A NOTE ON RANDOM MATRIX INTEGRALS, MOMENT IDENTITIES, AND CATALAN NUMBERS

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A NOTE ON RANDOM MATRIX INTEGRALS, MOMENT IDENTITIES, AND CATALAN NUMBERS NICHOLAS M. KATZ 1. Introduction In their paper Random Matrix Theory and L-Functions at s = 1/2, Keating and Snaith give explicit formulas [Ke-Sn, (10) on page 94] for the matrix integrals det(1 A) s da. Here is the compact symplectic group of size 2n, da is its Haar measure of total mass one, and det(1 A) is computed for the standard representation of A as a matrix of size 2n. Because the group contains the scalar matrix 1, and because Haar measure is translation invariant, we have det(1 A) s da = det(1 + A) s da. Their formula, valid for s C with R(s) > 3/2, is n det(1 + A) s da = 2 2ns Γ(n + j + 1)Γ(1/2 + s + j) Γ(1/2 + j)γ(1 + s + n + j). j=1 We were particularly interested in the case when s is an integer r 1. Out of idle curiosity, we looked what their formula gave for the case n = 1, when USp(2) is the group, and for integer values of r 1. For r = 1, 0, 1,..., 9, we found the sequence 1, 1, 2, 5, 14, 42, 132, 429, 1430, 4862, 16796, which is the start of the sequence of Catalan numbers C n, indexed by integers n 0: C n := 1 ( ) 2n. n + 1 n This made it seem likely that for every integer r 1, we had the relation det(1 + A) r da = C r+1. We will show Theorem 1.1. For every integer r 1, we have the relation det(1 + A) r da = C r+1. 1

2 NICHOLAS M. KATZ The Catalan numbers are themselves matrix integrals over. For integers r 0 we have C r = Tr(A) 2r da, 0 = Tr(A) 2r+1 da. So from Theorem 1.1, we have the identity, for integers r 0, Tr(A) 2r+2 da = det(1 + A) r da. For, we have the identity det(1 + A) = 2 + Tr(A). When we expand (2 + Tr(A)) r by the binomial theorem, we find the identity Corollary 1.2. C r+1 = 0 d r/2 ( ) r 2 r 2d C d. 2d This identity is presumably (?) known to Catalan experts. We then looked at what the Keating-Snaith formula gave for the case n = 2, i.e. for the group, and for integer values of r 1. For r = 1, 0, 1,..., 7, we found the sequence 1, 1, 3, 14, 84, 594, 4719, 40898, 379236. Inspired by what had happened in the case, we computed (using Mathematica) the integrals Tr(A) 2r+2 da for r = 1, 0, 1,..., 7, and found this same sequence. This led us to suspect that we had the identity det(1 + A) r da = Tr(A) 2r+2 da for every r 0. We will show Theorem 1.3. For every integer r 1, we have det(1 + A) r da = Tr(A) 2r+2 da. However, this identity failed for every n 3. Already for r = 1, the Keating- Snaith formula gives det(1 + A)dA = n + 1. However, one knows that for every n 2, one has Tr(A) 4 da = 3. What is to be done? It turns out that in order to understand the Keating-Snaith integrals det(1 + A) r da

