Classes of Alkenes. Alkenes and Alkynes. Saturated compounds (alkanes): Have the maximum number of hydrogen atoms attached to each carbon atom.

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Alkenes and Alkynes Saturated compounds (alkanes): ave the maximum number of hydrogen atoms attached to each carbon atom. Unsaturated compounds: ave fewer hydrogen atoms attached to the carbon chain than alkanes. ontaining double bond are alkenes. n 2n ontaining triple bonds are alkynes. n 2n-2 lasses of Alkenes 1

Structure and Bonding Orbital Description Sigma bonds around are sp 2 hybridized. Angles are approximately 120 degrees. No nonbonding electrons. Molecule is planar around the double bond. Pi bond is formed by the sideways overlap of parallel p orbitals perpendicular to the plane of the molecule. => 2

Bond Lengths and Angles ybrid orbitals have more s character. Pi overlap brings carbon atoms closer. Bond angle with pi orbitals increases. Angle =- is 121.7 Angle -- is 116. 6 => Pi Bond Sideways overlap of parallel p orbitals. No rotation is possible without breaking the pi bond (63 kcal/mole). is isomer cannot become trans without a chemical reaction occurring. => IUPA Nomenclature Parent is longest chain containing the double bond. -ane changes to -ene. (or -diene, -triene) Number the chain so that the double bond has the lowest possible number. In a ring, the double bond is assumed to be between carbon 1 and carbon 2. => Naming Alkenes & Alkynes Using the IUPA alkane names: Alkene names change the end to -ene. Alkyne names change the end to -yne Naming Alkenes & Alkynes 2 = 2 3 1 2 3 4 1-butene 3 = 3 2-butene Give the location for double and triple bond 1 2 3 4 3 3 = 3 2-methyl-2-butene 4 3 2 1 3 3 2-butyne 1 2 3 4 3

Naming Alkenes & Alkynes is & Trans Stereoisomers 3 2 3 5 4 3 2 1 3 2-pentyne 3 = 3 3 = 3 3 2 = 3 3-methyl-2-pentene 4 8 4 8 5 4 3 2 1 2 3 3 2 = 3 3-ethyl-2-pentene cis-2-butene trans-2-butene 5 4 3 2 1 Same molecular formula and same connectivity of their atoms but a different arrangement of their atoms in space. mp & bp of cis < mp & bp of trans Preparation of Alkenes Synthesis of Alkenes Dehydrohalogenation Addition Alkenes are commonly made by elimination of X from alkyl halide (dehydrohalogenation) Uses heat and KO X Y X Y Br KO 3 2 O KBr 2 O Elimination 21 22 Synthesis of Alkenes Dehydrohalogenation Synthesis of Alkenes Dehydration 4

Synthesis of Alkenes Dehydration elimination of -O from an alcohol (dehydration) require strong acids (sulfuric acid, 50 º) Elimination Reactions Dehydrohalogenation (-X) and Dehydration (- 2 O) are the main types of elimination reactions. 3 O 2 SO 4, 2 O TF, 50 o 3 2 O X Y X Y 25 Dehydrohalogenation (-X) strong base " X " X 1) E1 mechanism This reaction is done in strong base at low concentration, such as 0.01 M NaO in water) Br slow water helps to stabilize carbocation _ Br X = l, Br, I 2).. O : fast.. O E2 mechanism This reaction is done in strong base at high concentration, such as 1 M NaO in water... O :.. Br.. O : _ Br concerted mechanism 5

The E2 Mechanism Energy Diagram for the E2 Mechanism Effect of the Substrate on E2 Reactivity Effect of the LG on E2 Reactivity The E1Mechanism 6

Let s look at an E1 reaction mechanism using the rxn shown below. The E1 Mechanism First Step: Same as S N 1 The first step of the E1 and S N 1 mechanisms are identical. The E1 Mechanism Energy Diagram for E1 7

S N 2 3 O Br 3 O S N 1 3 O Br 3 O E1 3 O Br E2 3 O Br The Zaitsev Rule What about dehydrohalogenations involving RX with hydrogen atoms on different β carbon atoms The Zaitsev Rule- A Regioselective Rxn The Zaitsev Rule (Z-rule) Two possible organic products. Which is the major product? According to the Z-rule, the major product in a dehydrohalgenation is the.. KO( 3 ) 3 most stable product. l 8

Let s ask a different question about the products. Elimination Reactions l KO( 3 ) 3 Which is the most stable product? A compound with an electronegative atom bonded to an sp 3 carbon, when approached by a nucleophile/base can undergo either a substitution reaction OR an elimination reaction Elimination Reactions The E2 Mechanism There are 2 kinds of elimination reactions, E1 and E2. E2 = Elimination, Bimolecular (2nd order). Rate = k [RX] [Nu: - ] E2 reactions occur when a 2 or 3 alkyl halide is treated with a strong base such as O -, OR -, N 2-, -, etc. O - α Br- O β Br The Nu: - removes an from a β-carbon & the halogen leaves forming an alkene. All strong bases, like O -, are good nucleophiles. In 2 and 3 alkyl halides the α-carbon in the alkyl halide is hindered. In such cases, a strong base will abstract (remove) a hydrogen ion () from a β-carbon, before it hits the α-carbon. Thus strong bases cause elimination (E2) in 2 and 3 alkyl halides and cause substitution (S N 2) in unhindered methyl and 1 alkyl halides. The E2 Mechanism E2: Deprotonation is First Step The E2 Mechanism Energy Diagram 9

