some common terminology.

Discrete Mathematics for CS Spring 2007 Luca Trevisan Lecture 22

10.6 ALTERNATING SERIES

Some remarks for codes and lattices over imaginary quadratic

Course Outline. Designing Control Systems. Proportional Controller. Amme 3500 : System Dynamics and Control. Root Locus. Dr. Stefan B.

Math 155 (Lecture 3)

( ) = p and P( i = b) = q.

It is always the case that unions, intersections, complements, and set differences are preserved by the inverse image of a function.

Analysis of Experimental Measurements

ELEC1200: A System View of Communications: from Signals to Packets Lecture 3

(b) What is the probability that a particle reaches the upper boundary n before the lower boundary m?

Activity 3: Length Measurements with the Four-Sided Meter Stick

1 Hash tables. 1.1 Implementation

OPTIMAL ALGORITHMS -- SUPPLEMENTAL NOTES

Tennessee Department of Education

Section 7 Fundamentals of Sequences and Series

Last time, we talked about how Equation (1) can simulate Equation (2). We asserted that Equation (2) can also simulate Equation (1).

THE TUTTE POLYNOMIAL OF A FINITE PROJECTIVE SPACE

Math 113 Exam 3 Practice

Students will calculate quantities that involve positive and negative rational exponents.

In number theory we will generally be working with integers, though occasionally fractions and irrationals will come into play.

WORKING WITH NUMBERS

... and realizing that as n goes to infinity the two integrals should be equal. This yields the Wallis result-

IP Reference guide for integer programming formulations.

Lecture 3. Digital Signal Processing. Chapter 3. z-transforms. Mikael Swartling Nedelko Grbic Bengt Mandersson. rev. 2016

Sequences. Notation. Convergence of a Sequence

Recitation 4: Lagrange Multipliers and Integration

Roberto s Notes on Series Chapter 2: Convergence tests Section 7. Alternating series

Recursive Algorithms. Recurrences. Recursive Algorithms Analysis

Math 113 Exam 3 Practice

Oblivious Transfer using Elliptic Curves

Notes on the prime number theorem

Transcription:

CONSTRUCTING TRUNCATED IRRATIONAL NUMBERS AND DETERMINING THEIR NEIGHBORING PRIMES It is well kow that there exist a ifiite set of irratioal umbers icludig, sqrt(), ad e. Such quatities are of ifiite legth ad have the roerty that they ca ever be rereseted as the ratio of two real umbers. Segmets of irratioal umbers of fifty digit legth or so are of iterest i coectio with ublic key crytograhy (RSA) where the roduct of two segmets of differet irratioals adjusted to be rime ca lead to early ufactorable semi-rimes N=q. It is our urose here to exted several of our earlier studies o semi-rimes to geerate some large segmets of irratioal umbers lus some related semi-rimes usig fiite segmets of the roducts of some of the better kow irratioals. Our startig oit is to reset a few the better kow irratioal umbers i terms of their basic defiitios. We have ex() e.7888845945...! ( ) 4 3.459653589793... ( ) l()... J () - t ( ).6934785599453... ( ) 5.68339887498948... (!).4435637395....79585333667... l( t)ex( t) dt.577566495386... These costitute the best kow ad ofte used irratioal umbers occurrig i the mathematical literature. They are art of a ifiite set icludig such additioal irratioals as-

( ) ( )... Here is a root of ad lies ear. Thus the square root of five, which aears i the defiitio of the golde ratio above, is give by the cotiued fractio- 5.36679774997896964... 4 4 4... It is imortat to recogize that segmets of such irratioals eed ot ecessarily have their digits eter i a radom maer. If they did the all digits betwee ad 9 would aear equally. Let us demostrate this o-radomess by lookig at the first 5 terms of ex() ad. Here we have- e.788884594535368747356649775747937 =3.45965358979338466433837958849769399375 so that the digit cout looks as follows- digit 3 4 5 6 7 8 9 e 6 3 8 4 5 5 3 8 5 3 5 5 8 5 5 4 4 5 8 The cout shows that the fifty digit log segmets of these two irratioals are ot comletely radom because the aearaces of the te ossible digits are ot five each. The radomess will icrease as the segmet legths ad advace toward ifiity. The fact that fiite legth segmets of irratioals are ot comletely radom should ot iterfere with quickly comig u with some trucated roducts of irratioal umbers ad the rime umb ers located i their eighborhoods. This will make ossible the use of some semirimes for ublic keys roduced with a miimum of effort. I additio ay of these rimes will be idetifiable by short ad uique codes. We choose to defie a fiite segmet of a irratioal umber by the code- K L a ( ) m k k k