A NOTE ON RANDOM MATRIX INTEGRALS, MOMENT IDENTITIES, AND CATALAN NUMBERS3 along these lines, we must introduce the compact Spin group U Spin(2n + 1) (the universal covering of the group SO(2n + 1, R) for the sum of squares quadratic form) and its 2 n -dimensional spin representation. The general result is this. Theorem 1.4. For n 1 and r 0, we have the identity det(1 + A) r da = Tr(spin(A)) 2r+2 da. This result includes the identities for USp(2) = and for. Indeed, for n = 1 and n = 2, we have the accidents that is the group and that the spin representation of U Spin(2n + 1) is the standard representation of. 2. Proof of Theorem 1.4, via the Weyl integration formula For a group G, we denote by G # its space of conjugacy classes. When G is a topological group, we topologize G # so that continuous functions on G # are precisely the continuous central (invariant by conjugation) functions on G. The function det(1+a) is a continuous central function on with values in R 0, and the function Tr(spin(A)) is a continuous central function on with values in R. An element A has n pairs of eigenvalues e ±iθj, j = 1,..., n, with angles θ j [0, π], and A is determined up to conjugacy by the unordered n-tuple of its θ j s. So a continuous (respectively Borel measurable and R 0 -valued) central function A f(a) on # is a continuous (respectively Borel measurable and R 0 -valued) function f(θ 1,..., θ n ) on [0, π] n which is invariant under the symmetric group S n. For such a function f, the Weyl integration formula, cf. [Ka-Sar, 5.0.4] or [ Weyl, p. 218, (7.8B)], asserts that f(a)da = f(θ 1,..., θ n )µ, [0,π] n for µ the measure on [0, π] n given by µ = (1/n!)( (2 cos(θ i ) 2 cos(θ j )) 2 ) (2/π) sin(θ i ) 2 dθ i. 1 i<j n An element A SO(2n + 1, R) has the eigenvalue 1, and in addition it has n pairs of eigenvalues e ±iθj, j = 1,..., n, with angles θ j [0, π], and A is determined up to conjugacy by the unordered n-tuple of its θ j s. So a continuous (respectively Borel measurable and R 0 -valued) central function A f(a) on # is a continuous (respectively Borel measurable and R 0 -valued) function f(θ 1,..., θ n ) on [0, π] n which is invariant under the symmetric group S n. For such a function f, the Weyl integration formula, cf. [Ka-Sar, 5.0.5] or [ Weyl, p. 224, (9.7)], asserts that f(a)da = f(θ 1,..., θ n )µ, [0,π] n

4 NICHOLAS M. KATZ for µ the measure on [0, π] n given by µ = (1/n!)( 1 i<j n (2 cos(θ i ) 2 cos(θ j )) 2 ) (2/π) sin(θ i /2) 2 dθ i. Notice the similarity between the formulas for the measures µ and µ. The only difference is that each factor sin(θ i ) 2 in the first is replaced by sin(θ i /2) 2 in the second. The key lemma is this. Lemma 2.1. The measures µ and µ on [0, π] n are related by the identity µ = ( (2 + 2 cos(θ i ))µ. Proof. This is immediate from the trig identity whose verification is left to the reader. (2 + 2 cos(θ)) sin(θ/2) 2 = sin(θ) 2, The factor n (2 + 2 cos(θ i)) has the following two interpretations.. Lemma 2.2. We have the following identities. (1) For A SO(2n + 1, R) with eigenvalues 1 and n pairs of eigenvalues e ±iθj, j = 1,..., n, with angles θ j [0, π], (1/2) det(1 + A) = (2 + 2 cos(θ i )). (2) For A with n pairs of eigenvalues e ±iθj, j = 1,..., n, with angles θ j [0, π], det(1 + A) = (2 + 2 cos(θ i )). The spin representation of U Spin(2n + 1) does not descend to SO(2n + 1, R), but its tensor square spin 2 does. In terms of the standard representation std 2n+1 of SO(2n + 1, R), and the double covering projection map one knows [Var, Lemma 6.6.2] that p : USpin(2n + 1) SO(2n + 1, R), spin 2 = ( n Λ i (std 2n+1 )) p. i=0 Each representation Λ i (std 2n+1 ) is self-dual, and hence isomorphic to Λ 2n+1 i (std 2n+1 ). So we have 2n+1 2spin 2 = ( Λ i (std 2n+1 )) p. i=0 For A SO(2n + 1, R) (indeed for A GL(2n + 1, C)) we have the identity Λ i (A)) = det(1 + A). 2n+1 Tr( i=0