The E2 Mechanism The E2 Mechanism Reaction proceeds by Anti Elimination The Zaitsev (Saytzeff) Rule Z Rule What about dehydrohalogenations involving RX with hydrogen atoms on different β carbon atoms The Zaitsev (Saytzeff) Rule Z Rule In reactions of removal of hydrogen halides from alkyl halides or the removal of water from alcohols, the hydrogen which is lost will come from the more highly-branched β-carbon. More branched γ β α β Less branched A. N. Zaitsev -- 1875 3 X The Zaitsev (Saytzeff) Rule Z Rule Two possible organic products. Which is the major product? The Zaitsev (Saytzeff) Rule Z Rule According to the Z-rule, the major product in a dehydrohalgenation is the.. l KO( 3 ) 3 most stable product. 10

The Zaitsev (Saytzeff) Rule Z Rule Let s ask a different question about the products. l KO( 3 ) 3 Which is the most stable product? The Zaitsev (Saytzeff) Rule Z Rule When alkyl halides have two or more different β carbons, more than one alkene product is formed. When this happens, one of the products usually predominates. The major product is the more stable product the one with the more substituted double bond. This phenomenon is called the Zaitsev rule. The Zaitsev (Saytzeff) Rule Z Rule When a mixture of stereoisomers is possible from a dehydrohalogenation, the major product is the more stable stereoisomer. A reaction is stereoselective when it forms predominantly or exclusively one stereoisomer when two or more are possible. The E2 reaction is stereoselective because one stereoisomer is formed preferentially. The E2 Reaction: Regioselectivity 2-bromobutane has two structurally different β-carbons from which to abstract a hydrogen E2 reactions give more stable alkene if possible The E2 Reaction: Regioselectivity The E2 Reaction: Regioselectivity Zaitsev s rule (Saytzeff Rule): The more substituted alkene will be formed in elimination reactions Zaitsev s rule does not apply when the base is bulky E2 Rxn is kinetically-controlled 11

The E2 Reaction: Regioselectivity The E2 Reaction: Regioselectivity Zaitsev s rule does not apply when the leaving group is poor E2-carbanion mechanism operative Zaitsev s rule may not apply when conjugated dienes might be formed 3 2 2 3 l O 2 3 major product 3 2 2 3 3 The E2 Reaction: Regioselectivity The major product of an E2 reaction is the more substituted alkene unless: the base is large (i.e. bulky) the leaving group is poor (i.e. F ) the less substituted β carbon is allylic benzylic (ie. more stable) or The E2 Reaction: Stereochemistry If the elimination reaction removes two substituents from the same side of the molecule it is syn elimination If the elimination reaction removes two substituents from opposite sides of the molecule it is anti elimination The E2 Reaction: Stereochemistry The E2 Reaction: Stereochemistry In an E2 reaction, the bonds to the eliminated substituents must be in the same plane In this course E2 eliminations will all go via antiperiplanar conformation Product analysis possible by drawing Newman projections if only 1 β is available The E2 Reaction is stereoselective, but not stereospecific if 2 β s are available on carbon bearing eliminated The leading to more stable E isomer is selected to be extracted from β carbon regardless of streochem at α carbon 12

The E2 Reaction: Stereochemistry Effect of the Substrate on E2 Reactivity When only one hydrogen is on the β carbon predominantly anti elimination leads to high stereospecificity (2S,3S)-2-bromo-3-phenylbutane (E)-2-phenyl-2-butene (2S,3R)-2-bromo-3-phenylbutane (Z)-2-phenyl-2-butene Effect of the LG on E2 Reactivity The E1 Reaction E1 stands for Elimination unimolecular The E1 reaction is a two-step reaction The first step is rate-determining The E1 Mechanism The E1 Mechanism First Step: Same as S N 1 13

The E1 Mechanism The E1 Pathway ompetes with S N 1 Mechanisms of Elimination E1 The dehydrohalogenation of ( 3 ) 3 I with 2 O to form ( 3 )= 2 can be used to illustrate the second general mechanism of elimination, the E1 mechanism. An E1 reaction exhibits first-order kinetics: rate = k[( 3 ) 3 I] The E1 reaction proceed via a two-step mechanism: the bond to the leaving group breaks first before the π bond is formed. The slow step is unimolecular, involving only the alkyl halide. The E1 and E2 mechanisms both involve the same number of bonds broken and formed. The only difference is timing. In an E1, the leaving group comes off before the β proton is removed, and the reaction occurs in two steps. In an E2 reaction, the leaving group comes off as the β proton is removed, and the reaction occurs in one step. Mechanisms of Elimination E1 The E1 Reaction E1 reaction involves a carbocation Therefore rearrangements must be considered The E1 Mechanism Several Products are Possible The E1 Reaction: Stereochemistry With both syn and anti elimination can occur, so E1 reaction forms both E and Z products regardless of whether β-carbon is bonded to one or two s Product stability leads to stereoselectivity but not stereospecificity 14