Here a k reresets oe of K commo irratioals take to the k th ower. The segmet starts with the + term ad is m digits log. Thissegmet will be desigated by M. Let us look at a secific examle. Take- M 6{ e(4) (/ 3) }5 This code roduces the fifty digit log segmet- M=567978339363999754678559946956 Usig a bit of modular arithmetic, we have M mod(6)=4 which imlies that that M lies alog the radial lie 6+4 i the followig hexagoal iteger siral- We have show i several earlier otes (look at both our MATFUNC ad TECH-BLOG ages for the years -5) that all rimes greater tha 3 must lie alog the two radial lies 6. I the grah these rimes are desigated by blue circles. To fid all rimes i the immediate viciity of M will require we look at- isrime( M+3+6) ad isrime( M++6 ) This is a easy search usig the oe lie rogram- for from - to do {, isrime(m++6)}od;

I a slit secod oe fids that the two closest rimes are M+33 ad M-53. These read- P = 567978339363999754678559946989 P = 56797833936399975467855994693 Here P mod(6)= ad P mod(6)=5. Note that 5 is equivalet to - i the hexagoal diagram. So P will be a blue circle alog the radial lie 6+ ad P oe of the blue cirles alog 6-. As ca be see, it took very little effort to fid the above rimes sice determiig whether or ot a umber is rime is rovided by a very simle comuter evaluatio. I additio we ow have a way to store ad trasmit large rime umbers by a code which itself ca be ecryted. For examle we ca comletely describe the fifty digit log rime P by- P =M+33=6{e(4),(/),(-3)}5+33 Although the roduct of P ad P will ot make a good ublic key N because of their roximity to each other, oe ca easily costruct a coule of rimes searated from each other by orders of magitude. Such a semi-rime N will be almost ubreakable wheever the umber of digits i the Ps is large eough. Let us demostrate this for- M 3 =7{7(/3)(3)e(-)}5 where M 3 mod(6)=3 M 4 ={()J()l(-/)}45 where M 4 mod(6)= I this case we fid the earest rimes to be P 3 =M 3-4= 63559688988896367596354384574844557339 P 4 =M 4 +7= 877476347743974887933536866768567 Oe ca easily verify by comuter that these last two umbers of 5 ad 45 digit legth, resectively, are rime umbers. Their roduct yields the 95 digit log semi-rime- N=557648884349438984846573385487383563963664838774898 76986939646976775697

Without a kowledge of either P 3 or P 4 it is highly ulikely that ayoe icludig our big data Natioal Security Agecy ( NSA) would be successful i factorig this N i ay reasoable amout of time usig eve their latest high seed comuters. Although the RSA aroach to secret message trasmissio is at reset still secure usig fifty or so log rime umbers, this will ot cotiue to hold with time. Loger ad loger rime umbers will be required callig ito questio the efficacy of ublic keys N i RSA crytograhy. It suggests that erhas oe should cosider a ew ad simler aroach to ecryted electroic message trasmissio based o the reset method of usig ecoded forms for certai large irratioal umbers segmets adjusted to be rimes. Oe could evisio a way the roduct of M ad a message S would be set as D=S o the ublic airwaves. If the seder simultaeously seds a secod sigal cotaiig a ecryted form of M which oly he ad a friedly receiver would uderstad, the message will have bee secretly trasmitted. Cosider the case were the message is S=345 ad M is defied as- M=5{7(/)(-/5)}= 55944549933. The ecryted message becomes- D=(M)(S)= 683549366976699479985 There is o way a adversary could deciher D. However the friedly receiver (kowig what M is) will be able to raidly decode thigs as D/M=S=345. UHK Jue, 6