A NOTE ON RANDOM MATRIX INTEGRALS, MOMENT IDENTITIES, AND CATALAN NUMBERS5 So for any B USpin(2n + 1) lying over A, we have Tr(spin(B)) 2 = (1/2) det(1 + A). For any continuous function g on SO(2n+1, R), with pullback function G := g p on USpin(2n + 1), we have G(A)dA = g(a)da, simply because the direct image of Haar measure is Haar measure for any surjective homomorphism of compact groups, cf. [Ka-Sar, Lemma 1.3.1]. Putting this all together, we have, for r 1, det(1 + A) r da = (2 + 2 cos(θ i ))) r µ = ( [0,π] n = = ( [0,π] n (2 + 2 cos(θ i ))) r+1 µ This concludes the proof of Theorem 1.4. ((1/2) det(1 + A)) r+1 da Tr(spin(A)) 2r+2 da. Remark 2.3. The odd moments of the spin representation all vanish: Tr(spin(A)) 2r+1 da = 0 for all r 0. Indeed, this integral is the multiplicity of spin in the representation spin 2r, a representation which descends to SO(2n + 1, R). Hence all of its irreducible constituents also descend to SO(2n + 1, R). But none of these irreducible components can be isomorphic to spin, because the spin representation does not descend to SO(2n + 1, R). 3. A Catalan determinant interpretation Theorem 3.1. For integers n 1 and r 0, we have the (equivalent) identities Tr(spin(A)) 2r da = det (C r+i+j ), n n 0 i,j n 1 2 r det(1 + A)) r da = det (C r+i+j ), n n 0 i,j n 1 det(1 + A) r da = det (C r+1+i+j ). n n 0 i,j n 1 Proof. This is simply a matter of comparing the Keating-Snaith formula for det(1 + A) r da with the formula, cf. [Krat, Theorem 3] and [Ge-Vi, page 21, line 6], of Gessel- Viennot for the Catalan determinant, and checking that the two formulas give the

6 NICHOLAS M. KATZ same answer. Each is a product of n terms. The individual terms don t quite match, but their ratios turn out to have product one. Remark 3.2. For n = 1, 2, 3, 4, 5, these sequences of n n Catalan determinants indexed by r appear in the Online Encyclopedia of Integer Sequences [OEIS] as the sequences A000108, A005700, A006149, A006150, A006151 respectively.the interpretation of A000108, the sequence of Catalan numbers, as the even moments of the standard representation of is classical.the interpretation of A005700 as the sequence of even moments of the standard representation of U Sp(4) occurs in [Ked-Suth, (11) on page 131]. For higher n, the moment interpretation of these determinants seems to be new. Is it? Our proof of Theorem 1.4, det(1 + A) r da = 4. A question Tr(spin(A)) 2r+2 da, via the Weyl integration formula, comes down to the trig identity of Lemma 2.1. From the point of view of representation theory, the first integral is, for r 0, the multiplicity of the trivial representation in the r th tensor power of the exterior algebra Λ(std 2n ) := 2n k=0 Λk (std 2n )) as a representation of. The second integral is the multiplicity of the trivial representation in the 2r +2 nd tensor power of the spin representation of. Is there a representation theoretic proof that they are equal? References [Ge-Vi] Gessel, I., Viennot, X. Determinants, Paths, and Plane Partitions, 1989 preprint, available at http://www.cs.brandeis.edu/ ira. [Ka-Sar] Katz, N. M., Sarnak, P. C., Random matrices, Frobenius eigenvalues, and monodromy. American Mathematical Society Colloquium Publications, 45. American Mathematical Society, Providence, RI, 1999. xii+419 pp. [Ke-Sn] Keating, J. P., Snaith, N. C., Random matrix theory and ζ(1/2+it). Comm. Math. Phys. 214 (2000), no. 1, 57-89. [Ked-Suth] Kedlaya, K., Sutherland, A., Hyperelliptic curves, L-polynomials, and random matrices. Arithmetic, geometry, cryptography and coding theory, 119-162, Contemp. Math., 487, Amer. Math. Soc., Providence, RI, 2009. [Krat] Krattenthaler, C. Determinants of (generalised) Catalan numbers. J. Statist. Plann. Inference 140 (2010), no. 8, 2260-2270. [Var] Varadarajan, V. S. Supersymmetry for mathematicians: an introduction. Courant Lecture Notes in Mathematics, 11. New York University, Courant Institute of Mathematical Sciences, New York; American Mathematical Society, Providence, RI, 2004. [OEIS] Sloane, N.,, The on-line encyclopedia of integer sequences, https://oeis.org/. [ Weyl] Weyl, H.,Classical Groups. Princeton University Press, Princeton, N.J., 1946 Princeton University, Mathematics, Fine Hall, NJ 08544-1000, USA E-mail address: nmk@math.princeton.edu